Anybody can convert this query to active record codeigniter???
SELECT b.name,
SUM(CASE WHEN c.size = 'S' THEN 1 ELSE 0 END) S,
SUM(CASE WHEN c.size = 'M' THEN 1 ELSE 0 END) M,
SUM(CASE WHEN c.size = 'L' THEN 1 ELSE 0 END) L,
SUM(CASE WHEN c.size = 'XL' THEN 1 ELSE 0 END) XL
FROM orderTB a
INNER JOIN productTB b
ON a.id_product = b.id_shirt
INNER JOIN sizeTB c
ON a.id_size = c.id_size
GROUP BY b.name
i've tried like this
function get()
{
$this->db->select("b.name,SUM(CASE WHEN c.size ='S' THEN 1 ELSE 0 END) as S,SUM(CASE WHEN c.size = 'M' THEN 1 ELSE 0 END) as M,SUM(CASE WHEN c.size = 'L' THEN 1 ELSE 0 END) as L,SUM(CASE WHEN c.size = 'XL' THEN 1 ELSE 0 END) as XL");
$this->db->from('order');
$this->db->join('ukuran','order.id_size=ukuran.id_size');
$this->db->where('date',$date);
return $this->db->get();
}
but its wrong
Just try this one and let me know,
$this->db->select("b.name,SUM(CASE WHEN c.size = 'S' THEN 1 ELSE 0 END) S,SUM(CASE WHEN c.size = 'M' THEN 1 ELSE 0 END) M,SUM(CASE WHEN c.size = 'L' THEN 1 ELSE 0 END) L,SUM(CASE WHEN c.size = 'XL' THEN 1 ELSE 0 END) XL", FALSE );
$this->db->from('orderTB a');
$this->db->join('productTB b','a.id_product = b.id_shirt','inner');
$this->db->join('sizeTB c','a.id_size = c.id_size','inner');
$this->db->group_by('b.name');
From document here
$this->db->select() accepts an optional second parameter. If you set
it to FALSE, CodeIgniter will not try to protect your field or table
names with backticks. This is useful if you need a compound select
statement.
EDIT
Just add FALSE in your select statement
function get() {
$this->db->select("b.name,SUM(CASE WHEN c.size ='S' THEN 1 ELSE 0 END) as S,SUM(CASE WHEN c.size = 'M' THEN 1 ELSE 0 END) as M,SUM(CASE WHEN c.size = 'L' THEN 1 ELSE 0 END) as L,SUM(CASE WHEN c.size = 'XL' THEN 1 ELSE 0 END) as XL",FALSE);
$this->db->from('order');
$this->db->join('ukuran','order.id_size=ukuran.id_size');
$this->db->where('date',$date);
return $this->db->get();
}
Related
My Query :
SELECT
(ref_intake.intakeno) AS intake,
SUM(CASE WHEN(student.intakeid AND student.status = '3' AND (student.courseid=3 OR student.courseid=17)) THEN 1 else 0 END) as active,
SUM(CASE WHEN(student.intakeid AND student.status = '5' AND (student.courseid=3 OR student.courseid=17)) THEN 1 else 0 END) as deffered,
SUM(CASE WHEN(student.intakeid AND student.status = '16' AND (student.courseid=3 OR student.courseid=17)) THEN 1 else 0 END) as inactive,
SUM(CASE WHEN(student.intakeid AND student.status = '9' AND (student.courseid=3 OR student.courseid=17)) THEN 1 else 0 END) as missing,
SUM(CASE WHEN(student.intakeid AND student.status = '6' AND (student.courseid=3 OR student.courseid=17)) THEN 1 else 0 END) as widthdrawn,
SUM(CASE WHEN(student.intakeid AND student.status IN (18,7,36) AND (student.courseid=3 OR student.courseid=17)) THEN 1 else 0 END) as dis_ter_dereg
FROM student
LEFT JOIN ref_intake ON student.intakeid = ref_intake.intakeid
GROUP BY student.intakeid ORDER BY ref_intake.intakeno ASC
The the image is my result:
I do suspect that your query can be simplified as follows:
SELECT
s.intakeid AS intake,
SUM(CASE WHEN s.status = 3 THEN 1 ELSE 0 END) as active,
SUM(CASE WHEN s.status = 5 THEN 1 ELSE 0 END) as deffered,
SUM(CASE WHEN s.status = 16 THEN 1 ELSE 0 END) as inactive,
SUM(CASE WHEN s.status = 9 THEN 1 ELSE 0 END) as missing,
SUM(CASE WHEN s.status = 6 THEN 1 ELSE 0 END) as widthdrawn,
SUM(CASE WHEN s.status IN (18, 7, 36) THEN 1 ELSE 0 END) as dis_ter_dereg
FROM student s
INNER JOIN ref_intake ri ON s.intakeid = ri.intakeid
WHERE
s.intakeid
AND s.status IN (3, 5, 16, 9, 6, 18, 7, 36)
AND s.courseid IN (3, 17)
GROUP BY s.intakeid
ORDER BY ri.intakeno ASC
That is:
most conditions can be moved to the WHERE clause - this should actually remove rows where no condition matches
it seems like you actually want an INNER JOIN rather than a LEFT JOIN - but you can revert that change if needed
table aliases make the query easier to read and write
ORed conditions can be simplified to use IN
i need help for represent my query result into specific report with condition
Here's my query result
after get the result i need represent it as report with some condition, it would be like this:
City A - Company A
City A - Company B
City A - Company C - Service A
I've no idea how to do it since I'm really new to MySQL.
I want to put the query into PHP.
Thanks in Advance
You can do it this way:
City A - Company A:
select pick_date, sum(Weight),
sum(case when site = 'SiteA' then 1 else 0 end) as SiteA,
sum(case when site = 'SiteB' then 1 else 0 end) as SiteB,
sum(case when site = 'SiteC' then 1 else 0 end) as SiteC
From tbl
where company_name = 'CompanyA'
group by pick_date
For City A - Company B, replace 'CompanyA' with CompanyB in the query
For Company C - Service A:
select pick_date, sum(Weight),
sum(case when site = 'SiteA' then 1 else 0 end) as SiteA,
sum(case when site = 'SiteB' then 1 else 0 end) as SiteB,
sum(case when site = 'SiteC' then 1 else 0 end) as SiteC
From tbl
where company_name = 'CompanyC' and service_name = 'ServiceA'
group by pick_date
This should do the trick. If your original query is also from SQL, put it into a temp table, and then using the following query will get you 3 answers.
SELECT
pickup_date
,SUM( CASE WHEN [site] = 'SiteA' THEN 1 ELSE 0 END) as [SiteA]
,SUM(CASE WHEN [site] = 'SiteB' THEN 1 ELSE 0 END) as [SiteB]
,SUM(CASE WHEN [site] = 'SiteB' THEN 1 ELSE 0 END) as [SiteC]
FROM
tbl
WHERE
[city] = 'CityA'
AND
[company_name] = 'CompanyA'
GROUP BY
pickup_date
SELECT
pickup_date
,SUM( CASE WHEN [site] = 'SiteA' THEN 1 ELSE 0 END) as [SiteA]
,SUM(CASE WHEN [site] = 'SiteB' THEN 1 ELSE 0 END) as [SiteB]
,SUM(CASE WHEN [site] = 'SiteB' THEN 1 ELSE 0 END) as [SiteC]
FROM
tbl
WHERE
[city] = 'CityA'
AND
[company_name] = 'CompanyB'
GROUP BY
pickup_date
SELECT
pickup_date
,SUM( CASE WHEN [site] = 'SiteA' THEN 1 ELSE 0 END) as [SiteA]
,SUM(CASE WHEN [site] = 'SiteB' THEN 1 ELSE 0 END) as [SiteB]
,SUM(CASE WHEN [site] = 'SiteB' THEN 1 ELSE 0 END) as [SiteC]
FROM
tbl
WHERE
[city] = 'CityA'
AND
[company_name] = 'CompanyC'
AND
[service_name] = 'ServiceA'
GROUP BY
pickup_date
I am trying to convert a raw SQL query into eloquent and I am struggling with the join part as it gets quite complex.
I have got as far as the joins but I am looking at the documentation and struggling to work out how to convert the rest.
Here is the raw query
SELECT
SUM(CASE WHEN t2.field_2 = 1 THEN 1 ELSE 0 END) AS 'lead',
SUM(CASE WHEN t2.field_2 = 2 THEN 1 ELSE 0 END) AS 'in_review',
SUM(CASE WHEN t2.field_2 = 3 THEN 1 ELSE 0 END) AS 'pre_app_sent',
SUM(CASE WHEN t2.field_2 = 4 THEN 1 ELSE 0 END) AS 'pre_app_back',
SUM(CASE WHEN t2.field_2 = 5 THEN 1 ELSE 0 END) AS 'pre_app_ok',
SUM(CASE WHEN t2.field_2 = 6 THEN 1 ELSE 0 END) AS 'awaiting_kyc',
SUM(CASE WHEN t2.field_2 = 7 THEN 1 ELSE 0 END) AS 'kyc_complete',
SUM(CASE WHEN t2.field_2 = 8 THEN 1 ELSE 0 END) AS 'awaiting_full_app_data',
SUM(CASE WHEN t2.field_2 = 9 THEN 1 ELSE 0 END) AS 'full_app_sent',
SUM(CASE WHEN t2.field_2 = 10 THEN 1 ELSE 0 END) AS 'merchant_live'
FROM leads l
JOIN (SELECT
ae.id,
ae.model_id,
ae.fields,
TRIM(BOTH '"' FROM SUBSTRING_INDEX(SUBSTRING_INDEX(ae.fields,';', 1), ':', -1)) AS field_1,
TRIM(BOTH '"' FROM SUBSTRING_INDEX(SUBSTRING_INDEX(ae.fields,';', 2), ':', -1)) AS field_2,
ae.created_at
FROM action_events ae) t2
ON l.id = t2.model_id
WHERE t2.created_at >= '2019-01-01 00:00:00'
AND t2.created_at <= '2019-01-31 23:59:59'
And here is as far as I got with converting it to eloquent
$query->select(
DB::raw('SUM(CASE WHEN t2.field_2 = 1 THEN 1 ELSE 0 END) AS "lead"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 2 THEN 1 ELSE 0 END) AS "in_review"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 3 THEN 1 ELSE 0 END) AS "pre_app_sent"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 4 THEN 1 ELSE 0 END) AS "pre_app_back"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 5 THEN 1 ELSE 0 END) AS "pre_app_ok"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 6 THEN 1 ELSE 0 END) AS "awaiting_kyc"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 7 THEN 1 ELSE 0 END) AS "kyc_complete"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 8 THEN 1 ELSE 0 END) AS "awaiting_full_app_data"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 9 THEN 1 ELSE 0 END) AS "full_app_sent"'),
DB::raw('SUM(CASE WHEN t2.field_2 = 10 THEN 1 ELSE 0 END) AS "merchant_live"'));
This MySQL query gives me this error 'Unknown column 'winnings' in 'field list'
SELECT
o.user_id,
sum(case when o.result = 1 or o.result=2 or o.result = 0 then 1 else 0 end) as tahmins_no,
sum(case when o.result = 1 then 1 else 0 end) as winnings,
sum(case when o.result = 2 then 1 else 0 end) as loses,
sum(case when winnings = 10 then 0.5 else 0 end) as counter
FROM `odds_tahminler` o
I know that winnings is the value of the sum() aggregation function, But is there any way to check the winnings value within the query?
You can't use an aggregated column inside the select. However you can use a subquery to obtain the counter value after all the aggregated columns have been computed.
How is the counter value calculated? I assumed that the counter should be (winnings - 10) / 2 if there's at least 10 winnings and 0 otherwise. In that case you can obtain it with this query
SELECT O.*,
GREATEST( (O.winnings - 10) / 2, 0) as counter
FROM
(
SELECT u.username,
o.user_id,
sum(case when o.result = 1 or o.result=2 or o.result = 0 then 1 else 0 end) as tahmins_no,
sum(case when o.result = 1 then 1 else 0 end) as winnings,
sum(case when o.result = 2 then 1 else 0 end) as loses
FROM `odds_tahminler` o
) as O
you can try:
SELECT
o.user_id,
sum(case when o.result = 1 or o.result=2 or o.result = 0 then 1 else 0 end) as tahmins_no,
sum(case when o.result = 1 then 1 else 0 end) as winnings,
sum(case when o.result = 2 then 1 else 0 end) as loses,
sum(case when winnings = 10 then 0.5 else 0 end) as counter
FROM `odds_tahminler` o
GROUP BY o.user_id
HAVING counter>2
I have a database of user answers from a quiz which contains 8 questions. Q1 - Q8 all are their own columns, I'd like to compare all the rows and get a number back for everyone who answered the same for at least 5 questions.
so here, rows 5 and 6 would count as 2. Basically I'm trying to get a number for everyone who answered at least 5 questions the same. Is this possible with a mySQL query?
EDIT:
Here the user enters D B D A B C D B, matching with 2 similarly answered quizzes. The query here would return a count of 2.
If we test using just your single line of D B D A B C D B we can use the following example:
SELECT * FROM `answers` WHERE ((CASE WHEN q1 = 'D' THEN 1 ELSE 0 END) +
(CASE WHEN q2 = 'B' THEN 1 ELSE 0 END) +
(CASE WHEN q3 = 'D' THEN 1 ELSE 0 END) +
(CASE WHEN q4 = 'A' THEN 1 ELSE 0 END) +
(CASE WHEN q5 = 'B' THEN 1 ELSE 0 END) +
(CASE WHEN q6 = 'C' THEN 1 ELSE 0 END) +
(CASE WHEN q7 = 'D' THEN 1 ELSE 0 END) +
(CASE WHEN q8 = 'B' THEN 1 ELSE 0 END)) >= 5;
However, if we then want to go a step further and test each answer against the other answers in the table we can use the following statement:
SELECT *, (SELECT COUNT(answer_sub.idanswers) FROM `answers` answer_sub
WHERE ((CASE WHEN answer_sub.q1 = a.q1 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q2 = a.q2 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q3 = a.q3 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q4 = a.q4 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q5 = a.q5 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q6 = a.q6 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q7 = a.q7 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q8 = a.q8 THEN 1 ELSE 0 END)) >= 5
AND answer_sub.idanswers <> a.idanswers) as matching
FROM `answers` a
WHERE (SELECT COUNT(answer_sub.idanswers) FROM `answers` answer_sub
WHERE ((CASE WHEN answer_sub.q1 = a.q1 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q2 = a.q2 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q3 = a.q3 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q4 = a.q4 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q5 = a.q5 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q6 = a.q6 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q7 = a.q7 THEN 1 ELSE 0 END) +
(CASE WHEN answer_sub.q8 = a.q8 THEN 1 ELSE 0 END)) >= 5
AND answer_sub.idanswers <> a.idanswers) > 0
Because FALSE is 0 and TRUE is 1 in MySQL:
SELECT COUNT(*)
FROM quiz
WHERE ( (q1=#q1) + (q2=#q2) + (q3=#q3) + (q4=#q4)
+ (q5=#q5) + (q6=#q6) + (q7=#q7) + (q8=#q8)
) >= 5