Ok. I have some data in one table, that references on multiple occasions some data in another table.
Table1 - main client table
Table2 - user defined fields
Say I have a query that shows a client id from Table1 and all attached / used "used defined fields" from Table2
SELECT t1.Id, t2.udf
FROM Table1 t1
JOIN Table2 t2 ON t1.Id = t2.Index
WHERE t1.EndDate IS NULL AND
t1.Id = '1234.9876' AND
I would get the following for a result...
ID UDF
1234.9876 100
1234.9876 110
1234.9876 118
1234.9876 124
1234.9876 198
1234.9876 256
Now, say I wanted to query this same thing, and get ONLY the ID of the Client, but ONLY IF a value for t2.udf equaling '194' did not exist. So, I would simply get
ID
1234.9876
...as a result.
Make the join a LEFT join and filer where t2.Index is null
SELECT t1.Id
FROM Table1 t1
LEFT JOIN Table2 t2 ON t1.Id = t2.Index
AND t2.UDF = 194 -- has to be before where clause
WHERE t2.Index IS NULL
AND t1.EndDate IS NULL
AND t1.Id = '1234.9876' -- not sure if you want this part
Another way by using NOT EXISTS
SELECT t1.Id
FROM Table1 t1
WHERE NOT EXISTS (SELECT 1 FROM Table2 t2 WHERE t1.Id = t2.INDEX
AND t2.UDF = 194)
AND t1.EndDate IS NULL
AND t1.Id = '1234.9876'
See also JOINS
You can add AND t2.udf not in (select udf from table2 where udf <> '194').
But #SQLMenace solution is better
This should do it.
SELECT DISTINCT t1.Id
FROM Table1 t1
LEFT JOIN Table2 t2 ON t1.Id = t2.Index
WHERE t2.UDF NOT IN (194)
AND t2.Index IS NULL
Select DISTINCT gives you unique entries that satisfy the other conditions, and the first where clause
t2.UDF NOT IN (194)
Normall would return all the rows for the t1 where the t2.UDF is not 194, but it is limited by the Select Distinct to give you only distinct id's
Try the following:
SELECT t1.Id
FROM Table1 t1
JOIN Table2 t2 ON t1.Id = t2.Index
WHERE t1.EndDate IS NULL AND
t1.Id = '1234.9876' AND
t2.udf <> '194'
Related
I have two tables as such.
t1
id name
1 foo
2 bar
t2
tid id address
1 1 foss
I can execute select satement to select id 1 from t1 from both tables.
select * from t1 inner join t2 on (t1.id = 1 and t2.id = 1)
But, what I actually want is select bar from t1, and only bar, even though it isn't present in t2.
The above tables are similar to what I have been working on my project, and resembles to the same problem.
Here is what I tried.
1. I used left join t1.id = 2 and t2.id = 2
It lists all the values from t1, which I only wanted t1.id = 2.
2.inner join could be used, but since t2.id = 2 is not present.
Therefore, it doesn’t return anything.
But I wanted something that would display data from t1 and t2 if id is present in both tables, and if not display only from table t1 of only that id.
So, if I wanted to display t1.id = 2, the answer I would expect is using
select * from t1 join .....
id name tid id address
2 bar null null null
Based on your expected result this is a simple Left Join:
select *
from t1 left join t2
on t1.id = t2.id
where t1.id = 2
Use left join to get all elements of t1 even if a element of t2 with same id not exists.
Then use null to get only t1 when t2 not exists.
At last, you can add a where filter to get a subset of t1 (ie: id = 2)
SELECT t1.*, t2.*
FROM t1
LEFT JOIN t2
ON t1.id = t2.id
WHERE t2.id IS NULL
AND t1.id = 2;
Please consider this query:
SELECT table1.* ,
(SELECT quantity FROM table2 WHERE id = table1.id AND table2.location = 10) quantity,
(SELECT reorder_level FROM table2 WHERE id = table1.id AND table2.location = 10) reorder_level,
(SELECT stock_date FROM table2 WHERE id = table1.id AND table2.location = 10) stock_date
FROM table1
WHERE category_id = 5 ORDER BY table1.id;
The aliases quantity, location and stock_date are obviously referencing a a row in table2 that fulfill the condition: id=table1.id and location=10.
This query works, but is probably suboptimal as a result of the clumsy subqueries.
How can I best join table1 to table2 USING(id) but only on rows where location is also 10.
TIP: One row from table1 has many rows in table2.
Unfortunately, the actual table definitions are much more complex, and I reckoned it might be counter-productive to dump the entire thing on this thread.
You can use additional condition in ON() part so it will join only rows which fulfills the provided criteria
SELECT t1.* ,
t2.quantity ,
t2.reorder_level,
t2.stock_date
FROM table1 t1
LEFT JOIN table2 t2 ON t1.id = t2.id AND t2.location = 10
WHERE t1.category_id = 5
ORDER BY t1.id;
Another way would be use a subselect for your table2 and select only rows where location is equal to 10
SELECT t1.* ,
t2.quantity ,
t2.reorder_level,
t2.stock_date
FROM table1 t1
LEFT JOIN
(SELECT * FROM table2 WHERE t2.location = 10) t2
ON t1.id = t2.id
WHERE t1.category_id = 5
ORDER BY t1.id;
I have some SQL code that returns me some data from DB
SELECT t1.id as id, title, description FROM table1 t1
JOIN table2 t2 ON t1.id = t2.t1_id
WHERE t2.t3_id IN( SELECT id FROM table3 WHERE parent_id IN ( SELECT id FROM table3 WHERE parent_id = 1)) GROUP BY t1.id
I have some problem with counting number of rows of result. I know that I have to write almost the same code but with COUNT but I have there A problem, my code doesn't return me a number of rows.
Just use the COUNT(*) function. Also, your subqueries can be converted to a JOIN (and your sub-subquery is redundant):
SELECT COUNT(*)
FROM table1 t1
JOIN table2 t2
ON t1.id = t2.t1_id
JOIN table3 t2
ON t3.id = t2.t3_id
WHERE t3.parent_id = 1
I have the 2 following tables t1, t2 with values,
t1 t2
1 4
2 2
3 3
Now I want to output
1
4
How can I get this output in select query ?
This will get you each item from t1 that is not present in t2, and each item in t2 that is not present in t1:
select t1.id from t1
left join t2 on t2.id = t1.id
where t2.id is null
union all
select t2.id from t2
left join t1 on t1.id = t2.id
where t1.id is null
(I have assumed that the field name in each table is named id just for the sake of being able to write a query against the tables.)
Another way would be:
select coalesce(t1.id, t2.id)
from t1
full outer join t2 on t2.id = t1.id
where t1.id is null or t2.id is null
Another way. Just COUNT them.
This works if the values are unique per table
SELECT
CombinedValue
FROM
(
SELECT t1 AS CombinedValue FROM t1
UNION ALL
SELECT t2 FROM t2
) foo
GROUP BY
CombinedValue
HAVING
COUNT(*) = 1
If not unique per table
SELECT
CombinedValue
FROM
(
SELECT DISTINCT t1 AS CombinedValue FROM t1
UNION ALL
SELECT DISTINCT t2 FROM t2
) foo
GROUP BY
CombinedValue
HAVING
COUNT(*) = 1
you can use Joins in MySql to proceed and to obtain result.
this will help you
http://www.techrepublic.com/article/sql-basics-query-multiple-tables/1050307
I currently have a query
SELECT id FROM table1 WHERE {filters on table1} AND id NOT IN (SELECT table1ID FROM table2 WHERE condition = 0)
Table1 has a 1 - Many relationship with table2 and I'm looking for all the IDs that have no entries in table2 with condition=0.
Is there any way to rewrite this query without the inner select? I'm been scratching my head about it for a while now and any pointers would be welcome.
You can try something like
SELECT id
FROM table1 t1 LEFT JOIN
table2 t2 ON t1.ID = t2.table1ID
AND t2.Condition = 0
WHERE {filters on table1}
AND t2.table1ID IS NULL
Or just as good would be
SELECT id
FROM table1 t1
WHERE {filters on table1}
AND NOT EXISTS (
SELECT 1
FROM table2 t2
WHERE t1.ID = t2.table1ID
ADN t2.condition = 0
)