PHP Unidentified Function script [closed] - mysql

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Closed 10 years ago.
The code I am trying to use is below, Ive double checked it and everything and it keeps saying this error: Fatal error: Call to undefined function Votifier() , I dont know what the problem is here. This is my last resort to ask here, Ive been googling for 2 hours.. Thanks in advance.
<?php
if (isset($_COOKIE['votfed']) && $_COOKIE['vofted'] == 'true') {
exit();
} else {
mysql_connect("", "", "")or die("cannot connect");
mysql_select_db("")or die("cannot select DB");
$result = mysql_query('SELECT * FROM servers WHERE id = "' . $_GET["server"] . '"');
while ($row = mysql_fetch_array($result)) {
$public_key = $row['votifier_key'];
$server_ip = $row['ip'];
$server_port = $row['votifier_port'];
$username = 'USERNAME';
}
$username = preg_replace("/[^A-Za-z0-9_]+/", '', $username);
if (Votifier($public_key, $server_ip, $server_port, $username)) {
echo 'Success!';
} else {
echo 'Error!';
}
ini_set('error_reporting', E_ALL);
function Votifier($public_key, $server_ip, $server_port, $username) {
$public_key = wordwrap($public_key, 65, "\n", true);
$public_key = <<<EOF
-----BEGIN PUBLIC KEY-----
$public_key
-----END PUBLIC KEY-----
EOF;
$address = $_SERVER['REMOTE_ADDR'];
$timestamp = time();
$string = "VOTE\MC-ServerLists.com\n$username\n$address\n$timeStamp\n";
$leftover = (256 - strlen($string)) / 2;
while ($leftover > 0) {
$string .= "\x0";
$leftover--;
}
openssl_public_encrypt($string, $crypted, $public_key);
$socket = fsockopen($server_ip, $server_port, $errno, $errstr, 3);
if ($socket) {
fwrite($socket, $crypted);
return true;
} else
return false;
}
mysql_connect("", "", "")or die("cannot connect");
mysql_select_db("")or die("cannot select DB");
mysql_query('insert into voters (server_id, ipaddress) VALUES ("' . $_GET["server"] . '", "' . $_SERVER['REMOTE_ADDR'] . '")');
}

Answer 1

If you formatted your code correctly, you'd see that the function is conditionally defined, and because of this, its definition must occur before you call the function:
<?php
if (isset($_COOKIE['votfed']) && $_COOKIE['vofted'] == 'true') {
// ...
} else {
// ...
$username = preg_replace("/[^A-Za-z0-9_]+/", '', $username);
if (Votifier($public_key, $server_ip, $server_port, $username)) {
echo 'Success!';
} else {
echo 'Error!';
}
function Votifier($public_key, $server_ip, $server_port, $username)
{
// ...
}
// ...
}
?>
Essentially, you are executing this code:
<?php
if( false) {
} else {
if( foo()) {
echo 'Foo!';
}
function foo() {
return true;
}
}
Which should show you that foo() is not defined until after the else executes, but you call foo() at the beginning of the else block (before it's defined).
Your function should be outside of the if statement, like this:
<?php
function Votifier($public_key, $server_ip, $server_port, $username)
{
// ...
}
if (isset($_COOKIE['votfed']) && $_COOKIE['vofted'] == 'true') {
// ...
} else {
// ...
$username = preg_replace("/[^A-Za-z0-9_]+/", '', $username);
if (Votifier($public_key, $server_ip, $server_port, $username)) {
echo 'Success!';
} else {
echo 'Error!';
}
// ...
}
Alternatively, you can place it at the beginning of the else block, but I wouldn't recommend it from a readability standpoint.