using joins together with aggregates, and retrieving rows when no aggregate exists - mysql

The following query on my MySQL tables returns rows from the purchaseorder table that have corresponding entries in the deliveryorder table. How do I construct this query so that I get rows from the purchaseorder table even if no corresponding rows exist in the deliveryorder table? If the users want to see sql table CREATE statements, I can post those, but I'm not posting now as it really makes the question too big.
SELECT
`purchaseorder`.`id` AS `po_id`,
`purchaseorder`.`order_quantity` AS `po_order_quantity`,
`purchaseorder`.`applicable_approved_unit_rate` AS `po_unit_rate`,
`purchaseorder`.`applicable_sales_tax_rate` AS `po_tax_rate`,
`purchaseorder`.`order_date` AS `po_order_date`,
`purchaseorder`.`remarks` AS `po_remarks`,
`purchaseorder`.`is_open` AS `po_is_open`,
`purchaseorder`.`is_active` AS `po_is_active`,
`purchaseorder`.`approved_rate_id` AS `po_app_rate_id`,
`supplier`.`name` AS `sup_name`,
SUM(`deliveryorder`.`quantity`) AS `total_ordered`
FROM `purchaseorder`
LEFT JOIN `deliveryorder` ON (`deliveryorder`.`purchase_order_id` = `purchaseorder`.`id`)
INNER JOIN `approvedrate` ON (`purchaseorder`.`approved_rate_id` = `approvedrate`.`id`)
INNER JOIN `supplier` ON (`approvedrate`.`supplier_id` = `supplier`.`id`)
WHERE (
`purchaseorder`.`is_active` = 1
AND `purchaseorder`.`is_open` = 1
AND `deliveryorder`.`is_active` = 1
AND `approvedrate`.`material_id` = 2
)
HAVING `purchaseorder`.`order_quantity` >= `total_ordered` + 1

You have an aggregating function but no GROUP BY clause, which is wierd, but anyway - something like this? Oops - edited...
SELECT po.id po_id
, po.order_quantity po_order_quantity
, po.applicable_approved_unit_rate po_unit_rate
, po.applicable_sales_tax_rate po_tax_rate
, po.order_date po_order_date
, po.remarks po_remarks
, po.is_open po_is_open
, po.is_active po_is_active
, po.approved_rate_id po_app_rate_id
, s.name sup_name
, SUM(do.quantity) total_ordered
FROM purchaseorder po
LEFT
JOIN deliveryorder do
ON do.purchase_order_id = po.
AND do.is_active = 1
LEFT
JOIN approvedrate ar
ON ar.id = po.approved_rate_id
AND ar.material_id = 2
LEFT
JOIN supplier s
ON s.id = ar.supplier_id
WHERE po.is_active = 1
AND po.is_open = 1
HAVING po.order_quantity >= total_ordered + 1

I couldn't work out how to get the desired results all in one query, but ended up using the following two queries to fulfill my requirements: -
1st query
SELECT
pot.`id` AS `po_id`,
pot.`order_quantity` AS `po_order_quantity`,
pot.`applicable_approved_unit_rate` AS `po_unit_rate`,
pot.`applicable_sales_tax_rate` AS `po_tax_rate`,
pot.`is_open` AS `po_is_open`,
pot.`is_active` AS `po_is_active`,
st.`id` AS `sup_id`,
st.`name` AS `sup_name`,
SUM(dot.`quantity`) AS `total_ordered`
FROM `purchaseorder` pot
INNER JOIN `deliveryorder` dot ON (dot.`purchase_order_id` = pot.`id`)
INNER JOIN `approvedrate` art ON (pot.`approved_rate_id` = art.`id`)
INNER JOIN `supplier` st ON (art.`supplier_id` = st.`id`)
WHERE (
pot.`is_active` = 1
AND pot.`is_open` = 1
AND art.`material_id` = #materialid
AND art.`in_effect` = 1
AND art.`is_active` = 1
AND dot.`is_active` = 1
AND st.`is_active` = 1
)
HAVING pot.`order_quantity` >= `total_ordered` + #materialquantity
2nd query
SELECT
pot.`id` AS `po_id`,
pot.`order_quantity` AS `po_order_quantity`,
pot.`applicable_approved_unit_rate` AS `po_unit_rate`,
pot.`applicable_sales_tax_rate` AS `po_tax_rate`,
pot.`is_open` AS `po_is_open`,
pot.`is_active` AS `po_is_active`,
st.`id` AS `sup_id`,
st.`name` AS `sup_name`,
0 AS `total_ordered`
FROM `purchaseorder` pot
INNER JOIN `approvedrate` art ON (pot.`approved_rate_id` = art.`id`)
INNER JOIN `supplier` st ON (art.`supplier_id` = st.`id`)
WHERE (
pot.`is_active` = 1
AND pot.`is_open` = 1
AND art.`material_id` = #materialid
AND art.`in_effect` = 1
AND art.`is_active` = 1
AND st.`is_active` = 1
AND pot.`order_quantity` >= #materialquantity
AND pot.`id` NOT IN
(
SELECT dot.`purchase_order_id`
FROM `deliveryorder` dot
WHERE dot.is_active = 1
)
)

Related

MySQL: From sub query to a single query

I have this query which i believe can be optimized:
SELECT floors.id, floors.floor FROM floors
WHERE floors.societies_id = 1
AND floors.status = 'Y'
AND floors.id NOT IN (
SELECT DISTINCT(floors.id) FROM floors
INNER JOIN societies ON societies.id = floors.societies_id
INNER JOIN resident_floors ON resident_floors.floors_id = floors.id
WHERE societies.id = 1
AND floors.status = 'Y'
)
Is this query fine to use or there it can be improved..?
It looks like you want to get all floors that aren't present in resident_floors. For this we can left join RF in and ask for only rows where the join failed resulting in a null in RF:
SELECT floors.* FROM floors
INNER JOIN societies ON societies.id = floors.societies_id
LEFT JOIN resident_floors ON resident_floors.floors_id = floors.id
WHERE societies.id = 1
AND floors.status = 'Y'
AND resident_floors.floors_id IS NULL

Adding a subquery to a join

I've been using the following join, to pull rows of users whom have volunteered for various project positions.
SELECT p.id, up.position_id, title, max_vol, current_datetime, IF(up.id IS NULL, "0", "1") volunteered
FROM positions AS p
LEFT JOIN users_positions AS up
ON p.id = up.position_id
AND up.user_id = 1
AND up.calendar_date = '2016-10-03'
WHERE
p.project_id = 1
AND p.day = 1
...but in a change of functionality, I have to now account for the date of the latest edit to a project. In another query, I solved it like so
SELECT *
FROM positions
WHERE
current_datetime = (SELECT MAX(current_datetime)
FROM positions
WHERE
project_id = 1 AND day = 1)
Which works fine, but now I have to also incorporate the return of rows which match the latest datetime in the left join query.
I just can't seem to wrap my head around it. Any suggestions? Thanks.
Use a sub query, like this:
SELECT
p.id,
up.position_id,
title,
max_vol,
current_datetime,
IF(up.id IS NULL,
"0",
"1") volunteered
FROM
( SELECT
*
FROM
positions
WHERE
current_datetime = (
SELECT
MAX(current_datetime)
FROM
positions
WHERE
project_id = 1
AND day = 1
)
) AS p
LEFT JOIN
users_positions AS up
ON p.id = up.position_id
AND up.user_id = 1
AND up.calendar_date = '2016-10-03'
WHERE
p.project_id = 1
AND p.day = 1

MySQL query returning 0 rows while it should return one

Something is wrong with my MySQL query below but I can't find the problem. It's not returning any errors but the query below should return 1 row, but it returns none.
The table 'fws_product' contains all products. The table 'webits_product_has_kenmerken' contains the product specifications.
SELECT fws_product.*
FROM webits_product_has_kenmerken
LEFT JOIN fws_product ON webits_product_has_kenmerken.product_id = fws_product.ID
WHERE fws_product.CATID = 11
AND (
(webits_product_has_kenmerken.kenmerk_id = 8 AND webits_product_has_kenmerken.kenmerk_value = 'Buddha to Buddha')
AND
(webits_product_has_kenmerken.kenmerk_id = 19 AND webits_product_has_kenmerken.kenmerk_value = '10 mm')
)
Thanks in advance!
It looks a bit nasty, but the following should do as you have requested
SELECT
p.*
FROM fws_product AS p
INNER JOIN webits_product_has_kenmerken AS ps8
ON ps8.product_id = p.ID
AND ps8.kenmerk_id = 8
AND ps8.kenmark_value = 'Buddha to Buddha'
INNER JOIN webits_product_has_kenmerken AS ps19
ON ps19.product_id = p.ID
AND ps19.kenmerk_id = 19
AND ps19.kenmark_value = '10 mm'
WHERE p.CATID = 11
This is another potential option which may do the job, but still feels very nasty
SELECT
p.*
FROM fws_product AS p
INNER JOIN (
SELECT
product_id,
COUNT(*) AS numMatches
FROM webits_product_has_kenmerken
WHERE (kenmerk_id,kenmerk_value) IN (
(8,'Buddha to Buddha'),
(19,'10 mm')
)
GROUP BY product_id
HAVING numMatches = 2
) AS ps
ON ps.product_id = p.ID
WHERE p.CATID = 11
i think you need the following:
SELECT fws_product.*
FROM webits_product_has_kenmerken
LEFT JOIN fws_product ON webits_product_has_kenmerken.product_id = fws_product.ID
WHERE fws_product.CATID = 11
AND (
(webits_product_has_kenmerken.kenmerk_id = 8 AND webits_product_has_kenmerken.kenmerk_value = 'Buddha to Buddha')
OR
(webits_product_has_kenmerken.kenmerk_id = 19 AND webits_product_has_kenmerken.kenmerk_value = '10 mm')
)
checke these columns for NULL values:
fws_product.CATID
webits_product_has_kenmerken.kenmerk_id
webits_product_has_kenmerken.kenmerk_value
every comparison with NULL will exclude the row from the reult

Sum of rows with join

This is the current table layout.
There are 3 legs
Each leg has 2 points, where is_start = 1 is the start of the leg, and is_start is the end of the leg.
When the user check in at a point, a entry in points_user are created.
In this application you have multiple legs which has 2 points where one marks the start of the leg, where the other marks the end of the leg. So the sum of User's (with id = 2) Leg (with id= 1) is points_users.created where points_users.leg_id = 1 and points_users.user_id = 2 and points_users.is_start = 0 minus points_users where is_start = 1 (and the other parameters stay the same). And that's for just one leg.
What I would like is to sum all the time differences for each leg, we get the data like this:
| User.id | User.name | total_time |
| 1 | John | 129934 |
Anyone know how I can join these tables and sum it up grouped by user?
(No, this is not homework)
As far as I got:
SELECT
( `end_time` - `start_time` ) AS `diff`
FROM
(
SELECT SUM(UNIX_TIMESTAMP(`p1`.`created`)) AS `start_time`
FROM `points_users` AS `pu1`
LEFT JOIN `points` AS `p1` ON `pu1`.`point_id` = `p1`.`id`
WHERE `p1`.`is_start` = 1
) AS `start_time`,
(
SELECT SUM(UNIX_TIMESTAMP(`pu2`.`created`)) AS `end_time`
FROM `points_users` AS `pu2`
LEFT JOIN `points` AS `p2` ON `pu2`.`point_id` = `p2`.`id`
WHERE `p2`.`is_start` = 0
) AS `end_time`
Try this:
select users.user_id,
users.user_name,
SUM(timeDuration) totalTime
from users
join (
select
pStart.User_id,
pStart.leg_id,
(pEnd.created - pStart.created) timeDuration
from (select pu.user_id, pu.leg_id, pu.created
from points_users pu
join points p on pu.id = p.point_id and pu.leg_id = p.leg_id
where p.is_start = 1 ) pStart
join (select pu.user_id, pu.leg_id, pu.created
from points_users pu
join points p on pu.id = p.point_id and pu.leg_id = p.leg_id
where p.is_start = 0 ) pEnd
on pStart.user_id = pEnd.user_id
and pStart.leg_id = pEnd.leg_id
) tt
on users.user_id = tt.user_id
group by users.user_id, users.user_name
Subquery gets the time duration for each user/leg, and main query then sums them for all the legs of each user.
EDIT: Added the points table now that I can see your attempt at a query.
The simplest way is to join points_users to itself:
select leg_start.user_id, sum(leg_end.created - leg_start.created)
from points_users leg_start
join points_users leg_end on leg_start.user_id = leg_end.user_id
and leg_start.leg_id = leg_end.leg_id
join points point_start on leg_start.point_id = point_start.id
join points point_end on leg_end.point_id = point_end.id
where point_start.is_start = 1 and point_end.is_start = 0
group by leg_start.user_id
Some people prefer to put those is_start filters in the join condition, but since it's an inner join that's mainly just a point of style. If it were an outer join, then moving them from the WHERE to the JOIN could have an effect on the results.

MySQL join only selected rows

SELECT invoices.number_formatted, SUM(invoices_elements.netto)
FROM invoices
LEFT JOIN invoices_elements ON invoices_elements_code_invoices_id = invoices_id
WHERE invoices_enable = 1
AND invoices_elements_enable = 1
GROUP BY invoices_elements_code_invoices_id
If table "invoices_elements" doesn't have any rows with "invoices_elements_enable = 1" this query return NULL - but i want "number formatted". So i do this:
SELECT SUM(netto)
FROM (invoices)
LEFT JOIN (SELECT * FROM invoices_elements WHERE invoices_elements_enable = 1) ON invoices_elements_code_invoices_id = invoices_id
WHERE invoices_enable = 1
GROUP BY invoices_elements_code_invoices_id
... and this of coz works. But - is better way to do it?
You can do
SELECT SUM(netto)
FROM invoices
LEFT JOIN invoices_elements
ON invoices_elements_code_invoices_id = invoices_id
AND invoices_elements_enable = 1
WHERE invoices_enable = 1
GROUP BY invoices_elements_code_invoices_id
Note the restriction invoices_elements_enable = 1 is in the ON clause to avoid converting the query into an inner join.