I am using the 3 following tables:
First table
id
response
Second table
responseid
patientid
Third table
patientid
The relationship between first and second table is on id and responceid.
The relationship between third and second is on patientid.
Now I need to retrieve values from these tables like all values from first and third tables with the help of matching with patientid from second and 3rd table.
How can I do this?
Basically if all of the columns that defines their relationship are not nullable, then INNER JOIN will suffice. But if they are nullable and you still want to display all records from firstTB, you need to use LEFT JOIN instead of INNER JOIN.
SELECT a.*, b.*, c.*
FROM firstTB a
INNER JOIN secondTB b
ON a.ID = b.responceID
INNER JOIN thirdTB c
ON b.patientID = c.patientID
To further gain more knowledge about joins, kindly visit the link below:
Visual Representation of SQL Joins
You're probably looking for INNER JOIN or JOIN in general:
SELECT
response.id,
response.responce,
patient.patientid
FROM
`response_table` as `response`
INNER JOIN
`relation_table` as `relation`
ON
relation.responceid = response.id
INNER JOIN
`patient_table` as `patient`
ON
relation.patientid = patient.patientid
try
SELECT first.*
, third.*
FROM first
INNER JOIN second ON ( second.responseid = first.id )
INNER JOIN third ON ( third.patientid = second.patientid )
;
honestly, and no insult intended, if you have difficulties in coming up with queries like this one on your own, consider some training on db basics and db development, the sooner the better (just hoping i haven't blundered myself ... ;-)).
Related
I have two tables:- PERSON and DATA. What I want to do is fetch all details from PERSON table and only two columns from DATA table only when PERSON.personId = DATA.personId.
I am using this query:-
SELECT *
FROM PERSON AND SELECT DATA.value, DATA.field
FROM DATA where PERSON.personId = DATA.personId;
But I think this is wrong syntax. Can anyone tell me what is the right syntax for it.
SELECT p.*,d.column1,d.column2
FROM Person p
JOIN Data d
ON p.personId = d.personId
WHERE <Condition>
In this query person with all columns and data with your desire column you can fetch by this query.
Something like this:
select
P.*,
D.value,
D.field
from Person P
join Data D on P.PersonID = D.PersonID
change P.* to the specific columns that you need but P.* will get everything from the Person table.
check this post out LEFT JOIN vs. LEFT OUTER JOIN in SQL Server to learn about JOINS, the diagram is good to understand what the different ones do
Its really easy, Just execute this query:
SELECT
PERSON.*,
DATA.value,
DATA.field
FROM
PERSON INNER JOIN DATA USING (`personId`);
It selects all fields of PERSON + value and field from DATA.
Also it uses personId to join the two tables.
Fill free to ask if you need more info.
You can use join (LEFT JOIN)
SELECT * FROM PERSON LEFT JOIN DATA ON PERSON.personId = DATA.personId
Hope it will help you
Here's the correct syntax for achieving what you've asked for:
SELECT PERSON.column1,PERSON.column2,PERSON.columnN,DATA.value
FROM PERSON
INNER JOIN DATA
ON PERSON.personId = DATA.personId
Line#1: lists the columns that you want to select with references to their parent tables.
Line#2 and 3: are the two tables that you want to select from and join with
Line#4: is the join condition between the two tables (with matching IDs or other information)
Hopefully you are going to help me again :)
Well, the problem that I have is similar to the one which I've posted yesterday, but it is extended.
We are given three tables:
Pfleger
Station
Mitarbeiter
As states above, this problem is very similar to this problem.
What was the result? Well, I get back a table with the ID's and names of the workers who are living in Frankfurt.
Now I should additionally get back the ID'S and names of the workers who are living in Frankfurt AND working in the station called Onkologie.
How should I do this?
My code so far:
SELECT pfleger.PNR, Name
from mitarbeiter, ...
JOIN pfleger on (mitarbeiter.PNR=pfleger.PNR)
JOIN ...
where Ort='Frankfurt' and Name='Onkologie'
I don't know how to make 2nd JOIN.
You could try something like this
select m.PNR, m.Name
from Mitarbeiter m
inner join Station s on s.PNR = m.PNR
inner join Pfleger p on p.StationID = s.StationID
where
m.Ort = 'Frankfurt'
and p.Name = 'Onkologie'
Updated based on provided table names and column names for tables.
Notice: we eliminated the , notation after mitarbeiter, in your base query.
I don't see PNR in mitabeiter so I'm assuming stationID is how they join.
SELECT *
FROM pfleger P
INNER JOIN Station S
on S.StationId = P.StationID
INNER JOIN mitarbeiter M
on M.pnr = S.pnr
WHERE M.ORT='Frankfurt' and P.name = 'Onkologie'
Assumptions I made:
pfleger.stationID has a foreign key relationship to station.stationID
mitarbeiter.PNR has a foreign key relationship to station.PNR
We used inner joins here as we only want Mitarbeiter who exist in all 3 tables.
Otherwise we could use outer joins and return those who don't have records as well. (meaning it is unknown where they work it MIGHT be 'Onkologie' but we don't know as there is no record.)
I have two tables. part and activity. In part there are 4 columns. pid (part id), aid (activity id), uname (username) and active. In the activity tables there are a lot of rows like aid, aname,adescription etc.
I will be defining the uname. I want to check if that uname exists in the part table, and if it does, get all the aids where the activecolumn is equal to1 and check that aid with the activity table and get all the corresponding details like aname,adescription etc.
Data in the tables:
I am hopeless in trying to write this query out. Can someone please help me?
If I understood you correctly then you can use INNER JOIN with both tables:
SELECT
a.*,
p.uname
FROM activity a
INNER JOIN part p ON a.aid = p.aid
AND p.uname = {uname} <-- As you are defining unames -->
AND p.active = 1
By studying your requirements I get a feel that you do not require to output any data from the part table. So, I would suggest using "sub-queries" for you as it would be faster. If you require data from the part table you may want to go for INNER JOIN.
The query should using sub-query would be: -
SELECT a.* FROM activity a
WHERE a.aid IN (
SELECT p.aid FROM part p
WHERE p.uname = 'donor123' -- Inplace of 'donor123' please use the uname that you are searching for.
AND p.active = 1
);
The query using INNER JOIN would be: -
Select a.* FROM activity a INNER JOIN part p
ON a.aid = p.pid
AND p.uname = 'donor123' -- Inplace of 'donor123' please use the uname that you are searching for.
AND p.active = 1;
I have the following query:
SELECT
dashboard_data.headline,
dashboard_data.message,
dashboard_messages.image_id
FROM dashboard_data
INNER JOIN dashboard_messages
ON dashboard_message_id = dashboard_messages.id
So I am using an INNER JOIN and grabbing the image_id. So now, I want to take that image_id and turn it into images.filename from the images table.
How can I add that in to my query?
You can simply add another join like this:
SELECT dashboard_data.headline, dashboard_data.message, dashboard_messages.image_id, images.filename
FROM dashboard_data
INNER JOIN dashboard_messages
ON dashboard_message_id = dashboard_messages.id
INNER JOIN images
ON dashboard_messages.image_id = images.image_id
However be aware that, because it is an INNER JOIN, if you have a message without an image, the entire row will be skipped. If this is a possibility, you may want to do a LEFT OUTER JOIN which will return all your dashboard messages and an image_filename only if one exists (otherwise you'll get a null)
SELECT dashboard_data.headline, dashboard_data.message, dashboard_messages.image_id, images.filename
FROM dashboard_data
INNER JOIN dashboard_messages
ON dashboard_message_id = dashboard_messages.id
LEFT OUTER JOIN images
ON dashboard_messages.image_id = images.image_id
Just add another join:
SELECT dashboard_data.headline,
dashboard_data.message,
dashboard_messages.image_id,
images.filename
FROM dashboard_data
INNER JOIN dashboard_messages
ON dashboard_message_id = dashboard_messages.id
INNER JOIN images
ON dashboard_messages.image_id = images.image_id
I shared my experience of using two LEFT JOINS in a single SQL query.
I have 3 tables:
Table 1) Patient consists columns PatientID, PatientName
Table 2) Appointment consists columns AppointmentID, AppointmentDateTime, PatientID, DoctorID
Table 3) Doctor consists columns DoctorID, DoctorName
Query:
SELECT Patient.patientname, AppointmentDateTime, Doctor.doctorname
FROM Appointment
LEFT JOIN Doctor ON Appointment.doctorid = Doctor.doctorId //have doctorId column common
LEFT JOIN Patient ON Appointment.PatientId = Patient.PatientId //have patientid column common
WHERE Doctor.Doctorname LIKE 'varun%' // setting doctor name by using LIKE
AND Appointment.AppointmentDateTime BETWEEN '1/16/2001' AND '9/9/2014' //comparison b/w dates
ORDER BY AppointmentDateTime ASC; // getting data as ascending order
I wrote the solution to get date format like "mm/dd/yy" (under my name "VARUN TEJ REDDY")
Multi joins in SQL work by progressively creating derived tables one after the other.
See this link explaining the process:
https://www.interfacett.com/blogs/multiple-joins-work-just-like-single-joins/
This is the query that I am using to match up a members name to an id.
SELECT eve_member_list.`characterID` ,eve_member_list.`name`
FROM `eve_mining_op_members`
INNER JOIN eve_member_list ON eve_mining_op_members.characterID = eve_member_list.characterID
WHERE op_id = '20110821105414-741653460';
My issue is that I have two different member lists, one lists are members that belong to our group and the second list is a list of members that do not belong to our group.
How do i write this query so that if a member is not found in the eve_member_list table it will look in the eve_nonmember_member_list table to match the eve_mining_op_members.characterID to the charName
I apologize in advance if the question is hard to read as I am not quite sure how to properly ask what it is that I am looking for.
Change your INNER JOIN to a LEFT JOIN and join with both the tables. Use IFNULL to select the name if it appears in the first table, but if it is NULL (because no match was found) then it will use the value found from the second table.
SELECT
characterID,
IFNULL(eve_member_list.name, eve_nonmember_member_list.charName) AS name
FROM eve_mining_op_members
LEFT JOIN eve_member_list USING (characterID)
LEFT JOIN eve_nonmember_member_list USING (characterID)
WHERE op_id = '20110821105414-741653460';
If you have control of the database design you should also consider if it is possible to redesign your database so that both members and non-members are stored in the same table. You could for example use a boolean to specify whether or not they are members. Or you could create a person table and have information that is only relevant to members stored in a separate memberinfo table with an nullable foreign key from the person table to the memberinfo table. This will make queries relating to both members and non-members easier to write and perform better.
You could try a left join on both tables, and then selecting the non-null results from the resulting query -
select * from
(select * from
eve_mining_op_members as x
left join eve_member_list as y1 on x.characterID = y1.characterID
left join eve_member_list2 as y2 on x.characterID = y2.characterID) as t
where t.name is not null
Or, you could try the same thing with a union and using inner join (assuming joined tables are the same):
select * from
(select * from eve_mining_op_members as x
inner join eve_member_list as y1 on x.characterID = y1.characterID
UNION
select * from eve_mining_op_members as x
inner join eve_member_list2 as y2 on x.characterID = y2.characterID) as t
You can throw in your op_id condition where you see fit (sorry, I didn't really understand where it came from). Good luck!
You have several options but by
using a UNION between the eve_member_list and eve_nonmember_member_list table
and JOIN the results of this UNION with your original eve_mining_op_members table
you will get your required results.
SQL Statement
SELECT lst.`characterID`
, lst.`name`
FROM `eve_mining_op_members` AS m
INNER JOIN (
SELECT characterID
, name
FROM eve_member_list
UNION ALL
SELECT characterID
, name
FROM eve_nonmember_member_list
) AS lst ON lst.characterID = m.characterID
WHERE op_id = '20110821105414-741653460';