I would like to find the result -> 'the_red_cat' using sublime search. I have enabled the regex but cannot figure out how to get the result I need.
I would like to search something along the line of *the*ca* but it does not seem to yield any results.
The regex .*the.*ca.* finds the whole lines that contain the text. Searching for any number of characters with regex is done with .*.
Related
I am reading data (combination of letters and numbers) from an excel sheet and put it into a text field in target application, where the input should yield a unique item from a database.
However there (sometimes) is a whitespace behind the data in the excel cell, which results in a "no data found" when this whitespace is entered into the search field in target application. The whitespace does not seem to be a space though, since i am unable to trim that whitespace AA-internally. I guess it is a (or some similar html special character).
edit: confirmed to be a by now.
Q: How can i get rid of such characters AA internally?
Tried: Neither (a) Trim, (b) Replace " " ->"", nor (c) Replace " "->"" work.
Workaround: I am currently checking for the length of the data provided: if its longer than 10 chars i only take the leftmost 10 chars. This works here, since its a business rule for the data i am working with, but i am still interested in an original solution, since there may be upcoming cases, where no business rule will help me out.
AA Version: 11.3.1
Thankful for input...
Okay, since it's non-breaking spaces character, you can replace it using Regex in replace command.
Find: \u00a0
Options: Regular Expression.
Got rid of it using Replace Command with RegEx ticked:
[^a-z A-Z 0-9]
I'm trying to recognize quoting (citing) somebody's else sentence in a markdown text, which I have in my local copy of MySQL GHTorrent dataset. So I wrote this query:
select * from github_discussions where body rlike '(.)*(\s){1,}(>)(\s){1,}(.)+';
it matches some unwanted data, which according to https://regex101.com/, it should not with this particular regular expression.
Test string:
`Params` is plural -> contain<s>s</s>
Matched on MySQL database, not matched at regex101 dot com.
Obvious example of quoting, but not matched at db:
Yes, I believe so.\r\n\r\n\r\n\r\nK\r\n\r\n> On 19-Jul-2014, at 17:33, Stefan Karpinski <notifications#github.com> wrote:\r\n> \r\n> This is the standard 3-clause BSD license, right?\r\n> \r\n> —\r\n> Reply to this email directly or view it on GitHub.
Moreover, MySQL workbench didn't show those return carriage and new line symbols unless copy-pasted here.
Can I normalize (remove \r and \n) with some update query ?
Is MySQL regex implementation different from POSIX standard regex ?
Do you have by any chances maximally clean solution for recognizing quoting in a markdown text ?
Thanks!
You've got an awful lot of parens in there. Try this as functionally what you have above:
select * from github_discussions where body rlike '.*[:blank:]+>[:blank:]+.+'
However, I'm not sure that's really what you want. This would happily match this line:
this is before > and after
which by my understanding is not a quoted string in markdown. Instead I would anchor it at the beginning like this:
select * from github_discussions where body rlike '^[:blank:]*>[:blank:]+'
That will match a greater-than sign at the beginning of the line, optionally preceded by whitespace. Is that what you are looking for?
I'm not sure if your data has newlines embedded. If so, you may need to look into ways of having your regex identify newlines using the ^ anchoring symbol. As is the well accepted conclusion in regex literature, that is left as an exercise for the student. :-)
I am trying to find and replace all for loops in my (js) code with slightly different syntax. I want to find every for loop that used the syntax "for ( any code here ){". Is there a way to find all such instances?
That's a regular expression question I think. In SublimeText2 start the search functionality. Make sure regular expressions are on (first button, labeled .*) and the search for for\s*\(.*?\)\s*\{.
Enable the regex option and type for \(.+\)\{
Explanation:
the backslashes "escape" the parentheses and brace. In other words, they tell the regex that those are the characters within the search and not part of a regex command. The . searches for any character and the + modifies that to include one or more instances of any character.
Here's a screen shot of sublime text
You want to search by regular expression. Notepad++ supports this, not sure about Sublime Text but I would image it does also. With regular expression enabled, search for
xx.+xx
This will search for the characters xx, followed by any character (.) as many times as it can find it (+), followed by the characters xx. This should give you the result you are looking for.
Here is a article with some information about using regular expressions in Notepad++
So let's say I have this in my search file
Foo
Bez, Bez
Foobar
Foo
I want to search for Bez, Bez by using a regex.
This is what I have and I know it's not even remotely correct.
:%s/\([a-zA-Z]\),\([a-zA-Z])/\1,\1,\1/g
So basically what I want to do is make "Bez, Bez" into "Bez, Bez, Bez"
Really, I'm stumped on how to find 2 consecutive equivalent strings.
what about:
%s/\(\w\+\), \1/\1, \1, \1/g
it captures the expression between the parenthesis even before ending the expression whole match, pretty neat huh?.
You use capturing groups such as:
(\w+)\W+\1
but I don't recall the vim equivalent for such regex expression.
I tested using RegexPal and the input you gave
Edit
Found Back References in Vim
I have a document that was converted from PDF to HTML for use on a company website to be referenced and indexed for search. I'm attempting to format the converted document to meet my needs and in doing so I am attempting to clean up some of the junk that was pulled over from when it was a PDF such as page numbers, headers, and footers. luckily all of these lines that need to be removed are in blocks of 4 lines unfortunately they are not exactly the same therefore cannot be removed with a simple literal replace. The lines contain numbers which are incremental as they correlate with the pages. How can I remove the following example from my html file.
Title<br>
10<br>
<hr>
<A name=11></a>Footer<br>
I've tried many different regular expression attempts but as my skill in that area is limited I can't find the proper syntax. I'm sure i'm missing something fairly easy as it would seem all I need is a wildcard replace for the two numbers in the code and the rest is literal.
any help is apprciated
The search & replace of npp is quite odd. I can't find newline charactes with regular expression, although the documentation says:
As of v4.9 the Simple find/replace (control+h) has changed, allowing the use of \r \n and \t in regex mode and the extended mode.
I updated to the last version, but it just doesn't work. Using the extended mode allows me to find newlines, but I can't specify wildcards.
However, you can use the macros to overcome this problems.
prepare a search that will find a unique passage (like Title<br>\r\n, here you can use the extended mode)
start recording a macro
press F3 to use your search
mark the four lines and delete them
stop recording the macro ... done!
Just replay it and it deletes what you wanted to delete.
If I have understood your request correctly this pattern matches your string:
Title<br>( ?)\n([0-9]+)<br>( ?)\n<hr>( ?)\n<A name=([0-9]+)></a>Footer<br>
I use the Regex Coach to try out complicated regex patterns. Other utilities are available.
edit
As I do not use Notepad++ I cannot be sure that this pattern will work for you. Apologies if that transpires to be the case. (I'm a TextPad man myself, and it does work with that tool).