Convert Values to top 10 scale - mysql

Here is the problem. I have four columns that I want to present in a select query.
But, I want the RSV column to have a 10-1 scale instead of its + and - values.
The greatest number +8,6 should get 10. Several of the values in the bottom can have 1.
I have absolutley no idea how to solve this...
Nr is race horses start number.
A race can also contain less than fifteen horses
Nr RPO RSP RSV
1 10 9 +5,3
2 9 10 +8,6
3 8 7 -2,7
4 7 8 +3,8
5 6 4 +4,3
6 5 6 -1,0
7 4 5 +3,3
8 3 1 +6,6
9 2 1 +2,1
10 1 1 +3,8
11 1 3 +2,9
12 1 2 -2,1
13 1 1 +1,0
14 1 1 -1,0
15 1 1 +2,4
Last column shows the output:
Nr RPO RSP RSV RSVOutput
2 9 10 8,6 10
8 3 1 6,6 9
1 10 9 5,3 8
5 6 4 4,3 7
4 7 8 3,8 6
10 1 1 3,8 5
7 4 5 3,3 4
11 1 3 2,9 3
15 1 1 2,4 2
9 2 1 2,1 1
13 1 1 1 1
6 5 6 -1 1
14 1 1 -1 1
12 1 2 -2,1 1
3 8 7 -2,7 1
SELECT *
FROM rank
ORDER BY Nr


You could use something like this:
SELECT
Nr, RPO, RSP, RSV,
CASE WHEN #row>1 THEN #row:=#row-1 ELSE 1 END RSVOutput
FROM
yourtable, (SELECT #row:=11) rows
ORDER BY
RSV DESC
Please see fiddle here.

Related

How to add column in table grouped by value and max value in date column using sql query?

I have a table:
id date val
1 10.08.2022 10
1 12.08.2022 11
1 08.08.2022 15
1 16.08.2022 9
2 02.07.2022 2
2 01.07.2022 4
2 30.07.2022 7
I want to create two new columns last_v and max_v which are equal to last val for each id by date and maximum val per id. So desired output is:
id date val last_v max_v
1 10.08.2022 10 9 15
1 12.08.2022 11 9 15
1 08.08.2022 15 9 15
1 16.08.2022 9 9 15
2 02.07.2022 2 2 7
2 01.07.2022 4 2 7
2 30.06.2022 7 2 7
How could I do that?

You can use window functions!
select t.*,
first_value(val) over(partition by id order by dt desc) last_val,
max(val) over(partition by id) max_val
from mytable t
Demo on DB Fiddle:
id
dt
val
last_val
max_val
1
2022-08-08
15
9
15
1
2022-08-10
10
9
15
1
2022-08-12
11
9
15
1
2022-08-16
9
9
15
2
2022-06-30
7
2
7
2
2022-07-01
4
2
7
2
2022-07-02
2
2
7

calculating the average of marks from the beginning to this record

i have a table named test with the below structure like this
id mark join_id
1 5 1
2 4 1
3 9 1
4 5 2
5 7 2
6 12 2
i want to write a query that can get me the average of the marks from the beginning record to this record with the desired result as below
id mark join_id avg_of_previous_marks
1 5 1 5
2 4 1 4.5
3 9 1 6
4 5 2 5.75
5 7 2 6
6 12 2 7
i wrote this query but it doesn't seem to work correctly
SELECT test.id, test.mark, test.join_id, test_avg.avg_of_previous_marks FROM test
LEFT JOIN (SELECT id, join_id, AVG(mark) as avg_of_previous_marks FROM test GROUP BY
join_id) test_avg
ON test_avg.join_id = test.join_id AND test_avg.id <= test.id
and it gives this resault
id mark join_id avg_of_previous_marks
1 5 1 6
2 4 1 6
3 9 1 6
4 5 2 8
5 7 2 8
6 12 2 8

Its a simple running total that you need.
select id,mark,join_id, avg(mark) over (order by id) avg_of_previous_marks from test_avg ;
fiddle here

compare cell entries and return values In SAS

just would like to compare cell entries and return values.
coustmer_NO id A1 A2 A3 A4
1 5 10 20 45 0
1 13 0 45 2 5
2 4 0 10 7 8
2 3 7 9 55 0
2 10 0 0 0 0
3 4 90 8 14 3
3 10 20 7 4 15
how to count the ID that has (value > 030) for each customer_no
then, the min number of values before 030 appears.
The expected output would be something like:
cosutmer_no , count_ac_num , values
1 2 1
2 1 1
3 1 3

I would recommend converting to a more vertical structure. Then you can begin trying to apply your business logic, although I am having a hard time understanding what that is.
Assuming that the quotes are not meaningful (looks like someone had a string like "xxx" that had actual quote characters in it that was written to a CSV file and so extra quotes where added to protect the existing quotes so it became """xxx""") you could just use compress() function to remove them.
You could then just split the resulting string into 3 character substrings.
data want ;
set have ;
array h history1 history2 ;
do history=1 to dim(h);
h(history)=compress(h(history),'"');
length index 8 value $3 ;
do index=1 by 1 until (value=' ');
value=substrn(h(history),3*(index-1)+1,3);
if value ne ' ' then output;
end;
end;
drop history1 history2;
run;
So you end up with something like this:
Obs id type history index value
1 1 13 1 1 STD
2 1 13 1 2 STD
3 1 13 1 3 058
4 1 13 1 4 030
5 1 13 2 1 STD
6 1 13 2 2 030
7 1 13 2 3 066
8 1 13 2 4 036
9 1 13 2 5 030
10 1 13 2 6 STD
11 1 13 2 7 STD
12 1 13 2 8 STD
13 1 13 2 9 STD
14 1 13 2 10 STD
15 1 3 1 1 STD
16 1 3 1 2 STD
17 1 3 1 3 STD
18 1 3 1 4 XXX
19 1 3 1 5 STD
20 1 3 1 6 XXX
21 1 3 1 7 S

Query with CASE statement in Group By I need to create an entry where no results occur in the WHEN

I have a query which groups up incoming payments into date ranges (1-7 days, 3-6 months etc.) and it largely works as I had hoped. However, I want to return a row which says 0 when no income is expected in the date range.
The group by looks like this:
group by
CASE WHEN timestampdiff(day,curdate(),data.duedate) between 0 and 7 then 1
WHEN timestampdiff(day,curdate(),data.duedate) between 8 and 14 then 2
WHEN timestampdiff(day,curdate(),data.duedate) between 15 and 30 then 3
WHEN timestampdiff(month,curdate(),data.duedate) between 1 and 2 then 4
WHEN timestampdiff(month,curdate(),data.duedate) between 2 and 3 then 5
WHEN timestampdiff(month,curdate(),data.duedate) between 3 and 6 then 6
WHEN timestampdiff(month,curdate(),data.duedate) between 6 and 12 then 7
WHEN timestampdiff(year,curdate(),data.duedate) between 1 and 2 then 8
WHEN timestampdiff(year,curdate(),data.duedate) between 2 and 3 then 9
WHEN timestampdiff(year,curdate(),data.duedate) between 3 and 4 then 10
WHEN timestampdiff(year,curdate(),data.duedate) between 5 and 6 then 11
WHEN timestampdiff(year,curdate(),data.duedate) >= 7 then 12
This works correctly in that it will give me the correct amounts, but I want to force the code to give me a 0. So I currently get this:
1 300000
5 150000
8 300000
What I actually want is this:
1 300000
2 0
3 0
4 0
5 150000
6 0
7 0
8 300000
etc.
This is the entire query - I've tried using an IFNULL() but had no success:
select
sum(data.principaldue+data.interestdue) as m
from
(select
la.id
,rep.duedate
,rep.PRINCIPALDUE
,rep.INTERESTDUE
from repayment rep
join loanaccount la on la.ENCODEDKEY = rep.PARENTACCOUNTKEY
join loanproduct lp on lp.ENCODEDKEY = la.PRODUCTTYPEKEY
group by
CASE WHEN timestampdiff(day,curdate(),data.duedate) between 0 and 7 then 1
WHEN timestampdiff(day,curdate(),data.duedate) between 8 and 14 then 2
WHEN timestampdiff(day,curdate(),data.duedate) between 15 and 30 then 3
WHEN timestampdiff(month,curdate(),data.duedate) between 1 and 2 then 4
WHEN timestampdiff(month,curdate(),data.duedate) between 2 and 3 then 5
WHEN timestampdiff(month,curdate(),data.duedate) between 3 and 6 then 6
WHEN timestampdiff(month,curdate(),data.duedate) between 6 and 12 then 7
WHEN timestampdiff(year,curdate(),data.duedate) between 1 and 2 then 8
WHEN timestampdiff(year,curdate(),data.duedate) between 2 and 3 then 9
WHEN timestampdiff(year,curdate(),data.duedate) between 3 and 4 then 10
WHEN timestampdiff(year,curdate(),data.duedate) between 5 and 6 then 11
WHEN timestampdiff(year,curdate(),data.duedate) >= 7 then 12
END
Order by
CASE WHEN timestampdiff(day,curdate(),data.duedate) between 0 and 7 then 1
WHEN timestampdiff(day,curdate(),data.duedate) between 8 and 14 then 2
WHEN timestampdiff(day,curdate(),data.duedate) between 15 and 30 then 3
WHEN timestampdiff(month,curdate(),data.duedate) between 1 and 2 then 4
WHEN timestampdiff(month,curdate(),data.duedate) between 2 and 3 then 5
WHEN timestampdiff(month,curdate(),data.duedate) between 3 and 6 then 6
WHEN timestampdiff(month,curdate(),data.duedate) between 6 and 12 then 7
WHEN timestampdiff(year,curdate(),data.duedate) between 1 and 2 then 8
WHEN timestampdiff(year,curdate(),data.duedate) between 2 and 3 then 9
WHEN timestampdiff(year,curdate(),data.duedate) between 3 and 4 then 10
WHEN timestampdiff(year,curdate(),data.duedate) between 5 and 6 then 11
WHEN timestampdiff(year,curdate(),data.duedate) >= 7 then 12
END

This is not a complete answer, but would be too big for comments;
A temporary table with numbers could be useful:
MySql temporary tables:
CREATE TEMPORARY TABLE TempTable (num int);
INSERT INTO TmpTable VALUES(1,2,3,4,5,6,7,8,9,10,11,12 ...);
Then you could right join on this table to make sure missing values are included.
Lets say you have this:
results(num, val):
1 300000
5 150000
8 300000
This should result in your desired output:
SELECT numbers.num, COALESCE(results.val, 0) as val
FROM results RIGHT JOIN TempTable numbers on results.num = numbers.num
WHERE numbers.num <= 12 --or other max number
1 300000
2 0
...
5 150000
...
Hope this helps.
Edit:
If you don't have permission to create temporary tables, look for a workaround to select consecutive integers, for example:
SELECT #row := #row + 1 as row, t.*
FROM some_table t, (SELECT #row := 0) r
Where some_table is any table with enough rows.
Probably use a top N on that.
Another dirty workaround, might be good enough if you don't need many numbers:
SELECT 1 num
UNION
SELECT 2 num
UNION
...
Edit:
Slightly tidier workaround:
SELECT * FROM (VALUES (1), (2), (3), ... ) x(i)

Selecting items from one column based on values in another.

I have the following data:
id1，id2
1 3
1 8
1 10
1 11
2 3
2 10
2 11
3 2
3 18
3 20
4 3
4 8
5 3
5 10
5 11
5 40
5 45
5 50
6 1
6 59
6 70
I won't get all id1 with id2 ＝ 3，10，11.
For example, id1=4 only with id2=3, should not return.
The results should be
id1
1
2
5

SELECT distinct(ID1) FROM TBTEST WHERE ID2 IN(3,10,11)

SQL code
SELECT ID1,COUNT(ID2) FROM TBTEST
WHERE ID2 IN(3,10,11)
GROUP BY ID1
HAVING COUNT(ID2)=3
Is this what you need?