How to replace last occurrence of a substring in MYSQL? - mysql

Question

How can I replace the last occurrence of a substring with blank string in MYSQL?I could not find any such direct function in MYSQL
String: "American Corp National Corp"
Search String: "Corp"
Expected output: "American Corp National"
Could anyone suggest?

Answer 1

This is shorter and more readable:
SELECT TRIM(TRAILING 'Corp' FROM 'American Corp National Corp')

Answer 2

Try:
select reverse(concat(
left(reverse('American Corp National Corp'),
instr(reverse('American Corp National Corp'),reverse('Corp'))-1),
substr(reverse('American Corp National Corp'),
instr(reverse('American Corp National Corp'),reverse('Corp'))+
length('Corp')))) result
(SQLFiddle)

Answer 3

After researching this problem myself and reading the answers above, I created the following function to solve this problem. In my case, I needed to change the last separator in a sequence, so that e.g., "Aap, Noot, Mies" would become "Aap, Noot & Mies":
CREATE DEFINER=`root`#`localhost` FUNCTION `change_last_substring`(
input_string text,
separator_old tinytext,
separator_new tinytext
) RETURNS text CHARSET utf8
BEGIN
set #output_string=
trim(
leading separator_new from
concat
(
left(input_string,length(input_string)-length(substring_index(input_string,separator_old,-1))-2),
separator_new,
substring_index(input_string,separator_old,-1)
)
);
RETURN #output_string;
END

Answer 4

Here is an SQL-query:
select CONCAT(SUBSTRING_INDEX('<TEST_STRING>','<String that you want to replace>',(length('<TEST_STRING>') - length(replace('<TEST_STRING>', '<String that you want to replace>', '')))),'<String to be replaced>',SUBSTRING_INDEX('<TEST_STRING>', '<String that you want to replace>', -1)) as test

Answer 5

This feels like an awful way to do it, but... reverse the string, search for the first occurence of the reverse of the search string using locate, then calculate what index that would be in the non reversed string?
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_reverse
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_locate
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_char-length (Pretty sure you need to use this instead of length to be unicode compliant, but check to be sure!)
Worked example:
String: 0123456789 (char_length = 10)
Search string: 567 (char_length = 3)
Reverse string: 9876543210
Reverse search string: 765
Locate returns index = 2
index of end in real string = 7 (char_length(string) - 1 - index -> 10 - 1 - 2)
index of start in real string = 5 (char_length(string) - 1 - (char_length(search string) - 1) - index -> 10 - 1 - (3 - 1) - 2)

Answer 6

The accepted answer doesn't replace #FROM with #TO, it replaces #FROM with empty string. If you need to replace #FROM with #TO, here is a modification of that answer:
SELECT reverse(
concat(
concat(
left(reverse(value),
instr(reverse(value), reverse(#FROM)) - 1),
#TO
),
substr(reverse(value),
instr(reverse(value), reverse(#FROM)) +
length(#FROM))))
FROM `table`
WHERE `value` like '%' + #FROM + '%'
Notice additional WHEREvaluelike '%' + #FROM + '%', as this removes an extra character if the substring doesn't occur in the value, e.g. trying to replace "a" with "b" in "ccc" results in "cc"

Answer 7

More easy and reliable
CONCAT(SUBSTRING_INDEX('American Corp National Corp','Corp',2), "REPLACE_STRING" ,SUBSTRING_INDEX('American Corp National Corp','Corp',-1))
REPLACE_STRING you can change it with replace string or empty for replacing.

Answer 8

If you have a recent version of MySQL (>= v8) / MariaDB (>= v10.0.5), you can use REGEXP_REPLACE to replace the last occurrence of needle with replacement, like so:
REGEXP_REPLACE(haystack, "^.*needle", "\\1replacement")
This exploits the greediness of *.
If you are using MySQL, and know (or can calculate) the number of occurrences, you can use the optional occurence parameter of REGEXP_REPLACE.