Mysql case when and order by issue - mysql

Have this query:
SELECT
count(*) as Total,
SUM(CASE WHEN gender = 1 then 1 ELSE 0 END) Male,
SUM(CASE WHEN gender = 2 then 1 ELSE 0 END) Female,
SUM(CASE WHEN gender = 0 then 1 ELSE 0 END) Unknown,
CASE
WHEN age>2 AND age<15 THEN '2-15'
WHEN age>18 AND age<25 THEN '18-25'
END AS var
FROM
persons
WHERE
1=1
AND `date` > '2012-01-10'
AND `date` < '2013-01-07'
GROUP BY
CASE
WHEN age>2 AND age<15 THEN '2-15'
WHEN age>18 AND age<25 THEN '18-25'
END
And is resulting this:
Total Male Female Unknown var
29 17 12 0 NULL
7 0 7 0 18-25
3 0 3 0 2-15
1st question: Why is this resulting that NULL ? What could be done to only show results with values?
2nd question: mysql is ordering my var column with 18-25 before 2-15, migth be because of number 1 cames first then number 2. But the point is order that as numbers, and 2 came first then 18.
Cheers :)

1st answer:
It is NULL because it does not satisfy any of your CASE conditions for the age. Adding a clause to the WHERE like this should do it:
WHERE (age > 2 AND age < 15) OR (age > 18 AND age < 25)
2nd answer:
You are correct, it is ordering them by strings (because that is what they are). Just change the direction of the sort by doing ORDER ASC or ORDER DESC

This is because all CASE expression has an (implied, default) ELSE NULL part. SO, any age value that is not caught by either the age>2 AND age<15or the age>18 AND age<25 condition, results in the NULL value being grouped.
Solution is to add one more restriction at the WHERE clause:
WHERE 1=1
AND `date` > '2012-01-10' AND `date` < '2013-01-07'
AND ( (age>2 AND age<15) OR (age>18 AND age<25) ) -- this
For the second question, you can use a function on age to avoid the comparison being made on the var (which is a string):
ORDER BY MIN(age)
or just:
ORDER BY age
None of the above is by the SQL standard but it works in MySQL, under the default non-ANSI settings. If you want to be 100% by the book, you can change slightly the var:
SELECT count(*) as Total,
SUM(CASE WHEN gender = 1 then 1 ELSE 0 END) Male,
SUM(CASE WHEN gender = 2 then 1 ELSE 0 END) Female,
SUM(CASE WHEN gender = 0 then 1 ELSE 0 END) Unknown,
CASE
WHEN age>2 AND age<15 THEN '02-15' -- this was changed
WHEN age>18 AND age<25 THEN '18-25'
END AS var
FROM persons
WHERE 1=1
AND `date` > '2012-01-10' AND `date` < '2013-01-07'
AND ( (age>2 AND age<15) OR (age>18 AND age<25) )
GROUP BY
CASE
WHEN age>2 AND age<15 THEN '02-15'
WHEN age>18 AND age<25 THEN '18-25'
END
ORDER BY var ;

you are getting NULL
because it doesnt meet your CASE
CASE
WHEN age>2 AND age<15 THEN '2-15' // U HAVE BETWEEN 2-15
WHEN age>18 AND age<25 THEN '18-25' // u have between 18-25
// but u dont have between 15-18
//and u get null because your value is between 15-18
so try to add other case in that range.
second question because they are strings , not numbers.
try order them by age

Related

MySQL : using sum in( case when ) statement shows 0 as result

new to MySQL..so pls help me out with this basic code..
i have a query something like this...
select weekofyear(id_time),
(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
and it gives correct results as--here
however i want to use sum after case when statement so that I can get total values where BO=1 and group by week of year , so i made following changes-
select weekofyear(id_time),
count(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
sum(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
group by weekofyear(id_time)
but it always returns 0 as output.
Output --here 2
Please help , I don't know what am I doing wrong here.
Thanx !
As others have already said, session variables can be unpredictable (especially when aggregation gets mixed in). That said, it doesn't look like you're using the session variables to carry over values from one row to the next (as is often done), but to just make aliases of sorts for calculations you don't want to repeat.
A better way to handle that is just through subqueries.
SELECT woy, id, Tat1, Tat2, check1, check2
, CASE
WHEN check2=0 THEN (
CASE
WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+10))) THEN 1
ELSE 0
END
)
ELSE (
CASE WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+20))) THEN 1
ELSE 0
END
)
END AS BO
FROM (
SELECT WEEKOFYEAR(id_time) AS woy
, id
, exp1 AS Tat1
, exp2 AS Tat2
, exp3 AS check1
, exp4 AS check2
FROM datb
WHERE cid=18
AND id_time BETWEEN '2019-11-01 06:00:00' AND '2019-11-25 06:00:00'
) AS subQ
;
You can then tweak the above query for aggregation, or use it as a subquery for an aggregating outer query.

SQL count when value = 1

I'm doing a select on two tables with this:
SELECT m.torneio, m.deck, m.top, m.lugar, sum( m.quantidade ) AS quantidade, m.formato AS formato, q.quantidade AS qtorneio, t.season AS season, sum( m.top ) AS totaltops, count( m.lugar = '1' ) AS venceu
FROM `metagame` AS m, quantidade AS q, torneios AS t
WHERE m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY m.deck
My problem is that venceu is counting all instances instead of only the ones when lugar = 1. Why is that?
tried with sum() too with no good results too. How can i fix this?
I am surprised that count( m.lugar = '1' ) syntaxs but it does and returns the sames as count(*). You should probably change it to sum(case when lugar = 1 else 0 end) as venceu. You should also look closely at the group by to be sure it works as you expect (i suspect not).
count(x) does not accept an expression.
It's only counting how many times x is returned.
What you should do is check if m.lugar is 1 and yes add one to the counter else do nothing.
Inline checks can be done like so:
case when m.lugar = '1' then 1 else 0 end
Then add all the one you gets :
sum(case when m.lugar = '1' then 1 else 0 end)
Your final query should look like this:
SELECT
m.torneio,
m.deck,
m.top,
m.lugar,
sum( m.quantidade ) AS quantidade,
m.formato AS formato,
q.quantidade AS qtorneio,
t.season AS season,
sum( m.top ) AS totaltops,
sum(case when m.lugar = '1' then 1 else 0 end) AS venceu
FROM
`metagame` AS m,
quantidade AS q,
torneios AS t
WHERE
m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY
m.deck
If I understand your question you can use this:
sum(case when m.lugar = '1' then 1 else 0 end)
or you can try having clause
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);

Is it possible to have custom GROUP BY for MySQL query?

I have been trying to find the simplest way to group the two age groups in my query. Is it possible for something like this to work?
SELECT age,
sum(case when age < '20' then 1 else 0 end),
sum(case when age > '20' then 1 else 0 end)
FROM Contact
GROUP BY ...."custom group one"......"custom group one".....??
I know you should group on a column usually, but in my case I that doesn't work. Any suggestions? Thx!
Table: Desired Query Result:
Name Age 0 1
John 18 Under 20 2
Harry 22 Over 20 2
Mary 17
Megan 27
SOLVED:
SELECT CASE
WHEN age = '21' THEN 'young'
WHEN age BETWEEN '22' AND '60' THEN 'middle'
ELSE 'old'
END, Count(id)
FROM Contact
GROUP BY CASE
WHEN age = '21' THEN 'young'
WHEN age BETWEEN '22' AND '60' THEN 'middle'
ELSE 'old'
END
Note: AS can be used to assign alias to grouping conditions in SELECT statement and hence avoid repeating conditions twice, i.e.
SELECT CASE
WHEN age = '21' THEN 'young'
WHEN age BETWEEN '22' AND '60' THEN 'middle'
ELSE 'old'
END AS age_range, Count(id)
FROM Contact
GROUP BY age_range
So that will be:
SELECT
COUNT(1),
age>20 AS Above20
FROM t
GROUP BY age>20
-check this fiddle.
Or, alternatively, with SUM() and with column view:
SELECT
SUM(IF(age>20, 1, 0)) AS Above20,
SUM(IF(age<=20, 1, 0)) AS Below20
FROM
t
-check this fiddle.

MySQL using Sum and Case

I'm trying to create a GridView with ASP.NET connecting to a MySQL database. The data appears like below.
BusinessUnit OrderDate Canceled
UnitA 1/15/2013 N
UnitA 10/1/2013 N
UnitB 10/15/2013 N
UnitB 10/22/2013 N
UnitB 10/22/2013 N
Based on the records above, I'd like the result to appear like below
BusinessUnit TodaysOrders ThisMonthsOrders ThisYearsOrders
UnitA 0 1 2
UnitB 2 3 3
My current code is below. It's giving me error (something about DatabaseName.sum does not exist. Check the
Function Name Parsing and Resolution' section... )
Select
SUM (CASE WHEN (OrderDate)=DATE(NOW()) THEN 1 ELSE 0 END) AS TodaysOrders,
SUM (CASE WHEN YEAR(OrderDate) = YEAR(CURDATE()) AND MONTH(OrderDate) = MONTH(CURDATE()) THEN 1 ELSE 0 END) AS ThisMonthsOrders,
SUM (CASE WHEN YEAR(main_order_managers.creation_date) = YEAR(CURDATE()) THEN 1 ELSE 0 END) AS ThisYearsOrders
code continues
FROM OrderTable WHERE OrderTable.Canceled. <> 'Y';
Is Sum Case the best use here?
The error is caused by the space between function name and parenthesis
SUM (CASE WHEN ...
^^
Read more Function Name Parsing and Resolution
Try
SELECT BusinessUnit,
SUM(CASE WHEN OrderDate = CURDATE() THEN 1 ELSE 0 END) TodaysOrders,
SUM(CASE WHEN DATE_FORMAT(OrderDate, '%Y%m') = DATE_FORMAT(CURDATE(), '%Y%m') THEN 1 ELSE 0 END) ThisMonthsOrders,
SUM(CASE WHEN YEAR(OrderDate) = YEAR(CURDATE()) THEN 1 ELSE 0 END) ThisYearsOrders
FROM OrderTable
WHERE Canceled <> 'Y'
GROUP BY BusinessUnit
Here is SQLFiddle demo

get count of two table fields in one query

I am trying to get the count of females and males in the gender field of a table.
Is there a way to get the count of each in one query?
Something like:
select * from table count(where gender = 'm') as total_males, count(where gender = 'f') as total_females;
or will it require two queries?
select count(*) from table where gender = 'm';
select count(*) from table where gender = 'f';
This is basically a PIVOT. MySQL does not have a pivot so you can use an aggregate function with a CASE statement to perform this:
select
sum(case when gender = 'm' then 1 else 0 end) Total_Male,
sum(case when gender = 'f' then 1 else 0 end) Total_Female
from yourtable
See SQL Fiddle with Demo
Or using COUNT:
select
count(case when gender = 'm' then 1 else null end) Total_Male,
count(case when gender = 'f' then 1 else null end) Total_Female
from yourtable;
See SQL Fiddle with Demo
Something like this will work:
SELECT SUM(IF(t.gender='m',1,0)) AS total_males
, SUM(IF(t.gender='f',1,0)) AS total_females
FROM mytable t
The "trick" here is that we are using a conditional test to return either a 0 or a 1 for each row, and then adding up the 0's and 1's. To make this a little more clear, I am using the SUM aggregate function rather than COUNT, although COUNT could be used just as easily, though we'd need to return a NULL in place of the zero.
SELECT COUNT(IF(t.gender='m',1,NULL)) AS total_males
, COUNT(IF(t.gender='f',1,NULL)) AS total_females
FROM mytable t
Consider that the two expressions in the SELECT list of this query:
SELECT COUNT(1)
, SUM(1)
FROM mytable t
Will return the same value.
If you want to avoid the MySQL IF function, this can also be done using the ANSI SQL CASE expression:
SELECT SUM( CASE WHEN t.gender = 'm' THEN 1 ELSE 0 END )) AS total_males
, SUM( CASE WHEN t.gender = 'f' THEN 1 ELSE 0 END )) AS total_females
FROM mytable t
select sum(case when gender='m' then 1 else null end) as total_males, sum(case when gender='f' then 1 else null end) as total_females from ...
Should work just fine!
If your only issue is to avoid two queries, you can always write two queries as subselects of one query.
Select (select 1 from dual) as one, (select 2 from dual) as two from dual
This would work for your scenario, too.