MySQL not catching error - mysql

Question

Why is this code not catching the error when I try to delete a row that doesn't exist? No matter what parameter I pass in as the name of the row, it always returns "1 row deleted" and doesn't use the exit handlers. which are supposed to catch just this type of error.
USE yoga;
DROP PROCEDURE IF EXISTS delete_warmup;
DELIMITER //
CREATE PROCEDURE delete_warmup
(
warmup_name_param VARCHAR(100)
)
BEGIN
DECLARE row_not_found TINYINT DEFAULT FALSE;
DECLARE sql_exception TINYINT DEFAULT FALSE;
BEGIN
DECLARE EXIT HANDLER FOR 1329
SET row_not_found = TRUE;
DECLARE EXIT HANDLER FOR SQLEXCEPTION
SET sql_exception = TRUE;
DELETE FROM warmup
WHERE warmup_name = warmup_name_param;
SELECT '1 row was deleted.' AS message;
END;
IF row_not_found = TRUE THEN
SELECT 'Row not deleted - row not found' AS message;
ELSEIF sql_exception = TRUE THEN
SHOW ERRORS;
END IF;
END//
DELIMITER ;
CALL delete_warmup ('Monkey business');

Answer 1

You are using an exit handler for a duplicate parameter: http://www.briandunning.com/errors/596 which is 1329 as you specified
Perhaps you should try error code 1011 : http://www.briandunning.com/errors/278
Also, try looking for NOT FOUND as well as SQLException
Also, try to put the exit handler outside the begin/end clause.
so your BEGIN and END clause would be
DECLARE EXIT HANDLER FOR 1011
DECLARE EXIT HANDLER FOR SQLEXCEPTION, NOT FOUND
BEGIN
SET row_not_found = TRUE;
SET sql_exception = TRUE;
DELETE FROM warmup
WHERE warmup_name = warmup_name_param;
SELECT '1 row was deleted.' AS message;
END;