I run the above sql statement and i got this.[IMG]http://i1093.photobucket.com/albums/i422/walkgirl_1993/asd-1_zps5506632e.jpg[/IMG] i'm trying display the latest date which you can see the 3 and 4. For caseid 3, it should display the latest row which is the 2012-12-20 16:12:36.000. I tried using group by, order by. Google some website said to use rank but i'm not sure about the rank as i dont really get rank. Some suggestions?
select [Case].CaseID, Agent.AgentName, Assignment.Description, A.AgentName as EditedBy, A.DateEdited from Agent inner join [Case-Agent] on [Case-Agent].AgentID = Agent.AgentID inner join [Assignment] on Assignment.AssignmentID = [Case-Agent].AssignmentID inner join [Case] on [Case].CaseID = [Case-Agent].CaseID inner join (select EditedCase.CaseID, [EditedCase].DateEdited, [Agent].AgentName from EditedCase inner join [Agent] on [Agent].AgentID = [EditedCase].AgentID) A on A.CaseID = [Case].CaseID where [Assignment].AssignmentID = 0
To do it using RANK you just need to add the RANK to the subquery and get to rank the DateEdited for each CaseID and Agent and then in the main query put a WHERE clause to only select rows where the rank is 1. I think I have got the partition clause right - its a bit hard without seeing your data.
Like this:
SELECT
[Case].CaseID
,Agent.AgentName
,Assignment.Description
,A.AgentName AS EditedBy
,A.DateEdited
FROM Agent
INNER JOIN [Case-Agent] ON [Case-Agent].AgentID = Agent.AgentID
INNER JOIN [Assignment] ON Assignment.AssignmentID = [Case-Agent].AssignmentID
INNER JOIN [Case] ON [Case].CaseID = [Case-Agent].CaseID
INNER JOIN (SELECT
EditedCase.CaseID
,[EditedCase].DateEdited
,[Agent].AgentName
,RANK ( ) OVER (PARTITION BY EditedCase.CaseID, [Agent].AgentName
ORDER BY [EditedCase].DateEdited DESC ) AS pos
FROM EditedCase
INNER JOIN [Agent] on [Agent].AgentID = [EditedCase].AgentID) A on A.CaseID = [Case].CaseID
WHERE [Assignment].AssignmentID = 0
AND pos = 1
You could also change the sub query into an aggregate query that brings back the MAX date like this:
SELECT
[Case].CaseID
,Agent.AgentName
,Assignment.Description
,A.AgentName AS EditedBy
,A.DateEdited
FROM Agent
INNER JOIN [Case-Agent] ON [Case-Agent].AgentID = Agent.AgentID
INNER JOIN [Assignment] ON Assignment.AssignmentID = [Case-Agent].AssignmentID
INNER JOIN [Case] ON [Case].CaseID = [Case-Agent].CaseID
INNER JOIN (SELECT
EditedCase.CaseID
,MAX([EditedCase].DateEdited) AS DateEdited
,[Agent].AgentName
FROM EditedCase
INNER JOIN [Agent] on [Agent].AgentID = [EditedCase].AgentID
GROUP BY
EditedCase.CaseID
,[Agent].AgentName) A on A.CaseID = [Case].CaseID
WHERE [Assignment].AssignmentID = 0
AND pos = 1
You were on the right track; you need to use a ranking function here, for example row_number():
with LatestCase as
(
select [Case].CaseID
, Agent.AgentName
, Assignment.Description
, A.AgentName as EditedBy
, A.DateEdited
, caseRank = row_number() over (partition by [Case].CaseID order by A.DateEdited desc)
from Agent
inner join [Case-Agent] on [Case-Agent].AgentID = Agent.AgentID
inner join [Assignment] on Assignment.AssignmentID = [Case-Agent].AssignmentID
inner join [Case] on [Case].CaseID = [Case-Agent].CaseID
inner join
(
select EditedCase.CaseID
, [EditedCase].DateEdited
, [Agent].AgentName
from EditedCase
inner join [Agent] on [Agent].AgentID = [EditedCase].AgentID
) A on A.CaseID = [Case].CaseID where [Assignment].AssignmentID = 0
)
select *
from LatestCase
where caseRank = 1
Related
I want to have a subquery which returns multiple rows in MySQL. I used the IN function as well. However i am getting a "subquery returning multiple rows" error. I have attached an image of the tables used and the desired output
Here is my SQL code:
Select t2.STUID, t3.UnitCmd, //main query
(Select count(*) as 'FullDutyCount' from stormtroopers_officer A1 inner join st_officer_assign A2 ON A1.STID = A2.STID where A2.STUID IN('STU-1','STU-2','STU-3') AND A1.DutyStatus = 'Full Duty' group by A1.Dutystatus,A2.STUID), //subquery1
(Select count(*) as 'WoundedCount' from stormtroopers_officer A1 inner join st_officer_assign A2 ON A1.STID = A2.STID where A2.STUID IN('STU-1','STU-2','STU-3') AND A1.DutyStatus = 'Wounded' group by A1.Dutystatus,A2.STUID),//subquery2
(Select count(*) as 'KilledCount' from stormtroopers_officer A1 inner join st_officer_assign A2 ON A1.STID = A2.STID where A2.STUID IN('STU-1','STU-2','STU-3') AND A1.DutyStatus = 'Killed' group by A1.Dutystatus,A2.STUID) //subquery 3
FROM stormtroopers_officer t1 inner join st_officer_assign t2 ON t1.STID = t2.STID
inner join stormtrooper_unit t3 ON t2.STUID = t3.STUID where t2.STUID IN ('STU-1','STU-2','STU-3') group by t1.Dutystatus,t2.STUID;
You seem to want conditional aggregation:
select
su.stuid,
su.unitCmd unitHQ,
sum(so.dutyStatus = 'Full Duty') fullDutyCount,
sum(so.dutyStatus = 'Wounded' ) woundedCount,
sum(so.dutyStatus = 'Killed' ) killedCount
from st_officier_assign soa
inner join stormtrooper_unit su on su.stuid = soa.stuid
inner join stormtrooper_officer so on so.stid = so.stid
where su.stuid in ('STU-1','STU-2','STU-3')
group by su.stuid, su.unitCmd
Please check the below code.
SELECT
`order`.idorder
, order_status_code.idorder_status_code
, order_status_code.order_status_code
, user.iduser
, `order`.required_delivery_date
, `order`.cancel
, `order`.date_created
, `order`.last_updated
, COUNT(order_item.idorder_item)
from
`order`
INNER JOIN order_status_code
ON `order`.idorder_status_code = order_status_code.idorder_status_code
INNER JOIN user
ON `order`.iduser = user.iduser
INNER JOIN order_item
ON order_item.idorder = `order`.`idorder`
WHERE
`order`.iduser = 1
In here, I want the COUNT(order_item.idorder_item) to return the number of items under the idorder. In other words, if I run that SQL Part along, that would be like below
SELECT
COUNT(`idorder_item`)
from
order_item
where
idorder = 1
How can I get this done in my main query?
SELECT `order`.idorder,
order_status_code.idorder_status_code,
order_status_code.order_status_code,
user.iduser,
`order`.required_delivery_date,
`order`.cancel,
`order`.date_created,
`order`.last_updated,
COUNT(order_item.idorder_item),
(SELECT COUNT(`idorder_item`)
from order_item
where idorder=1) as count_idorder_item
from `order`
INNER JOIN order_status_code ON `order`.idorder_status_code = order_status_code.idorder_status_code
INNER JOIN user ON `order`.iduser = user.iduser
INNER JOIN order_item ON order_item.idorder = `order`.`idorder`
WHERE `order`.iduser= 1
I have the following query:
SELECT e_c.*, c.name, j.status, j.version, j.articleId, j.title FROM assetcategory AS c
INNER JOIN assetentries_assetcategories AS e_c
ON c.categoryId = e_c.categoryId AND c.name = 'news'
INNER JOIN assetentry AS e
ON e.entryId = e_c.entryId
INNER JOIN journalarticle AS j
ON j.resourcePrimKey = e.classPK
AND e.classNameId = (SELECT classNameId FROM classname_ WHERE value = 'com.liferay.portlet.journal.model.JournalArticle')
AND j.companyId= e.companyId
WHERE j.status = 0
which returns all the category news in the journalarticles. From the results I need to select the most recent versions for each articleId. For example suppose there is an article with 4 versions, even with different title, it is the same article because it will have the same articleId. So therefore for each unique articleId I need the latest version. How can I do that?
Add a join to a subquery which finds the most recent version for each article:
SELECT e_c.*, c.name, j1.status, j1.version, j1.articleId, j1.title
FROM assetcategory AS c
INNER JOIN assetentries_assetcategories AS e_c
ON c.categoryId = e_c.categoryId AND c.name = 'news'
INNER JOIN assetentry AS e
ON e.entryId = e_c.entryId
INNER JOIN journalarticle AS j1
ON j1.resourcePrimKey = e.classPK AND
e.classNameId = (SELECT classNameId FROM classname_
WHERE value = 'com.liferay.portlet.journal.model.JournalArticle') AND
j.companyId = e.companyId
INNER JOIN
(
SELECT articleId, MAX(version) AS max_version
FROM journalarticle
WHERE status = 0
GROUP BY articleId
) j2
ON j1.articleId = j2.articleId AND j1.version = j2.max_version;
The basic idea behind the join to the subquery aliased as j2 above is that it restricts the result set to only the most recent version of each article. We don't necessarily have to change the rest of the query.
Here's the code:
SELECT RD.INTREQDQUANTITY, I.strItemName, v.strVendName, iu.strItemUnitName,
ip.dblItemPAmount, MAX(ip.dtmItemPasOf) AS EXR
FROM TBLREQUESTDETAILS RD,tblitem I,tblvendor v,tblitemunit iu,tblitemprice ip`
WHERE RD.strReqDItemCode = I.strItemCode
AND RD.strReqDItemUnitCode = iu.strItemUnitCode
AND RD.strReqDVendCode = v.strVendCode
AND i.strItemCode = ip.strItemPItemCode
and RD.strReqDReqHCode = 'RQST121'
GROUP BY RD.INTREQDQUANTITY,I.strItemName,v.strVendName,iu.strItemUnitName, ip.dblItemPAmount
ORDER BY EXR desc ;
AND Here's The result:
What should I do If I want to fetch the current price for each itemname,vendorname and itemunit?? I want to fetch only those rows who's price is the Latest... Help me please those with boxes are the rows that i want to fetch
You can use where in the grouped value (and use explicict join notatio)
SELECT RD.INTREQDQUANTITY, I.strItemName, v.strVendName, iu.strItemUnitName,
ip.dblItemPAmount, ip.dtmItemPasOf AS EXR
FROM TBLREQUESTDETAILS RD
INNER JOIN tblitem I ON RD.strReqDItemCode = I.strItemCode
INNER JOIN tblvendor v ON D.strReqDVendCode = v.strVendCode
INNER JOIN tblitemunit iu ON RD.strReqDItemUnitCode = iu.strItemUnitCode
INNER JOIN tblitemprice ip ON i.strItemCode = ip.strItemPItemCode
WHERE RD.strReqDReqHCode = 'RQST121'
and ( RD.INTREQDQUANTITY, I.strItemName, v.strVendName, iu.strItemUnitName, ip.dtmItemPasOf)
in ( SELECT RD.INTREQDQUANTITY, I.strItemName, v.strVendName, iu.strItemUnitName,
MAX(ip.dtmItemPasOf)
FROM TBLREQUESTDETAILS RD
INNER JOIN tblitem I ON RD.strReqDItemCode = I.strItemCode
INNER JOIN tblvendor v ON D.strReqDVendCode = v.strVendCode
INNER JOIN tblitemunit iu ON RD.strReqDItemUnitCode = iu.strItemUnitCode
INNER JOIN tblitemprice ip ON i.strItemCode = ip.strItemPItemCode
WHERE RD.strReqDReqHCode = 'RQST121'
GROUP BY RD.INTREQDQUANTITY,I.strItemName,v.strVendName,iu.strItemUnitName
)
ORDER BY EXR desc ;
(and use explicict join notation .. i think is more readable)
Here is the database schema:
[redacted]
I'll describe what I'm doing with the query below:
Innermost query: Select all the saleIds satisfying the WHERE conditions
Middle query: Select all the productIds that were a part of the saleId
Outermost query: SUM the products.cost and select the vendors.name.
And here is the SQL query I came up with:
SELECT vendors.name AS Company
, SUM(products.cost) AS Revenue
FROM
products
INNER JOIN sold_products
ON (products.productId = sold_products.productId)
INNER JOIN vendors
ON (products.vendorId = vendors.vendorId)
WHERE sold_products.productId IN (
SELECT sold_products.productId
FROM
sold_products
WHERE sold_products.saleId IN (
SELECT sales.saleId
FROM
markets
INNER JOIN vendors
ON (markets.vendorId = vendors.vendorId)
INNER JOIN sales_campaign
ON (sales_campaign.marketId = markets.marketId)
INNER JOIN packet_headers
ON (sales_campaign.packetHeaderId = packet_headers.packetHeaderId)
INNER JOIN packet_details
ON (packet_details.packetHeaderId = packet_headers.packetHeaderId)
INNER JOIN sales
ON (sales.packetDetailsId = packet_details.packetDetailsId)
WHERE vendors.customerId=60
)
)
GROUP BY Company
ORDER BY Revenue DESC;
Any help in optimizing this?
Since you are just using inner joins you normally simplify the query to smth like this:
SELECT ve.name AS Company
, SUM(pr.cost) AS Revenue
FROM products pr
, sold_products sp
, vendors ve
, markets ma
, sales_campaign sc
, packet_headers ph
, packet_details pd
, sales sa
Where pr.productId = sp.productId
And pr.vendorId = ve.vendorId
And ve.vendorId = ma.vendorId
And sc.marketId = ma.marketId
And sc.packetHeaderId = ph.packetHeaderId
And pd.packetHeaderId = ph.packetHeaderId)
And sa.packetDetailsId = pd.packetDetailsId
And ve.customerId = 60
GROUP BY ve.Company
ORDER BY pr.Revenue DESC;
Please try if this works and if it is faster and let me know.