I'm trying to get a list of the number of entries in the changes_cc table by each user. Not all users have made entries into it, however for some reason it's returning "1" for each user that has 0 entries. I'm assuming that it's because it's counting the entries in the JOINed table. How can I make it so that it is "0" instead?
SELECT COUNT(*) as num, users.id, realname, username
FROM changes_cc
RIGHT JOIN users
ON changes_cc.user_id = users.id
GROUP BY users.id
I think this should work -- count a specific field in the changes_cc table vs counting *:
SELECT u.id, realname, username, COUNT(c.id) as num
FROM users u
LEFT JOIN changes_cc c
ON u.user_id = c.id
GROUP BY u.id
I prefer reading a LEFT JOIN over a RIGHT JOIN, but they are both OUTER JOINs and work the same.
You should not be using COUNT(*) (counts the record including null values) because it will normally give atleast 1 since it returns all records from the right table. If you specify the column name to be counted, it will gove you the result you want because COUNT only counts for NON_NULL value.
SELECT COUNT(changes_cc.user_id) as num,
users.id,
realname,
username
FROM changes_cc
RIGHT JOIN users
ON changes_cc.user_id = users.id
GROUP BY users.id
Instead of using count(*), use count(changes_cc.user_id).
The problem is that you are counting rows (with the *) rather than counting the non-NULL values in the "right-joined" table.
Related
I have this sql:
SELECT logins.*, users.*, invoices.number
FROM logins,
users,
invoices
WHERE logins.user_id = users.id
AND users.id = invoices.userId;
This is simplified version of my statement. The reality is more complicated.
When
users.id=invoices.userId
is false (because table invoices don't contain row with this userId) I need add to invoices.number=0.
Use a left join to return rows even if no invoices are found. For those rows, columns from the invoices table will be null. You can use coalesce to return 0 instead of null in that situation:
SELECT logins.*
, users.*
, COALESCE(invoices.number, 0) AS number
FROM logins
JOIN users
ON logins.user_id = users.id
LEFT JOIN
invoices
ON users.id = invoices.userId
use explicit join instead of comma separated join
SELECT logins.*, users.*, invoices.number
FROM logins
join users on logins.user_id=users.id
join invoices on users.id=invoices.userId;
I want to get customer data from all the businesses with more than 1 user.
For this I think I need a subquery to count more than 1 user and then the outer query to give me their emails.
I have tried subqueries in the WHERE and HAVING clause
SELECT u.mail
FROM users u
WHERE count IN (
SELECT count (u.id_business)
FROM businesses b
INNER JOIN users u ON b.id = u.id_business
GROUP BY b.id, u.id_business
HAVING COUNT (u.id_business) >= 2
)
I believe that you do not need a subquery, everything can be achieved in a joined aggregate query with a HAVING clause, like :
SELECT u.mail
FROM users u
INNER JOIN businesses b on b.id = u.id_business
GROUP BY u.id, u.email
HAVING COUNT (*) >= 2
NB : in case several users may have the same email, I have added the primary key of users to the GROUP BY clause (I assumed that the pk is called id) : you may remove this if email is a unique field in users.
I am trying to count users that are NOT referenced in another table... Right now, I have something along the lines of this:
SELECT COUNT(DISTINCT u.id) FROM users u INNER JOIN orders o ON o.assigned!=u.id;
However, it's returning an invalid value. Any suggestions?
Thank you!
I would suggest using a LEFT JOIN between the two tables and filter the rows without a matching id in the orders table:
select count(u.id)
from users u
left join orders o
on o.assigned = u.id
where o.assigned is null
See SQL Fiddle with Demo
Use a left join and count the rows with no match:
SELECT COUNT(*)
FROM users u
LEFT JOIN orders o
ON o.assigned = u.id
WHERE o.assigned IS NULL
An alternative is to use a NOT IN check:
SELECT COUNT(*)
FROM users
WHERE id NOT IN (SELECT distinct(assigned) FROM orders)
However, in my experience the left join performs better (assuming appropriate indexes).
Simply use this query, assuming that the id is unique in users table:
select count(*) From Users as u where u.id not in (select assigned from orders)
an inner join explicitly looks for rows that match so that isn't the way to go if you are looking for non matched records
assuming that ORDERS.ASSIGNED is matched with USER.ID an outer join could return values from both and show when there aren't matches like so
select
u.id,
o.*
from users u
full outer join orders o
on o.assigned = u.id;
if you only want to know which USER.ID don't have an ORDERS record you could also INTERSECT or use NOT IN () eg
select u.id from users u where id not in (select o.assigned from orders.o);
SELECT COUNT(1) FROM users u
WHERE NOT EXISTS (SELECT * FROM orders o WHERE o.assigned=u.id);
Are you wanting a straight count (like you mentioned), or do you need values returned? This will give you the count; if you want other values, you should take one of the other approaches listed above.
I have a table for referred users (contains an email address and date columns) and a table for users.
I run to get the top referers:
SELECT count(r.Email) as count, r.Email
FROM refs r
WHERE r.referredOn > '2011-12-13'
GROUP BY email
ORDER BY count DESC
But I want to join this with the users table so it displays with other data in the user table, I thought a join would work. Left join becuase emails may be entered incorrectly, some people put first name etc under refs.Email
SELECT count(r.Email) as count, r.Email, u.*
FROM refs r LEFT JOIN users u ON u.email_primary = r.Email
WHERE r.referredOn > '2011-12-13'
GROUP BY email
ORDER BY count DESC
With the above query the count is incorrect, but I don't know why.
Try this one:
SELECT count(r.Email) as count, r.Email
FROM refs r
INNER JOIN users u ON u.email_primary = r.Email
WHERE r.referredOn > '2011-12-13'
GROUP BY email
ORDER BY count DESC
if your adding new column from users u you also need to add it on your group by clause.
Regards
Unfortunately, a LEFT JOIN wont help you here; what this type of join says is give me all the rows in users that match my email, as well as all the rows that have no match on email. If the email doesn't match, then they wont come back as you want.
So you can't use a the left join condition here the way you want.
If you enforced the fact that they had to enter an email everytime, and it was a valid email etc, then you could use an INNER JOIN.
JOINs are usually used to follow referential integrity. So, for example, I have a user with an id in one table, and another table with the column userid - there is a strong relationship between the two tables I can join on.
Jeft Atwood has a good explantion of how joins work.
SEE if this will help you:
SELECT e.count, e.email, u.col1, u.col2 -- etc
FROM (
SELECT count(r.Email) as count, r.Email
FROM refs r
WHERE r.referredOn > '2011-12-13'
GROUP BY email
) e
INNER JOIN
users u ON u.email_primary = e.Email
Instead of a direct join, you could TRY to use your counting query as a subquery-table type..
I wrote this query
SELECT *, count(r.Email) as count FROM refs r
LEFT OUTER JOIN users u ON r.email = u.email_primary
WHERE u.uid IS NOT NULL
GROUP BY u.uid
ORDER BY count DESC
Which showed me that the reason the count was wrong was because some of the email addresses are used twice in the users table (users sharing 'family' email address), this doubled my count, the above query shows each separate user account.
I have a left join to a table and want to count columns from it, after grouping by a column of the parent table:
SELECT * , COUNT(list.id) AS listcount, COUNT(uploads.id) AS uploadcount
FROM members
LEFT JOIN lists ON members.id= list.mid
LEFT JOIN uploads ON members.id= uploads.mid
GROUP BY members.id
Assume that a user can have either lists or uploads based on the type of user. Then is above query good enough? If not why?
Or do I have to use this query?
SELECT * , l.listcount, u.uploadcount
FROM members
LEFT JOIN (select count(lists.id) as listscount,mid from lists group by mid) as l
on l.mid = m.id
LEFT JOIN (select count(uploads.id) as uploadscount
,mid from uploads group by mid) as u on u.mid = m.id
GROUP BY members.id
Or correlated subqueries?
SELECT *,
(select count(lists.id) as listscount from lists as l where l.mid = m.id
group by mid) as listcount
(select count(uploads.id) from uploads as u where u.mid = m.id
group by mid) as uploadscount
FROM members
GROUP BY members.id
And which is best solution?
The alias m for members is missing in query 2 and 3. Otherwise they should give the same numbers.
Query 2 (fixed) will perform fastest.
Query 1 is different in that it will give a higher number for uploads, if there are cases of multiple lists per member. After joining to lists, there will be multiple rows for a member too, which will increase the count for uploads. So query 1 is probably wrong.
Also, NULL values are not counted. The manual informs:
COUNT(expr)
Returns a count of the number of non-NULL values of expr in the rows
retrieved by a SELECT statement. The result is a BIGINT value.