I have a column called "s_timestamp."
How can I return all the records that have the current day in the timestamp?
For example,
s_timestamp
2012-12-27 1:00:00
2012-12-27 2:00:00
2012-12-26 0:00:01
2012-12-20 0:00:02
2012-12-21 0:00:03
I would like the following output:
2012-12-27 1:00:00
2012-12-27 2:00:00
Let me know if this is unclear.
just use CURDATE(). eg
SELECT *
FROM tableName
WHERE DATE(s_timestamp) = CURDATE()
DATE()
CURDATE()
This may be more efficient than casting the timestamps to DATE, especially if you have an index on the timestamp column (which you should have):
SELECT *
FROM tableName
WHERE s_timestamp >= CURDATE()
or, if you want to exclude any future dates:
SELECT *
FROM tableName
WHERE s_timestamp >= CURDATE()
AND s_timestamp < DATE_ADD(CURDATE(), INTERVAL 1 DAY)
This works because, when a DATETIME or a TIMESTAMP is compared with a DATE, the DATE is, in effect, interpreted as having a time part of 0:00:00.
Related
i am try to request date only yesterday but without success...
My query request.
SELECT registeredDaySell FROM new_sell WHERE DATE_SUB(CURDATE(), INTERVAL 1 DAY)
My date is organized this way.
16 September, 2017
Thanks for helping me out.
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp from employee_login page
Select * FROM `employee_login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)
The below code will display yesterday's timestamp
Select subdate(now(),1) ,subdate(now(),2))
This will give
SELECT producFinalPrice
FROM new_sell
WHERE WEEK (date) = WEEK( current_date ) - 1
As #Gordon mentioned, you should consider storing your dates either in some date type column, or possibly as a UNIX timestamp (seconds since the epoch). A possible workaround here would be to use STR_TO_DATE to convert your string dates to bona fide dates on the fly.
SELECT
producFinalPrice
FROM new_sell
WHERE
STR_TO_DATE(date_col, '%d %M, %Y') = DATE_SUB(CURDATE(), INTERVAL 1 DAY)
This assumes that date_col is the name of the column in your table which contains string dates.
SELECT producFinalPrice FROM new_sell
WHERE where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
-1 equates to "today" minus 1 day. You can change that number to get the number of days that you want to go back if further than 1.
I have this record in expiry_date column:
2015-04-30 04:15:29
2015-04-22 06:02:07
I need to select where the record is 26 days from expiring. Right now I'm using this which is not working. No records were selected.
SELECT * FROM `client` WHERE `expiry_date` = DATE_ADD(NOW(), INTERVAL 26 DAY)
I've searched this website and many of the answers are using <= operator. This solution partially work. It selects both of my record when I only need 2015-04-30 04:15:29 in expiry_date column.
How do I exactly select date that is going to expired and not all date?
The easy solution to this is to use the date function:
WHERE DATE(expiry_date) = DATE_ADD(CURRENT_DATE, INTERVAL 26 DAY)
However, this prevents the use of an index on expiry_date. An alternative that does work with indexes is:
WHERE expiry_date >= DATE_ADD(CURRENT_DATE, INTERVAL 26 DAY) AND
expiry_date < DATE_ADD(CURRENT_DATE, INTERVAL 26 + 1 DAY)
The reason you're having this issue is that expiry_date is a type of datetime so the time makes it not equal. Just change your code to be:
SELECT * FROM client WHERE DATE(expiry_date) = DATE(DATE_ADD(NOW(), INTERVAL 26 DAY))
I have a table session_dates with some fields and a timestamp field named timestart.
What I would like to do is select all the records from my table where the field timestart (TIMESTAMP) is equal to 21 days from now.
Like for example if today is 27 januari -> 17 februari.
I know how I can select all between two dates.
My SQL Query for between 2 dates:
SELECT timestart, timefinish, sessionid
FROM sessions_dates
WHERE timestart BETWEEN UNIX_TIMESTAMP(NOW()) AND UNIX_TIMESTAMP(DATE_ADD(NOW(), INTERVAL 21 DAY))
But how to select equal to a date?
UPDATE:
I know now that I just have to use the = statement. But how can I test this? How do I know what the UNIX_TIMESTAMP(DATE_ADD(NOW(), INTERVAL 21 DAY)) returns?
I think you want:
SELECT timestart, timefinish, sessionid
FROM sessions_dates
WHERE timestart >= UNIX_TIMESTAMP(DATE_ADD(NOW(), INTERVAL 21 DAY)) AND
tmestamp < UNIX_TIMESTAMP(DATE_ADD(NOW(), INTERVAL 22 DAY))
Presumably, timestart has a time component. This version takes that into account and still would allow the use of an index on timestart.
I am trying to compare timestamps by finding out if particular timestamp field is greater than 15 days ago.
So if I try this on my database, I get:
SELECT DATE_SUB(NOW(), INTERVAL 15 DAY) // 2012-04-08 11:00:54
The field concerned has a value: 2012-04-20 21:18:14.
So when I try:
SELECT * FROM (`payments`) WHERE `LastUpdated` >= 'DATE_SUB(NOW(), INTERVAL 15 DAY)'
I get no rows returned? Am I comparing dates incorrectly?
You are treating the DATE_SUB function as a string.
Try this instead:
SELECT * FROM (`payments`) WHERE `LastUpdated` >= DATE_SUB(NOW(), INTERVAL 15 DAY)
I would like to rows that have only been entered in the last 1 day.
I have a date column which stores YYYY-MM-DD, and I allow the user to send a date that they want to look at in this format yyymmdd how can I use this data to limit it to the previous day only?
I would imagine it is something to do with the BETWEEN keyword but I cant figure it out.
SELECT * from TABLE_NAME WHERE ROW_DATE BETWEEN '2011-03-20' AND '2011-03-21'
This query:
SELECT *
FROM mytable
WHERE mydate >= STR_TO_DATE('110321', '%y%m%d') - INTERVAL 1 DAY
AND mydate < STR_TO_DATE('110321', '%y%m%d')
will return all records for Mar 20, 2011
From the MySQL manual (here):
SELECT something FROM tbl_name WHERE DATE_SUB(CURDATE(), INTERVAL 1 DAY) <= date_col;
SELECT * FROM YourTable WHERE date_column = DATE_ADD(CURDATE(), INTERVAL -1 DAY)
This returns all rows for today and yesterday.