SELECT * but also use CAST() - mysql

I'm trying to select all fields for a number of rows from my MySQL table. One of my fields is called publication_date and it stores a string that represents a day that specific row is to be published on our website. It's stored in mm/dd/yyyy format.
I know I can cast that field to a DATE data type using CAST, but I'm not sure how to also grab the other fields' data.

Just add that column to your SELECT clause in addition to the *. Make sure to give it an alias so you can differentiate it from the regular datetime field.
SELECT *
, CAST(datefield AS date) AS aliasname
FROM tablename

You can do :
Select *,cast(publication_date as char) as newPublicationdate from tableName
Or if your table do not have lots of column it is much better to type it all
Select column1,column2,cast(publication_date as char) as publication_date from tableName
Regards

Related

Mysql selecting unique values in date type varchar

I have a column where the dates are type varchar. For example:
15-10-2018
16-10-2018
19-10-2018
23-10-2018
29-10-2018
8-11-2018
9-11-2018
10-11-2018
12-11-2018
when I consult with the following query
SELECT DISTINCT date FROM `test` WHERE date BETWEEN '15-10-2018' and '9-11-2018'.
I have the right result.
15-10-2018
16-10-2018
19-10-2018
23-10-2018
29-10-2018
8-11-2018
9-11-2018
but if the query is:
SELECT DISTINCT date FROM `test` WHERE date BETWEEN '15-10-2018' and '10-11-2018'.
or
SELECT DISTINCT date FROM `test` WHERE date BETWEEN '15-10-2018' and '12-11-2018'.
The answer I get is empty.
I think it's only validating the days in the sql.
I need to get the right dates.
I think the problem is the fact that the column is varchar, so it's comparing characters instead of a range of dates. I will recommend convert the column to date type and try again.
Alternative if you cannot change the type of the column you could cast it to date format like this:
SELECT DISTINCT `date` FROM `test` WHERE STR_TO_DATE(`date`,'%d-%m-%Y') BETWEEN '2018-10-15' AND '2018-11-10';
I tested with your data and it works. Of course this could put some extra effort on the database and will not use indexes.
You need to set the datatype to date and update your dates to be using date for a more reliable result. Once done you should be using the database format for the dates in your WHERE clause.
Try
SELECT DISTINCT date FROMtestWHERE date BETWEEN '2018-10-15' and '2018-11-10'

Grouping only by date in a varchar column in mysql

I have a mysql column where the data is stored as VARCHAR though the data values are of datetime in the format of yyyy-mm-dd hh:mm:ss.
Now my task is to group by the date part i.e yyyy-mm-dd by converting VARCHAR to date-time and then just taking date part out of it
QUERY
SELECT SUM(value)
FROM table
GROUP BY name , [date part of the varchar field]
Please let me know if this is at all possible and if yes, how?
Assuming that your data in this varchar field is properly formatted, you can work with the left function, like this:
SELECT LEFT(mydate, 10) AS myval,
SUM(myvalue)
FROM mytable
GROUP BY myval;
If this isn't a big issue; I'd advise converting your varchar column to datetime or timestamp. If not only for the possibly better data storage usage, it'll be way easier to do work with date and time related functions.
Just use the left function. You can leave the date as a string:
SELECT left(datecol, 10) as YYYYMMDD, SUM(value)
FROM table
GROUP BY left(datecol, 10);
I removed name from the group by because it doesn't seem relevant to the question. You can, of course, add it back in.
By the way, MySQL understands this format for dates, so if you really, really want a date:
SELECT date(left(datecol, 10)) as RealDate, SUM(value)
FROM table
GROUP BY RealDate;

SQL Server: Want to use between clause with dates, but dates in string form (YYYY.MM.DD)

Help! One column in my database is for dates. All of my dates are unfortunately in the String form (YYYY.MM.DD). I have a MASSIVE database (300+GB) so ideally would like to avoid transformations.
Is there a way I can select rows for dates in between YYYY.MM.DD and YYYY.MM.DD? What would the script look like?
Thank you!
If the months and days are stored with leading zeroes, the BETWEEN operator will work as expected. So will ORDER BY.
create table your_table (
date_value varchar(10) not null
);
insert into your_table values
('2013.01.01'), ('2013.01.13'), ('2013.01.30'), ('2013.01.31'),
('2013.02.01'), ('2013.02.13'), ('2013.02.28'), ('2013.02.31'),
('2013.03.01'), ('2013.03.15'), ('2013.03.30'), ('2013.03.31');
select date_value
from your_table
where date_value between '2013.01.01' and '2013-01-31'
order by date_value;
2013.01.01
2013.01.13
2013.01.30
One of the main problems with your structure is that you lose type safety. Look at this query.
select date_value
from your_table
where date_value between '2013.02.01' and '2013.02.31'
order by date_value;
2013.02.01
2013.02.13
2013.02.28
2013.02.31
If you'd used a column of type date or datetime or timestamp, the dbms would not have allowed inserting the values '2013.02.31', because that's not a value in the domain of date. It is a value in the domain of varchar. (And so is "Arrrrgh!", unless you've got a CHECK constraint on that column that severely restricts the acceptable values.)
Not good solution, but works (cost much performance).
You have formated date in order year, month, day (good order to compare strings, without transformation to datetime), so you can try
SELECT * FROM Table WHERE StringDate > '2013.07.10' AND StringDate < '2013.07.14'
It returns bad results if there are dates before year 1000 without leading zero ('999.07.14').
But I dont know how it works on big database.
SQL Fiddle
Between in SQL is inclusive of both bounds. If that is what you want, you can just use between:
where col between 'YYYY.MM.DD' and 'YYYY.MM.DD'
Where the two constants are whatever values you are looking for.
If you have an index on the column, then between (as well as >, >=, and so on) will use the index. You do not need to transform the values. If your constants are dates of one form or another, then you can use date_format() to create a string in the right format. For instance, to get dates within the past week:
where col >= date_format(adddate(now(), -7), '%Y.%m.%d')

Filter dates stored as varchar in mysql

I am working with a MySQL database where dates are stored as varchar like this:
'2013-01-31' in column cl_223
I need to select only records from 2013 so I tried:
SELECT ..
FROM ....
Where cl_223 Like '2013'
But that does not seem to work.
Thanks for all help!
You must add % as a wildcard :
SELECT ..
FROM ....
WHERE cl_223 LIKE '2013%'
Storing a datettime value in a varchar column complicates some functionality on date time operations. But of course you can select your values writing such a query as follow
SELECT * FROM table_name WHERE cl_223 LIKE '2013%'
But if you don't have any performance issue you can convert the varchar column to a datetime value and write stronger typed query like this:
SELECT * FROM table_name WHERE STR_TO_DATE(cl_223,'%Y-%m-%d2') BETWEEN '2013-01-01' AND '2013-12-31'
But if you need a date time value as a date time in your process you'd better store it in a datetime column instead of a varchar column.
The query should be
SELECT ..
FROM ....
Where cl_223 Like '2013%'
However, the better solution would be to store the dates as DATE data types. If the dates in that column are always used in the format they're in now, the change would be backwards compatible. It would also allow for easier processing of the date values.

Mysql query find specified rows

i have one table trip_data.Every one second i getting packets and inserting data to database.trip_data table contains four fields.trip_paramid,fuel_content,creation_time&vehicle_id.I want to select all rows in which difference between creation time is 2 minutes(Not exactly 2.Approximately 2).trip_data table contains 40 lacks rows.So i need a optimized select query for this.Can anyone help on this.Here is table schema&sample data for the trip_table..
SQlFiddle demo
SELECT
tp.*
FROM
trip_parameters tp
GROUP BY
CONVERT(UNIX_TIMESTAMP (tp.creation_time)/(2*60), unsigned)
ORDER BY
tp.creation_time asc
Note that using UNIX_TIMESTAMP does not allow you to handle dates beyond year 2037. Using the following instead fixes the problem:
CONVERT(TIMESTAMPDIFF(SECOND,'1970-01-01 00:00:00',tp.creation_time)/(2*60), unsigned)
You can do it in one table scan using MYSQL User defined variables. Unfortunately UDV's have a limited set of data types (integer, decimal, floating-point, binary or nonbinary string). So in this query I use a char #ti varible to store previous datetime using CAST to compare it with the Creation_time field. Also initial value for this variable I set to (now()-10000000) you can use any date you wish less than MIN(Creation_time)
Here is the SQLFiddle demo
select * from
(
select trip_parameters.*,
if(ABS(TIMESTAMPDIFF(MINUTE,Creation_time,cast(#ti as datetime)))>=2,1,0) t,
#ti:=if(ABS(TIMESTAMPDIFF(MINUTE,Creation_time,cast(#ti as datetime)))>=2,
cast(Creation_time as char(100)),#ti)
from trip_parameters,
(select #ti:=cast(now()-10000000 as char(100))) a
order by creation_time
) t2
where T=1
order by creation_time
Try this
SELECT trip_paramid, fuel_content, creation_time, vehicle_id
FROM trip_parameters
GROUP BY FLOOR(UNIX_TIMESTAMP(creation_time)/120)
This takes one item of every 2 minute block