Hi i am totally confused with a date logic in my mysql query for a cron job to be run everyday at 12:00 AM
I am working on a auto listing website where the car listings are having a expiry date in mysql datetime format.
All the expired listings will be deleted from the website after 7 days from the datetime of the expiry
When the cron job will run it has do following things
Task 1 - Send an email alert to the users telling them that their listing has expired.
So I need to select all those listings which have expired since last time the cron job has been run and not include listings before that in order to send the expiry alert email only once per listing.
I tried following sql query for this task (Again confused with this as well)
SELECT car_id FROM cars WHERE expiry_date > DATE_SUB(NOW(), INTERVAL 1 DAY) AND expiry_date < NOW()
Task 2 - Will send an email alert to users telling them that listing is going to be permanently deleted after 24 hours.
So I need to select all those listings which are going to be deleted in more than 24 hours / 6 days have passed since they were expired and i need to make sure that they get minimum 24 hours time to renew them. Also i need to select / build the sql query in such a way that only those listings get selected which are going to expiry in 1 days and not other in order to avoid multiple email alerts instead of one time email alert
I tried following sql query for this task (I am totally confused with this query)
SELECT car_id FROM cars WHERE expiry_date > DATE_SUB(NOW(), INTERVAL 7 DAY) AND expiry_date < DATE_SUB(NOW(), INTERVAL 1 DAY)
Task 3 - Delete all the listings which were expired more than 7 days ago
I tried following sql query for this task
SELECT car_id FROM cars WHERE expiry_date < DATE_SUB(NOW(), INTERVAL 7 DAY)
Please help me in perfecting all the 3 queries so that the cron does it job exactly as i want. Also please let me where it has to >= (greater than or equal to) or <= (less than or equal to)
Here is the sqlfiddle table structure and couple of records (though they are not expired yet)
http://sqlfiddle.com/#!2/cfcdf
I will really appreciate the help.
Is this what you are looking for? Please try to add another column to see the differnce between expiry_date and current date time for you to get a better idea of the dates you are dealing with. Please look into some dates functions in MYSQL.
SQLFIDDLE DEMO
-- 3rd query expiry dates older than 7 days from
-- today
SELECT car_id, expiry_Date,
DATE_sub(NOW(), INTERVAL 7 DAY)
FROM cars
WHERE expiry_date <=
DATE_sub(NOW(), INTERVAL 7 DAY)
;
-- same
SELECT car_id, expiry_Date,
DATE_ADD(NOW(), INTERVAL -7 DAY)
FROM cars
WHERE expiry_date <=
DATE_ADD(NOW(), INTERVAL -7 DAY)
;
-- 2nd query going to expire in exactly 1 day
SELECT car_id, expiry_date,
Now() + interval 1 day
FROM cars
WHERE expiry_Date = Now() + interval 1 day
;
-- 1st query: expired
SELECT car_id FROM cars
WHERE expiry_date < Now()
;
-- 1st query: expired last 24 hours
SELECT car_id,DATEDIFF(expiry_date, Now())
FROM cars
WHERE expiry_Date < Now()
AND expiry_Date >= Now() - interval 1 day
;
Check out these queries
select * from cars where datediff(EXPIRY_DATE,now())=-1;
select * from cars where
datediff(DATE_ADD(EXPIRY_DATE, interval 24 hour),now())>=1 and
datediff(DATE_ADD(EXPIRY_DATE, interval 24 hour),now()) <=2;
select * from cars where datediff(expiry_date,now())<=-7;
ope they are working according to your need.
fiddle http://sqlfiddle.com/#!2/785ea/5
There is nothing significantly wrong with your queries, if you do not understand the functions that you have used then google them and read about them until you do.
There is a fundamental problem in your approach in that it relies on the cron job being run at exactly 24 hour intevals - to the milisecond - or there will be double ups and/or omissions.
You need another table to store details of when your batch program last ran; intitialise this with 1 row with a date a long time in the past so that we have a starting point.
You can get the most recent batch by SELECT MAX(date_ran) FROM BatchRecordTables. Store this in a local variable T0. Get the current time, store this in a local variable T1 (Do not use NOW() in multiple queries as they will be slightly differant times and you need them to be the same). I do not know the syntax for this is MySQL - you will have to look it up.
Your situations then become.
Send email to people whose listings have expired since that last time the cron job was run i.e. SELECT car_id FROM cars WHERE Expiry_Date BETWEEN T0 AND T1. This will only select people whoose listings have expired between this batch and the previous one.
For the second case, we need to know that these people have got the first email i.e. that their listing had expired before the last batch run so SELECT car_id FROM cars WHERE Expiry_Date BETWEEN DATE_SUB(T1, INTERVAL 6 DAY) AND T0. This will only select people whoose listings expired before the last batch (i.e. they got the exprired email) and more than 6 days ago.
Same logi applies - we want to know they got the second email. SELECT car_id FROM cars WHERE Expiry_Date BETWEEN DATE_SUB(T1, INTERVAL 7 DAY) AND DATE_SUB(T0, INTERVAL 6 DAY)
May I also suggest that you do not permenantly delete the listings but either copy them to a DeletedListings table or Flag them with a Deleted column - each has its own pros and cons. In the information age, never throw data away - you never know when it might be valuable.
Related
I try to developp a cron task (PHP-MYSQL) that will be executed every 10 minutes to send an email only on the results of my query.
On this script, i would like to select the rows created 1 hour ago. I have a datetime field which contains the creation date.
How to select rows created 1 hour ago ? (without to take care of minutes and seconds)
I tried this code below but it returns me all the rows older than 1 hour, which is not what i need
SELECT email FROM clients WHERE (date_creation < DATE_SUB(NOW(), INTERVAL 1 HOUR))
You can use this query.
SELECT email FROM clients WHERE date_creation >= DATE_SUB(NOW(), INTERVAL 1 HOUR);
it will give you all records created in hour.
In my database I have a table containing some business offers. One of the columns is expire, which contains the date a certain offer expires.
I want to select all offers which expire in 10 days. Here is my code:
SELECT * FROM offers WHERE TIME_ADD(NOW(), INTERVAL 10 DAYS) = expire;
I want to select all columns from offers, where the expiry date is equal date now plus 10 days (so they expire in 10 days). MySQL doesn't let me do that, it marks "=expire" as an error
Syntax error unexpected 'expire' (expire).
Why is that? ( I'm working on MySQL workbench btw)
If you want to find all offers that expire in 10 days, but you're not concerned as to what time in 10 days that they expire, then you can use the following:
SELECT *
FROM offers
WHERE DATE(expire) = DATE_ADD(CURRENT_DATE(), INTERVAL 10 DAYS);
If however you want to find all offers that expire in 10 days, to the exact second, then you can use the following instead:
SELECT *
FROM offers
WHERE expire = DATE_ADD(NOW(), INTERVAL 10 DAYS);
Notice how the first query uses CURRENT_DATE(), which will return only a date value - 2018-08-03. Whereas the second query uses NOW(), which will return a datetime value - 2018-08-03 08:29:00.
replace INTERVAL 10 DAYS with INTERVAL 10 DAY
I have a report that is driven by a sql query that looks like this:
SELECT batch_log.userid,
batches.operation_id,
SUM(TIME_TO_SEC(ramses.batch_log.time_elapsed)),
SUM(ramses.tasks.estimated_nonrecurring + ramses.tasks.estimated_recurring),
DATE(start_time)
FROM batch_log
JOIN batches ON batch_log.batch_id=batches.id
JOIN ramses.tasks ON ramses.batch_log.batch_id=ramses.tasks.batch_id
JOIN protocase.tblusers on ramses.batch_log.userid = protocase.tblusers.userid
WHERE DATE(ramses.batch_log.start_time) > "2011-02-01"
AND ramses.batch_log.time_elapsed > "00:03:00"
AND DATE(ramses.batch_log.start_time) < now()
AND protocase.tblusers.active = 1
AND protocase.tblusers.userid NOT in ("ksnow","smanning", "dstapleton")
GROUP BY userid, batches.operation_id, date(start_time)
ORDER BY start_time, userid ASC
Since this is to be compared with the time from the current payperiod it causes an error.
Our pay periods start on a Sunday, the first pay period was 2011-02-01 and our last pay period started the 4th of this month. How do I put that into my where statement to strip the most recent pay period out of the query?
EDIT: So now I'm using date_sub(now(), INTERVAL 2 WEEK) but I really need a particular day of the week(SUNDAY) since it is wednesday it's chopping it off at wednesday.
You want to use DATE_SUB, and as an example.
Specifically:
select DATE_SUB(curdate(), INTERVAL 2 WEEK)
gets you two weeks ago. Insert the DATE_SUB ... part into your sql and you're good to go.
Edit per your comment:
Check out DAYOFWEEK:
and you can do something along the lines of:
DATE_SUB(DATE_SUB(curdate(), INTERVAL 2 WEEK), INTERVAL 2 + DAYOFWEEK(curdate()) DAY)
(I don't have a MySql instance to test it on .. but essentially subtract the number of days after Monday.)
Question isn't quite clear, especially after the edit - it isn't clear now is the "pay period" two weeks long or do you want just last two weeks back from last sunday? I assume that the period is two weeks... then you first need to know how many days the latest period (which you want to ignore, as it isn't over yet) has been going on. To get that number of days you can use expression like
DATEDIFF(today, FirstPeriod) % 14
where FirstPeriod is 2011-02-01. And now you strip that number of days from the current date in the query using date_sub(). The exact expression depends on how the period is defined but you should get the idea...
I can normally do this but it appears my brain is not functioning well right now and I'm missing something.
Every day via a cron job that is run at 1am, I want to get a count of rows that were inserted yesterday, and the date.
ie
SELECT DATE(added) as date, COUNT(*) FROM bookings WHERE added = DATE_SUB(NOW(), INTERVAL 1 DAY) GROUP BY date
'added' contains a timestamp ie '2011-04-18 12:31:31'
What am I getting wrong here? I know there are many rows added yesterday but my query is returning 0 results and no mysql_errors :(
Any ideas?
Please try
SELECT DATE(added) as yesterday, COUNT(*) FROM bookings WHERE DATE(added) = DATE(DATE_SUB(NOW(), INTERVAL 1 DAY)) GROUP BY yesterday
or perhaps
SELECT DATE(added) as yesterday, COUNT(*) FROM bookings WHERE DATE(added) = DATE_SUB(CURDATE(), INTERVAL 1 DAY) GROUP BY yesterday
Updated
Corrected the WHERE part.
well whatever NOW() is will return the time portion and unless they were added at exactly that time the day before they wont be counted.
So either use BETWEEN and specify time range, or format the date in your query to only match on the day month year components and not time
WHERE added = does only match exact NOW() - 1 DAY, you should select by a range instead.
I have a table where it stores the users.
And i want a query to find the users which are between eg 25 years old and 31 years old.
The age is stored at the mysql table as date (it stores the birthday).
(eg: 1980-02-25 (yyyy-mm-dd))
How the query should be written in order to find each time the people who are between two given ages?
Thanks.
You can either compute the necessary date range in your backend code, or in MySQL itself. Should you choose MySQL, here's what the query might look like:
SELECT user.* FROM user
WHERE birthdate >= DATE_SUB(NOW(), INTERVAL 31 YEAR)
AND birthdate <= DATE_SUB(NOW(), INTERVAL 25 YEAR)
There is also the somewhat shorter BETWEEN clause for MySQL. I'd recommend CURDATE() instead of NOW() because it does not have the time component.
SELECT * FROM user
WHERE birthdate
BETWEEN
(CURDATE() - INTERVAL 31 YEAR)
AND
(CURDATE() - INTERVAL 25 YEAR)
Note: it's inclusive.