I have 2 doubts related to SQL query's
id name update
1 some 2013-05-03
2 som 2013-05-08
3 smee 2013-06-05
How can i list items on a particular month (I want all records,year and date will not be specified I just want to check the month)
How can I arrange name in alphabetic order and arrange it as groups of names such as (limiting number of records =10)
Array A = names starting with A
Array B = names starting with B
The easiest way, to fetch MONTH from a DATE or DATETIME type of fields is to use the MySQL's date-time function MONTH().
For your query, it shall be:
SELECT *
FROM tblName
WHERE MONTH( `update` ) = <month Number such as 5>
The second would need a more complex query. I'd rather use php to do the grouping better(as I've more control over that language).
You can simply use datatype of the field as DATE or you can store any date as unix timestamp and then convert it whenever you want to show it.
Example: 1363979714 (ISO 8601:2013-03-22T19:15:14Z)
If you want list items on a particular date, you can write your query like this:
Month:
Select * from tableName where update like '%-5-%'
day:
Select * from tableName where update like '%-16'
year:
Select * from tableName where update like '2013-%'
Related
SELECT * FROM table WHERE '2016-03-31' > (SELECT MAX(year) from table where bill_id = 'somevalue')
I am using above query to check if 2016-03-31 is greater than all years present in table against bill_id. It is working fine. but is it correct approach to compare dates. dates will always in above format. Is there any need to convert date format for comparison. value 2016-03-31 will change dynamically but it will be always in Y-m-d format
Note : year is column name which contains full date in Y-m-d format like 2016-05-20
You are not comparing dates. You are comparing a string '2016-03-31' with a number, e.g. 2015.
In order to compare, MySQL silently converts the string to number. One would expect this to crash, as '2016-03-31' certainly isn't a number. MySQL, however, reads from left to right and takes from there all that can be considered a number, i.e. '2016'. Well, one could argue that some people put a minus sign at the end of a number, so this should be '2016-', i.e. -2016. Anyway, MySQL stops before the minus sign, gets 2016 and uses this for the comparision.
I don't know if all this is guaranteed to work in the future. I would not rely on this.
What result would you expect anyway? Is the 31st of March 2016 greater than the year 2016? That's a queer question, don't you think?
Try this. But do you really have a column year that stores only year?
SELECT * FROM table WHERE year(STR_TO_DATE('2016-03-31'))
> (SELECT MAX(year) from table where bill_id = 'somevalue')
SELECT * FROM table WHERE YEAR('2016-03-31') > (SELECT MAX(year) from table where bill_id = 'somevalue')
MySQL YEAR() returns the year for a given date or timestamp. The return value is in the range of 1000 to 9999 or 0 for 'zero' date.
I have a table
id |value |date
-------------------
1 |2.8 |28-3-14
2 |2.9 |28-7-14
3 |3.9 |20-1-14
in this table i need to get the value of 21-3-14.
but if value or object is not present for that then query get output of 20-1-14 directly without one by one search object by minus date by 1 day.
if any one know about this please give me suggestion.
You just need to sort by date
SELECT value FROM table WHERE date<='21-3-14' ORDER BY date DESC LIMIT 1;
Based on your table it should print:
2.8
Assuming the date 21-3-14 wasn't there, it should print:
3.9
try this,
SELECT
*
FROM
<tablename>
WHERE
STR_TO_DATE(`date`,'%d-%m-%y') <= STR_TO_DATE('YOUR_DATE','%d-%m-%y')
ORDER BY
`date` DESC < LIMIT 1 >
It is recommended to store date in date format i.e. < yyyy-mm-dd >
you may refer,
PHP mysql insert date format
I have a table which contains date (Field Type: Date and Date Format: %Y-%m-%d) as a field. I need to select all the rows from the table for all the years whose date is not between Dec 3rd and Dec 24th.
The table contains month and day as a separate fields.
The result can be obtained by using the following query:
select * from mytable where date not in (select date from mytable where month=12 and day between 3 and 24);
But i m trying to get the result in a single query like the below one but it gave empty rows:
select * from mytable where date not between '%Y-12-03' and '%Y-12-24';
Can it be done in a single query like the above one?
SELECT *
FROM mytable
WHERE MONTH(`date`) <> 12
OR DAY(`date`) NOT BETWEEN 3 AND 24
;
This will give you every row that meets the requirements. I'm sure someone has a faster way of doing this, since this will ignore all indexes and will likely be slow on a large dataset, but it does work and return the data you require, so if no-one can suggest an improvement this will answer your question.
I need a way to query a collection of data. I have a list of recent activity dates each stored in 1 row per user. Each row has a field of loginDates which consists of a comma separated list of timestamps.
What i need to do is run reports on this date to find people active since XXXXXX timestamp. The problem is the fact it's comma separated means i can't query it uses methods i know.
Here is an example row
id userID accessDates
2 6 1399494405,1399494465,1399494525,1399494585,1399494623
What i want to achieve in plain text
SELECT all_fields FROM accessTable WHERE accessDate > YESTERDAY
ALSO These dates may however span over several hundreds of days with hundreds of timestamps in the field.
Assuming the TimeStamp values are in order as your data sample shows, if any of the TimeStamp values in the string are greater than a given date, then the latest one would be greater than that value as well. So you only need the latest TimeStamp value to meet your requirement:
SET #Yesterday =
UNIX_TIMESTAMP(DATE_ADD(DATE(CURRENT_TIMESTAMP()),INTERVAL -1 DAY));
SELECT *
FROM accessTable
WHERE CAST(RIGHT(accessDates,10) AS UNSIGNED) > #Yesterday;
If you want to query each of those TimeStamps individually, the best solution is to put them into a single table column with a userid:
userID accessDate
------ ----------
6 1399494405
6 1399494465
6 1399494525
6 1399494585
6 1399494623
I have a MySQL DateTime field which represent opening times.
I want to write a statement that will allow me to select rows from my table independent of the year supplied (Ex. *-12-17 00:00:00)
Try this:
SELECT * FROM table1
WHERE DAYOFMONTH(datecolumn) = 17
AND MONTH(datecolumn) = 12
Reference for DAYOFMONTH.
You did not say what you wanted to choose by if not the year: Go to the MySQL page and choose the correct functions.
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html