How implementation my wants with MySQL JOIN - mysql

Question

_
Hello everyone!
I have table
CREATE TABLE `labels` (
`id` INT NULL AUTO_INCREMENT DEFAULT NULL,
`name` VARCHAR(250) NULL DEFAULT NULL,
`score` INT NULL DEFAULT NULL,
`before_score` INT NULL DEFAULT NULL,
PRIMARY KEY (`id`)
);
And I Have This Table
CREATE TABLE `scores` (
`id` INT NULL AUTO_INCREMENT DEFAULT NULL,
`name_id` INT NULL DEFAULT NULL,
`score` INT NULL DEFAULT NULL,
`date` DATETIME DEFAULT NULL,
PRIMARY KEY (`id`)
);
And i want have result where labels.score - have value last scores.score sorted by scores.date and labels.before_score where have value penultimate scores.score sorted by scores.date. Can I do This Only on Mysql slq and how?
Thanks.
ADD
For example i have this data on first table:
INSERT INTO `labels` (id, name, score, before_score) VALUES (1, 'John', 200, 123);
INSERT INTO `labels` (id, name, score, before_score) VALUES (2, 'Eddie', 2000, 2000);
INSERT INTO `labels` (id, name, score, before_score) VALUES (3, 'Bob', 400, 3101);
And second table
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('1','1','12','2013-07-10');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('2','2','2000','2013-05-04');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('3','3','654','2012-09-12');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('4','1','123','2013-12-17');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('5','1','200','2014-04-25');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('6','3','3101','2013-12-02');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('6','2','2000','2015-12-02');
INSERT INTO `scores` (`id`,`name_id`,`score`,`date`) VALUES ('6','3','400','2013-12-02');

Answer 1

If I understand correctly, you need the last two scores for each name_id.
I would tackle this with temporary tables:
Step 1. Last score:
create temporary table temp_score1
select name_id, max(`date`) as lastDate
from scores
group by name_id;
-- Add the appropriate indexes
alter table temp_score1
add unique index idx_name_id(name_id),
add index idx_lastDate(lastDate);
Step 2. Penultimate score. The idea is exactly the same, but using temp_score1 to filter the data:
create temporary table temp_score2
select s.name_id, max(`date`) as penultimateDate
from scores as s
inner join temp_score1 as t on s.nameId = t.nameId
where s.`date` < t.lastDate
group by name_id;
-- Add the appropriate indexes
alter table temp_score2
add unique index idx_name_id(name_id),
add index idx_penultimateDate(penultimateDate);
Step 3. Put it all together.
select
l.id, l.name,
s1.lastScore, s2.penultimateScore
from
`labels` as l
left join temp_score1 as s1 on l.id = s1.name_id
left join temp_score2 as s2 on l.id = s2.name_id
You can put this three steps inside a stored procedure.
Hope this helps you.