i have a table like :
id_cat id_city
1 33
1 33
1 33
2 44
2 33
2 55
and i want to obtain a result like :
id_cat id_city cat_count
1 33 3
2 44 1
2 33 1
2 55 1
how can i build my query ?
Thanks!
Use COUNT() which is an aggregate function and a GROUP BY clause.
SELECT id_cat, id_city, COUNT(*) cat_Count
FROM tableName
GROUP BY id_cat, id_city
SQLFiddle Demo
Related
I am trying to attain the count of users that ordered at least 1 product on multiple days.
Transactions Table
usr_id|transt_id|product_id|spend| transaction_date
4 8 32 40 2020-05-08 17:54:59
4 7 31 20 2020-05-01 17:54:59
4 7 31 40 2020-05-01 17:54:59
4 6 20 30 2020-05-02 17:54:59
4 6 19 20 2020-05-02 17:54:59
4 6 18 10 2020-05-02 17:54:59
3 5 17 20 2020-05-04 17:54:59
3 5 16 10 2020-05-04 17:54:59
2 3 14 30 2020-05-04 18:54:59
2 3 13 50 2020-05-04 18:54:59
1 2 12 30 2020-05-05 20:54:59
1 2 12 40 2020-05-05 20:54:59
1 2 12 40 2020-05-04 20:54:59
1 1 11 20 2020-05-05 21:54:59
1 1 10 40 2020-05-05 21:54:59
3 4 10 60 2020-05-06 17:54:59
Through my code I have been able to reach to a point where the output is:
select user_id, count(*)
from (
select user_id, date(transaction_date)
from transactions
group by user_id, date(transaction_date)) as abc
group by user_id
having count(user_id)>1;
user_id | count
1 2
3 2
4 3
I want to write a code without writing another subquery to get the count of users having count(*)>1;
The output should be: 3.
In other words, I don't want the following code; I want to write one less subquery or a completely new query
select count(*)
from (
select user_id, count(*)
from (
select user_id, date(transaction_date)
from transactions
group by user_id, date(transaction_date)) as abc
group by user_id
having count(user_id)>1) as bcd;
The query that you already have could be written without a subquery:
select user_id, count(distinct date(transaction_date)) count
from transactions
group by user_id
having count(distinct date(transaction_date))>1;
So what you need now can be written with only 1 subquery:
select count(*) count
from (
select user_id
from transactions
group by user_id
having count(distinct date(transaction_date))>1
) t
You can get the same result with EXISTS:
select count(distinct t.user_id) count
from transactions t
where exists (
select 1
from transactions
where user_id = t.user_id and date(transaction_date) <> date(t.transaction_date)
)
See the demo.
I have 4 tables in similar form. Structures of these tables are like:
id team_id position_id country_id
1 1 1 3
2 1 1 3
3 2 2 3
4 3 3 3
I can count rows of one table with:
SELECT count(position_id) as count1, position_id
FROM players1
where country_id = 3
group by position_id;
Getting result as:
position_id count1
1 54
2 41
3 39
4 32
I want join 4 tables and want to get a result like:
position_id count1 count2 count3 count4
1 54 42 51 61
2 41 40 49 59
3 39 29 44 50
4 32 21 37 47
Can you help me write this sql?
As I have understand you question. Execute this Mysql query.
SELECT
d1.position_id AS Positions_Id,
d1.count1 AS count1,
d2.count1 AS count2,
d3.count1 AS count3,
d4.count1 AS count4
FROM (
SELECT position_id, COUNT(position_id) AS count1
FROM players1
WHERE country_id=3
GROUP BY position_id) AS d1
LEFT JOIN (
SELECT position_id, COUNT(position_id) AS count1
FROM players2
WHERE country_id=3
GROUP BY position_id
) AS d2 ON d2.position_id = d1.position_id
LEFT JOIN (
SELECT position_id, COUNT(position_id) AS count1
FROM players3
WHERE country_id=3
GROUP BY position_id
) AS d3 ON d3.position_id = d1.position_id
LEFT JOIN (
SELECT position_id, COUNT(position_id) AS count1
FROM players4
WHERE country_id=3
GROUP BY position_id
) AS d4 ON d4.position_id = d1.position_id
I have this table:
id_user id_user2
1 54
1 53
1 53
1 54
1 54
1 55
2 23
2 23
2 20
2 21
2 25
2 25
And i would like to count, how many each of id_user have relationship with id_user2. Output should be:
id_user id_user2 result
1 54 3
1 53 2
1 55 1
2 23 2
2 20 1
2 21 1
2 25 2
You have to use group by clause
select id_user,id_user2, count(1) as result
from userstab
group by id_user,id_user2
try this query
select id_user,id_user2,count(id_user2) as result
from TABLE_NAME group by id_user2
On a MySQL database, I have the table below
package_content :
id | package_id | content_number | content_name | content_quality
1 99 11 Yellow 1
2 99 22 Red 5
3 101 11 Yellow 5
4 101 33 Green 5
5 101 44 Black 5
6 120 11 Yellow 5
7 120 55 White 5
8 135 66 Pink 5
9 135 99 Orange 5
10 135 11 Yellow 5
and i am looking a possibility to make search queries on it:
I would like to select the package_id where content_number could be 11 AND 22 (In this case it should select only package_id 99
I really don't know if it's possible in SQL since the statement AND will always results as false. If i use the statement OR i also get the package_id 99, 101, 120, 135 and that's not what i want.
Maybe my table is not well designed too, but any suggestions would help!
Thanks in advance
Edit
I added the content_quality column
I used the sql query from juergen, works very well
select package_id
from package_content
where content_number in (11,22)
group by package_id
having count(distinct content_number) = 2
My last question is how could i now add another criteria : Select the package_id where content_number is 11 and 22 and content_number 11 has content_quality 1
Edit 2:
For the 2nd question i use now this query. Thanks to both of you who helped me! :)
SELECT *
FROM (
SELECT package_id
FROM package_content
WHERE
(content_number=11 AND content_quality > 1)
OR (content_number = 33 AND content_quality = 5)
OR (content_number = 44 AND content_quality =5 AND content_name like 'Black')
GROUP BY package_id
HAVING count( DISTINCT content_number) = 3
)t1
LEFT JOIN package_content ON package_content.package_id = t1.package_id
This will output
id | package_id | content_number | content_name | content_quality
3 101 11 Yellow 5
4 101 33 Green 5
5 101 44 Black 5
You need to group by the package_id and then use having to perform an aggregate function over the grouped data
select package_id
from package_content
where content_number = 22
or
(
content_number = 11 and content_quality = 1
)
group by package_id
having count(distinct content_number) = 2
You could query with a self join for that:
SELECT DISTINCT package_id
FROM package_content a, package_content b
WHERE a.package_id = b.package_id
AND a.content_number = 11 AND b.content_number = 22
Edit: For your second question: Just add that to the query. The package_content renamed to a is responsible for the content_number 11. Therefore you can ask, wether a has content_quality 1:
SELECT DISTINCT package_id
FROM package_content a, package_content b
WHERE a.package_id = b.package_id
AND a.content_number = 11 AND b.content_number = 22
AND a.content_quality = 1
This is my table structure:
rec_id product_id quantity quantity_in quantity_out balance stock_date status
1 2 342 NULL 17 325 2009-10-23 1
2 2 325 NULL 124 201 2009-10-23 1
3 1 156 NULL 45 111 2009-10-23 1
4 2 201 NULL 200 1 2009-10-23 1
5 2 1 NULL 1 0 2009-10-23 1
6 1 111 NULL 35 76 2009-10-23 1
All I want is the last transaction done for a given product: product_id, quantity, quantity_out and balance from this table.
Example, there are 2 transaction done for product 2 (ids 1 & 2):
final balance for product_id 2 is 0 -> stored in rec_id 5
final balance for product_id 1 is 76 -> stored in rec_id 6
Final result/output should be like this:
recid productid quantity quantityin quantityout balance stock_date status
5 2 1 NULL 1 0 2009-10-23 1
6 1 111 NULL 35 76 2009-10-23 1
You can find the latest record for each product like:
select max(rec_id) as MaxRec
from YourTable
group by product_id
Using a subquery, you can retrieve the latest rows for their product:
select *
from YourTable
where rec_id in (
select max(rec_id) as MaxRec
from YourTable
group by product_id
)
Here's a single query with no subqueries:
SELECT main.*
FROM YourTable main
LEFT JOIN YourTable newer
ON newer.product_id = main.product_id AND newer.rec_id > main.rec_id
WHERE newer.rec_id IS NULL;
You can tweak the field list however you want--make sure you select fields from main, not newer, which should be all null.