I am trying to do a regex match to MySQL query (actually, it MariaDB) a table to find any word in a filepath that contains the string "!Mutex" or were the folder ends with a capital "M".
So if the cell contained the following paths.
-------------
|Path_Folder|
-------------------------------------------------------
|E:\folder01\folder01\folder03\!Mutex\folder05 |
|E:\folder01\folder01\folder03\folder4\!Mutex\folder06|
|E:\folder01\folder01\folder03\folder04\folderM |
-------------------------------------------------------
I'm NOT trying to port this anywhere (no php), just trying to find the results.
I know you asked for a regex solution, but sometimes that's not the answer. :-)
You can do this instead with a normal SQL LIKE expression.
SELECT
Path_Folder
FROM
Your_Table
WHERE
(Path_Folder LIKE '%!Mutex%')
OR
(Path_Folder LIKE '%M')
A LIKE should work just fine for what you need, and be faster (and easier to read/maintain) than a regex.
Related
I have a table
| John
| Robert
| Mary
| James
| Bond
i want to remove characters with prefix 'J' with substr
| ohn
| Robert
| Mary
| ames
| Bond
this my sql code, but still not working
SELECT SUBSTR(name,2) FROM table_name WHERE name LIKE 'J%'
The query you wrote says "show me all the names that needed to be modified", but what I think you want is, "Show me ALL the names, but names that follow a particular pattern I want you to modify first."
The job of modifying the data in the results is the responsibility of the SELECT statement. You've touched on it yourself with your use of SUBSTR. So you want to pull all the names, but only change some of them. Further study into the catalog of MySQL string operations reveals a dizzying array of options. The goal is "SELECT name but if name starts with 'J' then chop that off."
For educational purposes, I encourage you to try to implement this with IF logic, but ultimately that's not necessary.
And while the ultimately powerful regex functions are tempting, there's a simpler option, TRIM. TRIM allows you to say, "chop this string from the front and/or back of this other string."
Since you want all results, there is no WHERE clause anymore, and your query is simply
SELECT TRIM(LEADING 'J' FROM name) FROM table_name
Look at that. FROM meaning two different things. No one ever said SQL was pretty.
If your actual use-case is trickier than simple TRIM can handle, there's a whole bunch more functions to peruse, and ultimately there's regex.
You can able to check others forms to use TRIM function in a following link:
TRIM Functions
I am using PHP to access a mysql database field that contains up to 2500 characters per record.
I want to build queries that will return only the records that include a single word, like 'taco'.
Sometimes, however, the user will need to search for a word like 'jalapeno'. Except that jalapeno may exist in the database as 'jalapeno' or as 'jalapeño'. The query should return both instances.
As a further complication, the user may also need to search for a word like 'creme', which may appear as 'creme' or 'créme', but never as 'crémé'.
It seems like I should be able to construct something that uses a replace, and then a Regular Expression, so that the letter 'n' is always replaced with '[n|ñ]', and then search for a string with an embedded Regular Expression like this: 'jalape[n|ñ]o'. Except that does not work. MySQL treats the RegEx syntax as literals.
None of the following return the results that I am looking for:
SELECT id, record FROM table WHERE record like '%jalapeno%';
SELECT id, record FROM table WHERE record REGEXP 'jalapeno';
SELECT id, record FROM table WHERE record REGEXP 'jalape[n|ñ]o';
SELECT id, record FROM table WHERE REGEXP_LIKE(record, 'jalape[n|ñ]o', 'im');
Additionally, I can use PHP to do a replacement of the potential characters, but I end up with stuff like this:
SELECT id, record FROM table WHERE (record like '%creme%' || record like '%crémé%');
I would be Ok with a search like this, but it seems overly complicated to construct programmatically:
SELECT id, record FROM table WHERE (record like '%creme%' || record like '%crémé%' || record like '%cremé%' || record like '%cremé%' );
Is there a MySQL method that provides a REGEX 'OR' to be embedded within a String?
Maybe something like this:
SELECT id, record FROM table WHERE record like '%cr[e|é]m[e|é]%' ;
Or is there another solution that would not require the construction of an excessively convoluted SQL Statement?
Thanks for anyone who spent time trying to figure this out.
As I commented above, REGEXP_LIKE() does not appear to be a valid MySQL function for the current release.
Here is my solution; Note that this works for MySQL 5.7.x.
SELECT id, record FROM table WHERE record RLIKE 'jalape(n|ñ)o';
I need to find entries that contain more than 7 numbers in one of my mysql tables BUT the numbers are separated by letters or anything else.
What I have is this little piece of code I use to find entries like dsc123456789:
select * from crawl where title regexp '[0-9]{7}'
How can I find entries like dsc-123-456_78B9? I tried different things but without success so far.
Thanks
You can use the following solution:
SELECT *
FROM crawl
WHERE title REGEXP '(([^[:digit:]])?[[:digit:]]){8,}';
Why the original query of the answer doesn't work?
-- this query doesn't work!
SELECT *
FROM crawl
WHERE title REGEXP '\d([^\d]?\d){7,}'
MySQL can't use character groups like \d (digits). So the query fails every time. On PHP and other languages the regular expression would look like this:
\d([^\d]?\d){7,}
but on MySQL this isn't valid. So you have to use the character classes of MySQL to solve this:
(([^[:digit:]])?[[:digit:]]){8,}
Hint: Make sure you use {8} or {8,} instead of {7} since you want to find all entries with more than 7 numbers / digits.
I'm working on a query which I thought should be quite intuitive, but somehow I'm facing a bit of issues when implementing it. I guess what I'm trying to achieve is to match a string stored in MySQL DB without space and punctuation (other creative approaches are more than welcome). At the same time I would like the query to handle Unicode characters in diacritics insensitive fashion (so options like REGEXP are kinda out of luck). And the last condition is I'm on MySQL 5.5 with InnoDB engine, so full-text indexing is not supported (but I'm open to upgrade to 5.6/5.7 if it helps sorting this out).
Consider the scenario which the string Hello-World from John Doe is stored in DB. I would like to find it when given the search string HelloWorld or JohnDoe. To be more general, the string in DB can contain brackets, understores and any other punctuation (not limited to ASCII but can compromise for now), while the search string can be a combination of words with or without any separators in between. The closest I've gotten so far is to daisy chain the REPLACE function for a list of known punctuation, like below:
SELECT text FROM table WHERE REPLACE(REPLACE(text, '-', ''), ' ', '') LIKE '%JohnDoe%'
My questions are:
Is there a better way instead of using the daisy chain above?
If that's the only solution, how will the performance be impacted when I chain up hundred or more REPLACE functions?
Thanks in advance for your help.
I don't know how restrictive your searches must be, but you could try to strip out all non-alphanumeric characters from it, so that you end up with a string like "HelloWorldfromJohnDoe" that you match with instead.
Have a look at this answer: How to remove all non-alpha numeric characters from a string?
You might have to change it around a bit though to make it fir your purposes. I changed it from CHAR(32) to CHAR(255) to make sure I could get the column, but you might want to look into changing the function altogether to fit your data more precisely.
Then you something like this:
SELECT *
FROM testing
WHERE alphanum(test) LIKE CONCAT('%', alphanum('John Doe'), '%')
which should give you a hit.
Method 1
I would have another column on the schema containing an "hashed" version of the name, for example, let's say you have the user:
John Doe The Great
This name hashes to
johndoethegreat
The hash function is coded in such a way that all of the following strings:
John_Doe_THE_great
John Doe The GREAT
John.Doe.The.Great
johnDOE___theGreat
john Doe the great
___john____DOE____THE____great
hash to the same value
johndoethegreat
It's trivial to write such a function. This way you can get the user input, hash it and then compare it against the hash column in your database
Names like:
Jon Doe
John Doo
will not be found of course
Method 2
Use the FULLTEXT search feature built-in in MySQL, sort the results by score and pick the first non zero entry
http://blog.oneiroi.co.uk/mysql/php/mysql-full-text-search-with-percentage-scoring/
I am totally missing the point of your question. You appear to have the string:
Hello-World from John Doe
If you want to find this when the search string is JohnDoe or John Doe, then you only need to substitute spaces:
where replace(text, ' ') like concat('%', 'JohnDoe', '%')
If you want a string that contains both "John" and "Doe" in that order, then:
where replace(text, ' ') like concat('%', 'John%Doe', '%')
I fail to see why 100 nested replace()s would be needed.
I have a table with 3 columns something like below,
expert table
id - 1589
name - Jhonny
expert_in - 1,12,8 (Values similar like this)
The experts_in contains another table's foreign key
experts_in table
id - 1
expert_in - painting
I want search experts who are expert in some jobs while searching for experts
SELECT * FROM `experts` WHERE expert_in LIKE 1%
The above query brings all experts with 11,12,13...etc. I want only exact word. I know LIKE will bring all. Is there any way to achieve this without altering table. Thanks in advance.
You should use REGEXP. Try this query:
SELECT * FROM experts
WHERE expert_in REGEXP '[[:<:]]1[[:>:]]';
Output: See Live Demo on SQLFiddle
Note: You can adjust searching string based on your requirement above REGEXP is searching exact word.
if you can alter the data (not the table/schema) you should append and prepend another comma, so you can search with where col like "%,123,%", this will always fit on an exact value. Otherwise you have to use regex with something like ,?123,?