I want to add rounded corners to my images using CSS and also change the opacity on mouseover because this is cute. There's a bug: after mouseover, the image disappears.
The CSS is pretty simple:
.article img {
margin-bottom: 5px;
-moz-border-radius: 15px; /* for Firefox */
-webkit-border-radius: 15px; /* for Webkit-Browsers */
border-radius: 15px; /* regular */
}
.article:hover .img {
opacity: 0.8;
}
html also just for a test (this is first image that I have googled):
<li class="article">
<div class="img">
<a href="#">
<img src="http://i.telegraph.co.uk/multimedia/archive/02371/karen-ann-jones_2371086k.jpg" alt="Url">
</a>
</div>
</li>
You can see it on jsfiddle: http://jsfiddle.net/9DjLT/3/
Browser: ff19
I encountered this problem recently while trying to implement block-level links on my website, and I solved it by adding the following rule to the un-hovered img declaration:
border: 0.001em solid transparent;
A hack, to be sure, but it seems to work.
I think you have problem in css because of li:hover its taking 100% width. So till your mouse cursor on li your image effect by opacity. Just try below change in CSS
.img a:hover{
opacity: 0.8;
}
FWIW, I hit a similar problem in Chrome 38. In my case, I had a div with a border-radius value, and an image element with a transparency value, and the transparent image was hidden. To fix this, I added a non-1 opacity to the parent element (with the border-radius). Something like this:
.round_box {
border-radius: 5px;
opacity: 0.999999;
}
.transparent {
opacity: 0.6;
}
<div class="round_box">
<div class="transparent">
</div>
... Adding opacity: 0.999999; to the parent element made the transparent element display properly. I should note that I also have a lot of other interesting styles going on - drop shadows, column layout - but, maybe a similar hack will work for others.
Related
I have inserted an icon with an image inside.
In chrome I see the icon
But in IE icon disappear.
Here's my CSS
<div class="infoIcon"></div>
.infoIcon {
content: url('/assets/img/info-sign.png');
background-color: #919191;
width:15px;
border-radius: 8px;
margin-left:10px;
display: inline;
vertical-align: sub
}
you can achieve this using HTML entity.
.infoIcon {
font-size: 40px;
}
<div class="infoIcon">ⓘ</div>
In css "content" applies to ::before & ::after pseudo selectors.
As to why it Chrome is showing the image, Chrome tends to be flexible with css syntax most of the times. IE and FireFox are not showing the image because it is not the right syntax.
Edit:
Example
If you want to keep 'content' You'll have to move your content to
.:before
.icon:before{
content: url('src');
}
However you'll need to scale your image to the right size. (Icon libraries use fonts where they can change the font-size easily)
Second option is continue as you are now but switch to background-image
.info{
background-image:url('icon.svg.png');
background-size: 100% 100%;
width:40px;
height: 40px;
}
In IE11 and Edge (on Windows 10), the following HTML/CSS displays a strange, transparent border where there shouldn't be.
<!DOCTYPE html><html>
<head>
<style>
body {
background-color:red;
font-size: 10pt;
}
.menu {
background-color: #5f6062;
overflow:hidden; /* To contain floats */
box-sizing: content-box;
}
.right-menu {
float:right;
margin:auto;
padding:0 0 0 20px;
list-style: none;
}
.spacer {
background-color: #ffffff;
height: 20px;
}
.content {
background-color: #ffffff;
border-radius:0 0 10px 10px;
background-clip: content-box;
}
</style>
</head>
<body>
<div class="menu">
<ul class="right-menu">
<li>Link</li>
</ul>
</div>
<div class="spacer"></div>
<div class="content">
<div class="content-title">There shouldn't be a 'border' above this...</div>
</div>
</body>
</html>
JSFiddle (You may need to resize the window vertically to see the 'border' fade in and out in JSFiddle — which is even stranger.)
The most interesting part is that the issue seems to be caused by border-radius. If I remove it, the 'border' is gone. It will also go away if I remove some other element (the .menu div for example), but that is less of an option since I would prefer not having to mess with the structure of the site having this problem.
I've found mentions of background-clip: content-box or padding-box as a solution, but it doesn't seem to work here.
Also of note, while trying to reduce the size of my demonstration, I ended up with a code that showed the border in JSFiddle, but not in a plain HTML file. This is the smallest I could get to display the 'border' both inside JSFiddle and a plain HTML file.
Found the bug in EDGE's Platform Issues but still would like to find a workaround...
It looks like IE is rendering a transparent border to display the border-radius but picks the 'background' color further down the layers than it should (in my sample, using red instead of white).
So I went with workarounds...
On my actual page, two elements are having this bug. For one my workaround was to set the background-color of another element further behind the one with border-radius and for the other to set an actual border the same color as the element's background.
I have a page with popup displayed onload. The whole site is in greyscale but I want to popup div to be in non-greyscale. I have tried with filter: none or -webkit-filter: grayscale(0); but it is not working that the whole page is in greyscale. Does anyone have any idea on it? Thanks!
-webkit-filter: grayscale(0) !important;
filter: grayscale(0) !important;
My code: Jsfiddle
-webkit-filter isn't a property that cascades down and can be overwritten, it's applied on top of the whole element and its children. If you put a filter on the children, it stacks on top of the parent's filter.
Instead, you'll need to put the filter on an element that is the parent of all the things you want grayed out.
div {
height: 20px;
position: relative;
}
<div>
<div style="-webkit-filter: grayscale(1)">
<div style="background: red">Sample</div>
<div style="background: blue">Sample</div>
</div>
<div style="background: green; position: absolute; top: 10px;">Sample</div>
</div>
I've run in to a bit of a problem. I have a menu list where I custom made some image hover states for list items. This worked perfectly fine until I needed to change the menu items (list item text length, etc). I have to go back and re-make all of the images each time something changes.
Here are some images of what I'm trying to accomplish:
Basically the hover adds a red background and a duplicate of that red region rotated ~2 degrees and is lighter colored. Would it be possible to do this via CSS with :after and transform: rotate()? If not, what would be a nice way of accomplishing this effect for varying word lengths?
Thanks ahead of time!
Tre
This can easily be done with transform as you say. You'll need to have two elements in each button though, one for the text and one for the skewed background:
<div class="menu-button">
<div class="text">Screenings</div>
<div class="hover-bg"></div>
</div>
And style the .hover-bg class something like this:
#menu .menu-button:hover .hover-bg
{
z-index: 1;
position: absolute;
top: 0px;
left: 0px;
width: 100%;
height: 100%;
background-color: rgba(220, 50, 50, 0.4);
transform: rotate(2deg) scale(1.05, 1);
transform-origin: center right;
}
Here's an example on JSFiddle
Here's an example where I had some fun with transitions. Due to lazyness I only bothered to make it work in Webkit, meaning Chrome and Webkit.
Note that for cross-browser compatibility you'll need the vendor specific property prefixes (-webkit-, -moz-, etc)
this can be done in pure CSS (not even 3).
On hover have a tilted background image, position it a few pixel to the left and top and add background color.
Because of the background color, you will see only a part of the image:
<div class="text">Screenings</div>
.text {
color: #000;
margin-left: 5px;/*to make room for the hover image */
padding: 4px;
}
.text:hover {
background: #900 url(tiltedimage.png) no-repeat -5px -5px;
color: #fff;
}
This will point you to the solution.
Chrome and Safari are displaying a border around the image, but I don't want one. There is no border in Mozilla. I've looked through the CSS and HTML, and I can't find anything that is fixing it.
Here is the code:
<tr>
<td class="near">
<a href="../index.html"class="near_place">
<img class="related_photo" />
<h4 class="nearby"> adfadfad </h4>
<span class="related_info">asdfadfadfaf</span>
</a>
...
CSS:
a.near_place {
border: none;
background: #fff;
display: block;
}
a.near_place:hover{
background-color: #F5F5F5;
}
h4.nearby {
height: auto;
width: inherit;
margin-top: -2px;
margin-bottom: 3px;
font-size: 12px;
font-weight: normal;
color: #000;
display: inline;
}
img.related_photo {
width: 80px;
height: 60px;
border: none;
margin-right: 3px;
float: left;
overflow: hidden;
}
span.related_info {
width: inherit;
height: 48px;
font-size: 11px;
color: #666;
display: block;
}
td.near {
width: 25%;
height: 70px;
background: #FFF;
}
Sorry, I copied some old code before. Here is the code that is giving me trouble
Thanks in advance
Now I don't know if this is a bug with Chrome or not but the grey border appears when it can't find the image, the image url is broken or as in your case the src isn't there. If you give the image a proper URL and the browser finds it then the border goes away. If the image is to not have a src then you will need to remove the height and width.
sarcastyx is right, but if you want a workarround you can set the width and height to 0 and a padding to make space for your image.
If you want a icon of 36x36, you can set width and height to 0 and pading:18px
I know it is an old question. But another solution is to set the src to a 1x1 transparent pixel
<img class="related_photo"
src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" />
This works for me.
.related_photo {
content: '';
}
This may happen when the image is planted dynamically by css (e.g. by http://webcodertools.com/imagetobase64converter) in order to avoid extra HTTP requests. In this case we don't want to have a default image because of performance issues. I've solved it by switching from an img tag to a div tag.
img[src=""]{
content: "";
}
Lazy image solution (img loading="lazy")
If you are using lazy image loading you may notice this thin thin border before the image has loaded more than if you didn't.
You're more likely to see this for a horizontal scrolling gallery than a normal vertical scrolling webpage.
Why?
Lazy loading unfortunately only works on the vertical axis. I'm assuming this is because there's a high likelihood that you're going to scroll down, but not left to right. The whole point of lazy loading is to reduce images 'below the fold' from consuming unnecessary bandwidth.
Soution 1:
Detect when the user has scrolled (eg. using intersection observer) and then set loading="eager" on each image you want to immediately load.
I haven't actually tested this, and it's possible some browser's won't immediately load images - but it should be fine.
Solution 2:
Detect when the image has finished loading loaded and then fade it in.
img.setAttribute('imageLoaded', 'false');
img.onload = () =>
{
img.setAttribute('imageLoaded', 'true');
};
Then with css hide the image until it's loaded, after which it fades in nicely:
img
{
opacity: 1;
transition: opacity .5s;
}
img[imageLoaded='false']
{
opacity: 0; // hide image including gray outline
}
Also this behavior is subject to change, the browser may be clever enough to detect a horizontal scrolling element in future - but right now Chrome and Safari both seem to have a zero pixel window for looking for horizontal lazy images.
img.related_photo {
width: 80px;
height: 60px;
**border: solid thin #DFDFDF;** //just remove this line
margin-right: 3px;
float: left;
overflow: hidden;
}
Inside img.related_photo, you need to change border: solid thin #DFDFDF; to border: 0.
I have fixed this issue with:
<img src="img/1.jpg" style="height:150px; position: absolute; right: 15px;">
The right: 15px is where you want the image to be shown, but you can place it where you want.
I just added src="trans.png", trans.png is just a 100x100 transparent background png from photoshop.
Worked like a charm no borders
To summarise the answers given already: your options to remove the grey border from an img:not([src]), but still display an image using background-image in Chrome/Safari are:
Use a different tag that doesn't have this behaviour. (Thanks #Druvision) Eg: div or span. Sad face: it's not quite as semantic.
Use padding to define the dimensions. (Thanks #Gonzalo)Eg padding: 16px 10px 1px; replaces width:20px; height:17px; Sad face: dimensions and intentions aren't as obvious in the CSS, especially if it's not an even square like #Gonalo's example.