My table is looking as folowing:
unix_timestap ID value
1351058019 1 500
1351058029 1 505
1351058039 9 105
1351058049 9 200
1351076620 1 520
I would like be able to generate a new column contain the differences between the values per ID between the current value and the first available "past" value. With past I mean that unixtimestamp is not placed in order in the original table.
The output would be:
unix_timestap ID value difference
1351058019 1 500 0
1351058029 1 505 5
1351058039 9 105 0
1351058049 9 200 95
1351076620 1 520 15
If no previous unix_timestamp exists, the value should be zero.
A Hint/tip would be much appreciated.
Thanks
if solution still needed
select
t3.unix_timestamp, t3.id, t3.value, ifnull(t3.value - t5.value, 0) as diff
from test1 t3
join (
SELECT t1.unix_timestamp, t1.id, max(t2.unix_timestamp) as old_stamp
FROM `test1` t1
left join test1 t2 on t1.id = t2.id and t1.unix_timestamp > t2.unix_timestamp
group by t1.unix_timestamp, t1.id) as t4
on t3.unix_timestamp = t4.unix_timestamp and t3.id = t4.id
left join test1 t5 on t4.old_stamp = t5.unix_timestamp and t4.id = t5.id
Related
I am having two tables, t1, t2. My tables and expected result are given below.
My table schema is in sqlfiddle
t1:
id branch_name
1 branch1
2 branch2
3 branch3
4 branch4
5 branch5
t2:
id VBRNCH VTOBRN vqty
1 1 0 10
2 2 0 20
3 3 0 30
4 0 4 40
5 0 5 50
Expected Result is:
branch_name send received
1 10 0
2 20 0
3 30 0
4 0 40
5 0 50
What i have tried is:
SELECT
b1.branch_name,
i1.vqty AS send,
i2.vqty AS received
FROM t2 i1
INNER
JOIN t1 b1
ON b1.id = i1.VBRNCH
INNER JOIN t2 i2
ON b1.id = i2.VTOBRN
GROUP
BY i1.VTOBRN,
i2.VBRNCH;
But I am getting zero rows.
I think this is the query you are looking for:
SELECT t1.branch_name,
COALESCE(SUM(send.vqty), 0) AS send,
COALESCE(SUM(receive.vqty), 0) AS received
FROM t1
LEFT JOIN t2 AS send on t1.id = send.VBRNCH
LEFT JOIN t2 AS receive on t1.id = receive.VTOBRN
GROUP BY t1.branch_name
Demo here
E.g.
SELECT x.*
, COALESCE(sent,0) sent
, COALESCE(received,0) received
FROM t1 x
LEFT
JOIN
( SELECT from_br
, SUM(vqty) sent
FROM t2
GROUP
BY from_br
) a
ON a.from_br = x.id
LEFT
JOIN
( SELECT to_br
, SUM(vqty) received
FROM t2
GROUP
BY to_br
) b
ON b.to_br = x.id
ORDER
BY id;
http://sqlfiddle.com/#!9/af0973/21
I need to get all the records where table1.user is in table2.userid and table2.country = 8 and table2.status = 1
This is the sample data in my database
table1
id user
-- ----
1 12
2 23
3 34
4 32
5 85
6 38
table2
id userid country_id status
-- ---- ----- ----
1 12 5 1
2 12 8 1
3 85 8 1
4 38 8 0
5 38 7 1
6 23 8 1
7 23 4 1
in this case I should only get the id #3 in table2
Inner join will do the job taking only record with match in the two tables.
SELECT *
FROM table1 t1
INNER JOIN table2 t2 on t1.user = t2.userid
WHERE t2.country=8 and t2.status=1
You mean
"get all the records where table1.user is in table2.userid
with table2.country = 8 and table2.status = 1 ?"
If so, then:
Select * from table1 t1
Where Exists(Select * from table2
Where userId = t1.user
and country = 8
and status = 1)
Well to accomplish that is quite simple, you just need to make use of an inner join. An SQL JOIN clause is used to combine rows from two or more tables, based on a common field between them.
In your case, the INNER JOIN will return all rows from table2 where the join condition is met.
For a more detailed explanation and examples just visit this link: http://www.w3schools.com/sql/sql_join.asp
based on your response to Adam's approach "
I tried this but it didn't work, yes it gets the records but the id #2 in table2 is also included. what I need to get is the id #3 in table2. Thanks :) ". I changed my SQL query to:
SELECT
*
FROM
table1
INNER JOIN
table2
ON
table1.user = table2.userid
WHERE
table2.userid = 85
I assumed you only want the data of that particular userid in table2
How can i edit the ON operator part of my query below such that i would like the current code to work where id<4 (which is t2.id <= t1.id as shown below) so when t1 id=3, t2 is the cumulative id from id=1 to id=3 (as it is now).
but for id >3 I would like the ON operator to be (t2.id=t1.id>=t1.id-2 and <=t1.id) so when t1 id=4, t2.id should be between 2 and 4 inclusive. when t1 id =5, t2.id should be between 3 and 5 inclusive and so on.
I'm doing this because when i calculate col E for ids after id=3, i am only interested in getting the average of the previous 2 rows for C and D on a moving average.
Iam translating my excel formula into SQL so i know what is the correct values for col E.
My query has 2 sub queries and it updates column E. The table and correct data in EXCEL looks like this:
id A B C D E
1 NULL NULL NULL NULL NULL
2 4 6 1 1 1
3 6 9 1.2 1.2 1.2
4 8 7 1.33 0.954 1.143
5 10 5 1.25 0.714 0.982
6 12 2 1.2 0.428 0.814
http://www.sqlfiddle.com/#!2/17a0ad/1
EXCEL formulas (notice that the formulas change after id=3 to a moving average):
id C D E
2 =A2/AVERAGE(A1:A2) =B2/AVERAGE(B1:B2) =(C2+D2)/2
3 =A3/AVERAGE(A1:A3) =B3/AVERAGE(B1:B3) =(C3+D3)/2
4 =A4/AVERAGE(A2:A4) =B4/AVERAGE(B2:B4) =(C4+D4)/2
5 =A5/AVERAGE(A3:A5) =B5/AVERAGE(B3:B5) =(C5+D5)/2
6 =A6/AVERAGE(A4:A6) =B6/AVERAGE(B4:B6) =(C6+D6)/2
Here is my SQL query:
Update followers join
(
SELECT t1.id ,ifnull(t1.A/AVG(t2.A),null) C ,ifnull(t1.B/AVG(t2.B),null) D
FROM followers t1
JOIN followers t2
ON
case when t2.id < 4 then t2.id <= t1.id else t2.id<= t1.id and t2.id>=t1.id-2 end
group by t1.id
) AS tt on(followers.id = tt.id)
SET E = (tt.C + tt.D)/2;
Although this query works, the numbers that i want for col E are not exactly correct. They are correct only for id<=4 but not for id=5 or id=6 in col E.
I believe my syntax for CASE by the ON operator might be wrong.
I ran this query in sql fiddle and got this result:
ID A B E
1(null)(null)(null)
2 4 6 1
3 6 9 1.2
4 8 7 1.14
5 10 5 1.08
6 12 2 0.92
As we can see, the excel and sql output are different.
Thanks,
I think the query that you want is a very slight modification:
Update followers join
(SELECT t1.id, ifnull(t1.A/AVG(t2.A),null) as C, ifnull(t1.B/AVG(t2.B),null) as D
FROM followers t1 JOIN
followers t2
ON (case when t1.id < 4 then t2.id <= t1.id
----------------------------^
else t2.id<= t1.id and t2.id>=t1.id-2
end)
group by t1.id
) tt
on followers.id = tt.id
SET E = (tt.C + tt.D)/2;
You can express the on using basic boolean logic as:
on t2.id <= t1.id and (t1.id < 4 or t2.id >= t1.id - 2)
How can i edit the ON operator part of my query below such that i would like the current code to work where id<=14 (which is t2.id <= t1.id as shown below) so when t1 id =14, t2 is the cumulative id from 1 to 14 (as it is now).
but for id >14 I would like the ON operator to be (t2.id=t1.id>=t1.id-2 and <=t1.id) so when t1 id=15, t2.id should be between 13 and 15. when t1 id =16, t2.id should be between 14 and 16 and so on.
I'm doing this because when i calculate col E for ids after id=14, i am only interested in getting the average of the previous 2 rows for C and D on a moving average.
My query has 2 sub queries and it updates column E. The table looks like this:
--------------------------
id | A | B | E |
--------------------------
1 | NULL | NULL |NULL|
--------------------------
2 | 4 | 6 |NULL|
--------------------------
3 | 6 | 9 |NULL|
--------------------------
This is my query where i got help from this link: Mysql Nested sub queries unknown column error
Update t join
(SELECT t1.id ,ifnull(t1.A/AVG(t2.A),0) C ,ifnull(t1.B/AVG(t2.B),0) D
FROM t t1
JOIN t t2
ON t2.id <= t1.id
group by t1.id ) AS tt
on(t.id = tt.id)
SET E = (tt.C + tt.D)/2;
Thanks,
where id<=14 (which is t2.id <= t1.id as shown below) so when t1 id =14, t2 is the cumulative id from 1 to 14 (as it is now).
Update t join
(
SELECT t1.id ,ifnull(t1.A/AVG(t2.A),0) C ,ifnull(t1.B/AVG(t2.B),0) D
FROM t t1
JOIN t t2
ON case when t2.id < 15 then t2.id <= t1.id else t2.id=t1.id>=t1.id-2 and <=t1.id end
group by t1.id
) tt on(t.id = tt.id)
SET E = (tt.C + tt.D)/2;
I have a table like this and type is innodb and id and sid are indexed.
id | sid
##########
1 | 100
1 | 101
1 | 102
1 | 103
1 | 104
1 | 105
2 | 100
2 | 101
3 | 100
3 | 101
I need id's have sid 100,...105 like id=1.
I have this query
select t1.id
from test as t1, test as t2, test as t3,
test as t4, test as t5, test as t6
where t1.sid=100
and t2.sid=101
and t3.sid=102
and t4.sid=103
and t5.sid=104
and t6.sid=105
and t1.id = t2.id = t3.id = t4.id = t5.id = t6.id
but phpmyadmin hangs when I run query.
The number of records is 2000.
What is optimized query?
It is surprising that the SQL statement shown compiles/runs.
However, you can probably rescue it by rewriting what is currently the last line to:
select t1.id
from test as t1, test as t2, test as t3,
test as t4, test as t5, test as t6
where t1.sid = 100
and t2.sid = 101
and t3.sid = 102
and t4.sid = 103
and t5.sid = 104
and t6.sid = 105
and t1.id = t2.id
and t1.id = t3.id
and t1.id = t4.id
and t1.id = t5.id
and t1.id = t6.id;
Is this query optimal?
Given your comment to Maulik Vora's answer that the range { 100 .. 105 } is just an example, then we need to know whether it is always 6 values or whether it could be 5 or 7 or some other number. However, it is likely that the optimal structure uses a temporary table (call it ListToMatch with a non-null unique column SID) containing whatever values are needed, and that the query is:
SELECT T.ID
FROM Test AS T JOIN ListToMatch AS L ON T.SID = L.SID
GROUP BY T.ID
HAVING COUNT(*) = (SELECT COUNT(*) FROM ListToMatch);
You insert the set of values you're interested in to ListToMatch; you can then get the list of ID values that match. This is likely to be more nearly optimal, not least because it adapts to 1 value and 100 values as easily as it does to 6, whereas rewriting the SQL with a 100-way self-join doesn't bear much thinking about.
select t2.id from (select id, max(sid) as mxsid, min(sid) as mnsid from test
group by id having count(id) = 6) as t2
where t2.mxsid = 105 and t2.mnsid = 100