Mysql: which pizza prefer client - mysql

Question

I have table with this data :
1. John | seafood pizza
2. Mike | pepperoni pizza
3. Mike | pepperoni pizza
4. John | original pizza
5. Mike | original pizza
6. John | seafood pizza
7. John | pepperoni pizza
....
How can I write a query that give me result such this:
John | seafood pizza
Mike | pepperoni pizza
If client have same quantity for many pizzas, the result may be any pizza's name.

Answer 1

Let's take it step by step
the following query will give you number of times each client ordered each kind of pizza
SELECT name, pizza, COUNT(*) AS cnt
FROM yourTable
GROUP BY name, pizza
So how do we get the most often ordered pizza from that? We must first know, what is the highest number of pizza ordered by each client
SELECT name, MAX(cnt) AS cnt FROM (
SELECT name, pizza, COUNT(*) AS cnt
FROM yourTable
GROUP BY name, pizza
) AS subquery GROUP BY name
then use this number to select actual pizza name
SELECT name, pizza, COUNT(*) AS cnt
FROM yourTable AS t
CROSS JOIN (
SELECT name, MAX(cnt) AS cnt FROM (
SELECT name, pizza, COUNT(*) AS cnt
FROM yourTable
GROUP BY name, pizza
) AS subquery GROUP BY name
) AS sq
USING(name,cnt)
GROUP BY name, pizza

Answer 2

I'd go with grouping the counts by user and pizza then using this as a datasource for a query which finds the groupwise maximum (using the max concat trick). It's not hard:
SELECT user, SUBSTRING(MAX(CONCAT(LPAD(freq, 6, '0'),pizza)),7)
FROM
(SELECT user, pizza, COUNT(*) AS freq
FROM user_likes
GROUP BY user, pizza) ilv
GROUP BY user

Answer 3

Let's have a simple solution :
First of all, we have two columns,name and food.
You can list of favorite customer's food easily :
CREATE TEMPORARY TABLE tbltemp AS (
SELECT name, food, COUNT( * ) c
FROM food
GROUP BY name, food
);
Now we have all of foods by count.
Then you can order it by count descending :
SELECT *
FROM tbltemp
ORDER BY c DESC
Now you have a list that describes your customer's favorite.
UPDATE :
Instead of second query ,replace this one :
SELECT tbl1 . *
FROM (
SELECT name, food, COUNT( * ) c
FROM food
GROUP BY name, food
) AS tbl1, (
SELECT name, food, COUNT( * ) c
FROM food
GROUP BY name, food
) AS tbl2
WHERE tbl1.c = tbl2.c
AND tbl2.name = tbl1.name
AND tbl2.food = tbl1.food
AND tbl1.c = (
SELECT c
FROM tbltemp
ORDER BY c DESC
LIMIT 1 )
This query result is your question goal.