Having trouble with accessing json values formed from php array
var latlag = '<?php echo json_encode($coordinates); ?>';
alert(latlng) produces:
[{
"1280":{"lat":"-1.197070","lng":"-1.197070"},
"1239":{"lat":"-1.222410","lng":"-1.222410"},
"1258":{"lat":"-1.153020","lng":"-1.153020"},
...
}]
I've tried all sorts of ways to access lat and lag for a specific ID and the only result other than undefined has been the nth character of latlng as if its being treated like a string?!
alert(latlng[10]); # {
alert(latlng[1280]['lat]); # undefined
alert(latlng['1280'].lat); # undefined
You don't want to put the JSON in quotes, so:
var latlag = <?php echo json_encode($coordinates); ?>;
(Technically, that's not JSON at all, it's a JavaScript object initializer. But that's fine, JSON is a subset of initializer syntax and so all valid JSON texts are also valid JavaScript initializers.)
If the structure is really as you've quoted it, it's an array with one entry, which is an object with properties with names like 1280 and 1258, whose values are objects with properties named lat and lng. So you'd access those like this:
alert(latlng[0]["1280"].lat);
latlng is the array, latlng[0] is the one object it holds, and latlng[0]["1280"] is the {"lat":"-1.197070","lng":"-1.197070"} object.
You may be wondering why I've used quotes around 1280 above. It's because those keys are clearly given as strings (as is required in JSON, though not in JavaScript initializers), and so I can't be sure there aren't entries like "0012". Property names are always strings even when not written as strings, so latlng[0][1280] and latlng["0"]["1280"] both mean the same thing (because the 0 and the 1280 are converted to string [yes, really]), but naturally latlng[0]["0012"] is not the same as latlng[0][12] because the latter uses "12", not "0012", as the property name. If you know you won't have leading zeros, you can ditch the quotes.
Related
I kind of feel stupid for asking this, but haven't been able to find a way to get the key of a JSON value. I know how to retrieve the key if I have an iterator of the object. I also know of operator[].
In my case the key is not a known value, so can't use get(const char *key) or operator[]. Also can't find a getKey() method.
My JSON looks like this:
{Obj_Array: [{"122":{"Member_Array":["241", "642"]}}]}
For the piece of code to parse {"122":{"Member_Array":["241", "642"]}} I want to use get_key()-like function just to retrieve "122" but seems like I have to use an iterator which to me seems to be overkill.
I might have a fundamental lack of understanding of how jsoncpp is representing a JSON file.
First, what you have won't parse in JsonCPP. Keys must always be enclosed in double quotes:
{"Obj_Array": [{"122":{"Member_Array":["241", "642"]}}]}
Assuming that was just an oversight, if we add whitespace and tag the elements:
{
root-> "Obj_Array" : [
elem0-> {
key0-> "122":
val0-> {
key0.1-> "Member_Array" :
val0.1-> [
elem0.1.0-> "241",
elem0.1.1-> "642" ]
}
}
]
}
Assuming you have managed to read your data into a Json::Value (let's call it root), each of the tagged values can be accessed like this:
elem0 = root[0];
val0 = elem0["122"]
val0_1 = val0["Member_Array"];
elem0_1_0 = val0_1[0];
elem0_1_1 = val0_1[1];
You notice that this only retrieves values; the keys were known a priori. This is not unusual; the keys define the schema of the data; you have to know them to directly access the values.
In your question, you state that this is not an option, because the keys are not known. Applying semantic meaning to unknown keys could be challenging, but you already came to the answer. If you want to get the key values, then you do have to iterate over the elements of the enclosing Json::Value.
So, to get to key0, you need something like this (untested):
elem0_members = elem0.getMemberNames();
key0 = elem0_members[0];
This isn't production quality, by any means, but I hope it points in the right direction.
This is strange, I've used json encoding arrays and the output is something like [{" etc, but in another code this time the output is "{"1":{".. causing multiple errors. I don't understand what is going on.
this is the part of the code:
$json_arr = json_decode($json_str, true);
$fecha = date("Y-m-d H:i:s");
foreach (array_column($json_arr, 'f') AS $k => $fecha) {
if($fecha < $ahora){
unset($json_arr[$k]);
}
}
$json_str = json_encode($json_arr,true);//this will be inserted in the DB table
but the $json_str is in the form of "{"1":{".. but I need in the form of [{".
Here some of the images when debugging:
in orange, the json_str is readed from the BD table
after decoding, you see the json_arr is an array of three elements
after deleting some row, you see json_arr is still an array
after encoding the json_arr, I get the "{"1":{" format, in other cases of encoding arrays I had the [{" format, which is what I need.
You are starting with an array of 3 arrays, with the indices of 0, 1, and 2.
Then you are deleting the first one. If you compare your 2nd and 3rd screenshots, specifically the popup portion, you'll see that what you have lost is index 0. Your array now starts with index 1.
But in JavaScript, an array can't start with index 1. It has to start with index 0, so PHP is encoding it as an object, instead of an array.
If you use the PHP function array_values() it will re-index your array and you should be good to go.
I want to check if an array of strings occur in a dataset and print those rows where the string array elements occur.
rareTitles = {"Capt", "Col", "Countess", "Don", "Dr", "Jonkheer", "Lady",
"Major", "Mlle", "Mme", "Ms", "Rev", "Sir"}
dataset[rareTitles in (dataset['Title'])]
I am getting following error:
TypeError: unhashable type: 'set'
First of all, I think the comparison should go the other way around - you look for a dataset['Title'], that contains string from rareTitles.
You can use str attribute of a pandas DataSeries, which allows as to use string methods, like contains. As this method accepts also a pattern as a regular expression, you can put as an argument something like 'Capt|Col...'. To join all elements of a set you can use str.join() method.
So the solution would be
dataset[dataset['Title'].str.contains('|'.join(rareTitles))]
Link to documentation: pandas.Series.str.contains
I have a chunk of json that has the following format:
{"page":{"size":7,"number":1,"totalPages":1,"totalElements":7,"resultSetId":null,"duration":0},"content":[{"id":"787edc99-e94f-4132-b596-d04fc56596f9","name":"Verification","attributes":{"ruleExecutionClass":"VerificationRule"},"userTags":[],"links":[{"rel":"self","href":"/endpoint/787edc99-e94f-4132-b596-d04fc56596f9","id":"787edc99-e94f-...
Basically the size attribute (in this case) tells me that there are 7 parts to the content section. How do I convert this chunk of json to an array in Perl, and can I do it using the size attribute? Or is there a simpler way like just using decode_json()?
Here is what I have so far:
my $resources = get_that_json_chunk(); # function returns exactly the json you see, except all 7 resources in the content section
my #decoded_json = #$resources;
foreach my $resource (#decoded_json) {
I've also tried something like this:
my $deserialize = from_json( $resources );
my #decoded_json = (#{$deserialize});
I want to iterate over the array and handle the data. I've tried a few different ways because I read a little about array refs, but I keep getting "Not an ARRAY reference" errors and "Can't use string ("{"page":{"size":7,"number":1,"to"...) as an ARRAY ref while "strict refs" in use"
Thank you to Matt Jacob:
my $deserialized = decode_json($resources);
print "$_->{id}\n" for #{$deserialized->{content}};
I am confused about accessing the contents of some JSON data that I have decoded. Here is an example
I don't understand why this solution works and my own does not. My questions are rephrased below
my $json_raw = getJSON();
my $content = decode_json($json_raw);
print Data::Dumper($content);
At this point my JSON data has been transformed into this
$VAR1 = { 'items' => [ 1, 2, 3, 4 ] };
My guess tells me that, once decoded, the object will be a hash with one element that has the key items and an array reference as the value.
$content{'items'}[0]
where $content{'items'} would obtain the array reference, and the outer $...[0] would access the first element in the array and interpret it as a scalar. However this does not work. I get an error message use of uninitialized value [...]
However, the following does work:
$content->{items}[0]
where $content->{items} yields the array reference and [0] accesses the first element of that array.
Questions
Why does $content{'items'} not return an array reference? I even tried #{content{'items'}}, thinking that, once I got the value from content{'items'}, it would need to be interpreted as an array. But still, I receive the uninitialized array reference.
How can I access the array reference without using the arrow operator?
Beginner's answer to beginner :) Sure not as profesional as should be, but maybe helps you.
use strict; #use this all times
use warnings; #this too - helps a lot!
use JSON;
my $json_str = ' { "items" : [ 1, 2, 3, 4 ] } ';
my $content = decode_json($json_str);
You wrote:
My guess tells me that, once decoded, the object will be a hash with
one element that has the key items and an array reference as the value.
Yes, it is a hash, but the the decode_json returns a reference, in this case, the reference to hash. (from the docs)
expects an UTF-8 (binary) string and tries to parse that
as an UTF-8 encoded JSON text,
returning the resulting reference.
In the line
my $content = decode_json($json_str);
you assigning to an SCALAR variable (not to hash).
Because you know: it is a reference, you can do the next:
printf "reftype:%s\n", ref($content);
#print: reftype:HASH ^
#therefore the +------- is a SCALAR value containing a reference to hash
It is a hashref - you can dump all keys
print "key: $_\n" for keys %{$content}; #or in short %$content
#prints: key: items
also you can assing the value of the "items" (arrayref) to an scalar variable
my $aref = $content->{items}; #$hashref->{key}
#or
#my $aref = ${$content}{items}; #$hash{key}
but NOT
#my $aref = $content{items}; #throws error if "use strict;"
#Global symbol "%content" requires explicit package name at script.pl line 20.
The $content{item} is requesting a value from the hash %content and you never defined/assigned such variable. the $content is an scalar variable not hash variable %content.
{
#in perl 5.20 you can also
use 5.020;
use experimental 'postderef';
print "key-postderef: $_\n" for keys $content->%*;
}
Now step deeper - to the arrayref - again you can print out the reference type
printf "reftype:%s\n", ref($aref);
#reftype:ARRAY
print all elements of array
print "arr-item: $_\n" for #{$aref};
but again NOT
#print "$_\n" for #aref;
#dies: Global symbol "#aref" requires explicit package name at script.pl line 37.
{
#in perl 5.20 you can also
use 5.020;
use experimental 'postderef';
print "aref-postderef: $_\n" for $aref->#*;
}
Here is an simple rule:
my #arr; #array variable
my $arr_ref = \#arr; #scalar - containing a reference to #arr
#{$arr_ref} is the same as #arr
^^^^^^^^^^ - array reference in curly brackets
If you have an $arrayref - use the #{$array_ref} everywhere you want use the array.
my %hash; #hash variable
my $hash_ref = \%hash; #scalar - containing a reference to %hash
%{$hash_ref} is the same as %hash
^^^^^^^^^^^ - hash reference in curly brackets
If you have an $hash_ref - use the %{$hash_ref} everywhere you want use the hash.
For the whole structure, the following
say $content->{items}->[0];
say $content->{items}[0];
say ${$content}{items}->[0];
say ${$content}{items}[0];
say ${$content->{items}}[0];
say ${${$content}{items}}[0];
prints the same value 1.
$content is a hash reference, so you always need to use an arrow to access its contents. $content{items} would refer to a %content hash, which you don't have. That's where you're getting that "use of uninitialized value" error from.
I actually asked a similar question here
The answer:
In Perl, a function can only really return a scalar or a list.
Since hashes can be initialized or assigned from lists (e.g. %foo = (a => 1, b => 2)), I guess you're asking why json_decode returns something like { a => 1, b => 2 } (a reference to an anonymous hash) rather than (a => 1, b => 2) (a list that can be copied into a hash).
I can think of a few good reasons for this:
in Perl, an array or hash always contains scalars. So in something like { "a": { "b": 3 } }, the { "b": 3 } part has to be a scalar; and for consistency, it makes sense for the whole thing to be a scalar in the same way.
if the hash is quite large (many keys at top-level), it's pointless and expensive to iterate over all the elements to convert it into a list, and then build a new hash from that list.
in JSON, the top-level element can be either an object (= Perl hash) or an array (= Perl array). If json_decode returned a list in the former case, it's not clear what it would return in the latter case. After decoding the JSON string, how could you examine the result to know what to do with it? (And it wouldn't be safe to write %foo = json_decode(...) unless you already knew that you had a hash.) So json_decode's behavior works better for any general-purpose library code that has to use it without already knowing very much about the data it's working with.
I have to wonder exactly what you passed as an array to json_decode, because my results differ from yours.
#!/usr/bin/perl
use JSON qw (decode_json);
use Data::Dumper;
my $json = '["1", "2", "3", "4"]';
my $fromJSON = decode_json($json);
print Dumper($fromJSON);
The result is $VAR1 = [ '1', '2', '3', '4' ];
Which is an array ref, where your result is a hash ref
So did you pass in a hash with element items which was a reference to an array?
In my example you would get the array by doing
my #array = #{ $fromJSON };
In yours
my #array = #{ $content->{'items'} }
I don't understand why you dislike the arrow operator so much!
The decode_json function from the JSON module will always return a data reference.
Suppose you have a Perl program like this
use strict;
use warnings;
use JSON;
my $json_data = '{ "items": [ 1, 2, 3, 4 ] }';
my $content = decode_json($json_data);
use Data::Dump;
dd $content;
which outputs this text
{ items => [1 .. 4] }
showing that $content is a hash reference. Then you can access the array reference, as you found, with
dd $content->{items};
which shows
[1 .. 4]
and you can print the first element of the array by writing
print $content->{items}[0], "\n";
which, again as you have found, shows just
1
which is the first element of the array.
As #cjm mentions in a comment, it is imperative that you use strict and use warnings at the start of every Perl program. If you had those in place in the program where you tried to access $content{items}, your program would have failed to compile, and you would have seen the message
Global symbol "%content" requires explicit package name
which is a (poorly-phrased) way of telling you that there is no %content so there can be no items element.
The scalar variable $content is completely independent from the hash variable %content, which you are trying to access when you write $content{items}. %content has never been mentioned before and it is empty, so there is no items element. If you had tried #{$content->{items}} then it would have worked, as would #{${$content}{items}}
If you really have a problem with the arrow operator, then you could write
print ${$content}{items}[0], "\n";
which produces the same output; but I don't understand what is wrong with the original version.