So I'm trying to add Foreign Key constraints to my database as a project requirement and it worked the first time or two on different tables, but I have two tables on which I get an error when trying to add the Foreign Key Constraints.
The error message that I get is:
ERROR 1215 (HY000): Cannot add foreign key constraint
This is the SQL I'm using to create the tables, the two offending tables are Patient and Appointment.
SET #OLD_UNIQUE_CHECKS=##UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET #OLD_FOREIGN_KEY_CHECKS=##FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=1;
SET #OLD_SQL_MODE=##SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';
CREATE SCHEMA IF NOT EXISTS `doctorsoffice` DEFAULT CHARACTER SET utf8 ;
USE `doctorsoffice` ;
-- -----------------------------------------------------
-- Table `doctorsoffice`.`doctor`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `doctorsoffice`.`doctor` ;
CREATE TABLE IF NOT EXISTS `doctorsoffice`.`doctor` (
`DoctorID` INT(11) NOT NULL AUTO_INCREMENT ,
`FName` VARCHAR(20) NULL DEFAULT NULL ,
`LName` VARCHAR(20) NULL DEFAULT NULL ,
`Gender` VARCHAR(1) NULL DEFAULT NULL ,
`Specialty` VARCHAR(40) NOT NULL DEFAULT 'General Practitioner' ,
UNIQUE INDEX `DoctorID` (`DoctorID` ASC) ,
PRIMARY KEY (`DoctorID`) )
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8;
-- -----------------------------------------------------
-- Table `doctorsoffice`.`medicalhistory`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `doctorsoffice`.`medicalhistory` ;
CREATE TABLE IF NOT EXISTS `doctorsoffice`.`medicalhistory` (
`MedicalHistoryID` INT(11) NOT NULL AUTO_INCREMENT ,
`Allergies` TEXT NULL DEFAULT NULL ,
`Medications` TEXT NULL DEFAULT NULL ,
`ExistingConditions` TEXT NULL DEFAULT NULL ,
`Misc` TEXT NULL DEFAULT NULL ,
UNIQUE INDEX `MedicalHistoryID` (`MedicalHistoryID` ASC) ,
PRIMARY KEY (`MedicalHistoryID`) )
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8;
-- -----------------------------------------------------
-- Table `doctorsoffice`.`Patient`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `doctorsoffice`.`Patient` ;
CREATE TABLE IF NOT EXISTS `doctorsoffice`.`Patient` (
`PatientID` INT unsigned NOT NULL AUTO_INCREMENT ,
`FName` VARCHAR(30) NULL ,
`LName` VARCHAR(45) NULL ,
`Gender` CHAR NULL ,
`DOB` DATE NULL ,
`SSN` DOUBLE NULL ,
`MedicalHistory` smallint(5) unsigned NOT NULL,
`PrimaryPhysician` smallint(5) unsigned NOT NULL,
PRIMARY KEY (`PatientID`) ,
UNIQUE INDEX `PatientID_UNIQUE` (`PatientID` ASC) ,
CONSTRAINT `FK_MedicalHistory`
FOREIGN KEY (`MEdicalHistory` )
REFERENCES `doctorsoffice`.`medicalhistory` (`MedicalHistoryID` )
ON DELETE CASCADE
ON UPDATE CASCADE,
CONSTRAINT `FK_PrimaryPhysician`
FOREIGN KEY (`PrimaryPhysician` )
REFERENCES `doctorsoffice`.`doctor` (`DoctorID` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `doctorsoffice`.`Appointment`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `doctorsoffice`.`Appointment` ;
CREATE TABLE IF NOT EXISTS `doctorsoffice`.`Appointment` (
`AppointmentID` smallint(5) unsigned NOT NULL AUTO_INCREMENT ,
`Date` DATE NULL ,
`Time` TIME NULL ,
`Patient` smallint(5) unsigned NOT NULL,
`Doctor` smallint(5) unsigned NOT NULL,
PRIMARY KEY (`AppointmentID`) ,
UNIQUE INDEX `AppointmentID_UNIQUE` (`AppointmentID` ASC) ,
CONSTRAINT `FK_Patient`
FOREIGN KEY (`Patient` )
REFERENCES `doctorsoffice`.`Patient` (`PatientID` )
ON DELETE CASCADE
ON UPDATE CASCADE,
CONSTRAINT `FK_Doctor`
FOREIGN KEY (`Doctor` )
REFERENCES `doctorsoffice`.`doctor` (`DoctorID` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `doctorsoffice`.`InsuranceCompany`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `doctorsoffice`.`InsuranceCompany` ;
CREATE TABLE IF NOT EXISTS `doctorsoffice`.`InsuranceCompany` (
`InsuranceID` smallint(5) NOT NULL AUTO_INCREMENT ,
`Name` VARCHAR(50) NULL ,
`Phone` DOUBLE NULL ,
PRIMARY KEY (`InsuranceID`) ,
UNIQUE INDEX `InsuranceID_UNIQUE` (`InsuranceID` ASC) )
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `doctorsoffice`.`PatientInsurance`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `doctorsoffice`.`PatientInsurance` ;
CREATE TABLE IF NOT EXISTS `doctorsoffice`.`PatientInsurance` (
`PolicyHolder` smallint(5) NOT NULL ,
`InsuranceCompany` smallint(5) NOT NULL ,
`CoPay` INT NOT NULL DEFAULT 5 ,
`PolicyNumber` smallint(5) NOT NULL AUTO_INCREMENT ,
PRIMARY KEY (`PolicyNumber`) ,
UNIQUE INDEX `PolicyNumber_UNIQUE` (`PolicyNumber` ASC) ,
CONSTRAINT `FK_PolicyHolder`
FOREIGN KEY (`PolicyHolder` )
REFERENCES `doctorsoffice`.`Patient` (`PatientID` )
ON DELETE CASCADE
ON UPDATE CASCADE,
CONSTRAINT `FK_InsuranceCompany`
FOREIGN KEY (`InsuranceCompany` )
REFERENCES `doctorsoffice`.`InsuranceCompany` (`InsuranceID` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
USE `doctorsoffice` ;
SET SQL_MODE=#OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=#OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=#OLD_UNIQUE_CHECKS;
To find the specific error run this:
SHOW ENGINE INNODB STATUS;
And look in the LATEST FOREIGN KEY ERROR section.
The data type for the child column must match the parent column exactly. For example, since medicalhistory.MedicalHistoryID is an INT, Patient.MedicalHistory also needs to be an INT, not a SMALLINT.
Also, you should run the query set foreign_key_checks=0 before running the DDL so you can create the tables in an arbitrary order rather than needing to create all parent tables before the relevant child tables.
I had set one field as "Unsigned" and other one not. Once I set both columns to Unsigned it worked.
Engine should be the same e.g. InnoDB
Datatype should be the same, and with same length. e.g. VARCHAR(20)
Collation Columns charset should be the same. e.g. utf8
Watchout: Even if your tables have same Collation, columns still could have different one.
Unique - Foreign key should refer to field that is unique (usually primary key) in the reference table.
Try to use the same type of your primary keys - int(11) - on the foreign keys - smallint(5) - as well.
Hope it helps!
Confirm that the character encoding and collation for the two tables is the same.
In my own case, one of the tables was using utf8 and the other was using latin1.
I had another case where the encoding was the same but the collation different. One utf8_general_ci the other utf8_unicode_ci
You can run this command to set the encoding and collation for a table.
ALTER TABLE tablename CONVERT TO CHARACTER SET utf8 COLLATE utf8_unicode_ci;
I hope this helps someone.
To set a FOREIGN KEY in Table B you must set a KEY in the table A.
In table A:
INDEX id (id)
And then in the table B,
CONSTRAINT `FK_id` FOREIGN KEY (`id`) REFERENCES `table-A` (`id`)
I had same problem and the solution was very simple.
Solution : foreign keys declared in table should not set to be not null.
reference : If you specify a SET NULL action, make sure that you have not declared the columns in the child table as NOT NULL. (ref
)
Check following rules :
First checks whether names are given right for table names
Second right data type give to foreign key ?
Please ensure that both the tables are in InnoDB format. Even if one is in MyISAM format, then, foreign key constraint wont work.
Also, another thing is that, both the fields should be of the same type. If one is INT, then the other should also be INT. If one is VARCHAR, the other should also be VARCHAR, etc.
I faced the issue and was able to resolve it by making sure that the data types were exactly matching .
I was using SequelPro for adding the constraint and it was making the primary key as unsigned by default .
Check the signing on both your table columns. If the referring table column is SIGNED, the referenced table column should be SIGNED too.
My problem was that I was trying to create the relation table before other tables!
So you have two ways to fix it:
change the order of MSQL commands
run this before your queries:
SET foreign_key_checks = 0;
NOTE: The following tables were taken from some site when I was doing
some R&D on the database. So the naming convention is not proper.
For me, the problem was, my parent table had the different character set than that of the one which I was creating.
Parent Table (PRODUCTS)
products | CREATE TABLE `products` (
`productCode` varchar(15) NOT NULL,
`productName` varchar(70) NOT NULL,
`productLine` varchar(50) NOT NULL,
`productScale` varchar(10) NOT NULL,
`productVendor` varchar(50) NOT NULL,
`productDescription` text NOT NULL,
`quantityInStock` smallint(6) NOT NULL,
`buyPrice` decimal(10,2) NOT NULL,
`msrp` decimal(10,2) NOT NULL,
PRIMARY KEY (`productCode`),
KEY `productLine` (`productLine`),
CONSTRAINT `products_ibfk_1` FOREIGN KEY (`productLine`) REFERENCES `productlines` (`productLine`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
Child Table which had a problem (PRICE_LOGS)
price_logs | CREATE TABLE `price_logs` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`productCode` varchar(15) DEFAULT NULL,
`old_price` decimal(20,2) NOT NULL,
`new_price` decimal(20,2) NOT NULL,
`added_on` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
KEY `productCode` (`productCode`),
CONSTRAINT `price_logs_ibfk_1` FOREIGN KEY (`productCode`) REFERENCES `products` (`productCode`) ON DELETE CASCADE ON UPDATE CASCADE
);
MODIFIED TO
price_logs | CREATE TABLE `price_logs` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`productCode` varchar(15) DEFAULT NULL,
`old_price` decimal(20,2) NOT NULL,
`new_price` decimal(20,2) NOT NULL,
`added_on` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
KEY `productCode` (`productCode`),
CONSTRAINT `price_logs_ibfk_1` FOREIGN KEY (`productCode`) REFERENCES `products` (`productCode`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=latin1
One additional cause of this error is when your tables or columns contain reserved keywords:
Sometimes one does forget these.
If you are getting this error with PhpMyAdmin, disable foreign key checks before importing the SQL file.
For me the target table was blocking the foreign key.
I had to set Auto-Increment (AI) on the table the Foreign-Key was pointing to.
I had a similar error in creating foreign key in a Many to Many table where the primary key consisted of 2 foreign keys and another normal column. I fixed the issue by correcting the referenced table name i.e. company, as shown in the corrected code below:
create table company_life_cycle__history -- (M-M)
(
company_life_cycle_id tinyint unsigned not null,
Foreign Key (company_life_cycle_id) references company_life_cycle(id) ON DELETE CASCADE ON UPDATE CASCADE,
company_id MEDIUMINT unsigned not null,
Foreign Key (company_id) references company(id) ON DELETE CASCADE ON UPDATE CASCADE,
activity_on date NOT NULL,
PRIMARY KEY pk_company_life_cycle_history (company_life_cycle_id, company_id,activity_on),
created_on datetime DEFAULT NULL,
updated_on datetime DEFAULT NULL,
created_by varchar(50) DEFAULT NULL,
updated_by varchar(50) DEFAULT NULL
);
I had similar error with two foreign keys for different tables but with same key names! I have renamed keys and the error had gone)
Had a similar error, but in my case I was missing to declare the pk as auto_increment.
Just in case it could be helpful to anyone
I got the same error. The cause in my case was:
I created a backup of a database via phpmyadmin by copying the whole database.
I created a new db with the same name the old db had und selected it.
I started an SQL script to create updated tables and data.
I got the error. Also when I disabled foreign_key_checks. Altough the database was completely empty.
The cause was: Since i used phpmyadmin to create some foreign keys in the renamed database - the foreign keys where created with a database name prefix but the database name prefix was not updated. So there were still references in the backup-db pointing to the newly created db.
My solution is maybe a little embarrassing and tells the tale of why you should sometimes look at what you have in front of you instead of these posts :)
I had ran a forward engineer before, which failed, so that meant that my database already had a few tables, then i have been sitting trying to fix foreign key contraints failures trying to make sure that everything was perfect, but it ran up against the tables previously created, so it was to no prevail.
In my case, there was a syntax error which was not explicitly notified by MySQL console upon running the query. However, SHOW ENGINE INNODB STATUS command's LATEST FOREIGN KEY ERROR section reported,
Syntax error close to:
REFERENCES`role`(`id`) ON DELETE CASCADE) ENGINE = InnoDB DEFAULT CHARSET = utf8
I had to leave a whitespace between REFERENCES and role to make it work.
For me it was - you can't omit prefixing the current DB table if you create a FK for a non-current DB referencing the current DB:
USE currrent_db;
ALTER TABLE other_db.tasks ADD CONSTRAINT tasks_fk FOREIGN KEY (user_id) REFERENCES currrent_db.users (id);
If I omit "currrent_db." for users table, I get the FK error. Interesting that SHOW ENGINE INNODB STATUS; shows nothing in this case.
My Solution!!
If we want to have column1 of table1 as a foreign key of table2, then column1 should be a key of table1.
For example, consider we have departments table, which has dept_id column.
Now let's say we have another table named employees which has emp_dept_id column.
If we want to use the dept_id column of the department table as a foreign key for the emp_dept_id column of emp, then the dept_id of department table SHOULD ATLEAST BE a key if not a primary key.
So make sure that dept_id of depratment is either a primary key or a unique key before using it as a foreign key for another table.
I had this same issue then i corrected the Engine name as Innodb in both parent and child tables and corrected the reference field name
FOREIGN KEY (c_id) REFERENCES x9o_parent_table(c_id)
then it works fine and the tables are installed correctly. This will be use full for someone.
Related
When I execute the follow two queries (I have stripped them down to absolutely necessary):
mysql> CREATE TABLE foo(id INT PRIMARY KEY);
Query OK, 0 rows affected (0.01 sec)
mysql> CREATE TABLE bar ( id INT, ref INT, FOREIGN KEY (ref) REFERENCES foo(id)) ENGINE InnoDB;
I get the following error:
ERROR 1005 (HY000): Can't create table './test/bar.frm' (errno: 150)
Where the **** is my error? I haven't found him while staring at this for half an hour.
From FOREIGN KEY Constraints
If you re-create a table that was
dropped, it must have a definition
that conforms to the foreign key
constraints referencing it. It must
have the right column names and types,
and it must have indexes on the
referenced keys, as stated earlier. If
these are not satisfied, MySQL returns
error number 1005 and refers to error
150 in the error message.
My suspicion is that it's because you didn't create foo as InnoDB, as everything else looks OK.
Edit: from the same page -
Both tables must be InnoDB tables and they must not be TEMPORARY tables.
You can use the command SHOW ENGINE INNODB STATUS to get more specific information about the error.
It will give you a result with a Status column containing a lot of text.
Look for the section called LATEST FOREIGN KEY ERROR which could for example look like this:
------------------------
LATEST FOREIGN KEY ERROR
------------------------
190215 11:51:26 Error in foreign key constraint of table `mydb1`.`contacts`:
Create table `mydb1`.`contacts` with foreign key constraint failed. You have defined a SET NULL condition but column 'domain_id' is defined as NOT NULL in ' FOREIGN KEY (domain_id) REFERENCES domains (id) ON DELETE SET NULL ON UPDATE CASCADE,
CONSTRAINT contacts_teams_id_fk FOREIGN KEY (team_id) REFERENCES teams (id) ON DELETE SET NULL ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT' near ' ON DELETE SET NULL ON UPDATE CASCADE,
CONSTRAINT contacts_teams_id_fk FOREIGN KEY (team_id) REFERENCES teams (id) ON DELETE SET NULL ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT'.
To create a foreign key ,
both the main column and the reference column must have same definition.
both tables engine must be InnoDB.
You can alter the engine of table using this command , please take the backup before executing this command.
alter table [table name] ENGINE=InnoDB;
I had the same problem, for those who are having this also:
check the table name of the referenced table
I had forgotten the 's' at the end of my table name
eg table Client --> Clients
:)
Apart form many other reasons to end up with MySql Error 150 (while using InnoDB), One of the probable reason, is the undefined KEY in the create statement of the table containing the column name referenced as a foreign key in the relative table.
Let's say the create statement of master table is -
CREATE TABLE 'master_table' (
'id' int(10) NOT NULL AUTO_INCREMENT,
'record_id' char(10) NOT NULL,
'name' varchar(50) NOT NULL DEFAULT '',
'address' varchar(200) NOT NULL DEFAULT '',
PRIMARY KEY ('id')
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
and the create syntax for the relative_table table where the foreign key constraint is set from primary table -
CREATE TABLE 'relative_table' (
'id' int(10) NOT NULL AUTO_INCREMENT,
'salary' int(10) NOT NULL DEFAULT '',
'grade' char(2) NOT NULL DEFAULT '',
'record_id' char(10) DEFAULT NULL,
PRIMARY KEY ('id'),
CONSTRAINT 'fk_slave_master' FOREIGN KEY ('record_id') REFERENCES 'master' ('record_id')
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
This script is definitely going to end with MySql Error 150 if using InnoDB.
To solve this, we need to add a KEY for the The column record_id in the master_table table and then reference in the relative_table table to be used as a foreign_key.
Finally, the create statement for the master_table, will be -
CREATE TABLE 'master_table' (
'id' int(10) NOT NULL AUTO_INCREMENT,
'record_id' char(10) NOT NULL,
'name' varchar(50) NOT NULL DEFAULT '',
'address' varchar(200) NOT NULL DEFAULT '',
PRIMARY KEY ('id'),
KEY 'record_id' ('record_id')
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
I had very same problem and the reason was the "collation" of columns was different. One was latin1 while the other was utf8
This may also happen if you have not given correct column name after "references" keyword.
While creating 2 tables in phpmyadmin I am getting an error like this.
MySQL said: Documentation
#1215 - Cannot add foreign key constraint
My table structures are
CREATE TABLE `iwd_storelocator_manufacturer` (
`entity_id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT ,
`name` varchar(255) NOT NULL ,
`code` varchar(255) NOT NULL ,
`grayscale_image` varchar(255) NULL ,
`color_image` varchar(255) NULL ,
PRIMARY KEY (`entity_id`)
);
CREATE TABLE `iwd_storelocator_manufacturer_to_store` (
`manufacturer_id` int(11) UNSIGNED NOT NULL ,
`store_id` int(11) NOT NULL ,
`preferred` int NULL ,
PRIMARY KEY (`manufacturer_id`, `store_id`),
FOREIGN KEY (`store_id`) REFERENCES `iwd_storelocator_store` (`store_id`) ON DELETE RESTRICT ON UPDATE CASCADE,
FOREIGN KEY (`manufacturer_id`) REFERENCES `iwd_storelocator_manufacturer` (`entity_id`) ON DELETE RESTRICT ON UPDATE CASCADE
);
Can you tell me whats the problem in it?
This is my iwd_storelocator_store table
iwd_storelocator_store
In order to know exactly what is wrong, you must check in LATEST FOREIGN KEY ERROR section.
Use this query to find this out:
SHOW ENGINE INNODB STATUS
Also, make sure that all the data types are the same: the data type of the child column must match the data type from the parent column.
If the problem is the order of creation of the tables (which can cause this error), just run set foreign_key_checks=0 so you can create the tables in any order rather than having to create all the parents tables BEFORE the child tables.
Finally, make sure that the encoding is the same for all the tables.
EDIT: in your case, you should also give us the structure of iwd_storelocator_store table
Now that we have your iwd_storelocator_store table, I think that you should create an index on store_id column as it is not the primary key of the table
I built a database with mySql Workbench, but when I try to forward engineer my model to the server, I get the following error :
ERROR: Error 1215: Cannot add foreign key constraint
followed by the definition of the table where the foreign key is defined, salaire_annee_ca
I read similar topics to identify the usual causes for this error, and checked :
if the foreign key defined in salaire_annee_ca references the primary key of another table, which it does
if something in the code allowed my key to be null, which it doesn't
if the types of the reference and of the foreign key were the same
It seems to me that all these conditions are ok, so I don't understand why I still get that message. Here are the definitions of my tables :
These are the two main ones :
-- Table `credit_impot_db`.`salaires_annee`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `credit_impot_db`.`salaires_annee` (
`salaire_annee_id` INT(11) NOT NULL ,
`salaire_annuel` DOUBLE NOT NULL DEFAULT 0 ,
`heures_travaillees` DOUBLE NOT NULL DEFAULT 0 ,
`pourcentage_rsde` DOUBLE NOT NULL DEFAULT 0 ,
`jours_travailles` INT(3) NOT NULL DEFAULT 0 ,
PRIMARY KEY (`salaire_annee_id`) ,
CONSTRAINT `salaire_annee_id`
FOREIGN KEY (`salaire_annee_id` )
REFERENCES `credit_impot_db`.`employes_ac` (`employe_ac_id` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
This one is at the origin of the message :
-- -----------------------------------------------------
-- Table `credit_impot_db`.`salaire_annee_ca`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `credit_impot_db`.`salaire_annee_ca` (
`salaire_annee_ca_id` INT(11) NOT NULL ,
PRIMARY KEY (`salaire_annee_ca_id`) ,
CONSTRAINT `salaire_annee_ca_id`
FOREIGN KEY (`salaire_annee_ca_id` )
REFERENCES `credit_impot_db`.`salaires_annee` (`salaire_annee_id` )
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
And the following two are also referenced :
-- -----------------------------------------------------
-- Table `credit_impot_db`.`employes`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `credit_impot_db`.`employes` (
`employe_id` INT(11) NOT NULL AUTO_INCREMENT ,
`employe_nom` VARCHAR(255) NOT NULL ,
`employe_prenom` VARCHAR(255) NOT NULL ,
`employe_fonction` VARCHAR(255) NULL ,
`employe_experience` VARCHAR(255) NULL DEFAULT NULL ,
PRIMARY KEY (`employe_id`) )
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `credit_impot_db`.`employes_ac`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `credit_impot_db`.`employes_ac` (
`employe_ac_id` INT(11) NOT NULL AUTO_INCREMENT ,
`fk_employe_ac_employe_id` INT(11) NULL ,
`fk_employe_ac_ac_id` INT(11) NULL ,
PRIMARY KEY (`employe_ac_id`) ,
INDEX `fk_employe_ac_employe_id_idx` (`fk_employe_ac_employe_id` ASC) ,
INDEX `fk_employe_ac_ac_id_idx` (`fk_employe_ac_ac_id` ASC) ,
CONSTRAINT `fk_employe_ac_employe_id`
FOREIGN KEY (`fk_employe_ac_employe_id` )
REFERENCES `credit_impot_db`.`employes` (`employe_id` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_employe_ac_ac_id`
FOREIGN KEY (`fk_employe_ac_ac_id` )
REFERENCES `credit_impot_db`.`dossier_client` (`ac_id` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
Any help would be appreciated!
I hit the dreaded error 1215 while using the Workbench and spent a long time trying to work out what was wrong. I eventually noticed that some of my tables were defined with "latin1 - default collation", while others were defined with "Schema Default". I had to expand the table definitions one by one in the EER diagram to see the option to change this. I changed all the definitions to "Schema Default" and the problem disappeared. Wow!
Ok I think I figured it out. It seems to be a problem with mySql Workbench, the error disappears if :
I first create my primary key in salaire_annee_ca,
Then Forward engineer my database
Declare my primary key as being a foreign key which references the primary key of salaire_annee
Forward engineer my database again
The error gets resolved:
To create a Foreign key for a table like this
CREATE TABLE users_so
(
username VARCHAR(10) NOT NULL,
password VARCHAR(32) NOT NULL,
enabled SMALLINT,
PRIMARY KEY (username)
);
The below code works fine
CREATE TABLE authorities_so
(
username VARCHAR(10) NOT NULL,
authority VARCHAR(10) NOT NULL,
FOREIGN KEY (username) REFERENCES users_so(username)
);
One of possible cause could be default storage engine on production db.
My problem was similar. I also worked with Workbench, and in local worked perfectly, also worked good in production, until I recreate schema on production server with Forward Engineering.
One of tables become MyISAM instead of InnoDb, and Row format from Don't use become Dynamic.
My solution was:
In Workbench,
Check every table that requires foreign keys to be InnoDb, and
Row format to be Default.
I have the following tables:
specie (MyIsam)
image (InnoDB)
specie_map (InnoDB)
The specie_map table should map an image to a specie, and therefore has the following columns:
specie_id
image_id
Both are int 11, just like the id columns of the specie and image tables. I know I can't create a foreign key between specie_id and specie=>id, since the specie table is a MyIsam table. However, I would expect it to be possible to create a foreign key between image_id and image=>id.
I can create that foreign key and it will save it, however, the CASCADE action I have associated with it does not work. When I delete an image, it does not delete the specie_map entry that is associated with it. I would expect this to work, as this foreign key is between InnoDB tables. Both columns are indexed and of the same data type.
Is this a limitation of MySQL, or am I doing something else wrong?
Update: as requested hereby the table definitions. I have snipped unimportant columns:
-- ----------------------------
-- Table structure for `image`
-- ----------------------------
DROP TABLE IF EXISTS `image`;
CREATE TABLE `image` (
`id` int(11) NOT NULL auto_increment,
`guid` char(36) default NULL,
`title` varchar(255) NOT NULL,
`description` text,
`user_id` int(11) NOT NULL,
`item_id` int(11) default NULL,
`date_uploaded` timestamp NOT NULL default '0000-00-00 00:00:00',
`date_created` timestamp NOT NULL default '0000-00-00 00:00:00',
`date_modified` timestamp NOT NULL default '0000-00-00 00:00:00',
`status` enum('softdeleted','tobedeleted','active') default 'active',
PRIMARY KEY (`id`),
KEY `image_user` (`user_id`),
KEY `image_item` (`item_id`),
KEY `image_mod_by` (`moderated_by`),
CONSTRAINT `image_mod_by` FOREIGN KEY (`moderated_by`) REFERENCES `user` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `image_user` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='stores image data (not file data)';
-- ----------------------------
-- Table structure for `specie`
-- ----------------------------
DROP TABLE IF EXISTS `specie`;
CREATE TABLE `specie` (
`id` int(11) NOT NULL auto_increment,
`name` varchar(256) NOT NULL,
`commonname` varchar(256) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=22 DEFAULT CHARSET=utf8 ROW_FORMAT=DYNAMIC;
-- ----------------------------
-- Table structure for `specie_map`
-- ----------------------------
DROP TABLE IF EXISTS `specie_map`;
CREATE TABLE `specie_map` (
`id` int(11) NOT NULL auto_increment,
`image_id` int(11) NOT NULL,
`specie_id` int(11) NOT NULL,
`user_id` int(11) NOT NULL,
`karma` int(11) NOT NULL,
`date_created` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP,
PRIMARY KEY (`id`),
KEY `image_id` (`image_id`),
KEY `specie_id` (`specie_id`),
CONSTRAINT `specie_map_ibfk_1` FOREIGN KEY (`image_id`) REFERENCES `image` (`id`) ON DELETE CASCADE ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Foreign keys works only with InnoDb in mysql. MyISAM doesn't support them (the statements are ignored).
And is there any reason why you mix multiple DB engines?
I think you should post the exact DDL statements you used when you attempted to create these tables and the foreign key. Foreign keys between innodb tables work fine, but there are still a few things to look out for:
0) Both tables must be InnoDB. This was already highlighted by the other posters and this is probably the immediate cause of your problem.
1) the data type of the referencing columns (those that make up the foreign key) and their respective referenced columns should be the same. For example, you can't create a foreign key constrain on an INT UNSIGNED column to a plain INT column.
2) if the foreign key is created as part of the table DDL, be sure to put the foreign key definition in the constraints section, that is, below all column definitions. For example:
CREATE TABLE parent (
id int unsigned PRIMARY KEY
);
CREATE TABLE child (
parent_id int unsigned
, foreign key (parent_id)
references parent (id)
);
will work but this:
CREATE TABLE child (
parent_id int unsigned
foreign key references parent (id)
);
won't. It will fail silently because MySQL's parser ignores these types of constraint definitions even before InnoDB gets to create the table (silly, but that's how it is)
3) There must be an index over all the referenced columns. Usually the referenced columns will together make up a primary key or a unique constraint anyway, but it is your job to define this before defining the foreign key.
Final word of advice: if you think your DDL is ok but you still get an error when you execute it, for example like this:
ERROR 1005 (HY000): Can't create table 'test.child' (errno: 150)
Warning (Code 150): Create table 'test/child' with foreign key constraint failed. There is no index in the referenced table where the referenced columns appear as the first columns.
Error (Code 1005): Can't create table 'test.child' (errno: 150)
Then these errors may still not reveal the true nature of the error (silly again, but that's how it is). To shed more light on it, run this command immediately after your attempt to create the foreign key:
SHOW ENGINE INNODB STATUS;
This will give you a bunch of status info, and one section there looks like this:
------------------------
LATEST FOREIGN KEY ERROR
------------------------
120122 11:38:28 Error in foreign key constraint of table test/child:
foreign key (parent_id) references parent (id) ):
Cannot find an index in the referenced table where the
referenced columns appear as the first columns, or column types
in the table and the referenced table do not match for constraint.
Note that the internal storage type of ENUM and SET changed in
tables created with >= InnoDB-4.1.12, and such columns in old tables
cannot be referenced by such columns in new tables.
See http://dev.mysql.com/doc/refman/5.5/en/innodb-foreign-key-constraints.html
for correct foreign key definition.
As you can see, this gives a bit more information and reveals the true problem, namely "column types in the table and the referenced table do not match for constraint"
So please, post your actual DDL, I'm sure there is a problem in there somewhere.
I used MySQL Workbench to generate a database and now I inserted it into the command-line client using:
mysql> . C:\Documents and
Settings\kdegroote\My
Documents\School\2008-2009\ICT2
\Gegevensbanken\Labo\Hoofdstuk 3 oef
6\pizzasecondtry.sql
For some reason, the last table won't be accepted. "Cannot create table" is the error message.
I manually editted the data to basically be the same, just without the special options Workbench adds to it and it worked like that.
I've been studying the original but I don't understand why it won't show me the tables.
So I was wondering if anybody here could have a look at it. Maybe someone else will see what I'm overlooking.
SET #OLD_UNIQUE_CHECKS=##UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET #OLD_FOREIGN_KEY_CHECKS=##FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET #OLD_SQL_MODE=##SQL_MODE, SQL_MODE='TRADITIONAL';
CREATE SCHEMA IF NOT EXISTS `PizzaDelivery` DEFAULT CHARACTER SET utf8 COLLATE utf8_general_ci;
USE `PizzaDelivery`;
CREATE TABLE IF NOT EXISTS `PizzaDelivery`.`Visitors` (
`visitor_id` INT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(45) NOT NULL ,
`adres` VARCHAR(45) NOT NULL ,
`telephone` MEDIUMBLOB NOT NULL ,
`email` VARCHAR(45) NOT NULL ,
PRIMARY KEY (`visitor_id`))ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS `PizzaDelivery`.`Employees` (
`employee_id` INT NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(45) NOT NULL ,
PRIMARY KEY (`employee_id`))ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS `PizzaDelivery`.`Orders` (
`order_id` INT NOT NULL AUTO_INCREMENT ,
`pizza` VARCHAR(45) NOT NULL ,
`extra` VARCHAR(45) NULL ,
`kind` VARCHAR(45) NOT NULL ,
`amount` VARCHAR(45) NOT NULL ,
`visitor_id` INT NOT NULL ,
`employee_id` INT NOT NULL ,
`order_time` TIME NOT NULL ,
PRIMARY KEY (`order_id`) ,
INDEX `visitor_id` (`visitor_id` ASC) ,
INDEX `employee_id` (`employee_id` ASC) ,
CONSTRAINT `visitor_id`
FOREIGN KEY (`visitor_id` )
REFERENCES `PizzaDelivery`.`Visitors` (`visitor_id` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `employee_id`
FOREIGN KEY (`employee_id` )
REFERENCES `PizzaDelivery`.`Employees` (`employee_id` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)ENGINE=InnoDB;
CREATE TABLE IF NOT EXISTS `PizzaDelivery`.`Deliveries` (
`employee_id` INT NOT NULL ,
`order_id` INT NOT NULL ,
`voertuig_id` INT NOT NULL ,
`deliverytime` TIME NOT NULL ,
PRIMARY KEY (`employee_id`, `order_id`) ,
INDEX `employee_id` (`employee_id` ASC) ,
INDEX `order_id` (`order_id` ASC) ,
CONSTRAINT `employee_id`
FOREIGN KEY (`employee_id` )
REFERENCES `PizzaDelivery`.`Employees` (`employee_id` )
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `order_id`
FOREIGN KEY (`order_id` )
REFERENCES `PizzaDelivery`.`Orders` (`order_id` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)ENGINE=InnoDB;
SET SQL_MODE=#OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=#OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=#OLD_UNIQUE_CHECKS;
You can often get more information from an InnoDB error like this:
mysql> SHOW ENGINE INNODB STATUS;
The output is long, but among the status output I saw this:
------------------------
LATEST FOREIGN KEY ERROR
------------------------
081221 12:02:36 Error in foreign key constraint creation
for table `pizzadelivery/deliveries`.
A foreign key constraint of name `pizzadelivery/employee_id`
already exists.
The problem is that the Deliveries and the Orders tables both declare a foreign key constraint named employee_id.
Constraint names must be unique across all tables in a given database. The "errno: 121" is an InnoDB error code indicating a duplicate key error. In this case, the uniqueness of constraint names is not satisfied.
You can fix this problem and still keep your foreign key constraints if you just change the name of the declared constraint, for example:
CREATE TABLE IF NOT EXISTS `PizzaDelivery`.`Deliveries` (
. . .
CONSTRAINT `employee_id2`
FOREIGN KEY (`employee_id` )
. . .
PROBLEM SOLVED.
I solved my problem here rather by accident.
The problem appeared to be the constraints in the "Deliveries" table.
The 2 primairy keys are foreign keys at the same time and that generates and error if you want to constrain them.
So I simply left out the constraints and everything works.
Try use PizzaDelivery before running show tables. You created your tables in the PizzaDelivery schema, but you probably connected with a different default schema. The default schema is the parameter to the mysql command line client:
$ mysql -h <db-host> -u <username> -p <schema-name>
(note: -p means prompt for password when it is not given an argument, which you generally shouldn't do because arguments show up in ps output and also get saved to disk in shell history. All of the command line parameters are optional.)