I have the below data in my MySQL table "categories":
id Name
-----------------
1 Books & CDs
2 Dress
When I try to get the value from table it works fine with below SQL.
SELECT * FROM `categories` WHERE `name` = 'Books & Cds';
But when using in PHP, it gives me some SQL error.
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an
error in your SQL syntax; check the manual that corresponds to your
MySQL server version for the right syntax to use near '' at line 5
Where can I find the actual reason for this? How to debug this?
If you want to search for rows in your Category table in your PHP code, I recommend that you add a column in your table for a code to use instead of searching on the name that you use for the end users. The potential problem that you're facing is that if you want to change the name of a category, you'd have to find everywhere in your code that you referred to that category by name and change it too. But if your table looked like this:
ID code name
1 BCDS Books & CDs
2 DRS Dress
then your code can do things like "where code = 'BCDS'" and you can call that category "Books & CDs", "CDs and Books", or anything else you like.
Now, as far as fixing your syntax problem, you'll have to post the PHP that you use to generate the query that fails. As another poster said, you're probably escaping something incorrectly and MySQL isn't getting the query you think it's getting.
Related
I want to create simple app to search some data in specific table.
I've got one database and can connect to it.
Also when I hardcoded table name it works great.
But I want to make url like that:
/demo/{table}/{author}
It should work that i give specific table for eg. 'comedy' and next I set name of author for eg. 'smith'.
My booksRepository:
#Query(value = "SELECT * FROM :table WHERE author = :author",
nativeQuery=true)
public List<Book> findByAuthor(#Param("author") String author, #Param("table") String table);
But it didn't work. I've got error:
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ''comedy' WHERE author = 'Smith'' at line 1
It's adding ' to Query. Is there way to delete that? Is it possible or I need to put everything in one table?
Cheers :)
I haven't looked it up, but it seems that the variables in the query SQL can only be used to insert quoted values, not unquoted identifiers like a table name.
I get the usual errors ( already tried to read previous questions ) Query failedYou have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''','',now(),'','This is great! ','', 'published')' at line 1
Thank you for helping!!
Here is my code:
My Code
The page in question is here:enter link description here
Thanks you very much for helping
The problem was on the line 20--> $query .= "VALUES({$post_category_id}. It need to be quotes around '{$post_category_id}'.
I don't know exactly why. the category id is a number , so for that shouldn't be around quotes because is a number.That's how our teacher explained to as.Thanks for your help.
The $connection variable isn't defined anywhere...
I just populated your page with some example data and that was the query I got:
INSERT INTO posts(post_category_id, post_title, post_author,post_date,post_image,post_content,post_tags,post_status) VALUES(,'','',now(),'',' Test','', 'Test')
The problem is near the VALUES keyword: VALUES (, is wrong. You should check first if every input value is populated correctly, eg if $post_category_id is defined with a valid value.
I need to search same query on multiple columns using fatfree.
This works correctly on one column:
$f3->set('list', $users->find(array('name LIKE ?','%'.$queries.'%')));
However, if I try:
$f3->set('list', $users->find(array('name, email LIKE ?','%'.$queries.'%')));
I get error:
PDOStatement: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' email LIKE '%invent%'' at line 1
How can I do this?
Regards.
It should be:
$f3->set('list', $users->find(array(
'name LIKE ? OR email LIKE ?',
'%'.$queries.'%',
'%'.$queries.'%'
)));
NB: PDO doesn't allow to use a same placeholder twice so you have to give twice the same argument ('%'.$queries.'%').
I'm using JDevelper 11.1.2.4 and MySql DB 5.6.19. The version of JConnector I am using is mysql-connector-java-5.1.30-bin.
I've created two tables country and city.
In table city, there is foreign key to link it with the country table.
JDevelper have created associations and view links for these tables which I've tested using ADF Model Tester and they are looking fine.
I've created a transient column CountryName and set the default value (as Expression) to Country1.CountryName.
Now when I run the ADF Model Tester again, I get the following error:
(oracle.jbo.SQLStmtException) JBO-27122: SQL error during statement preparation.
Statement:
SELECT CountryEO.country_id, CountryEO.country_name, CountryEO.country_code,
CountryEO.country_short_name, CountryEO.currency_id, CountryEO.created_date,
CountryEO.created_by, CountryEO.last_updated_date, CountryEO.last_updated_by
FROM cms.country CountryEO WHERE CountryEO.country_id = ?
----- Level 1: Detail 0 -----
(com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException)
You have an error in your SQL syntax; check the manual that corresponds
to your MySQL server version for the right syntax to use near
'OPTION SQL_SELECT_LIMIT=1' at line 1
What may be the problem?
Please check your country view object query by sql puls / toad etc. If its correct please post your question
I'm querying against an IP address stored in a table of a database with the following:
"SELECT user_id, is_login FROM users WHERE last_ip_address = '" + this.GetIPAddress() + "'"
I know that the IP is in the table because I see it there. I'm literally staring at it, but this query returns no rows.
When I run it without the single tick quotes ('), I get a syntax error:
"SELECT user_id, is_login FROM users WHERE last_ip_address = " + this.GetIPAddress()
So where is this going wrong? The IP returned by the function is the standard format ###.###.###.### IP address, and the syntax error itself is this:
{"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.##.#' at line 1"}
Edit: Some more info, the field itself is a varchar(30) type, and it says Collation = latin1_swedish_ci, but I don't even know what that is.
Thanks
Try using a LIKE then:
"SELECT user_id, is_login FROM users WHERE last_ip_address LIKE '%" + this.GetIPAddress() + "%'"
Edit: I would try to change that collation to UTF8.
Okay I am sorry for the confusion. I am very new to using MySql with C# and very VERY new (like I mean I just started today) with MySqlConnector.
To make a long answer short, I was trying to treat the table like, well, a table, and just read from it like a two dimensional array, when what I needed to be doing was using the MySqlDataReader. I found a good answer here:
How to read columns and rows with C#?
Thanks all for your help and advice.