Get dynamic column value - mysql

I have a table student that contains :
student_id , prefered_cell , cell_1 , cell_2 , cell_3
now under prefered cell values we have (cell_1,cell2,cell3)
what is the best way to get the value of the prefered cell in mysql ?
those are the available rows :
1 , 'cell_1' , '123-321-1231' , '431-2133-321' , '123-123-4111'
2 , 'cell_2' , '122-333-3333' , '455-123-123' , '123-421-2345'
so i want to have the preferred number for student 1 and 2 :
will get :
1 , '123-321-1231'
2 , '455-123-123'

Try this Query.
Select student_id, case when prefered_cell = 'cell_1' then cell_1
when prefered_cell = 'cell_2' then cell_2
when prefered_cell = 'cell_3' then cell_3
else '0'
End as cell_value from student

we have switch in sql.You can use that
select student_id ,case from table_name
CASE prefered_cell
WHEN 'cell_1' THEN 'value is cell_1 '
WHEN 'cell_2' THEN 'value is cell_2'
WHEN 'cell_3'= 'cell_3' then cell_3
END
else '0'
End from student

Related

SQL Convert a char to boolean

I have in my table one row with a char value. When the value is NULL then a false should be outputted. If the value is not NULL then a true should be outputted.
So when I try to set user_group.tUser to 0 or 1 then I'm getting this error:
Invalid column name 'false'.
Invalid column name 'true'.
SELECT COALESCE((SELECT name
FROM v_company
WHERE companyId = userView.companyId), ' ') AS company,
userView.value AS companyUser,
userView.display AS displayedUser,
CASE
WHEN user_group.tUser IS NULL THEN 0
ELSE 1
END AS userIsMemberOfGroup
FROM v_user userView
LEFT OUTER JOIN cr_user_group user_group
ON ( user_group.group = 'Administrators'
AND user_group.tUser = userView.value )
ORDER BY company ASC,
displayedUser ASC
I think this is the logic you want:
SELECT COALESCE(v.name, ' ') as company,
u.value as companyUser, u.display as displayedUser,
(EXISTS (SELECT 1
FROM cr_user_group ug
WHERE ug.group = 'Administrators' AND
ug.tUser = uv.value
)
) as userIsMemberOfGroup
FROM v_user u LEFT JOIN
v_company c
ON c.companyId = v.companyId
ORDER BY company ASC, displayedUser ASC ;
In general, MySQL is very flexible about going between booleans and numbers, with 0 for false and 1 for true.
You can use MySQL IF function to return 'false' when name IS NULL, else 'true':
SELECT IF(name IS NULL, 'false', 'true')
FROM table;
A simple CASE expression would work here:
SELECT
name,
CASE WHEN name IS NOT NULL THEN true ELSE false END AS name_out
FROM yourTable;
We could also shorten the above a bit using IF:
IF(name IS NOT NULL, true, false)
SELECT
CASE
WHEN name IS NULL THEN 'false'
ELSE 'true'
END
FROM
table1;

How to use Group By correclty?

I have this query that worked fine:
select isnull(email,'') as Email ,isnull([ERPM First Name],'')+' '+isnull([ERPM Last Name],'')[User Name],
geo,CustomerID,BusinessID,courseid, MIN (CompletionDate) [1st Training Course],
CASE WHEN COURSEID IN (37445,37644,37443,37778,37435,37733,37584,37483,37392,37817,
37259,37597,37391,37393,37792,37816,37256,37257,37258,37484,37485,37486)
THEN 'Yes' ELSE 'No'
END AS [Is it a campaing course?],
CASE WHEN CompletionDate BETWEEN '2017-03-10' AND '2017-09-03' THEN 'Yes' ELSE 'No'
END AS [During Campaign],
CASE WHEN COURSEID IN (37256,37257,37258,37484,37485,37486) AND
CompletionDate BETWEEN '2017-03-10' AND '2017-09-03' THEN 'ON Period Bonus' ELSE '-'
END AS [1st BONUS]
from vw_Training_Cube
where [Is disti or subdisti?] = 'No' and [Is test account?] = 'No'
and Email<>'0'
GROUP BY isnull(email,''),isnull([ERPM First Name],'')+' '+isnull([ERPM Last Name],''),geo,CustomerID,BusinessID,courseid,
CASE WHEN COURSEID IN (37445,37644,37443,37778,37435,37733,37584,37483,37392,
37817,37259,37597,37391,37393,37792,37816,37256,37257,37258,37484,37485,37486)
THEN 'Yes' ELSE 'No'
END,
CASE WHEN CompletionDate BETWEEN '2017-03-10' AND '2017-09-03' THEN 'Yes' ELSE 'No'
END,
CASE WHEN COURSEID IN (37256,37257,37258,37484,37485,37486) AND
CompletionDate BETWEEN '2017-03-10' AND '2017-09-03' THEN 'ON Period Bonus' ELSE '-5'
END
but now instead of grouping by email, I want to group by business id. But simply swapping the order doesnt solve the problem.
Unless you need an aggregate function such as COUNT() MIN() or MAX() then you can simplify your query by using select distinct.
SELECT DISTINCT
ISNULL(email, '')
AS Email
, ISNULL([ERPM First Name], '') + ' ' + ISNULL([ERPM Last Name], '')
[User Name]
, geo
, CustomerID
, BusinessID
, courseid
, MIN(CompletionDate) [1st Training Course]
, CASE
WHEN COURSEID IN (37445, 37644, 37443, 37778, 37435, 37733, 37584, 37483, 37392, 37817,
37259, 37597, 37391, 37393, 37792, 37816, 37256, 37257, 37258, 37484, 37485, 37486) THEN
'Yes'
ELSE
'No'
END AS [Is it a campaing course?]
, CASE
WHEN CompletionDate BETWEEN '2017-03-10' AND '2017-09-03' THEN
'Yes'
ELSE
'No'
END AS [During Campaign]
, CASE
WHEN COURSEID IN (37256, 37257, 37258, 37484, 37485, 37486) AND
CompletionDate BETWEEN '2017-03-10' AND '2017-09-03' THEN
'ON Period Bonus'
ELSE
'-'
END AS [1st BONUS]
FROM vw_Training_Cube
WHERE [Is disti or subdisti?] = 'No'
AND [Is test account?] = 'No'
AND Email <> '0'
ORDER BY BusinessID
To reduce the rows further, you also need to remove columns - OR - start using aggregate functions. e.g. the following would produce the minimum set of rows to list every BusinessID that meets the where conditions.
SELECT DISTINCT
BusinessID
FROM vw_Training_Cube
WHERE [Is disti or subdisti?] = 'No'
AND [Is test account?] = 'No'
AND Email <> '0'
ORDER BY BusinessID
;
Keep adding columns to that to see the effect on number of rows.

MySQL - Rows to Columns and keeps NULL

We have the following table (TEST2) in the MySQL database (MySQL 5.6):
TEAM_ID,MEMBER_ID,TYPE,SCORE
1,2,A,150
1,3,B,200
1,1,B,50
1,1,A,100
1,2,B,NULL
We try to transform/pivot the above table based on the TYPE column:
If the TYPE column has value == A, move the value in the SCORE column into a new column called A_SCORE. If the value in the SCORE column is NULL, it should show NULL in the new A_SCORE column.
If the TYPE column has value == B, move the value in the SCORE column into a new column called B_SCORE. If the value in the SCORE column is NULL, it should show NULL in the new B_SCORE column.
The following table is the one we are looking for (the wanted table):
TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE,A_SCORE_MINUS_B_SCORE
1,1,100,50,50
1,2,150,NULL,NULL
1,3,0,200,-200
We tried the following query
SELECT TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE,SUM(A_SCORE-B_SCORE) AS ACTUAL_MINUS_B_SCORE FROM
(SELECT TEAM_ID,MEMBER_ID,
CASE
WHEN SCORE IS NULL
THEN NULL
ELSE SUM(if(TYPE = 'A', SCORE,0) )
END A_SCORE,
CASE
WHEN SCORE IS NULL
THEN NULL
ELSE SUM(if(TYPE = 'B', SCORE,0) )
END B_SCORE
FROM TEST2
GROUP BY TEAM_ID,MEMBER_ID,SCORE) AS A
GROUP BY TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE);
It returns something we don’t want:
TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE,A_SCORE_MINUS_B_SCORE
1,1,0,50,-50
1,1,100,0,100
1,2,0,0,0
1,2,150,0,150
1,3,0,200,-200
If we tried the following, it generates a table close to what we want, but it doesn’t return any NULL value.
SELECT TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE,SUM(A_SCORE-B_SCORE) AS A_SCORE _MINUS_B_SCORE FROM
(SELECT TEAM_ID,MEMBER_ID,
SUM(if(TYPE = 'A', SCORE,0) ) AS A_SCORE,
SUM(if(TYPE = 'B', SCORE,0) )AS B_SCORE
FROM TEST2
GROUP BY TEAM_ID,MEMBER_ID) AS A
GROUP BY TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE;
The result of the above query:
TEAM_ID,MEMBER_ID,A_SCORE,B_SCORE,A_SCORE_MINUS_B_SCORE
1,1,100,50,50
1,2,150,0,0
1,3,0,200,-200
Could any guru enlighten how to generate the wanted table in this case using MySQL? The SQL fiddle is here for your convenience.
http://sqlfiddle.com/#!9/cfe7a1/1
Thanks!
Try this;)
SELECT TEAM_ID, MEMBER_ID, A_SCORE, B_SCORE, A_SCORE - B_SCORE AS A_SCORE_MINUS_B_SCORE
FROM (
SELECT
TEAM_ID, MEMBER_ID,
CASE
WHEN A_SCORE IS NULL AND NOT EXISTS (
SELECT 1 FROM TEST2
WHERE TEAM_ID = T1.TEAM_ID
AND MEMBER_ID = T1.MEMBER_ID
AND TYPE = 'A'
) THEN 0 ELSE A_SCORE END AS A_SCORE,
CASE
WHEN B_SCORE IS NULL AND NOT EXISTS (
SELECT 1 FROM TEST2
WHERE TEAM_ID = T1.TEAM_ID
AND MEMBER_ID = T1.MEMBER_ID
AND TYPE = 'A'
) THEN 0 ELSE B_SCORE END AS B_SCORE
FROM (
SELECT
TEAM_ID, MEMBER_ID,
MAX(CASE WHEN TYPE = 'A' THEN SCORE END) AS A_SCORE,
MAX(CASE WHEN TYPE = 'B' THEN SCORE END) AS B_SCORE
FROM TEST2
GROUP BY TEAM_ID, MEMBER_ID
) T1
)T
SQLFiddle demo here
I don't quite understand the calculation criteria, but something like this should work...
SELECT team_id
, member_id
, COALESCE(MAX(CASE WHEN type = 'A' THEN score END),0) a_score
, COALESCE(MAX(CASE WHEN type = 'B' THEN score END),0) b_score
, COALESCE(MAX(CASE WHEN type = 'A' THEN score END),0)
- COALESCE(MAX(CASE WHEN type = 'B' THEN score END),0) diff
FROM test2
GROUP
BY team_id
, member_id;

Unable to update multiple records with one single query (CASE/WHEN))

I am trying to update multiple records for few columns in a table in SQL with following query.
(I wish to update A with A1, B with B1, C with C1 and on..)
UPDATE Employee
SET CASE WHEN name ='A' then 'A1' END
CASE WHEN name ='B' then 'A2' END
CASE WHEN name ='C' then 'A3' END
CASE WHEN name ='D' then 'A4' END
CASE WHEN name ='E' then 'A5' END
CASE WHEN name ='F' then 'A6' END
CASE WHEN name ='G' then 'A7' END
CASE WHEN name ='H' then 'A8' END
CASE WHEN name ='J' then 'A9' END
CASE WHEN name ='K' then 'B0' END
CASE WHEN name ='L' then 'B1' END ,
CASE WHEN Category = 'recrods' THEN 'records' END ,
CASE WHEN featureID ='140' then 'CV5' END
WHERE School = '5000'
Getting error : Incorrect syntax near the keyword 'CASE'. Sure I am missing something here.
Please help me. Thanks a lot in advance :)
You need a column as the first thing after the set. Perhaps:
UPDATE Employee
SET name = (CASE WHEN name ='A' then 'A1'
WHEN name ='B' then 'A2'
WHEN name ='C' then 'A3'
WHEN name ='D' then 'A4'
WHEN name ='E' then 'A5'
WHEN name ='F' then 'A6'
WHEN name ='G' then 'A7'
WHEN name ='H' then 'A8'
WHEN name ='J' then 'A9'
WHEN name ='K' then 'B0'
WHEN name ='L' then 'B1'
ELSE name
END),
category = (CASE WHEN Category = 'recrods' THEN 'records' ELSE category END),
featureID = (CASE WHEN featureID ='140' then 'CV5' else featureID END)
WHERE School = '5000' ;

How to solve this subquery error?

Can you please tell me whats wrong with this?
It throws error
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
And whats meant by using({?SUB_ALLOC_PARM})) I guess its parameter value right?
select distinct LFS_LFS as DN
, LFS_VONNR
, LZL_REFNR
, AGR_TEXT
, LFS_KNR as Store
, LFS_DATOK
, FIL_INDEX as Store_name
, LAN_TEXT as COUNTRY
, LZL_MENGE as Qty
, ANS_NAME1 AS 'Customer Name'
, ANS_NAME2 AS 'Customer Address line 1'
, ANS_STRASSE AS 'Customer Address line 2'
, ANS_STRASSE_2 AS 'Customer Address line 3'
, ANS_ORT AS 'City'
, ANS_TITEL AS 'State'
, LAN_TEXT AS 'Country'
, ANS_PLZ AS 'PostCode'
, ( select FIL_NUMMER
from FUTURA..V_FILIALEN as HO
where HO.FIL_LAND = STORE.FIL_LAND
and HO.FIL_MANDANT = 1
and HO.FIL_ART = 0
) as HO_BRANCH
from FUTURA..V_LIEFHEAD,
FUTURA..V_ARTIKEL,
FUTURA..V_ART_KOPF,
FUTURA..V_LIEFZEIL,
FUTURA..V_LAGER as BR5,
FUTURA..V_FILIALEN as STORE,
FUTURA..V_ANSCHRIF,
FUTURA..V_LAND
where AGR_MANDANT = ART_MANDANT
and AGR_WARENGR = ART_WARENGR
and AGR_ABTEILUNG = ART_ABTEILUNG
and AGR_TYPE = ART_TYPE
and AGR_GRPNUMMER = ART_GRPNUMMER
and LZL_REFNR = ART_REFNUMMER
and ART_MANDANT = LFS_MANDANT
and LFS_LFS = LZL_LFS and LFS_MANDANT = LZL_MANDANT
and LFS_MANDANT = 1
and LZL_REFNR <> 0
and LZL_REFNR = BR5.LAG_REFNUMMER
and LZL_MANDANT = BR5.LAG_MANDANT
and BR5.LAG_MANDANT = 1
and BR5.LAG_FILIALE = LFS_VONNR
and FIL_MANDANT = LZL_MANDANT
and FIL_NUMMER = LFS_KNR
and LAN_MANDANT = FIL_MANDANT
and LAN_NUMMER = FIL_LAND
AND ANS_TYP = 2 -- branches
AND ANS_COUNT = 1 -- sequence 1
AND ANS_MANDANT = FIL_MANDANT
AND ANS_NUMMER = FIL_NUMMER
and LFS_LFS IN (
select distinct PVG_LIEFERSCHEIN
from FUTURA..V_PVERFIL
where PVG_NUMMER IN ({?SUB_ALLOC_PARM})
)
order by
LFS_KNR
Most likely, your
select FIL_NUMMER
from FUTURA..V_FILIALEN as HO
where HO.FIL_LAND = STORE.FIL_LAND
and HO.FIL_MANDANT = 1
and HO.FIL_ART = 0
clause is returning more than one value.