I need a column from row value.
I have two table.
Table 1 : working_day Contains list of all working day date.
date
--------
2013-03-30
2013-03-29
2013-03-28
Table 2 : entry contains each employee in and out time.
id In Out Date
1 9 0 2013-03-30
2 8 0 2013-03-30
3 7 0 2013-03-30
1 8 18 2013-03-29
2 9 16 2013-03-29
3 6 20 2013-03-29
4 12 15 2013-03-29
Expected Output :
ID 29-03-2013_IN 29-03-2013_Out 30-03-2013_In
1 8 18 9
2 9 16 8
3 6 20 7
4 12 15 0
Tried :
SELECT id,
Case condition1 for 29_in, // I don't know which condition suite here.
Case condition1 for 29_out,
Case condition1 for 30_in
FROM entry
WHERE DATE
IN (
SELECT *
FROM (
SELECT DATE
FROM working_day
ORDER BY DATE DESC
LIMIT 0 , 2
)a
)
You could try something like that:
select
e.id,
(SELECT `in` FROM entry WHERE id = e.id AND date = '2013-03-30') as '2013-03-30_in',
(SELECT `in` FROM entry WHERE id = e.id AND date = '2013-03-29') as '2013-03-29_in',
(SELECT `out` FROM entry WHERE id = e.id AND date = '2013-03-29') as '2013-03-29_out'
from entry e
group by e.id;
Here is Demo
IMO you should do this in application instead of SQL
Related
I am working on a program that will track a salespersons sold units, these units can be full deals (1) or half deals (0.5). What I need to do is find a way to get the SUM of the full deals and the half deals grouped by a salespersons ID.
Here is the database structure:
id
salesperson_id
salesperson_two_id
sold_date
1
5
null
2022-07-02
2
3
5
2022-07-18
3
4
null
2022-07-16
4
5
3
2022-07-12
5
3
5
2022-07-17
6
5
null
2022-07-18
I have a query that works if I only want to retrieve the SUM for one salesperson:
SELECT
SUM(case when salesperson_id = 5 and isnull(salesperson_two_id) then 1 end) as fullDeals,
SUM(case when salesperson_id != 5 and salesperson_two_id = 5
or salesperson_id = 5 and salesperson_two_id != 5 then 0.5 end) as halfDeals
FROM sold_logs WHERE MONTH(sold_date) = 07 AND YEAR(sold_date) = 2022;
Output would be as expected:
fullDeals
halfDeals
2
1.5
What I am trying to accomplish is get these results for all salespeople in the table and have no clue how to make it happen. Here is what I am trying to get in the results:
salesperson_id
totalDeals
5
3.5
3
1.5
4
1
I would like the results sorted by totalDeals if at all possible.
Use UNION ALL to get a resultset with all the rows for each salesperson, filter for the month that you want and aggregate:
SELECT salesperson_id,
SUM(CASE WHEN salesperson_two_id IS NULL THEN 1 ELSE 0.5 END) totalDeals
FROM (
SELECT salesperson_id, salesperson_two_id, sold_date FROM sold_logs
UNION ALL
SELECT salesperson_two_id, salesperson_id, sold_date FROM sold_logs WHERE salesperson_two_id IS NOT NULL
) t
WHERE MONTH(sold_date) = 7 AND YEAR(sold_date) = 2022
GROUP BY salesperson_id
ORDER BY totalDeals DESC;
See the demo.
I have 3 tables that I have joined in the MySQL query below. All works well EXCEPT I would like the timeadj value with a 1 in column countingtime
to show from table 'data', not the first timeadj value the query finds.
I know this needs to be a query within a query but I am going around in circles and getting no where.
SELECT ttt_entries.tttid, ttt_teams.teamname, data.RacersInTeam,
ttt_entries.CoffeeClass, SEC_TO_TIME(data.timeadj),
COUNT(IF(data.division=5,1,NULL)) 'A+',
COUNT(IF(data.division=10,1,NULL)) A,
COUNT(IF(data.division=20,1,NULL)) B,
COUNT(IF(data.division=30,1,NULL)) C,
COUNT(IF(data.division=40,1,NULL)) D
FROM ttt_entries
INNER JOIN ttt_teams
ON ttt_entries.tttid = ttt_teams.tttid
INNER JOIN (SELECT * FROM data ORDER BY data.countingtime DESC) as data
ON ttt_entries.tttid = data.teamid
WHERE ttt_entries.eventDate = DATE_ADD(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE()) >4, -5, 2) + DAYOFWEEK(CURDATE())) * -1 DAY) -- last Thursday
AND data.wtrlid = '22'
GROUP BY ttt_teams.tttid
ORDER BY data.timeadj ASC
For example.... In Team 1 (data.teamid=1) there are 8 time values in timeadj. In the adjacent column (countingtime) is a value either 1 or 0 but only ever 1x 1 per team.
Table ttt_entries
ID tttid CoffeeClass
1 23 Mocha
2 52 Espresso
3 6 Frappe
Table ttt_teams
tttid Name
6 Team A
23 Team 1
52 Team 2
Table 'data'
id wtrlid teamid timeadj countingtime division
1 22 23 3467.123 0 10
2 22 23 3467.125 0 20
3 22 23 3467.432 0 10
4 22 23 3469.000 1 10
5 22 23 3469.112 0 10
6 22 23 3468.987 0 5
My code brings back
tttid teamname RacersInTeam CoffeeClass Time A+ A B C D
23 Team 1 6 Mocha 3467.123 1 4 1 0 0
I need it to bring back the same data but a different time:
tttid teamname RacersInTeam CoffeeClass Time A+ A B C D
23 Team 1 6 Mocha 3469.000 1 4 1 0 0
You can try below way -
SELECT ttt_entries.tttid, ttt_teams.teamname, data.RacersInTeam,
ttt_entries.CoffeeClass, SEC_TO_TIME(max(case when countingtime=1 then data.timeadj end)),
COUNT(IF(data.division=5,1,NULL)) 'A+',
COUNT(IF(data.division=10,1,NULL)) A,
COUNT(IF(data.division=20,1,NULL)) B,
COUNT(IF(data.division=30,1,NULL)) C,
COUNT(IF(data.division=40,1,NULL)) D
FROM ttt_entries
INNER JOIN ttt_teams
ON ttt_entries.tttid = ttt_teams.tttid
INNER JOIN (SELECT * FROM data ORDER BY data.countingtime DESC) as data
ON ttt_entries.tttid = data.teamid
WHERE ttt_entries.eventDate = DATE_ADD(CURDATE(), INTERVAL (IF(DAYOFWEEK(CURDATE()) >4, -5, 2) + DAYOFWEEK(CURDATE())) * -1 DAY) -- last Thursday
AND data.wtrlid = '22'
GROUP BY ttt_teams.tttid
ORDER BY data.timeadj ASC
Currently I am honestly at loss what I am doing wrong. It is a rather simple query I think.
Tables:
operations:
id processedon clientid
1 2018-01-01 9
2 2018-03-16 9
3 2018-04-21 9
4 2018-04-20 9
5 2018-05-09 9
items:
id operation_id quantity unitprice
1 1 10 2
2 1 5 3
3 2 20 4
4 3 10 2
5 4 8 4
6 4 10 4
7 5 2 2
The expected result of the operation/query is:
month total_value
1 35
3 80
4 92
5 4
That is quantity * unitprice based. For some reason, it only returns month=4
SELECT
month(`operations`.`processedon`) AS `month`,
SUM((`items`.`quantity` * `items`.`unitprice`)) AS `total_value`
FROM `items`
INNER JOIN `operations` ON (`items`.`operation_id` = `operations`.`id`)
GROUP BY 'month'
ORDER BY 'month'
According to the info provided the join should be
INNER JOIN operations ON items.operation_id = operations.id
Eg
SELECT
month(`operations`.`processedon`) AS `month`,
SUM((`items`.`quantity` * `items`.`unitprice`)) AS `total_value`
FROM `items`
INNER JOIN `operations` ON `items`.`operation_id` = `operations`.`id`
GROUP BY month(`operations`.`processedon`)
ORDER BY `month`
There is no efficiency gain by using a column alias in the group by clause, I prefer to avoid using them except perhaps in the order by clause.
The following query will give you the required answer
SELECT
month(`operations`.`processedon`) AS `month`,
SUM((`items`.`quantity` * `items`.`unitprice`)) AS `total_value`
FROM items
INNER JOIN operations ON (items.operation_id = operations.id)
GROUP BY month(operations.processedon)
ORDER BY month(operations.processedon)
You need to specify month correctly since it is not an existing column.
You'll get the following result
month total_value
1 35
3 80
4 92
5 4
I have two tables e_sku and e_availability, In e_sku table i have 45 rows with the default availability as 1, below is an example
id is_available name
1 1 UN001N
2 1 UN002N
3 1 UN003N
4 1 UN004N
5 1 UN005N
6 1 UN006N
7 1 UN007N
8 1 UN008N
9 1 UN009N
10 1 UN010N
11 1 UN011N
12 1 UN012N
13 1 UN013N
14 1 UN014N
15 1 UN015N
16 1 UN016N
17 1 UN017N
18 1 UN018N
19 1 UN019N
20 1 UN020N
21 1 UN021N
22 1 UN022N
23 1 UN023N
24 1 UN024N
25 1 UN025N
26 1 UN026N
27 1 UN027N
28 1 UN028N
29 1 UN029N
30 1 UN030N
31 1 UN031N
32 1 UN032N
33 1 UN033N
34 1 UN034N
35 1 UN035N
36 1 UN036N
37 1 UN037N
38 1 UN038N
39 1 UN039N
40 1 UN040N
41 1 UN041N
42 1 UN042N
43 1 UN043N
44 1 UN044N
45 1 UN045N
Second table is e_availability in this table i am only storing the unavailability with dates below is the example
id e_sku_id is_available working_date
1 5 0 10/20/2016
2 8 0 10/20/2016
3 10 0 10/20/2016
4 1 0 10/20/2016
5 15 0 10/20/2016
6 11 0 10/19/2016
7 1 0 10/19/2016
Because the data is capturing every date for unavailability so i am only gathering the unavailable product's data in e_availability table w.r.t. dates, Now i am looking to show the data for each day as complete skus in such a way that every day report will show 45 skus and for available sku it will show 1 from e_sku table's column is_available and for unavailable sku it will show the column of is_availability from e_availability table
I am using mysql database, I tried many join queries but not getting the report.
can any one guide about which join i require
I got the result by using this query
SELECT * FROM (SELECT id,NAME,1 AS is_available FROM e_sku
WHERE company_id = 2
AND id NOT IN (SELECT id FROM (SELECT e_sku.id,e_sku.name, edge_availability.is_available FROM edge_availability
JOIN edge_working ON edge_working.`id` = edge_availability.`working_id`
JOIN e_sku ON e_sku.id = edge_availability.`sku_id`
WHERE edge_working.`working_date` = '2016-10-19' AND edge_availability.`store_id` = 84) X)
UNION
SELECT e_sku.id,e_sku.name, edge_availability.is_available FROM edge_availability
JOIN edge_working ON edge_working.`id` = edge_availability.`working_id`
JOIN e_sku ON e_sku.id = edge_availability.`sku_id`
WHERE edge_working.`working_date` = '2016-10-19' AND edge_availability.`store_id` = 84) Y
ORDER BY id
You can use a LEFT JOIN to detect when a date isn't found in the e_availability table. The join will return NULL for all the columns in that table, then you can default to the value from e_sku.
SELECT d.date, s.id, IFNULL(a.is_available, s.is_available) AS is_available
FROM all_dates AS d
CROSS JOIN e_sku AS s
LEFT JOIN e_availability ON d.working_date = a.date AND s.id = a.e_sku_id
You need to create an additional table all_dates that contains all the dates that you want to report on. See What is the most straightforward way to pad empty dates in sql results (on either mysql or perl end)? for how you can create such a table dynamically.
I have a schema like the following
id (INT)
Cycle_Number (INT)
Cycle_Day (INT)
Date (date)
...other columns irrelevant to the question...
How can I get the row that has the max Cycle_Day within the max Cycle_Number
For example, say I have the following data
ID Cycle_Number Cycle_Day Date
1 1 1 2011-12-01
2 1 2 2011-12-02
3 2 1 2011-12-03
4 2 2 2011-12-04
5 2 3 2011-12-05
6 2 4 2011-12-06
7 3 1 2011-12-07
8 3 2 2011-12-08
9 3 3 2011-12-09
The query would return row 9. (It has the highest Cycle_Day within the highest Cycle_Number)
Thanks
this one is compatible MySql 5.5 with no joint tables
SELECT id
FROM cycles
ORDER BY Cycle_Number DESC , Cycle_Day DESC
LIMIT 0 , 1
Regards
This SQL query should provide the max value you want.
SELECT ID, Cycle_Number, Cycle_Day, Date
FROM yourTable AS t
CROSS JOIN (
SELECT MAX(Cycle_Number) AS Cycle_Number FROM yourTable
) AS sq USING (Cycle_Number)
ORDER BY Cycle_Day DESC LIMIT 1