I'm trying to get the list of categories with number of child records present in there. If the categories doesn't have records it should return NULL or 0 but my query returning categories with child records looks like its skipping the one without child records. ... will really appreciate the help.
here's my code:
SELECT
t_gal.f_sub_category_id,
t_sub_cat.f_sub_cat_name,
t_gal.f_image_thumb, (
SELECT COUNT(*)
FROM t_gallery
WHERE f_sub_category_id = t_gal.f_sub_category_id)
AS f_image_total
FROM t_gallery t_gal
LEFT JOIN t_sub_category t_sub_cat ON t_sub_cat.r_id = t_gal.f_sub_category_id
GROUP BY t_sub_cat.r_id
ORDER BY t_gal.f_added_on DESC, t_gal.r_id DESC
Here's the two tables:
Problem appears to be your group by clause.
You are grouping by a field that is on the LEFT JOINed table, hence when it does the group by all the rows which do not have a matching row on that table would appear to be aggregated into a single row.
I think what you are trying to get is a list of gallery items, along with the category they are in (if found) and the count of other galleries in the same category. If so try the following (if not let me know!)
SELECT t_gal.f_sub_category_id, t_sub_cat.f_sub_cat_name, t_gal.f_image_thumb, Sub1.GalleryCount
FROM t_gallery t_gal
LEFT JOIN t_sub_category t_sub_cat
ON t_sub_cat.r_id = t_gal.f_sub_category_id
LEFT OUTER JOIN (SELECT f_sub_category_id, COUNT(*) AS GalleryCount FROM t_gallery GROUP BY f_sub_category_id) Sub1
ON Sub1.f_sub_category_id = t_gal.f_sub_category_id
ORDER BY t_gal.f_added_on DESC, t_gal.r_id DESC
It LOOKS like for every sub-category (of a previously selected category), you want to include ALL of that sub-category... And, of those sub-categories, you want a count of how many images for that category wheather or not there even IS an image in the gallery table.
What you may have been running into is the select statement for the FIELD used to count images... first, that could become a performance killer. Instead, you could just do a left-join directly to the gallery table and COUNT the distinct R_IDs from the gallery FOR the corresponding sub-category
SELECT
t_sub_cat.r_id,
t_sub_cat.f_sub_cat_name,
MIN( COALESCE( t_gal.f_image_thumb, '' )) as JustOneThumbImg,
COUNT( DISTINCT( t_gal.r_id )) SubCategoryImageCount
FROM
t_sub_category t_sub_cat
LEFT JOIN t_gallery t_gal
ON t_sub_cat.r_id = t_gal.f_sub_category_id
GROUP BY
t_sub_cat.r_id
ORDER BY
t_sub_cat.f_added_on DESC
Since you are not grabbing all gallery images (since some may not exist FOR a given sub-category), ordering by the t_gal.r_id doesn't make sense
Also, the reason I'm not pre-grabbing aggregates in a sub-query to join against... I don't want to get everything from every category / sub-category without knowing which sub-categories are associated with the category you actually want.
the problem with your query is that you are using t_gallery as your main table and not t_sub_category while using left join.
you could try this: sqlfiddle
select
t_gal.f_sub_category_id,
t_sub_cat.f_sub_cat_name,
(
SELECT COUNT(*)
FROM t_gallery
WHERE f_sub_category_id = t_gal.f_sub_category_id)
AS f_image_total
from t_sub_category as t_sub_cat
left join t_gallery t_gal on t_gal.f_sub_category_id = t_sub_cat.r_id
GROUP BY t_sub_cat.r_id
ORDER BY t_gal.r_id DESC;
Related
I am using the following query to join tables together and it seems to be working although I can't really understand why:
SELECT
listing.name,
biggestLot.price,
FROM Listings listing
LEFT JOIN Lots biggestLot ON biggestLot.lotNumber = (
SELECT lotNumber
FROM Lots
WHERE lotNumber IN
(
SELECT lotNumber
FROM Listings listingInner
WHERE listingInner.listingNumber = listing.listingNumber
)
ORDER BY size DESC
LIMIT 1
)
GROUP BY listing.listingNumber
The context is that each "Listing" is associated with one or more "Lots" through a "lotNumber" field. The tables aren't normalized; i.e. for any given Listing, there may be one or more rows in the "Listings" table that have duplicate values for all fields except for "lotNumber". The intent of the above query is to find the price of the biggest Lot associated with each Listing.
The inner SELECT is getting the largest Lot for a given Listing and I understand how that works. What I don't understand is how the LEFT JOIN merges the biggestLot result with the outer SELECT Listings query. I'm not specifying an ON field to combine the two tables so how does it know how to combine the results?
You could can use window functions along with the JOIN:
SELECT l.name, lo.price,
FROM Listings l LEFT JOIN
(SELECT lo.*,
ROW_NUMBER() OVER (PARITION BY lo.lotNumber ORDER BY lo.size DESC) as seqnum
FROM Lots lo
) lo
USING (lotNmber);
I have table products and table seen. Every time a customer views a product an entry is added for that product in seen table. I want to retrieve list of all products from products table and sort the list of products in desc order of how many times its been viewed.Note if a product hasn't been viewed even once then there will be no entry in seen table, and that product should be put at top of the list followed by products which have been viewed once,twice and so on
SELECT products.product_id ,products.product_name , anon_1.seen_count
FROM products
LEFT OUTER JOIN (
SELECT seen.product_id , count(*) AS seen_count
FROM seen
GROUP BY seen.product_id
) AS anon_1 ON anon_1.product_id = products.product_id
ORDER BY anon_1.seen_count ASC;
My above query puts the products that haven't been viewed at the bottom. How do i fix this?
I have tried both descending and ascending. Descending puts the ones that have been least viewed at the bottom and ascending puts the ones that have not been viewed at the bottom
For LEFT OUTER JOIN, you should consider NULL value for products that haven't been viewed. So you should use this:
SELECT products.product_id ,products.product_name,
COALESCE(anon_1.seen_count, 0) seen_count
FROM products
LEFT OUTER JOIN (
SELECT seen.product_id , count(*) AS seen_count
FROM seen
GROUP BY seen.product_id
) AS anon_1 ON anon_1.product_id = products.product_id
ORDER BY seen_count ASC;
ORDER BY anon_1.seen_count DESC;
it sorts them from the greatest value to smallest.
You should use
ORDER BY anon_1.seen_count ASC;
to sort from the smallest to greatest.
Try this
SELECT products.product_id ,products.product_name , CASE WHEN anon_1.seen_count IS NULL THEN 0 ELSE anon_1.seen_count END AS count
FROM products
LEFT OUTER JOIN (
SELECT seen.product_id , count(*) AS seen_count
FROM seen
GROUP BY seen.product_id
) AS anon_1 ON anon_1.product_id = products.product_id
ORDER BY count DESC;
In Mysql and SqlServer, null value is the min value. But for Oracle, null value is the max value.
So you might using MySql or SqlServer, right?
Current result would be as follow, we need to put the last one to the top, which seen_count is null.
In order to do this, I add an additional column to solve it. Does that meet with your need? Hope that could help you!
I'm having some trouble formulating a complex SQL query. I'm getting the result I'm looking for and the performance is fine but whenever I try to grab distinct rows for my LEFT JOIN of product_groups, I'm either hitting some performance issues or getting incorrect results.
Here's my query:
SELECT
pl.name, pl.description,
p.rows, p.columns,
pr.sku,
m.filename, m.ext, m.type,
ptg.product_group_id AS group,
FROM
product_region AS pr
INNER JOIN
products AS p ON (p.product_id = pr.product_id)
INNER JOIN
media AS m ON (p.media = m.media_id)
INNER JOIN
product_language AS pl ON (p.product_id = pl.product_id)
LEFT JOIN
products_groups AS ptg ON (ptg.product_id = pr.product_id)
WHERE
(pl.lang = :lang) AND
(pr.region = :region) AND
(pt.product_id = p.product_id)
GROUP BY
p.product_id
LIMIT
:offset, :limit
The result I'm being given is correct however I want only distinct rows returned for "group". For example I'm getting many results back that have the same "group" value but I only want the first row to show and the following records that have the same group value to be left out.
I tried GROUP BY group and DISTINCT but it gives me incorrect results. Also note that group can come back as NULL and I don't want those rows to be effected.
Thanks in advance.
I worked out a solution an hour after posting this. My goal was to group by product_group_id first and then the individual product_id. The requirement was that I would eliminate product duplicates and have ONE product represent the group set.
I ended up using COALESCE(ptg.product_group_id, p.product_id). This accounts for the fact that most of my group IDs were null except for a few dispersed products. In using COALESCE I'm first grouping by the group ID, if that value is null it ignores the group and collects by product_id.
I have 4 tables in an existing mysql database of a directory type site.
Table mt_links contains basic info for each listing
Table mt_cl contains which listing above is in what category (I only want cat_id=1)
Table mt_cfvalues contains more details for each listing It Can have repeated values
Table mt_images contains image names for each listing.
I want all records from mt_links where the mt_cl cat_id=1, and for each of those records, I need all records in mt_cfvalues and cf_images matching the link_id.
I set up a select with Group_Concat and left joins, but ended up with repeating values in my results. I added Distinct, which cured the repeating values, but mt_cfvalues can have records with the same value, so now I'm missing a value I should have.
SELECT a.link_id,
a.link_name,
a.link_desc,
GROUP_CONCAT(DISTINCT b.value ORDER BY b.cf_ID) AS details,
GROUP_CONCAT(DISTINCT c.filename ORDER BY c.ordering) AS images
FROM mt_links a
LEFT JOIN mt_cfvalues b ON a.link_id = b.link_ID
LEFT JOIN mt_images c ON b.link_id = c.link_ID
LEFT JOIN mt_cl d ON a.link_id = d.link_ID WHERE d.cat_ID = '1'
GROUP BY a.link_id
I put together a SQLFiddle here: http://www.sqlfiddle.com/#!2/f39e9/1
Is there an easier way? How do I fix the repeating / no repeating issue?
Here is one way of accomplishing what you seek. Because the two subqueries return independent results, you can't combine the GROUP BY, which is why you were getting duplicates.
SELECT a.link_id,
a.link_name,
a.link_desc,
cvf.details,
imgs.images
FROM mt_links a
LEFT JOIN (
SELECT link_ID, GROUP_CONCAT(value ORDER BY cf_ID) AS details
FROM mt_cfvalues
GROUP BY link_ID
) cvf ON cvf.link_ID = a.link_id
LEFT JOIN (
SELECT link_ID, GROUP_CONCAT(filename ORDER BY ordering) AS images
FROM mt_images
GROUP BY link_ID
) imgs ON imgs.link_ID = a.link_id
INNER JOIN mt_cl d ON a.link_id = d.link_ID
WHERE d.cat_ID = '1'
I have three tables that are joined. I almost have the solution but there seems to be one small problem going on here. Here is statement:
SELECT items.item,
COUNT(ratings.item_id) AS total,
COUNT(comments.item_id) AS comments,
AVG(ratings.rating) AS rate
FROM `items`
LEFT JOIN ratings ON (ratings.item_id = items.items_id)
LEFT JOIN comments ON (comments.item_id = items.items_id)
WHERE items.cat_id = '{$cat_id}' AND items.spam < 5
GROUP BY items_id ORDER BY TRIM(LEADING 'The ' FROM items.item) ASC;");
I have a table called items, each item has an id called items_id (notice it's plural). I have a table of individual user comments for each item, and one for ratings for each item. (The last two have a corresponding column called 'item_id').
I simply want to count comments and ratings total (per item) separately. With the way my SQL statement is above, they are a total.
note, total is the total of ratings. It's a bad naming scheme I need to fix!
UPDATE: 'total' seems to count ok, but when I add a comment to 'comments' table, the COUNT function affects both 'comments' and 'total' and seems to equal the combined output.
Problem is you're counting results of all 3 tables joined. Try:
SELECT i.item,
r.ratetotal AS total,
c.commtotal AS comments,
r.rateav AS rate
FROM items AS i
LEFT JOIN
(SELECT item_id,
COUNT(item_id) AS ratetotal,
AVG(rating) AS rateav
FROM ratings GROUP BY item_id) AS r
ON r.item_id = i.items_id
LEFT JOIN
(SELECT item_id,
COUNT(item_id) AS commtotal
FROM comments GROUP BY item_id) AS c
ON c.item_id = i.items_id
WHERE i.cat_id = '{$cat_id}' AND i.spam < 5
ORDER BY TRIM(LEADING 'The ' FROM i.item) ASC;");
In this query, we make the subqueries do the counting properly, then send that value to the main query and filter the results.
I'm guessing this is a cardinality issue. Try COUNT(distinct comments.item_id)