Bash script: Mysql query field to variable - mysql

Question

I'm trying to obtain a recordset and read a few fields from it. I'm not able to figure it out how put the fields into variables. The script is:
#!/bin/bash
sqlQuery="$(mysql -h host -u user -ppass -D oberonsaas_v2 -s -N -e
'select ventas.id_venta,
ventas_entradas.id_ventas_entradas,
ventas.id_evento,
id_tarifa,
DATE_FORMAT(fecha_evento,"%Y%m%d") as fecha,
TIME_FORMAT(pase,"%H%i") as pase
from pases,ventas,ventas_entradas,recintos
where ventas.id_recinto = recintos.id_recinto
and ventas.id_pase = pases.id_pase
and ventas.id_venta = ventas_entradas.id_venta
and recintos.id_cliente = 32
and ventas.estado="Pagada"
and date(fecha_venta) = date_add(date(CURRENT_TIMESTAMP),INTERVAL -1 day)')"
echo $sqlQuery
I get all the recordset in $sqlQuery, but i want to do a loop and concat the fields.

Answer 1

Well I have invented some output
#!/bin/bash
Result="21,336,purchase,tarif_exspensive,Jose"
(IFS=","
for i in $Result
do
echo "I Have: " $i
done
)
Ouput is
$ bash t5.sh
I Have: 21
I Have: 336
I Have: purchase
I Have: tarif_exspensive
I Have: Jose

Answer 2

Collapse this into the simplest possible construct.
Put returned recordset into a bash array (for example):
sqlQuery=( pases_value ventas_value ventas_entradas_value recintos_value )
note: yours could look like:
sqlQuery=( $(mysql -h host ... )
new lines between the array operators "(" and ")" are ok
each will be in a distinct sqlQuery array location.
for example return: recintos_value
echo ${sqlQuery[3]}
concat all:
echo ${sqlQuery[*]}
if delimiters are of concern, use the mysql --delimiter switch to define a desired character, then
set concatValue=${sqlQuery[*]}
then to remove the delimiter character ("," for example):
set finalValue=${concatValue//,}