How to print every item resulted from group by statement - mysql

Question

I have made a statement that used group by. Now, I need to know the details for every record but I need to perform this at one statement.
For example: I made the following query to query about the files that ends with _1 and share the same number:
SELECT number, COUNT(*) AS sum domains
FROM table
WHERE file LIKE '%_1'
GROUP BY number HAVING sum domains > 1
So, if I have the following table:
domain | file | Number
------------------------------------
aaa.com | aaa.com_1 | 111
bbb.com | bbb.com_1 | 222
ccc.com | ccc.com_2 | 111
ddd.com | ddd.com_1 | 222
eee.com | eee.com_1 | 333
qqq.com | qqq.com_1 | 333
The result of the query is (the number that is shared by more than file and the count of the file(s) that ends with _1 and shared this number):
number | sum domains
------------------------
222 | 2
333 | 2
What I need to do is to print out the file names. I need:
number | file
------------------------
222 | bbb.com_1
222 | ddd.com_1
333 | eee.com_1
333 | qqq.com_1
How can I do this since group by clause does not allow me to print the file(s) ?

Answer 1

You can JOIN your query back against the main table as a subquery, to get the original rows and filenames:
SELECT
main.number,
main.file
FROM
table AS main
/* Joined against your query as a derived table */
INNER JOIN (
SELECT number, COUNT(*) AS sum domains
FROM table
WHERE RIGHT(file, 2) = '_1'
GROUP BY number
HAVING sum domains > 1
/* Matching `number` against the main table, and limiting to rows with _1 */
) as subq ON main.number = subq.number AND RIGHT(main.file, 2) = '_1'
http://sqlfiddle.com/#!2/cb05b/6
Note that I have replaced your LIKE '%_1' with RIGHT(file, 2) = '_1'. Hard to tell which will be faster without a benchmark though.