I wrote a MySQL command in bash (Ubuntu) :
[XXXX:~]$ mysql -h localhost -u XXXX -pXXXX -e "DROP DATABASE IF EXISTS `f-XXXX`;"
I need backquote in this command, cause database name is variable.
That command doesn't work and it sends f-XXXX command not found
I think my problem is related to backquotes. How can I do?
You need not use backtick for variable substitution here.
[XXXX:~]$ mysql -h localhost -u XXXX -pXXXX -e "DROP DATABASE IF EXISTS ${DB};""
Bash takes the content of the backtick and runs another bash process with that as a command.
This is a backtick. Backtick is not a quotation sign, it has a very special meaning. Everything you type between backticks is evaluated (executed) by the shell before the main command (like chown in your examples), and the output of that execution is used by that command, just as if you'd type that output at that place in the command line.
Use $(commands) instead.
mysql -h localhost -u XXXX -pXXXX -e "DROP DATABASE IF EXISTS $('f-XXXX');"
Related
I what to write a shell script to loging in to mariadb. The shell script read one password containing special characters(blank, !#) in a ini file.
The OS is Ubuntu 18.04
the ini file as follows:
user=xxx-xxx-xxx
password=xxx /xxx /xx/ !\#
the shell script as follows:
#!/bin/bash
baseDir="$(cd "$(dirname "$0")" && pwd)"
iniPath="$baseDir/backup.ini"
echo "iniPath is $iniPath"
dbUser="$(grep 'user' $iniPath | cut -d '=' -f 2)"
echo "user is $dbUser"
dbPassword="$(grep 'password' $iniPath | cut -d '=' -f 2)"
echo "password is $dbPassword"
mysql -h localhost -u $dbUser -p'$dbPassword'
if I input the command as follows:
mysql -h localhost -u xxxxxx -p'xxx /xxx /xx/ !#'
in command line, it loging successfully.
But If I execute the shell script, it always results in accessing denied for user.
Have any suggestions? thanks.
Have you tried to use: mysql -h localhost -u $dbUser -p'echo $dbPassword' ? (special character ` is on US like keyboards under esc key left upper corner, it looks like back apostroph) Looks like the variable with password is not correctly "printed" into a mysql command before its run. Other way I would recommend trying is to use -p"$dbPassword"
FWIW, the issue is that the shell will not interpolate variables into a string surrounded by single quotes. As Honza specified, the double-quotes will work.
See Difference between single and double quotes in Bash for details.
I'm writing a bash script to do some db stuff. New to MySQL. I'm on Mac and have MySQL installed via homebrew.
Am using username "root" right now and there isn't a pw set. I included the pw syntax below just to help others out that may have a pw.
My goal is to have mysql commands be as "clean" as possible in my bash script
Not a hige deal, but would like to do this if possible.
Example
# If I can do it without logging in (*ideal)
mysql CREATE DATABASE dbname;
# Or by logging in with - mysql -u root -pPassword
CREATE DATABASE dbname;
# Instead of
mysql -u root -pPassword -e"CREATE DATABASE dbname";
Tried to simplify it. I have a handful of things I gotta do, so would rather keep my code cleaner if possible. I tried logging in with the bash script, but the script stopped once logged into MySQL and didn't run any commands.
Another option I was considering (but don't really like) would be just to keep username and pw string in a var and call it for every commmand like so
# Set the login string variable
login_details="-u root -p password -e"
# example command
mysql $login_details"CREATE DATABASE dbname";
So any ideas?
Write a new bash script file and run this file after putting all your commands into it. Don't forget to give right username and password in your bash script.
For bash script:
#!/bin/bash
mysql -u root -pSeCrEt << EOF
use mysql;
show tables;
EOF
If you want to run single mysql command.
mysql -u [user] -p[pass] -e "[mysql commands]"
Example:
mysql -h 192.168.1.10 -u root -pSeCrEt -e "show databases"
To execute multiple mysql commands:
mysql -u $user -p$passsword -Bse "command1;command2;....;commandn"
Note: -B is for batch, print results using tab as the column separator, with each row on a new line. With this option, mysql does not use the history file. Batch mode results in nontabular output format and escaping of special characters. -s is silent mode. Produce less output. -e is to execute the statement and quit
Am facing problem to connect the MySQL DB from shell script. Please find the below snippet i have written for connecting the MySQL data base. please suggest on this.
My shell Script:
#!bin/bash
Query="select * from Main"
MySQL -u root -p '!!root!!' -e kpi << EOF
$Query;
EOF
Please check the above code and suggest me how to connect the DB.
I think it should be
-pThePassword
So you should delete the space between -p and the pass. Also you should not use an apostrophe (except it is part of the pass itself. Use a backslash to escape special characters.
Second: *nix systems are case sensitive, please try mysql instead of MySQL
Update
You could also try to type your password into a file and read it with your script
mysql -u root -p`cat /tmp/pass` -e "SHOW DATABASES"
The file /tmp/pass should contain your password without any newline char at the end.
Update 2
Your Script is wrong.
You can either use mysql ... -e SELECT * FROM TABLE or mysql ... << EOF (without -e). You should not mix them.
Don't forget to pass the databasename as a parameter (or with use databasename;) in the sql
Don't forget to add a ; after every sql command, if you have multiple statements
Method One:
mysql -u root -ppassword databasename -e "SELECT * FROM main"
Method Two:
mysql -u root -ppassword databasename << EOF
SELECT * FROM main
EOF
Method Three:
mysql -u root -ppassword << EOF
USE databasename;
SELECT * FROM main;
EOF
mysql --user=root --password=xxxxxx -e "source dbscript.sql"
This should work for Windows and Linux.
If the password content contains a ! (Exclamation mark) you should add a \ (backslash) in front of it.
I am trying to run MySQL query on remote machine with this command:
ssh user#192.168.2.26 "mysql -uroot -proot -e \"use test";""
I am not able to use that database.
Please suggest a working command.
Try this:
mysql -h host -u root -proot -e "show databases;";
Try this:
ssh root#host "mysql database -e 'query to run on table_name; more queries to run;'"
Same can be done with user#host if that user has permission to execute SQL queries let alone launch mysql in general. Using -e is the same as --execute, which will run whatever you put within the trailing quotes (single or double) and quit. The standard output format would be the same as you would see using --batch.
MySql seems to have a special command line syntax which includes the database.
mysql -u user -p -e 'SQL Query' database
This documentation is rather old but I got it to work
http://www.cyberciti.biz/faq/run-sql-query-directly-on-the-command-line/
Final working command with ssh:
ssh user#host "mysql -u user -e 'show tables;' databasename"
This ended up working for me in a bash script:
query='USE [database]; SELECT ...'
mysql='mysql -u [username] -p[password] -e '"'""$query""'"
ssh [username]#[server] -t "$mysql"
If you want to make it more safe then add a prompt for the password instead of storing it somewhere potentially unsafe.
This worked for me after a few tests (basically same answer as #King-Wzrd):
ssh -t kom "mysql -uroot -p -e 'show databases;'"
ssh -t kom "mysql -uroot -p < /home/ling/websites/jin_test/.deploy/tmp.sql"
The "trick" was the quotes around the command.
The -t option allows for prompting password interactively via the remote shell.
The kom here is just a ssh config identifier defined in my ~/.ssh/config file (see more here: https://www.cyberciti.biz/faq/create-ssh-config-file-on-linux-unix/).
Running this from my Host environment against MySQL within my Homestead VM produced a nice result... although I did have to set the root password from within the VM first in order for it to work.
ssh vagrant#192.168.10.10 mysql -h localhost -u root -p -e "'SELECT * FROM user;' mysql";
I tried to execute the following mysql command in one of my scripts:
mysql -e 'show global status like 'open_files''
But it doesn't seem to work, because of the single quotes around the string 'open_files'.
How can I issue a command like this, that contains a single quote?
Use double quote outside.
mysql -h127.0.0.1 -uxxxxx -pxxxxx -A databasename -e "show global status like 'open_files'"
or the reverse way:
mysql -h127.0.0.1 -uxxxxx -pxxxxx -A databasename -e 'show global status like "open_files"'
or you could escape the single quote.
And you are using LIKE, didn't you miss the wild char %?