Limit query results to total results minus 10 results - mysql

Question

guys I cant figure this out.. I red a lot but no luck...
I have the following query, and I need to limit it in order to show the total results minus a specific number os results, let's say 10.
I mean, if the query would return 1000 total results, I want it to return 990, and the last 10 results need to be excluded.
Is this possible?
see the query call:
$query = ' SELECT p.*,c.name as name_category,t.name as name_type,cy.name as name_country,s.name as name_state,l.name as name_locality,l.alias as locality_alias,pf.name as name_profile, '
. ' CASE WHEN CHAR_LENGTH(p.alias) THEN CONCAT_WS(":", p.id, p.alias) ELSE p.id END as Pslug,'
. ' CASE WHEN CHAR_LENGTH(c.alias) THEN CONCAT_WS(":", c.id, c.alias) ELSE c.id END as Cslug,'
. ' CASE WHEN CHAR_LENGTH(cy.alias) THEN CONCAT_WS(":", cy.id, cy.alias) ELSE cy.id END as CYslug,'
. ' CASE WHEN CHAR_LENGTH(s.alias) THEN CONCAT_WS(":", s.id, s.alias) ELSE s.id END as Sslug,'
. ' CASE WHEN CHAR_LENGTH(l.alias) THEN CONCAT_WS(":", l.id, l.alias) ELSE l.id END as Lslug, '
. ' CASE WHEN CHAR_LENGTH(t.alias) THEN CONCAT_WS(":", t.id, t.alias) ELSE t.id END as Tslug '
. ' FROM #__properties_products AS p '
. ' LEFT JOIN #__properties_country AS cy ON cy.id = p.cyid '
. ' LEFT JOIN #__properties_state AS s ON s.id = p.sid '
. ' LEFT JOIN #__properties_locality AS l ON l.id = p.lid '
. ' LEFT JOIN #__properties_profiles AS pf ON pf.mid = p.agent_id '
. ' LEFT JOIN #__properties_category AS c ON c.id = p.cid '
. ' LEFT JOIN #__properties_type AS t ON t.id = p.type '
. ' WHERE p.published = 1 '
.' ORDER BY p.id DESC '
;

Answer 1

If you are using MySQL, then use limit and offset:
limit 10, 9999999
This starts at the 10th record and continues to the end of the data (or to 9999999 rows, technically).
You are ordering by p.id desc, so this will remove the 10 rows with the highest id.
To really do what you seem want (remove the 10 with the lowest id), use a subquery and then sort again after the subquery:
select t.*
from (<most of your query here>
order by p.id asc
limit 10, 999999
) t
order by id desc
To remove the rows with the highest id, just add the limit statement:
$query = 'SELECT p.*,c.name as name_category,t.name as name_type,cy.name as name_country,s.name as name_state,l.name as name_locality,l.alias as locality_alias,pf.name as name_profile, '
. ' CASE WHEN CHAR_LENGTH(p.alias) THEN CONCAT_WS(":", p.id, p.alias) ELSE p.id END as Pslug,'
. ' CASE WHEN CHAR_LENGTH(c.alias) THEN CONCAT_WS(":", c.id, c.alias) ELSE c.id END as Cslug,'
. ' CASE WHEN CHAR_LENGTH(cy.alias) THEN CONCAT_WS(":", cy.id, cy.alias) ELSE cy.id END as CYslug,'
. ' CASE WHEN CHAR_LENGTH(s.alias) THEN CONCAT_WS(":", s.id, s.alias) ELSE s.id END as Sslug,'
. ' CASE WHEN CHAR_LENGTH(l.alias) THEN CONCAT_WS(":", l.id, l.alias) ELSE l.id END as Lslug, '
. ' CASE WHEN CHAR_LENGTH(t.alias) THEN CONCAT_WS(":", t.id, t.alias) ELSE t.id END as Tslug '
. ' FROM #__properties_products AS p '
. ' LEFT JOIN #__properties_country AS cy ON cy.id = p.cyid '
. ' LEFT JOIN #__properties_state AS s ON s.id = p.sid '
. ' LEFT JOIN #__properties_locality AS l ON l.id = p.lid '
. ' LEFT JOIN #__properties_profiles AS pf ON pf.mid = p.agent_id '
. ' LEFT JOIN #__properties_category AS c ON c.id = p.cid '
. ' LEFT JOIN #__properties_type AS t ON t.id = p.type '
. ' WHERE p.published = 1 '
.' ORDER BY p.id desc limit 10, 999999'
;