I have a table which looks something like this...
supplier_name status count
supplier_a Unavailable 1
supplier_a Refunded 5
supplier_a Shipped 10
supplier_z Refunded 2
supplier_z Shipped 4
I know exactly what columns I want and I would like to use the values from the first table to return values structured like the following...
supplier_name unavailable refunded shipped
supplier_a 1 5 10
supplier_z 0 2 4
(note: in cases where there is no value for a specific column it should be set to 0)
Would this be possible to achieve in a query?
I think something like this should work:
SELECT Supplier_Name,
MAX(CASE WHEN STATUS = 'Unavailable' THEN Count ELSE 0 END) as Unavailable,
MAX(CASE WHEN STATUS = 'Refunded' THEN Count ELSE 0 END) as refunded,
MAX(CASE WHEN STATUS = 'Shipped' THEN Count ELSE 0 END) as shipped
FROM YourTable
GROUP BY Supplier_Name
And here is the SQL Fiddle.
Good luck.
Try this:
SELECT
supplier_name,
SUM(COALESCE(CASE WHEN status = 'unavailable' THEN `count` END, 0)) unavailable,
SUM(COALESCE(CASE WHEN status = 'refunded' THEN `count` END, 0)) refunded,
SUM(COALESCE(CASE WHEN status = 'shipped' THEN `count` END, 0)) shipped
FROM tbl
GROUP BY supplier_name
SQL FIDDLE DEMO
Related
I am having problems trying to create a query that allow me to group by months and by a column that has different values.
The following is a small representation of the table and columns I need to query.
Table name is requests and has two columns date and status. Status may have the values pending, attended, absent and canceled.
I want to get a query that looks like this
Right now i am trying a subquery on status for each possible value. It works but is a very slow query. It takes arround 48s for 8000 rows.
SELECT
MONTHNAME(date)
(SELECT count(status) FROM requests WHERE status = "pending"),
(SELECT count(status) FROM requests WHERE status = "attended"),
(SELECT count(status) FROM requests WHERE status = "absent"),
(SELECT count(status) FROM requests WHERE status = "canceled")
FROM request
GROUP BY 1;
Any recommendations on how to get the result efficiently? Thank you very much
You could use case whene on status instead of several subselect
select
MONTHNAME(date)
, sum( case when status = "pending" then 1 else 0 end) pending
, sum( case when status = "attended" then 1 else 0 end) attended
, sum( case when status = "absent" then 1 else 0 end) absent
, sum( case when status = "canceled" then 1 else 0 end) canceled
FROM request
GROUP BY MONTHNAME(date) ;
I have a table which looks something like the following...
id price condition sell
21039 20.40 new 0
21039 20.41 used 1
12378 10.40 new 1
12378 5 used 0
45898 30.30 new 1
45898 12.20 used 0
(note: there will only ever be 1 new and used value for each id)
What I am trying to do is group all rows with the same id number but in the process creating new columns for each condition, which should look something like...
id new_price new_sell used_price new_sell
21039 20.40 0 20.41 1
12378 10.40 1 5 0
45898 30.30 1 12.20 0
All that I have come up with is the following query, which looks silly
SELECT id, price, condition,
IF(price > 3, 1, 0) AS sell
FROM products
GROUP BY id
How can I get the desired affect of the 2nd table.
This is known as a pivot table. It is done with a series of CASE statements for each column you need to produce, along with an aggregate MAX() or SUM() to eliminate NULLs and collapse it down to a single row.
SELECT
id,
SUM(CASE WHEN `condition` = 'new' THEN price ELSE 0 END) AS new_price,
SUM(CASE WHEN `condition` = 'new' THEN sell ELSE 0 END) AS new_sell,
SUM(CASE WHEN `condition` = 'used' THEN price ELSE 0 END) AS used_price,
SUM(CASE WHEN `condition` = 'used' THEN sell ELSE 0 END) AS used_sell
FROM
products
GROUP BY id
Without the SUM() and GROUP BY, you would still get 2 rows per id, with each having half its columns (not matched by condition in the CASE) as NULL. The SUM() (could also use MAX() in this case) eliminates the NULLs and produces one row since aggregate functions exclude NULL values while the GROUP BY groups the rows by id.
Here is a working sample on SQLFiddle.com
Update after comment:
To calculate sell based on the price, just replace the condition in the sell CASE statements:
SELECT
id,
SUM(CASE WHEN `condition` = 'new' THEN price ELSE 0 END) AS new_price,
SUM(CASE WHEN `condition` = 'new' AND price > 3 THEN 1 ELSE 0 END) AS new_sell,
SUM(CASE WHEN `condition` = 'used' THEN price ELSE 0 END) AS used_price,
SUM(CASE WHEN `condition` = 'used' AND price > 3 THEN 1 ELSE 0 END) AS used_sell
FROM
products
GROUP BY id
(Updated sample...)
Hi I am trying to display COUNT result in horizontal way but to no success. Is there any easyway to do this?
I have this table (created in excel for demo purposes)
Now I want to display the result like this.
Any advise will be greatly appreciated.
SELECT store_name,
SUM(CASE WHEN status = 'hold' THEN 1 ELSE 0 END) AS hold_count,
SUM(CASE WHEN status = 'ship' THEN 1 ELSE 0 END) AS ship_count,
SUM(CASE WHEN status = 'return' THEN 1 ELSE 0 END) AS return_count
FROM table
group by store_name
Use if clause inside sum-aggregate.
select store_name,
sum(if(status='hold', 1, 0)) as 'hold',
sum(if(status='ship', 1, 0)) as 'ship',
sum(if(status='return', 1, 0)) as 'return'
from mytable
group by store_name;
I have a table
id, location, status
1, london, 1
2, london, 0
3, boston, 1
4, boston, 1
I'd like my query to generate something like this: -
location, status_1, status_0
london, 1, 1
boston, 2, 0
so far I have: -
select count(id) as freq, location from my_table
group by location order by freq desc;
I'm completely lost as to where to go from here.
That sort of transformation is better done in whatever client is issuing the query, but if you have to do it in the database, then
select location,
sum(status = 1) AS status_1,
sum(status = 0) AS status_0
from my_table
group by location
it's a bit hackish, but the 'status = 1' when status really is 1 will evaluate to a boolean true, which MySQL will politely cast to an integer '1', which then gets summed up. Same goes for when status is 0 and status = 0 evaluates to true.
So you want to count the records for each status per city?
In the query below, I group by location (like your did), and then add a sum for each state. Inside the sum is a case, that either returns 1 if the record matches the desired state, or 0 otherwise. That way, you effectively count the number of records for each state per location.
select
a.location,
sum(case when a.status = 1 then 1 else 0 end) as status_1,
sum(case when a.status = 0 then 1 else 0 end) as status_0
from
YourTable a
group by
a.location
select location,
sum(case when status = 1 then 1 else 0 end) as status_1,
sum(case when status = 0 then 1 else 0 end) as status_0,
from my_table
group by location;
I have a table named 'sales' with following fields
salesid (type: int)
stime (type: datetime)
status (type: enum, values: remaining OR cancelled OR done)
... and other fields
I need a query that can output as
SalesDate TotalSales TotalDone TotalRemaining TotalCancelled
2010-11-06 10 5 3 2
2010-11-06 15 14 1 0
Anyone know how to achieve this?
Help appreciated, thanks.
You can use conditional summation to get the results you want.
select stime as sales_date
,sum(1) as total_sales
,sum(case when status = 'remaining' then 1 else 0 end) as total_done
,sum(case when status = 'cancelled' then 1 else 0 end) as total_remaining
,sum(case when status = 'done' then 1 else 0 end) as total_cancelled
from sales
group by stime;
You can also use COUNT(expr) and exploit the fact it doesn't include NULLS, but personally I find that the above best conveys the intent of the developer.
Use a CASE statement in your SELECT to create pseudo columns using the status values of remaining, cancelled and done
SELECT
date(stime),
COUNT(salesid),
SUM(CASE status WHEN 'done' THEN 1 ELSE 0 END) as TotalDone,
SUM(CASE status WHEN 'remaining' THEN 1 ELSE 0 END) as TotalRemaining,
SUM(CASE status WHEN 'cancelled' THEN 1 ELSE 0 END) as TotalCancelled
FROM sales
GROUP BY date(stime)
Note: This is what i was trying to refer to. I think this should work but i have no access to MySQL to try out the syntax and verify it. Sorry about that. But this should get you going.