I have two repos, dev and testing. In dev, I've made several commits since the last push to testing. However, now I want to shelve all those commits, make a different change, push it to testing, and then get those commits back. Shelving only works on uncommitted files.
What should I do? Backout or rollback or revert each commit in reverse order? Rename dev, clone testing to dev, make changes, push to testing, push to renamed dev, delete dev, rename renamed dev back to dev?
What's the cleanest/easiest way to do this?
For clarity to other readers: the actual HG shelve command is not the correct approach for this situation; it does not work on already-committed changes, but nor is it necessary to use in this case.
Here's what you can do:
In dev, update to the version before the commits you don't want to push to testing.
Make your desired changes in dev and commit. This will create a new head (which will also be the new tip).
Push to testing
In dev, merge the tip with the other head that contains the changes you have avoided pushing, then commit.
Original suggestion (not possible to implement in this case):
Clone dev into a new repo and update to the version before the commits (or just clone testing instead)
Make the change you want, commit and push to both testing and dev
Discard the clone
Pull the testing from testing into dev and merge the heads at your leisure, establishing a single head once more
Another workflow may be: Use MQ extension
Enable MQ extension for repository
Init MQ
Convert needed changesets into MQ-patches (How to convert N local topmost commits to an MQ patch? and "Converting to and from permanent revisions" topic in Chapter 12. Managing change with Mercurial Queues of HG Book)
Unapply all created patches 'hg qpop -a'
Make change, commit, push
Return back patches into changesets state (hg qpush -a + hg qfinish -a)
Related
I cloned a project to my local directory and made a lot of changes. My current goal is to push my changed code to a new branch in the remote repository. And eventually this new branch will be merged back to default.
My problem is, because of some stupid effort in the past a few weeks to try to recover some missing files, I end up with a few branch names that I don't want being shown in public.
Here's what I have:
$hg branches
dev-v02 197:xxxxx
dev2 194:xxxxx
dev 183:xxxxx
qa 189:xxxxx
$hg branch
dev-v02
My question is, if I push my current branch dev-v02 to the remote repository by "hg push --new-branch", and this branch later get merged back to default, will the unwanted branches show up in history of default? And if so, is there a safe way to purge them?
I do NOT want to discard my changes. I just don't want the unwanted branches showing up in "hg branches" or "hg his" commands by whoever later clones the project from the remote repository. I searched online and found "hg strip" but I couldn't tell from the article if it would also remove the changes I've made. Thanks.
Edit: I just cloned my local repository by "hg clone -r 197 original-dir dest-dir" as suggested by both kevin and chessbot and now hg branches shows:
dev-02 192:xxxxx
qa 187:xxxxx (inactive)
I guess "qa" remains because I had pushed it to the remote as a QA branch and closed it later, and I just have to live with that. I will push from this new directory from now on. Thanks guys for your help.
Try hg push --new-branch -b dev-v02 to specify that you're pushing only that branch.
(See: https://www.mercurial-scm.org/repo/hg/help/push)
Another thing you could do: Clone the repository locally on your machine, strip out the branches you don't want, and then push that clone to the server. Then you retain your history locally without pushing it to everyone else.
It depends.
Branches are permanently associated with a commit. The branch is part of the commit, and contributes to the hash. Changing the branch of a commit in the past would alter all commit hashes from that point forward. This is quite different from Git, where a branch is little more than an ephemeral pointer to a HEAD. Such pointers are implemented in Mercurial as bookmarks.
If the unwanted branches appear on commits which are (ancestors of) commits you want to publish, there is very little you can do, short of recreating the history with all-new hashes. This could (for instance) be done with hg export and hg import, along with local cloning and (probably) a certain amount of shell scripting. More efficiently, you could use the convert extension to automate the process. Since this changes commit hashes, it will likely cause serious problems if any of the commits have already been distributed publicly.
If you have no interest in sharing the offending commits, you can simply not publish them. This can be done with selective pushing. However, since you'll always have to manually exclude those commits every time you push, it's probably safer to clone and strip (or clone selectively with the -r flag). You can then push from your partial clone with impunity. Assuming you have a sufficiently recent version of Mercurial, you can also force the commits into the secret phase, so that they will not be pushed:
hg phase -fs revisions
You don't want to use hg strip, because it permanently removes the commits from the history (see Editing History in the Mercurial wiki)
If I were you, I would close the branches instead:
hg up -C badbranch
hg commit --close-branch -m 'close badbranch, this approach never worked'
hg up -C default
(source: Pruning branches in the Mercurial wiki)
After closing a branch, hg branches doesn't show it anymore.
If you do want to see closed branches, use the -c parameter:
hg branches -c
Disadvantage:
hg his still shows closed branches.
You could use the -b parameter though, to show only the default branch:
hg his -b default
We have a code review repository where people hg push -f all sorts of stuff. After reviews are complete, we pull from the project's central repository, rebase, and push. I recently upgraded to mercurial 2.1 and get this message:
abort: can't rebase immutable changeset 43ab8134e7af
(see hg help phases for details)
when I try to hg pull --rebase from the central repository. How do I fix it?
In the review repository's .hg/hgrc file, add these lines:
[phases]
publish = False
The problem is due to a new feature in mercurial 2.1 called phases. It's great. Here is a nice introduction to its use.
To make the changesets in question mutable right now, use hg phase -f -d REV to force REV to be mutable again. Once the hgrc file has been changed, you shouldn't have to do that any more.
As a side note, hg push -f is lame. Make an alias hg review that pushes with -f to that repository.
I don't think disabling phase support on the server is the correct solution, but your problem sounds weird.
Pull --rebase should rebase your local changes, on top of the remote changes, which should be allowed, even if phases are supported by the client, as long as these changes have not been seen by anyone else, eg. they haven't been pushed out anywhere.
Is it possible that you have already pushed your your own changes, to somewhere else (which set them to public phase), and after that tried pulling from the testing repo? Because then, this is the correct behaviour that you are seeing.
Most of the time it is a bad idea to mess with phases manually (with hg phase -f), because it can easily lead to a history rewrite, which can lead to duplicated changesets, or various errors when other people try to pull/push. If a changeset became marked as public (as in your case), it probably happened for a good reason.
I've encountered such behaviour with collapsed rebase. Phasing out back to draft hadn't helped me. So I've just pulled up (hg pull -u) to sync with remote repo, then just grafted the problem commit (hg graft <problem_commit>) and then amended this very new commit.
Many times it happens that I have few commits on my local Hg repository which I don't want to push and sometimes I want to remove the local branch altogether. But I cannot rollback more than one commit which leaves me no choice than creating a new clone and download the whole repository again. This feels stupid, since if I could just delete my local branch which has not affected the remote repository in anyway, then I wouldn't have to create and setup a new clone. So, is it how it is in Mercurial or is there some way to discard a local branch?
Thanks!
If you enable the mq extension (bundled with Mercurial), you can use hg strip. Be careful, though, as this will modify the history of your repository. The safe method is to clone your repository up to the revision preceding the creation of the branch you want to discard, then to pull the remaining changesets that you want to keep.
I know its too late but it may be useful for any one:
If your branch is not pushed yet.
First rollback changes hg rollback only if you have done commit but
not yet pushed
Second run hg update --clean
Third run hg branch any-existing-branch
Fourth run hg pull -u
If you find yourself doing this often perhaps you should be using bookmarks instead of named branches. http://stevelosh.com/blog/2009/08/a-guide-to-branching-in-mercurial/
I want to completely delete a Mercurial commit as if it was never entered in the repository and move back to my prior commit.
Is this possible?
If it was your last commit and you haven't pushed it anywhere, you can do that with rollback. Otherwise, no. Not really. Time to change your passwords.
Edit: It has been pointed out that you can clone from an older revision and merge in the changes you want to keep. That's also true, unless you have pushed it to a repo you don't control. Once you push, your data is very likely to be very hard to get back.
You can try to remove mq info about your commit.
For this you need to go File->Settings->Extensions.
There check mq and restart gui.
After that just right click on unneeded commit and
ModifyHistory->Strip
To edit the history I would use the Histedit Extension extension.
hg histedit 45:c3a3a271d11c
However keep in mind this only makes sense in a situation where you have not yet pushed the commits to the public repository, you own the public repository and/or you can account for all the clones out there. If you receive the following error:
abort: can't rebase immutable changeset 43ab8134e7af
It means that Mecurial thinks this is a public changeset (see phases) that has already been pushed - you can force it to be a draft again doing:
hg phase -f -d 45:c3a3a271d11c
I encounter this fairly often. I make a commit and then pull to push. But then there is something incoming that makes my newly made commit unnecessary. A plain hg rollback isn't enough because it only undoes the pull...
This is the thing to do:
hg strip <rev>
Things are painless when you don't push your changesets anywhere.
If it's more than one commit and/or you already pushed it somewhere else, you can clone your repository and specify the last changeset that should be cloned.
See my answer here how to do this:
Mercurial: Fix a borked history
If you only committed locally and didn't push, you can just create a clone locally (as described in my link) and you're done.
If you already pushed to some remote repository, you would have to replace that with your clone.
Of course it depends if you are able (or allowed) to do this.
You can use "hg backout" to do a reverse merge basically. All options are discussed in the freely available book "Mercurial: The Definitive Guide":
http://hgbook.red-bean.com/read/finding-and-fixing-mistakes.html
If using tortoise you can use modify history > strip...
Yes. Unless I am mistaken, as of v2.3 (rel. 2012/08/01) you can use the HisteditExtension with a drop command to drop a commit, along with strip or backout to remove changes.
A simple Google search on the feature: https://www.google.com/webhp#q=histedit+drop
In 2022 I do use evolve extension. It is one of the best extensions for this purpose.
To prune unwanted changeset, if you for example did a quick hack to get the code working:
$ echo 'debug hack' >> file1.c
$ hg commit -m 'debug hack'
Now you have a proper patch you can do hg prune .:
$ hg prune .
1 files updated, 0 files merged, 0 files removed, 0 files unresolved
working directory is now at 2a39221aaebb
1 changesets pruned
If you push the change to the remote repository you will find only obsolescence markers:
$ hg push
searching for changes
no changes found
remote: 1 new obsolescence markers
To check the changes to your local repo you can pull from the remote one:
$ hg pull
pulling from ssh://userid#server/repo
searching for changes
no changes found
I have an mercurial repositry a bitbucket.org and a clone on my wokstation. The clone has some uncommited (unfished) work in it. I have to copy these clone to my laptop because I will be on a trip for one or two weeks and want to do some work.
Is there a simple and save way to copy the repository with its uncommited changes to another device? I knew I could clone the repo from the workstation to my laptop but this won't copy uncommited work.
Simply copy the entire repository's folder.
Just commit that work. That work needs to be finished to be committed is left-over CVS/SVN thinking. Commit it, and then update to its parent and work on whatever else you want to work on. When eventually the work is done you're pushing a changegroup not individual changesets, so no one will have the uncompiling stage at the end of those interstitial changesets on them.
Avoiding committing work in Mercurial (using shelve, attic, copying repos, etc.) is the only way to lose work -- avoid it.
I prefer my first answer (commit it) but if you positively can't bring yourself to commit unfinished work then you should be using Mercurial Queues with a patch queue that lives in its own repository. This is easily done with:
hg qinit --create-repo
Then you import your uncomitted changes as a patch using:
hg qnew --force name-for-this-work
then you can:
hg qcommit -m "work in progress"
Then you can qclone that repo and get both the work in progress and the base repository on which it's overlayed. More details are available in the Mercurial book's chapter on queues.
Really, though, there's just never a good reason to have uncommitted work for more than an hour or two.