Get images from wordpress post with json in windows phone - json

I would like to get Images from a wordpress Blog. I would start only with one post not with all the posts images.
I am using this code. It works to get the title, excerpt, url... But I cant get images :
namespace WpWordpressJson
{
public class MainViewModel : INotifyPropertyChanged
{
public MainViewModel()
{
this.Items = new ObservableCollection<ItemViewModel>();
}
/// <summary>
/// A collection for ItemViewModel objects.
/// </summary>
public ObservableCollection<ItemViewModel> Items { get; private set; }
private string _sampleProperty = "Sample Runtime Property Value";
/// <summary>
/// Sample ViewModel property; this property is used in the view to display its value using a Binding
/// </summary>
/// <returns></returns>
public string SampleProperty
{
get
{
return _sampleProperty;
}
set
{
if (value != _sampleProperty)
{
_sampleProperty = value;
NotifyPropertyChanged("SampleProperty");
}
}
}
public bool IsDataLoaded
{
get;
private set;
}
/// <summary>
/// Creates and adds a few ItemViewModel objects into the Items collection.
/// </summary>
public void LoadData()
{
WebRequest.RegisterPrefix("http://automaticband.es/bio/", WebRequestCreator.ClientHttp);
Uri serviceUri = new Uri("http://automaticband.es/bio/?json=get_recent_posts");
WebClient downloader = new WebClient();
downloader.OpenReadCompleted += new OpenReadCompletedEventHandler(downloader_OpenReadCompleted);
downloader.OpenReadAsync(serviceUri);
}
public event PropertyChangedEventHandler PropertyChanged;
private void NotifyPropertyChanged(String propertyName)
{
PropertyChangedEventHandler handler = PropertyChanged;
if (null != handler)
{
handler(this, new PropertyChangedEventArgs(propertyName));
}
}
void downloader_OpenReadCompleted(object sender, OpenReadCompletedEventArgs e)
{
if (e.Error == null)
{
try
{
Stream responseStream = e.Result;
DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(Posts));
Posts response = (Posts)ser.ReadObject(responseStream);
if (response.posts != null && response.posts.Count > 0)
{
foreach (Post post in response.posts)
{
this.Items.Add(new ItemViewModel() { LineOne = post.title, LineTwo = post.excerpt });
}
}
}
catch (Exception x)
{
return;
}
this.IsDataLoaded = true;
}
}
}
[DataContract]
public class Post
{
[DataMember]
public int id;
[DataMember]
public string type;
[DataMember]
public string slug;
[DataMember]
public string title;
[DataMember]
public string content;
[DataMember]
public string excerpt;
}
[DataContract]
public class Posts
{
[DataMember]
public int count;
[DataMember]
public int count_total;
[DataMember]
public List<Post> posts;
}
I got it from this site:
http://kevinashley.com/connect-windows-phone-7-apps-to-wordpress-using-json/
Thank you for all

You are missing the DataMember for thumbnails in Post. Here you can find a full class for WordPress JSON API: http://msicc.net/?p=2929
Hope this helps :-)

Related

Api Controller: Json decapitalizes the names of properties

I have an api controller in my webcore application:
[Route("api/[controller]")]
public class DataController : Controller
{
protected ApplicationDbContext dbContext;
public DataController(ApplicationDbContext dc)
{
dbContext = dc;
}
[HttpGet("Categories")]
public List<Category> GetCategories()
{
var l = dbContext.Categories.OrderBy(c => c.Name).ToList();
return l;
}
}
And the class:
public class Category
{
public long Id { get; set; }
public string Name { get; set; }
public string Description { get; set; }
}
When I Invoke the controller action to get the categories, in the response the name of properties are all decapitalized. That is:
Id becomes id,
Name becomes name,
Description becomes description.
**Edit:
I have tried also:
[HttpGet("Test")]
public IActionResult Test()
{
var l = dbContext.Categories.OrderBy(c => c.Name).ToList();
return Json(l);
}
And still the properties are all decapitalized
/// <summary>
/// Welcome Note Message
/// </summary>
/// <returns>In a Json Format</returns>
public JsonResult WelcomeNote()
{
Category cs = new Category();
cs.Id = 123456;
cs.Name = "ExampleName";
cs.Description = "Abcd";
return Json(cs, JsonRequestBehavior.AllowGet);
}
This, I am getting from above code which you want I guess
Refer this for more good Examples

Jackson JSON Can not construct instance of "About" : deserialize issue

I've make HttpsURLConnection to receive some information about my server.
The result of response is :
{"about":{"title":"NiFi","version":"1.1.0","uri":"https://localhost:443/api/","contentViewerUrl":"/nifi-content-viewer/","timezone":"CET"}}
How is possible to extract all attributes and key/value ?
About.class file
public class About {
private List<AboutObject> about;
public About()
{
// this.about = about;
}
public List<AboutObject> getAbout() {
return this.about;
}
public void setAbout(List<AboutObject> about) {
this.about = about;
}
}
AboutObject.class
public class AboutObject {
private String title;
private String uri;
private String contentViewerUrl;
private String timezone;
public String getTitle()
{
return this.title;
}
public void setTitle(String title)
{
this.title = title;
}
public String getUri()
{
return this.uri;
}
public void setUri(String uri)
{
this.uri = uri;
}
public String getContentViewerUrl()
{
return this.contentViewerUrl;
}
public void setContentViewerUrl(String contentViewerUrl)
{
this.contentViewerUrl = contentViewerUrl;
}
public String getTimeZone()
{
return this.timezone;
}
public void setTimeZone(String timezone)
{
this.timezone = timezone;
}
}
Main.class
HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();
// optional default is GET
con.setRequestMethod("GET");
//add request header
con.setRequestProperty("User-Agent", USER_AGENT);
int responseCode = con.getResponseCode();
System.out.println("\nSending 'GET' request to URL : " + url);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
//print result
System.out.println(response.toString());
System.out.println("Contenu de in = " + in.toString());
ObjectMapper mapper = new ObjectMapper();
//Staff objStaff = new Staff();
System.out.println("Object to JSON in file");
mapper.writeValue(new File("output/file.json"), response);
System.out.println("Convert JSON string from file to Object");
//String about = mapper.readValue(new File("output/file.json"), String.class);
About about = mapper.readValue(new File("output/file.json"), About.class);
Error
Exception in thread "main" com.fasterxml.jackson.databind.JsonMappingException: Can not construct instance of About: no String-argument constructor/factory method to deserialize from String value ('{"about":{"title":"NiFi","version":"1.1.0","uri":"https://localhost:443/api/","contentViewerUrl":"/nifi-content-viewer/","timezone":"CET"}}') at [Source: output/file.json; line: 1, column: 1]
Thanks for you help
The test json you show doesn't have the array wrapper used in your About object. You're also missing the version field in your AboutObject and the timezone field uses the wrong case.
Your example worked when I updated your objects:
public class About {
private AboutObject about;
public AboutObject getAbout() {
return about;
}
public void setAbout(AboutObject about) {
this.about = about;
}
}
public class AboutObject {
private String title;
private String uri;
private String contentViewerUrl;
private String timezone;
private String version;
public String getTitle() {
return this.title;
}
public void setTitle(String title) {
this.title = title;
}
public String getUri() {
return this.uri;
}
public void setUri(String uri) {
this.uri = uri;
}
public String getContentViewerUrl() {
return this.contentViewerUrl;
}
public void setContentViewerUrl(String contentViewerUrl) {
this.contentViewerUrl = contentViewerUrl;
}
public String getTimezone() {
return timezone;
}
public void setTimezone(String timezone) {
this.timezone = timezone;
}
public String getVersion() {
return version;
}
public void setVersion(String version) {
this.version = version;
}
}
Test:
public static void main(String[] args) throws IOException {
ObjectMapper mapper = new ObjectMapper();
String obj = "{\"about\":{\"title\":\"NiFi\",\"version\":\"1.1.0\",\"uri\":\"https://localhost:443/api/\",\"contentViewerUrl\":\"/nifi-content-viewer/\",\"timezone\":\"CET\"}}";
About about = mapper.readValue(obj, About.class);
}

.NET NewtonSoft JSON deserialize map to a different property name

I have following JSON string which is received from an external party.
{
"team":[
{
"v1":"",
"attributes":{
"eighty_min_score":"",
"home_or_away":"home",
"score":"22",
"team_id":"500"
}
},
{
"v1":"",
"attributes":{
"eighty_min_score":"",
"home_or_away":"away",
"score":"30",
"team_id":"600"
}
}
]
}
My mapping classes:
public class Attributes
{
public string eighty_min_score { get; set; }
public string home_or_away { get; set; }
public string score { get; set; }
public string team_id { get; set; }
}
public class Team
{
public string v1 { get; set; }
public Attributes attributes { get; set; }
}
public class RootObject
{
public List<Team> team { get; set; }
}
The question is that I don't like the Attributes class name and the attributes field names in the Team class. Instead, I want it to be named TeamScore and also to remove _ from the field names and give proper names.
JsonConvert.DeserializeObject<RootObject>(jsonText);
I can rename Attributes to TeamScore, but if I change the field name (attributes in the Team class), it won't deserialize properly and gives me null. How can I overcome this?
Json.NET - Newtonsoft has a JsonPropertyAttribute which allows you to specify the name of a JSON property, so your code should be:
public class TeamScore
{
[JsonProperty("eighty_min_score")]
public string EightyMinScore { get; set; }
[JsonProperty("home_or_away")]
public string HomeOrAway { get; set; }
[JsonProperty("score ")]
public string Score { get; set; }
[JsonProperty("team_id")]
public string TeamId { get; set; }
}
public class Team
{
public string v1 { get; set; }
[JsonProperty("attributes")]
public TeamScore TeamScores { get; set; }
}
public class RootObject
{
public List<Team> Team { get; set; }
}
Documentation: Serialization Attributes
If you'd like to use dynamic mapping, and don't want to clutter up your model with attributes, this approach worked for me
Usage:
var settings = new JsonSerializerSettings();
settings.DateFormatString = "YYYY-MM-DD";
settings.ContractResolver = new CustomContractResolver();
this.DataContext = JsonConvert.DeserializeObject<CountResponse>(jsonString, settings);
Logic:
public class CustomContractResolver : DefaultContractResolver
{
private Dictionary<string, string> PropertyMappings { get; set; }
public CustomContractResolver()
{
this.PropertyMappings = new Dictionary<string, string>
{
{"Meta", "meta"},
{"LastUpdated", "last_updated"},
{"Disclaimer", "disclaimer"},
{"License", "license"},
{"CountResults", "results"},
{"Term", "term"},
{"Count", "count"},
};
}
protected override string ResolvePropertyName(string propertyName)
{
string resolvedName = null;
var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
}
}
Adding to Jacks solution. I need to Deserialize using the JsonProperty and Serialize while ignoring the JsonProperty (or vice versa). ReflectionHelper and Attribute Helper are just helper classes that get a list of properties or attributes for a property. I can include if anyone actually cares. Using the example below you can serialize the viewmodel and get "Amount" even though the JsonProperty is "RecurringPrice".
/// <summary>
/// Ignore the Json Property attribute. This is usefule when you want to serialize or deserialize differently and not
/// let the JsonProperty control everything.
/// </summary>
/// <typeparam name="T"></typeparam>
public class IgnoreJsonPropertyResolver<T> : DefaultContractResolver
{
private Dictionary<string, string> PropertyMappings { get; set; }
public IgnoreJsonPropertyResolver()
{
this.PropertyMappings = new Dictionary<string, string>();
var properties = ReflectionHelper<T>.GetGetProperties(false)();
foreach (var propertyInfo in properties)
{
var jsonProperty = AttributeHelper.GetAttribute<JsonPropertyAttribute>(propertyInfo);
if (jsonProperty != null)
{
PropertyMappings.Add(jsonProperty.PropertyName, propertyInfo.Name);
}
}
}
protected override string ResolvePropertyName(string propertyName)
{
string resolvedName = null;
var resolved = this.PropertyMappings.TryGetValue(propertyName, out resolvedName);
return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
}
}
Usage:
var settings = new JsonSerializerSettings();
settings.DateFormatString = "YYYY-MM-DD";
settings.ContractResolver = new IgnoreJsonPropertyResolver<PlanViewModel>();
var model = new PlanViewModel() {Amount = 100};
var strModel = JsonConvert.SerializeObject(model,settings);
Model:
public class PlanViewModel
{
/// <summary>
/// The customer is charged an amount over an interval for the subscription.
/// </summary>
[JsonProperty(PropertyName = "RecurringPrice")]
public double Amount { get; set; }
/// <summary>
/// Indicates the number of intervals between each billing. If interval=2, the customer would be billed every two
/// months or years depending on the value for interval_unit.
/// </summary>
public int Interval { get; set; } = 1;
/// <summary>
/// Number of free trial days that can be granted when a customer is subscribed to this plan.
/// </summary>
public int TrialPeriod { get; set; } = 30;
/// <summary>
/// This indicates a one-time fee charged upfront while creating a subscription for this plan.
/// </summary>
[JsonProperty(PropertyName = "SetupFee")]
public double SetupAmount { get; set; } = 0;
/// <summary>
/// String representing the type id, usually a lookup value, for the record.
/// </summary>
[JsonProperty(PropertyName = "TypeId")]
public string Type { get; set; }
/// <summary>
/// Billing Frequency
/// </summary>
[JsonProperty(PropertyName = "BillingFrequency")]
public string Period { get; set; }
/// <summary>
/// String representing the type id, usually a lookup value, for the record.
/// </summary>
[JsonProperty(PropertyName = "PlanUseType")]
public string Purpose { get; set; }
}
Expanding Rentering.com's answer, in scenarios where a whole graph of many types is to be taken care of, and you're looking for a strongly typed solution, this class can help, see usage (fluent) below. It operates as either a black-list or white-list per type. A type cannot be both (Gist - also contains global ignore list).
public class PropertyFilterResolver : DefaultContractResolver
{
const string _Err = "A type can be either in the include list or the ignore list.";
Dictionary<Type, IEnumerable<string>> _IgnorePropertiesMap = new Dictionary<Type, IEnumerable<string>>();
Dictionary<Type, IEnumerable<string>> _IncludePropertiesMap = new Dictionary<Type, IEnumerable<string>>();
public PropertyFilterResolver SetIgnoredProperties<T>(params Expression<Func<T, object>>[] propertyAccessors)
{
if (propertyAccessors == null) return this;
if (_IncludePropertiesMap.ContainsKey(typeof(T))) throw new ArgumentException(_Err);
var properties = propertyAccessors.Select(GetPropertyName);
_IgnorePropertiesMap[typeof(T)] = properties.ToArray();
return this;
}
public PropertyFilterResolver SetIncludedProperties<T>(params Expression<Func<T, object>>[] propertyAccessors)
{
if (propertyAccessors == null)
return this;
if (_IgnorePropertiesMap.ContainsKey(typeof(T))) throw new ArgumentException(_Err);
var properties = propertyAccessors.Select(GetPropertyName);
_IncludePropertiesMap[typeof(T)] = properties.ToArray();
return this;
}
protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
{
var properties = base.CreateProperties(type, memberSerialization);
var isIgnoreList = _IgnorePropertiesMap.TryGetValue(type, out IEnumerable<string> map);
if (!isIgnoreList && !_IncludePropertiesMap.TryGetValue(type, out map))
return properties;
Func<JsonProperty, bool> predicate = jp => map.Contains(jp.PropertyName) == !isIgnoreList;
return properties.Where(predicate).ToArray();
}
string GetPropertyName<TSource, TProperty>(
Expression<Func<TSource, TProperty>> propertyLambda)
{
if (!(propertyLambda.Body is MemberExpression member))
throw new ArgumentException($"Expression '{propertyLambda}' refers to a method, not a property.");
if (!(member.Member is PropertyInfo propInfo))
throw new ArgumentException($"Expression '{propertyLambda}' refers to a field, not a property.");
var type = typeof(TSource);
if (!type.GetTypeInfo().IsAssignableFrom(propInfo.DeclaringType.GetTypeInfo()))
throw new ArgumentException($"Expresion '{propertyLambda}' refers to a property that is not from type '{type}'.");
return propInfo.Name;
}
}
Usage:
var resolver = new PropertyFilterResolver()
.SetIncludedProperties<User>(
u => u.Id,
u => u.UnitId)
.SetIgnoredProperties<Person>(
r => r.Responders)
.SetIncludedProperties<Blog>(
b => b.Id)
.Ignore(nameof(IChangeTracking.IsChanged)); //see gist
I am using JsonProperty attributes when serializing but ignoring them when deserializing using this ContractResolver:
public class IgnoreJsonPropertyContractResolver: DefaultContractResolver
{
protected override IList<JsonProperty> CreateProperties(Type type, MemberSerialization memberSerialization)
{
var properties = base.CreateProperties(type, memberSerialization);
foreach (var p in properties) { p.PropertyName = p.UnderlyingName; }
return properties;
}
}
The ContractResolver just sets every property back to the class property name (simplified from Shimmy's solution). Usage:
var airplane= JsonConvert.DeserializeObject<Airplane>(json,
new JsonSerializerSettings { ContractResolver = new IgnoreJsonPropertyContractResolver() });
Also if you want to ignore something use this
[JsonIgnore]
public int Id { get; set; }
[JsonProperty("id")]
Public string real_id { get; set; }

How can I deseralize json object in java pojo class?

I have a simple JSON statement which type is very per need. like this
{
actor:{name:"kumar",mbox:"kumar#gmail.com"}
verb :"completed"
}
or
{
actor:{name:["kumar","manish"],mbox:["kumar#gmail.com","manish#gmail.com"]}
verb :{
"id" : "http://adlnet.gov/expapi/verbs/completed",
"display" : {
"en-US" : "completed"
}
}
I am using using POJO class to map this json string and pojo class code is given bleow
#JsonProperty("actor")
Actor actor;
#JsonProperty("verb")
Verb objVerb;
#JsonProperty("verb")
String verb;
public Actor getActor() {
return actor;
}
public void setActor(Actor actor) {
this.actor = actor;
}
public Verb getObjVerb() {
return objVerb;
}
public void setObjVerb(Verb objVerb) {
this.objVerb = objVerb;
}
#JsonIgnore
public String getVerb() {
return verb;
}
#JsonIgnore
public void setVerb(String verb) {
this.verb = verb;
}
public static class Actor {
String objectType;
#JsonProperty("name")
ArrayList<String> listName;
#JsonProperty("name")
String name;
#JsonProperty("mbox")
ArrayList<String> listMbox;
#JsonProperty("mbox")
String mbox;
#JsonProperty("mbox_sha1sum")
ArrayList<String> Listmbox_sha1sum;
#JsonProperty("mbox_sha1sum")
String mbox_sha1sum;
#JsonProperty("openid")
String openid;
#JsonProperty("account")
Account account;
public String getObjectType() {
return objectType;
}
public void setObjectType(String objectType) {
this.objectType = objectType;
}
public ArrayList<String> getListName() {
return listName;
}
public void setListName(ArrayList<String> listName) {
this.listName = listName;
}
#JsonIgnore
public String getName() {
return name;
}
#JsonIgnore
public void setName(String name) {
this.name = name;
}
public ArrayList<String> getListMbox() {
return listMbox;
}
public void setListMbox(ArrayList<String> listMbox) {
this.listMbox = listMbox;
}
#JsonIgnore
public String getMbox() {
return mbox;
}
#JsonIgnore
public void setMbox(String mbox) {
this.mbox = mbox;
}
public ArrayList<String> getListmbox_sha1sum() {
return Listmbox_sha1sum;
}
public void setListmbox_sha1sum(ArrayList<String> listmbox_sha1sum) {
Listmbox_sha1sum = listmbox_sha1sum;
}
#JsonIgnore
public String getMbox_sha1sum() {
return mbox_sha1sum;
}
#JsonIgnore
public void setMbox_sha1sum(String mbox_sha1sum) {
this.mbox_sha1sum = mbox_sha1sum;
}
public String getOpenid() {
return openid;
}
public void setOpenid(String openid) {
this.openid = openid;
}
public Account getAccount() {
return account;
}
public void setAccount(Account account) {
this.account = account;
}
public static class Account {
#JsonProperty("homePage")
String homePage;
#JsonProperty("name")
String name;
public String getHomePage() {
return homePage;
}
public void setHomePage(String homePage) {
this.homePage = homePage;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
}
public static class Verb {
String id;
Map<String,String> display;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public Map<String, String> getDisplay() {
return display;
}
public void setDisplay(Map<String, String> display) {
this.display = display;
}
}
I am using jaxb and jakson. I am implementing the webservice to handle the json statement
so I use the bean class to map with json. But when I use to map this json then it gives the following exceptions
org.codehaus.jackson.map.JsonMappingException : property with the name "mbox" have two entry.
Define a proper bean structure so it directly mapped to the beans class
Try to leave only #JsonProperty("mbox") ArrayList<String> listMbox; field (don't need #JsonProperty("mbox")
String mbox;)
and add Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY=true to Jackson object mapper config.
So in deserialization it will be able to get as both array and single element.
you can use gson.
class cls = gson.fromJson(jsonString, clazz);
here jsonString can be stringified java script object. gson.fromJson method can map your java script key to java property.

MVC3 JSON Serialization: How to control the property names?

I want to serialize a simple object to JSON:
public class JsonTreeNode
{
[DataMember(Name = "title")]
public string Title { get; set; }
[DataMember(Name = "isFolder")]
public bool IsFolder { get; set; }
[DataMember(Name = "key")]
public string Key { get; set; }
[DataMember(Name = "children")]
public IEnumerable<JsonTreeNode> Children { get; set; }
[DataMember(Name = "select")]
public bool SelectedOnInit { get; set; }
}
But whenever I do it:
return Json(tree, JsonRequestBehavior.AllowGet);
The property names are not as specified in the [DataMember] section, but similar to the ones defined directly in the class e.g. in the case of SelectOnInit it is not select but SelectOnInit.
What am I doing wrong?
I solved the problem by using the technique provided in the answer in this question:
ASP.NET MVC: Controlling serialization of property names with JsonResult
Here is the class I made:
/// <summary>
/// Similiar to <see cref="JsonResult"/>, with
/// the exception that the <see cref="DataContract"/> attributes are
/// respected.
/// </summary>
/// <remarks>
/// Based on the excellent stackoverflow answer:
/// https://stackoverflow.com/a/263416/1039947
/// </remarks>
public class JsonDataContractActionResult : ActionResult
{
/// <summary>
/// Initializes a new instance of the class.
/// </summary>
/// <param name="data">Data to parse.</param>
public JsonDataContractActionResult(Object data)
{
Data = data;
}
/// <summary>
/// Gets or sets the data.
/// </summary>
public Object Data { get; private set; }
/// <summary>
/// Enables processing of the result of an action method by a
/// custom type that inherits from the ActionResult class.
/// </summary>
/// <param name="context">The controller context.</param>
public override void ExecuteResult(ControllerContext context)
{
if (context == null)
throw new ArgumentNullException("context");
var serializer = new DataContractJsonSerializer(Data.GetType());
string output;
using (var ms = new MemoryStream())
{
serializer.WriteObject(ms, Data);
output = Encoding.UTF8.GetString(ms.ToArray());
}
context.HttpContext.Response.ContentType = "application/json";
context.HttpContext.Response.Write(output);
}
}
Usage:
public ActionResult TestFunction()
{
var testObject = new TestClass();
return new JsonDataContractActionResult(testObject);
}
I also had to modify the initial class:
// -- The DataContract property was added --
[DataContract]
public class JsonTreeNode
{
[DataMember(Name = "title")]
public string Title { get; set; }
[DataMember(Name = "isFolder")]
public bool IsFolder { get; set; }
[DataMember(Name = "key")]
public string Key { get; set; }
[DataMember(Name = "children")]
public IEnumerable<JsonTreeNode> Children { get; set; }
[DataMember(Name = "select")]
public bool SelectedOnInit { get; set; }
}
This is a solution that uses newtonsoft Json.net (for performance concerned)
I've found part of the solution here and on SO
public class JsonNetResult : ActionResult
{
public Encoding ContentEncoding { get; set; }
public string ContentType { get; set; }
public object Data { get; set; }
public JsonSerializerSettings SerializerSettings { get; set; }
public Formatting Formatting { get; set; }
public JsonNetResult(object data, Formatting formatting)
: this(data)
{
Formatting = formatting;
}
public JsonNetResult(object data):this()
{
Data = data;
}
public JsonNetResult()
{
Formatting = Formatting.None;
SerializerSettings = new JsonSerializerSettings();
}
public override void ExecuteResult(ControllerContext context)
{
if (context == null)
throw new ArgumentNullException("context");
var response = context.HttpContext.Response;
response.ContentType = !string.IsNullOrEmpty(ContentType)
? ContentType
: "application/json";
if (ContentEncoding != null)
response.ContentEncoding = ContentEncoding;
if (Data == null) return;
var writer = new JsonTextWriter(response.Output) { Formatting = Formatting };
var serializer = JsonSerializer.Create(SerializerSettings);
serializer.Serialize(writer, Data);
writer.Flush();
}
}
So that in my controller, I can do that
return new JsonNetResult(result);
In my model, I can now have:
[JsonProperty(PropertyName = "n")]
public string Name { get; set; }
Note that now, you have to set the JsonPropertyAttribute to every property you want to serialize.