I have a table with a column that has CSV.
TableA:
field_id | matches
---------------------
1 1,2,4,6,8,11,14,56
Now I need to get the field_id that matches a user given csv. So for instance, user string is 1,4,11, then it should return some value may be just true.
1.) Find_in_set does not work. Because it takes only one element and searches that in a SET/CSV column.
2.) Cannot use like concat('%,', user_input , ',%'). Because user input may not be in order.
Any other ideas? I guess this is a very common scenario.
Note: I dont need to search all records. I need to search a specific record. So in the above table, I just need to search one record that has field_id = 1. i.e. (where field_id = 1). (May not matter, but just an info)
Well, this is a good argument for having data in a proper relational form. But, you can try:
select t.*
from t
where (find_in_set($user_input, 1) = 0 or
find_in_set(substring_index(substring_index($user_input, ',', find_in_set($user_input, 1)), ',', -1), matches) > 0) and
(find_in_set($user_input, 2) = 0 or
find_in_set(substring_index(substring_index($user_input, ',', find_in_set($user_input, 2)), ',', -1), matches) > 0) and
. . .
Do this for however many values you might have in the userinput set.
I presume there is no straight solution with MySQL query like Find_In_Set. So I guess I will have to handle this with multiple queries or with Looping.
Related
In my database table, Due to some mistake same row has been entered twice, But it is now having one column value with some appended numeric value in the duplicate entry.
For example,
If my table has a column named filename, Then in one row it has value 'some-random-name.pdf'.
And in the duplicate row, it has value 'some-random-name-1532.pdf'.
I need to identify all such records. Please note that there can be any or zero number of dash(-) in the filename. So Like query something like '%-____-%.pdf did not help me.
Assuming that complete filename contains only one dot between name and extension you may try this:
WHERE SUBSTRING_INDEX(t1.value, '.', -1) = SUBSTRING_INDEX(t2.value, '.', -1)
AND LOCATE(SUBSTRING_INDEX(t1.value, '.', 1), SUBSTRING_INDEX(t2.value, '.', 1)) = 1
I have data stored in a comma-separated format and I would like to run a query so that the users are ordered by the second value in the column.
So for this sample data:
user | Data
________________________________________
player1 | 45471,2529,32196008193896,99
admin | 1136,2595,17760808279311,95
gamer | 13495,2432,32196008193896,98
________________________________________
The order would be (2595-2529-2432) which is admin => player1 => gamer.
As I mentioned in the comments, you should really try to avoid storing delimited lists like that.
However, you can write a query to parse out the second value by using the SUBSTRING_INDEX() function. This function takes a string, the delimiter character, and an integer whether or not to take from the left/right of the delimiter and for how many. In other words, to get everything left of the second comma, it would look like this:
SELECT SUBSTRING_INDEX(data, ',', 2)
FROM myTable;
Then, from that string, you want everything to the right of the first comma, so you'll have to nest the functions. (Note, this may hurt efficiency, but that's the downfall of delimited lists):
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(data, ',', 2), ',', -1)
FROM myTable;
Then, you can just order by that value:
SELECT *
FROM myTable
ORDER BY SUBSTRING_INDEX(SUBSTRING_INDEX(data, ',', 2), ',', -1) DESC;
Here is an SQL Fiddle example.
Good Evening Everyone;
I have a table in MySql that I would like to update as follows. Just as an FYI I have searched this topic and have yet to find a solution.
The table name is ALK_Results_NEW in a MySQl database, the data in the ICD9 column contains data seperated by commas.
I need to keep the first set in the ICD9 column so for example the first row has V57.9 , 246.9.
I need to keep the V57.9 in the ICD9 column and move 246.9 into the ICD9_SECONDARY column.
If a row has more than 2 then I need to move all other into the ICD9_OTHER column (This column can have mulitple ICD9 Codes separated by commas)
To summarize the first code needs to stay in the ICD9 column and the second set of codes needs to be moved into the ICD9_SECONDARY. After the data is moved the ICD9 Column should only have the forst set of codes.
Any help would be greatly appreciated.
Assuming the two columns already exist in the table, you can change the data using an update:
update alk_results_new
set icd9_secondary = substr(icd9, instr(icd9, ',') + 1),
icd9 = substring_index(icd9, ',', 1)
where icd9 like '%,%';
EDIT:
Oops, I didn't realize there were three columns. The approach is similar, but a little more complicated because you need to take into account the length of the strings. I think the following should do what you want:
update alk_results_new
set icd9_other = (case when icd9 like '%,%,%'
then substr(icd9, length(substring_index(icd9, ',', 2)) + 2)
end),
icd9_secondary = (case when icd9 like '%,%'
then substring_index(substring_index(icd9, ',', 2), ',', -1)
end),
icd9 = substring_index(icd9, ',', 1);
Note: test the logic out on a select before running the update.
I need to search a string in a mysql field for a substring and return the number to the right of it, if it is the highest number of all the rows returned. (The word will most likely occur many times in the string.)
SELECT max(cast(substring(mq.my_query_string, (locate("near/", mq.my_query_string)+5), 2) as signed)) AS "MaxNearDistance"
FROM my_query mq, my_test mt
WHERE mt.company_id = 123
AND mq.search_query_id = mt.my_query_id
AND locate("near/", mq.my_query_string) > 0;
This works, but it only gives me the highest number of the FIRST substring and among all rows returned. I need the highest number among ALL hits for the substring and among all rows.
Thank you for your help!
I would create a table- numbers- with every number string I want to be able to find ('0' - '99' for you) then join it to my data like:
SELECT
mq.my_query_string, MAX(numbers.ns)
FROM my_query AS mq
JOIN numbers ON CONCAT(mq.my_query_string, ' ') LIKE CONCAT('%near ', numbers.ns, ' %')
GROUP BY mq.my_query_string
I'm CONCATing a space to the data so that '11' won't match '1'.
SQLFiddle here: http://sqlfiddle.com/#!2/8fda1c/4
(Actually, the right way is to normalize your data so you have a table of my_query_nears with one value per row but sometimes we must play the hand we are dealt.)
My table column has rows like this 1001, 1002, 1003 and so on separated by commas. There may be 1 or more comma separated values in each column. I need the total count of these comma separated values in the table. For example if my table has 2 rows one having 1001, 1002, 1003, 1004 and another with 1001, 1005 the output i should get is 6 i.e. 4+2. Kindly assist
there is no function in mysql to count char occurences. but you can replace every comma with nothing. and then you calculate the difference of lenghts which will give you the number of commas, which is one less than the number of values.
select
( LENGTH(col1) - LENGTH(REPLACE(col1, ',', '')) + 1 )
+ ( LENGTH(col2) - LENGTH(REPLACE(col2, ',', '')) + 1 )
AS valCount
from T;
(didn't test that explicitely but at least something very similar to that will do the job.)
replace()
length()
Try:
SELECT SUM(LEN(ColumnName) - LEN(REPLACE(ColumnName, ',', ''))) FROM TableName
This is one of those tasks that'd be much, much easier in the server-side script accessing your database than the database itself. Assuming you've already assigned the comma-separated strings to an array (where $array[1] is equal to the string from row 1:
$array = array("1001, 1002, 1003, 1004", "1001, 1005"); // assigned from database
foreach($array as $k => $v){
$numbersInString[$k] = count(explode(', ', $v));
}
echo implode(' + ',$numbersInString);
This is possible, with creative solutions (such as that from Raffael1984), in MySQL, but seems to much more easily, and concisely, implemented in PHP.
References:
count().
explode().
implode().
foreach().
Did you try using the count() function? You can specify which rows if you need to.
.row[COUNT(name)]
in your query. What does your table look like? I might be able to help more if I know what it looks like