output of shell script in json form - json

I want to get output of following small shell script in json form.
#!/bin/bash
top -b -d1 -n1 | grep Cpu
Output:
Cpu(s): 6.2%us, 1.6%sy, 0.2%ni, 90.9%id, 1.1%wa, 0.0%hi, 0.0%si, 0.0%st
Required Output:
{"Cpu": "6.3" }
How can I convert output of such every shell scripts in json form ?

You could try this
echo "{\"Cpu\":\"`top -b -d1 -n1 | grep Cpu | cut -f3 -d " " | cut -f1 -d %`\"}"
A brief description: First, take a look at man cut, especially -f and -d arguments. The \"s are simply double quotations, which should be preceded with a backslash to avoid misunderstanding by shell interpreter. And at last, anything enclosed in back quotation marks `` would be executed, as described here.

try this line:
your commands ...|awk 'BEGIN{FS="\\(s\\):\\s*";OFS="";q="\x22" }{$1=q$1q;sub(/%.*$/,"%",$2);$2=q$2q; print $1,$2}'
test with your data:
kent$ echo "Cpu(s): 6.2%us, 1.6%sy, 0.2%ni, 90.9%id, 1.1%wa, 0.0%hi, 0.0%si, 0.0%st"|awk 'BEGIN{FS="\\(s\\):\\s*";OFS="";q="\x22" }{$1=q$1q;sub(/%.*$/,"%",$2);$2=q$2q; print $1,$2}'
"Cpu""6.2%"

Related

Storing aws ssm parameter as variable in bash script [duplicate]

I have a pretty simple script that is something like the following:
#!/bin/bash
VAR1="$1"
MOREF='sudo run command against $VAR1 | grep name | cut -c7-'
echo $MOREF
When I run this script from the command line and pass it the arguments, I am not getting any output. However, when I run the commands contained within the $MOREF variable, I am able to get output.
How can one take the results of a command that needs to be run within a script, save it to a variable, and then output that variable on the screen?
In addition to backticks `command`, command substitution can be done with $(command) or "$(command)", which I find easier to read, and allows for nesting.
OUTPUT=$(ls -1)
echo "${OUTPUT}"
MULTILINE=$(ls \
-1)
echo "${MULTILINE}"
Quoting (") does matter to preserve multi-line variable values; it is optional on the right-hand side of an assignment, as word splitting is not performed, so OUTPUT=$(ls -1) would work fine.
$(sudo run command)
If you're going to use an apostrophe, you need `, not '. This character is called "backticks" (or "grave accent"):
#!/bin/bash
VAR1="$1"
VAR2="$2"
MOREF=`sudo run command against "$VAR1" | grep name | cut -c7-`
echo "$MOREF"
Some Bash tricks I use to set variables from commands
Sorry, there is a loong answer, but as bash is a shell, where the main goal is to run other unix commands and react on result code and/or output, ( commands are often piped filter, etc... ).
Storing command output in variables is something basic and fundamental.
Therefore, depending on
compatibility (posix)
kind of output (filter(s))
number of variable to set (split or interpret)
execution time (monitoring)
error trapping
repeatability of request (see long running background process, further)
interactivity (considering user input while reading from another input file descriptor)
do I miss something?
First simple, old (obsolete), and compatible way
myPi=`echo '4*a(1)' | bc -l`
echo $myPi
3.14159265358979323844
Compatible, second way
As nesting could become heavy, parenthesis was implemented for this
myPi=$(bc -l <<<'4*a(1)')
Using backticks in script is to be avoided today.
Nested sample:
SysStarted=$(date -d "$(ps ho lstart 1)" +%s)
echo $SysStarted
1480656334
bash features
Reading more than one variable (with Bashisms)
df -k /
Filesystem 1K-blocks Used Available Use% Mounted on
/dev/dm-0 999320 529020 401488 57% /
If I just want a used value:
array=($(df -k /))
you could see an array variable:
declare -p array
declare -a array='([0]="Filesystem" [1]="1K-blocks" [2]="Used" [3]="Available" [
4]="Use%" [5]="Mounted" [6]="on" [7]="/dev/dm-0" [8]="999320" [9]="529020" [10]=
"401488" [11]="57%" [12]="/")'
Then:
echo ${array[9]}
529020
But I often use this:
{ read -r _;read -r filesystem size using avail prct mountpoint ; } < <(df -k /)
echo $using
529020
( The first read _ will just drop header line. ) Here, in only one command, you will populate 6 different variables (shown by alphabetical order):
declare -p avail filesystem mountpoint prct size using
declare -- avail="401488"
declare -- filesystem="/dev/dm-0"
declare -- mountpoint="/"
declare -- prct="57%"
declare -- size="999320"
declare -- using="529020"
Or
{ read -a head;varnames=(${head[#]//[K1% -]});varnames=(${head[#]//[K1% -]});
read ${varnames[#],,} ; } < <(LANG=C df -k /)
Then:
declare -p varnames ${varnames[#],,}
declare -a varnames=([0]="Filesystem" [1]="blocks" [2]="Used" [3]="Available" [4]="Use" [5]="Mounted" [6]="on")
declare -- filesystem="/dev/dm-0"
declare -- blocks="999320"
declare -- used="529020"
declare -- available="401488"
declare -- use="57%"
declare -- mounted="/"
declare -- on=""
Or even:
{ read _ ; read filesystem dsk[{6,2,9}] prct mountpoint ; } < <(df -k /)
declare -p mountpoint dsk
declare -- mountpoint="/"
declare -a dsk=([2]="529020" [6]="999320" [9]="401488")
(Note Used and Blocks is switched there: read ... dsk[6] dsk[2] dsk[9] ...)
... will work with associative arrays too: read _ disk[total] disk[used] ...
Other related sample: Parsing xrandr output: and end of Firefox tab by bash in a size of x% of display size? or at AskUbuntu.com Parsing xrandr output
Dedicated fd using unnamed fifo:
There is an elegent way! In this sample, I will read /etc/passwd file:
users=()
while IFS=: read -u $list user pass uid gid name home bin ;do
((uid>=500)) &&
printf -v users[uid] "%11d %7d %-20s %s\n" $uid $gid $user $home
done {list}</etc/passwd
Using this way (... read -u $list; ... {list}<inputfile) leave STDIN free for other purposes, like user interaction.
Then
echo -n "${users[#]}"
1000 1000 user /home/user
...
65534 65534 nobody /nonexistent
and
echo ${!users[#]}
1000 ... 65534
echo -n "${users[1000]}"
1000 1000 user /home/user
This could be used with static files or even /dev/tcp/xx.xx.xx.xx/yyy with x for ip address or hostname and y for port number or with the output of a command:
{
read -u $list -a head # read header in array `head`
varnames=(${head[#]//[K1% -]}) # drop illegal chars for variable names
while read -u $list ${varnames[#],,} ;do
((pct=available*100/(available+used),pct<10)) &&
printf "WARN: FS: %-20s on %-14s %3d <10 (Total: %11u, Use: %7s)\n" \
"${filesystem#*/mapper/}" "$mounted" $pct $blocks "$use"
done
} {list}< <(LANG=C df -k)
And of course with inline documents:
while IFS=\; read -u $list -a myvar ;do
echo ${myvar[2]}
done {list}<<"eof"
foo;bar;baz
alice;bob;charlie
$cherry;$strawberry;$memberberries
eof
Practical sample parsing CSV files:
As this answer is loong enough, for this paragraph,
I just will let you refer to
this answer to How to parse a CSV file in Bash?, I read a file by using an unnamed fifo, using syntax like:
exec {FD}<"$file" # open unnamed fifo for read
IFS=';' read -ru $FD -a headline
while IFS=';' read -ru $FD -a row ;do ...
... But using bash loadable CSV module.
On my website, you may find the same script, reading CSV as inline document.
Sample function for populating some variables:
#!/bin/bash
declare free=0 total=0 used=0 mpnt='??'
getDiskStat() {
{
read _
read _ total used free _ mpnt
} < <(
df -k ${1:-/}
)
}
getDiskStat $1
echo "$mpnt: Tot:$total, used: $used, free: $free."
Nota: declare line is not required, just for readability.
About sudo cmd | grep ... | cut ...
shell=$(cat /etc/passwd | grep $USER | cut -d : -f 7)
echo $shell
/bin/bash
(Please avoid useless cat! So this is just one fork less:
shell=$(grep $USER </etc/passwd | cut -d : -f 7)
All pipes (|) implies forks. Where another process have to be run, accessing disk, libraries calls and so on.
So using sed for sample, will limit subprocess to only one fork:
shell=$(sed </etc/passwd "s/^$USER:.*://p;d")
echo $shell
And with Bashisms:
But for many actions, mostly on small files, Bash could do the job itself:
while IFS=: read -a line ; do
[ "$line" = "$USER" ] && shell=${line[6]}
done </etc/passwd
echo $shell
/bin/bash
or
while IFS=: read loginname encpass uid gid fullname home shell;do
[ "$loginname" = "$USER" ] && break
done </etc/passwd
echo $shell $loginname ...
Going further about variable splitting...
Have a look at my answer to How do I split a string on a delimiter in Bash?
Alternative: reducing forks by using backgrounded long-running tasks
In order to prevent multiple forks like
myPi=$(bc -l <<<'4*a(1)'
myRay=12
myCirc=$(bc -l <<<" 2 * $myPi * $myRay ")
or
myStarted=$(date -d "$(ps ho lstart 1)" +%s)
mySessStart=$(date -d "$(ps ho lstart $$)" +%s)
This work fine, but running many forks is heavy and slow.
And commands like date and bc could make many operations, line by line!!
See:
bc -l <<<$'3*4\n5*6'
12
30
date -f - +%s < <(ps ho lstart 1 $$)
1516030449
1517853288
So we could use a long running background process to make many jobs, without having to initiate a new fork for each request.
You could have a look how reducing forks make Mandelbrot bash, improve from more than eight hours to less than 5 seconds.
Under bash, there is a built-in function: coproc:
coproc bc -l
echo 4*3 >&${COPROC[1]}
read -u $COPROC answer
echo $answer
12
echo >&${COPROC[1]} 'pi=4*a(1)'
ray=42.0
printf >&${COPROC[1]} '2*pi*%s\n' $ray
read -u $COPROC answer
echo $answer
263.89378290154263202896
printf >&${COPROC[1]} 'pi*%s^2\n' $ray
read -u $COPROC answer
echo $answer
5541.76944093239527260816
As bc is ready, running in background and I/O are ready too, there is no delay, nothing to load, open, close, before or after operation. Only the operation himself! This become a lot quicker than having to fork to bc for each operation!
Border effect: While bc stay running, they will hold all registers, so some variables or functions could be defined at initialisation step, as first write to ${COPROC[1]}, just after starting the task (via coproc).
Into a function newConnector
You may found my newConnector function on GitHub.Com or on my own site (Note on GitHub: there are two files on my site. Function and demo are bundled into one unique file which could be sourced for use or just run for demo.)
Sample:
source shell_connector.sh
tty
/dev/pts/20
ps --tty pts/20 fw
PID TTY STAT TIME COMMAND
29019 pts/20 Ss 0:00 bash
30745 pts/20 R+ 0:00 \_ ps --tty pts/20 fw
newConnector /usr/bin/bc "-l" '3*4' 12
ps --tty pts/20 fw
PID TTY STAT TIME COMMAND
29019 pts/20 Ss 0:00 bash
30944 pts/20 S 0:00 \_ /usr/bin/bc -l
30952 pts/20 R+ 0:00 \_ ps --tty pts/20 fw
declare -p PI
bash: declare: PI: not found
myBc '4*a(1)' PI
declare -p PI
declare -- PI="3.14159265358979323844"
The function myBc lets you use the background task with simple syntax.
Then for date:
newConnector /bin/date '-f - +%s' #0 0
myDate '2000-01-01'
946681200
myDate "$(ps ho lstart 1)" boottime
myDate now now
read utm idl </proc/uptime
myBc "$now-$boottime" uptime
printf "%s\n" ${utm%%.*} $uptime
42134906
42134906
ps --tty pts/20 fw
PID TTY STAT TIME COMMAND
29019 pts/20 Ss 0:00 bash
30944 pts/20 S 0:00 \_ /usr/bin/bc -l
32615 pts/20 S 0:00 \_ /bin/date -f - +%s
3162 pts/20 R+ 0:00 \_ ps --tty pts/20 fw
From there, if you want to end one of background processes, you just have to close its fd:
eval "exec $DATEOUT>&-"
eval "exec $DATEIN>&-"
ps --tty pts/20 fw
PID TTY STAT TIME COMMAND
4936 pts/20 Ss 0:00 bash
5256 pts/20 S 0:00 \_ /usr/bin/bc -l
6358 pts/20 R+ 0:00 \_ ps --tty pts/20 fw
which is not needed, because all fd close when the main process finishes.
As they have already indicated to you, you should use `backticks`.
The alternative proposed $(command) works as well, and it also easier to read, but note that it is valid only with Bash or KornShell (and shells derived from those),
so if your scripts have to be really portable on various Unix systems, you should prefer the old backticks notation.
I know three ways to do it:
Functions are suitable for such tasks:**
func (){
ls -l
}
Invoke it by saying func.
Also another suitable solution could be eval:
var="ls -l"
eval $var
The third one is using variables directly:
var=$(ls -l)
OR
var=`ls -l`
You can get the output of the third solution in a good way:
echo "$var"
And also in a nasty way:
echo $var
Just to be different:
MOREF=$(sudo run command against $VAR1 | grep name | cut -c7-)
When setting a variable make sure you have no spaces before and/or after the = sign. I literally spent an hour trying to figure this out, trying all kinds of solutions! This is not cool.
Correct:
WTFF=`echo "stuff"`
echo "Example: $WTFF"
Will Fail with error "stuff: not found" or similar
WTFF= `echo "stuff"`
echo "Example: $WTFF"
If you want to do it with multiline/multiple command/s then you can do this:
output=$( bash <<EOF
# Multiline/multiple command/s
EOF
)
Or:
output=$(
# Multiline/multiple command/s
)
Example:
#!/bin/bash
output="$( bash <<EOF
echo first
echo second
echo third
EOF
)"
echo "$output"
Output:
first
second
third
Using heredoc, you can simplify things pretty easily by breaking down your long single line code into a multiline one. Another example:
output="$( ssh -p $port $user#$domain <<EOF
# Breakdown your long ssh command into multiline here.
EOF
)"
You need to use either
$(command-here)
or
`command-here`
Example
#!/bin/bash
VAR1="$1"
VAR2="$2"
MOREF="$(sudo run command against "$VAR1" | grep name | cut -c7-)"
echo "$MOREF"
If the command that you are trying to execute fails, it would write the output onto the error stream and would then be printed out to the console.
To avoid it, you must redirect the error stream:
result=$(ls -l something_that_does_not_exist 2>&1)
This is another way and is good to use with some text editors that are unable to correctly highlight every intricate code you create:
read -r -d '' str < <(cat somefile.txt)
echo "${#str}"
echo "$str"
You can use backticks (also known as accent graves) or $().
Like:
OUTPUT=$(x+2);
OUTPUT=`x+2`;
Both have the same effect. But OUTPUT=$(x+2) is more readable and the latest one.
Here are two more ways:
Please keep in mind that space is very important in Bash. So, if you want your command to run, use as is without introducing any more spaces.
The following assigns harshil to L and then prints it
L=$"harshil"
echo "$L"
The following assigns the output of the command tr to L2. tr is being operated on another variable, L1.
L2=$(echo "$L1" | tr [:upper:] [:lower:])
Mac/OSX nowadays come with old Bash versions, ie GNU bash, version 3.2.57(1)-release (arm64-apple-darwin21). In this case, one can use:
new_variable="$(some_command)"
A concrete example:
newvar="$(echo $var | tr -d '123')"
Note the (), instead of the usual {} in Bash 4.
Some may find this useful.
Integer values in variable substitution, where the trick is using $(()) double brackets:
N=3
M=3
COUNT=$N-1
ARR[0]=3
ARR[1]=2
ARR[2]=4
ARR[3]=1
while (( COUNT < ${#ARR[#]} ))
do
ARR[$COUNT]=$((ARR[COUNT]*M))
(( COUNT=$COUNT+$N ))
done

Using awk to extract a token from a larger JSON string

I have a string assigned to a variable:
#/bin/bash
fullToken='{"type":"APP","token":"l0ng_Str1ng.of.d1fF3erent_charAct3rs"}'
I need to extract only l0ng_Str1ng.of.d1fF3erent_charAct3rs without quotes and assign that to another variable.
I understand I can use awk, sed, or cut but I am having trouble getting around the special characters in the original string.
Thanks in advance!
EDIT: I was not awake I should specify this is JSON. Thanks for the replies so far.
EDIT2: I am using BSD (macOS)
It looks like you have a JSON string there. Keep in mind that JSON is unordered, so most sed, awk, cut solutions will fail if you string comes next time in a different order.
It is most robust to use a JSON parser.
You could use ruby with its JSON parser library:
$ echo "$fullToken" | ruby -r json -e 'p JSON.parse($<.read)["token"];'
"l0ng_Str1ng.of.d1fF3erent_charAct3rs"
Or, if you don't want the quoted string (which is useful for Bash):
$ echo "$fullToken" | ruby -r json -e 'puts JSON.parse($<.read)["token"];'
l0ng_Str1ng.of.d1fF3erent_charAct3rs
Or with jq:
$ echo "$fullToken" | jq '.token'
"l0ng_Str1ng.of.d1fF3erent_charAct3rs"
All these solutions will work even if the JSON string is in a different order:
$ echo '{"type":"APP","token":"l0ng_Str1ng.of.d1fF3erent_charAct3rs"}' | jq '.token'
"l0ng_Str1ng.of.d1fF3erent_charAct3rs"
$ echo '{"token":"l0ng_Str1ng.of.d1fF3erent_charAct3rs", "type":"APP"}' | jq '.token'
"l0ng_Str1ng.of.d1fF3erent_charAct3rs"
But KNOWING that you SHOULD use a JSON parser, you can also use a PCRE with a look behind in Gnu Grep:
$ echo "$fullToken" | grep -oP '(?<="token":)"([^"]*)'
Or in Perl:
$ echo "$fullToken" | perl -lane 'print $1 if /(?<="token":)"([^"]*)/'
Both of those also work if the string is in a different order.
Or, with POSIX awk:
$ echo "$fullToken" | awk -F"[,:}]" '{for(i=1;i<=NF;i++){if($i~/"token"/){print $(i+1)}}}'
Or, with POSIX sed, you can do:
$ echo "$fullToken" | sed -E 's/.*"token":"([^"]*).*/\1/'
Those solutions are presented strongest (use a JSON parser) to more fragile (sed). But the sed solution I have there is better than the other because it will support the key, values in the JSON string being in different order.
Ps: If you want to remove the quotes from a line, that is a great job for sed:
$ echo '"quoted string"'
"quoted string"
$ echo '"quoted string"' | sed -E 's/^"(.*)"$/UN\1/'
UNquoted string
In awk:
$ awk -v f="$fullToken" '
BEGIN{
while(match(f,/[^:{},]+:[^:{},]+/)) { # search key:value pairs
p=substr(f,RSTART,RLENGTH) # set pair to p
f=substr(f,RSTART+RLENGTH) # remove p from f
split(p,a,":") # split to get key and value
for(i in a) # remove leadin and trailing "
gsub(/^"|"$/,"",a[i])
if(a[1]=="token") { # if key is token
print a[2] # output value
exit # no need to process further
}
}
}'
l0ng_Str1ng.of.d1fF3erent_charAct3rs
l0ng_String can't have characters :{}.
GNU sed:
fullToken='{"type":"APP","token":"l0ng_Str1ng.of.d1fF3erent_charAct3rs"}'
echo "$fullToken"|sed -r 's/.*"(.*)".*/\1/'
grep method would be,
$ grep -oP '[^"]+(?="[^"]+$)' <<< "$fullToken"
l0ng_Str1ng.of.d1fF3erent_charAct3rs
Brief explanation,
[^"]+ : grep would extract the non-" pattern
(?="[^"]+$): extract until the pattern ahead of last "
You may also use sed method to do that,
$sed -E 's/.*"([^"]+)"[^"]+$/\1/' <<< "$fullToken"
l0ng_Str1ng.of.d1fF3erent_charAct3rs
If the source of your string is JSON, then you should use JSON-specific tools. If not, then consider:
Using awk
$ fullToken='{"type":"APP","token":"l0ng_Str1ng.of.d1fF3erent_charAct3rs"}'
$ echo "$fullToken" | awk -F'"' '{print $8}'
l0ng_Str1ng.of.d1fF3erent_charAct3rs
Using cut
$ echo "$fullToken" | cut -d'"' -f8
l0ng_Str1ng.of.d1fF3erent_charAct3rs
Using sed
$ echo "$fullToken" | sed -E 's/.*"([^"]*)"[^"]*$/\1/'
l0ng_Str1ng.of.d1fF3erent_charAct3rs
Using bash and one of the above
The above all work with POSIX shells. If the shell is bash, then we can use a here-string and eliminate the pipeline. Taking cut as the example:
$ cut -d'"' -f8 <<<"$fullToken"
l0ng_Str1ng.of.d1fF3erent_charAct3rs

BATCH: grep equivalent

I need some help what ith the equivalent code for grep -v Wildcard and grep -o in batch file.
This is my code in shell.
result=`mysqlshow --user=$dbUser --password=$dbPass sample | grep -v Wildcard | grep -o sample`
The batch equivalent of grep (not including third party tools like GnuWin32 grep), will be findstr.
grep -v finds lines that don't match the pattern. The findstr version of this is findstr /V
grep -o shows only the part of the line that matches the pattern. Unfortunately, there's no equivalent of this, but you can run the command and then have a check along the lines of
if %errorlevel% equ 0 echo sample

Printing column separated by comma using Awk command line

I have a problem here. I have to print a column in a text file using awk. However, the columns are not separated by spaces at all, only using a single comma. Looks something like this:
column1,column2,column3,column4,column5,column6
How would I print out 3rd column using awk?
Try:
awk -F',' '{print $3}' myfile.txt
Here in -F you are saying to awk that use , as the field separator.
If your only requirement is to print the third field of every line, with each field delimited by a comma, you can use cut:
cut -d, -f3 file
-d, sets the delimiter to a comma
-f3 specifies that only the third field is to be printed
Try this awk
awk -F, '{$0=$3}1' file
column3
, Divide fields by ,
$0=$3 Set the line to only field 3
1 Print all out. (explained here)
This could also be used:
awk -F, '{print $3}' file
A simple, although awk-less solution in bash:
while IFS=, read -r a a a b; do echo "$a"; done <inputfile
It works faster for small files (<100 lines) then awk as it uses less resources (avoids calling the expensive fork and execve system calls).
EDIT from Ed Morton (sorry for hi-jacking the answer, I don't know if there's a better way to address this):
To put to rest the myth that shell will run faster than awk for small files:
$ wc -l file
99 file
$ time while IFS=, read -r a a a b; do echo "$a"; done <file >/dev/null
real 0m0.016s
user 0m0.000s
sys 0m0.015s
$ time awk -F, '{print $3}' file >/dev/null
real 0m0.016s
user 0m0.000s
sys 0m0.015s
I expect if you get a REALY small enough file then you will see the shell script run in a fraction of a blink of an eye faster than the awk script but who cares?
And if you don't believe that it's harder to write robust shell scripts than awk scripts, look at this bug in the shell script you posted:
$ cat file
a,b,-e,d
$ cut -d, -f3 file
-e
$ awk -F, '{print $3}' file
-e
$ while IFS=, read -r a a a b; do echo "$a"; done <file
$

Converting a bash command output into JSON and serving it over http on the fly

I want to convert the output of ifstat command into JSON and serve it over http on the fly to be used for a javascript graph app. Are there any lightweight -- sed or awk -- command-line solutions which I can use? I do not want to store JSON output on the disk and it would be good if the web-server was a small lightweight command line tool into which I can pipe JSON output.
EDIT 1:
This is the live streaming chart library which will use the data. I'm not keen on a specific web server; any webserver that does the job would be fine.
This is what I have tried.
Terminal #1
ifstat -n | awk 'NR>2{print systime(),$0; fflush()}' | tee ifstat.log
Terminal #2
while :
do
{
echo -e "HTTP/1.1 200 OK"
echo -e "Content-Type: application/json\n"
tail -n1 ifstat.log | awk '{ printf("{\"time\":%s, \"in\":%s, \"out\":%s}\n", $1, $2, $3) }'
} | nc -l 8000
done
firefox
open: http://localhost:8000
{"time":1332052321, "in":1.24, "out":2.62}
I know little about JSON. Maybe the output is invalid. You should rewrite the awk command.