combining multiple sql queries together - mysql

I have multiple table for a project (sessions , charges and payments)
To get the sessions i'm doing the following :
SELECT
sess.file_id, SUM(sess.rate * sess.length) AS total
FROM
sess
WHERE sess.sessionDone = 1
GROUP BY sess.file_id
This will return the amount that a specific student should pay
I also have another table "charges"
SELECT
file_charges.file_id, SUM(file_charges.price) AS total_charges
FROM
file_charges
GROUP BY file_charges.file_id
And finally the payment query :
SELECT
file_payments.file_id, SUM(file_payments.paymentAmount) AS total_payment
FROM
file_payments
GROUP BY file_payments.file_id
Can i combine those 3 in a way to have :
Total = Payments - (Session + Charges)
Note that it could be negative so i could have file_id that exists in session , charges but not in payments and i could have a payment without sessions or charges ...
Edit : http://sqlfiddle.com/#!2/a90d9

One issue that needs to be addressed is whether one of these queries can be the "driver", in cases where we don't have rows for a given file_id returned by one or more of the queries. (e.g. there might be rows from sess, but none from file_payments. If we want to be sure to include every possible file_id that appears in any of the queries, we can get a list of all possible file_id with a query like this:
SELECT ss.file_id FROM sess ss
UNION
SELECT fc.file_id FROM file_charges fc
UNION
SELECT fp.file_id FROM file_payments fp
(NOTE: The UNION operator will remove any duplicates)
To get the specified resultset, we can use that query, along with "left joins" of the other three original queries. The outline of the query will be:
SELECT a.file_id, p.total_payment - ( s.total + c.total_charges)
FROM a
LEFT JOIN s ON s.file_id = a.file_id
LEFT JOIN c ON c.file_id = a.file_id
LEFT JOIN p ON p.file_id = a.file_id
ORDER BY a.file_id
In that statement a is a standin for the query that gets the set of all file_id values (as shown above). The s, c and p are standins for your three original queries, on sess, file_charges and file_payments, respectively.
If any of the file_id values is "missing" from any of the queries, we are going to need to substitute a zero for the missing value. We can use the IFNULL function to handle that for us.
This query should return the specified resultset:
SELECT a.file_id
, IFNULL(p.total_payment,0) - ( IFNULL(s.total,0) + IFNULL(c.total_charges,0)) AS t
FROM ( -- all possible values of file_id
SELECT ss.file_id FROM sess ss
UNION
SELECT fc.file_id FROM file_charges fc
UNION
SELECT fp.file_id FROM file_payments fp
) a
LEFT
JOIN ( -- the amount that a specific student should pay
SELECT sess.file_id, SUM(sess.rate * sess.length) AS total
FROM sess
WHERE sess.sessionDone = 1
GROUP BY sess.file_id
) s
ON s.file_id = a.file_id
LEFT
JOIN ( -- charges
SELECT file_charges.file_id, SUM(file_charges.price) AS total_charges
FROM file_charges
GROUP BY file_charges.file_id
) c
ON c.file_id = a.file_id
LEFT
JOIN ( -- payments
SELECT file_payments.file_id, SUM(file_payments.paymentAmount) AS total_payment
FROM file_payments
GROUP BY file_payments.file_id
) p
ON p.file_id = a.file_id
ORDER BY a.file_id
(The EXPLAIN for this query is not going to be pretty, with four derived tables. On really large sets, performance may be horrendous. But the resultset returned should meet the specification.)
Beware of queries that JOIN all three tables together... that will likely give incorrect results when there are (for example) two (or more) rows for the same file_id in the file_payment table.
There are other approaches to getting an equivalent result set, but the query above answers the question: "how can i get the results of these queries joined together into a total".
Using correlated subqueries
Here's another approach, using correlated subqueries in the SELECT list...
SELECT a.file_id
, IFNULL( ( SELECT SUM(file_payments.paymentAmount) FROM file_payments
WHERE file_payments.file_id = a.file_id )
,0)
- ( IFNULL( ( SELECT SUM(sess.rate * sess.length) FROM sess
WHERE sess.file_id = a.file_id )
,0)
+ IFNULL( ( SELECT SUM(file_charges.price) FROM file_charges
WHERE file_charges.file_id = a.file_id )
,0)
) AS tot
FROM ( -- all file_id values
SELECT ss.file_id FROM sess ss
UNION
SELECT fc.file_id FROM file_charges fc
UNION
SELECT fp.file_id FROM file_payments fp
) a
ORDER BY a.file_id

try this
SELECT sess.file_id, SUM(file_payments.paymentAmount) - (SUM(sess.rate * sess.length)+SUM(file_charges.price)) as total_payment FROM sess , file_charges , file_payments
WHERE sess.sessionDone = 1
GROUP BY total_payment
EDIT.
SELECT a.file_id
, IFNULL(p.total_payment,0) - ( IFNULL(s.total,0) + IFNULL(c.total_charges,0)) AS tot
FROM (
SELECT ss.file_id FROM sess ss
UNION
SELECT fc.file_id FROM file_charges fc
UNION
SELECT fp.file_id FROM file_payments fp
) a
LEFT JOIN (
SELECT sess.file_id, SUM(sess.rate * sess.length) AS total
FROM sess
WHERE sess.sessionDone = 1
GROUP BY sess.file_id
) s
ON s.file_id = a.file_id
LEFT JOIN (
SELECT file_charges.file_id, SUM(file_charges.price) AS total_charges
FROM file_charges
GROUP BY file_charges.file_id
) c
ON c.file_id = a.file_id
LEFT JOIN (
SELECT file_payments.file_id, SUM(file_payments.paymentAmount) AS total_payment
FROM file_payments
GROUP BY file_payments.file_id
) p
ON p.file_id = a.file_id
ORDER BY a.file_id
DEMO HERE

Related

How to write a mysql with respect to the following conditions

I have 3 table
tmp (pid,title,price)
tmp_studyarea(areaid, tittle, tm_pid)
tmp_module(mid,title, duration, areaid)
I am trying to write a query where I can obtain (tmp.pid, tmp.title, tmp.price, SUM(tmp_module.duration Where tmp_module.areaid = tmpstudyarea.areaid and tmp_studyarea.tmp_pid = tmp.pid) Group by tmp.pid
Here is a query I wrote and i'm unable to get expected results. Help please
SELECT s.title, s.pid, SUM(duration) IN (SELECT a.tmpid, a.areaid, a.title, SUM(m.duration) as duration FROM tmp_studyarea AS a, tmp, tmp_module as m WHERE m.areaid = a.areaid AND a.tmpid = s.pid GROUP BY a.areaid) FROM tmp as s;
Here is my expected resultst
title
pid
duration
tmp Title 1
1
3000
tmp Title 3
4
1000
EDIT
Found a solution
SELECT DISTINCT s.title,s.pid, (SELECT SUM(m.duration) as duration FROM tmp_studyarea AS a, tmp_module as m WHERE m.areaid = a.areaid AND a.tmpid = s.pid GROUP BY a.tmpid) as duration FROM tmp as s, tmp_studyarea, tmp_module GROUP by pid
You must join the 3 tables properly and aggregate:
SELECT t.pid, t.title, t.price,
SUM(m.duration) total_duration
FROM tmp t
INNER JOIN tmp_studyarea s ON s.tmp_pid = t.pid
INNER JOIN tmp_module m ON m.areaid = s.areaid
GROUP BY t.pid, t.title, t.price

SQL: How to get cells by 2 last dates from 3 different tables?

I have 3 tables (stars mach the ids from the table before):
product:
prod_id* prod_name prod_a_id prod_b_id prod_user
keywords:
key_id** key_word key_prod* kay_country
data:
id dat_id** dat_date dat_rank_a dat_traffic_a dat_rank_b dat_traffic_b
I want to run a query (in a function that gets a $key_id) that outputs all these columns but only for the last 2 dates(dat_date) from the 'data' table for the key_id inserted - so that for every key_word - I have the two last dat_dates + all the other variables included in my SQL query:
So... This is what I have so far. and I don't know how to get only the MAX vars. I tried using "max(dat_date)" in different ways that didn't work.
SELECT prod_id, prod_name, prod_a_id, prod_b_id, key_id, key_word, kay_country, dat_date, dat_rank_a, dat_rank_b, dat_traffic_a, dat_traffic_b
FROM keywords
INNER JOIN data
ON keywords.key_id = data.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
Is there a possability to do this with only one query?
EDIT (FOR IgorM):
public function newnew() {
$query = $this->db->query('WITH CTE AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY dat_id ORDER BY dat_date ASC) AS
RowNo FROM data
)
SELECT *
FROM CTE
INNER JOIN keywords
ON keywords.key_id = CTE.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
WHERE RowNo < 3
');
$result = $query->result();
return $result;
}
This is the error on the output:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CTE AS ( SELECT *, ROW_NUMBER() OVER (' at line 1
WITH CTE AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY dat_id ORDER BY dat_date ASC) AS RowNo FROM data ) SELECT * FROM CTE INNER JOIN keywords ON keywords.key_id = CTE.dat_id INNER JOIN prods ON keywords.key_prod = prods.prod_id WHERE RowNo < 3
For SQL
WITH CTE AS
(
SELECT *,
ROW_NUMBER() OVER (PARTITION BY dat_id ORDER BY dat_date ASC) AS
RowNo FROM data
)
SELECT *
FROM CTE
INNER JOIN keywords
ON keywords.key_id = CTE.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
WHERE RowNo < 3
For MySQL (not tested)
SET #row_number:=0;
SET #dat_id = '';
SELECT *,
#row_number:=CASE WHEN #dat_id=dat_id THEN #row_number+1 ELSE 1 END AS row_number,
#dat_id:=dat_id AS dat_id_row_count
FROM data d
INNER JOIN keywords
ON keywords.key_id = d.dat_id
INNER JOIN prods
ON keywords.key_prod = prods.prod_id
WHERE d.row_number < 3
The other approach is self joining. I don't want to take credit for somebody else's job, so please look on the following example:
ROW_NUMBER() in MySQL
Look for the following there:
SELECT a.i, a.j, (
SELECT count(*) from test b where a.j >= b.j AND a.i = b.i
) AS row_number FROM test a
If you only want to do this for one key_id at a time (as alluded to in your responses to other answers) and only want two rows, you can just do:
SELECT p.prod_id,
p.prod_name,
p.prod_a_id,
p.prod_b_id,
k.key_id,
k.key_word,
k.key_country,
d.dat_date,
d.dat_rank_a,
d.dat_rank_b,
d.dat_traffic_a,
d.dat_traffic_b
FROM keywords k
JOIN data d
ON k.key_id = d.dat_id
JOIN prods p
ON k.key_prod = p.prod_id
WHERE k.key_id = :key_id /* Bind in key id */
ORDER BY d.dat_date DESC
LIMIT 2;
Whether you want this depends on your data structure and whether there is more than one key/prod combination per date.
Another option limiting just the data rows would be:
SELECT p.prod_id,
p.prod_name,
p.prod_a_id,
p.prod_b_id,
k.key_id,
k.key_word,
k.key_country,
d.dat_date,
d.dat_rank_a,
d.dat_rank_b,
d.dat_traffic_a,
d.dat_traffic_b
FROM keywords k
JOIN (
SELECT dat_id,
dat_date,
dat_rank_a,
dat_rank_b,
dat_traffic_a,
dat_traffic_b
FROM data
WHERE dat_id = :key_id /* Bind in key id */
ORDER BY dat_date DESC
LIMIT 2
) d
ON k.key_id = d.dat_id
JOIN prods p
ON k.key_prod = p.prod_id;
If you want some kind of grouped results for all the keywords, you'll need to look at the other answers.
I think a window function is the best way to go. without knowing a lot about the structure of the data you can try a subquery of what you are trying to restrict and then joining that to the rest of the data. Then within the where clause restrict the rows you pull back.
select p.prod_id, p.prod_name, p.prod_a_id, p.prod_b_id,
t.key_id, t.key_word, t.kay_country, t.dat_date,
t.dat_rank_a, t.dat_rank_b, t.dat_traffic_a, t.dat_traffic_b
from
(
select
k.key_id, k.key_word, k.kay_country, d.dat_date, d.dat_rank_a,
d.dat_rank_b, d.dat_traffic_a, d.dat_traffic_b,
row_number() over (partition by dat_id order by dat_date desc) as 'RowNum'
from keywords as k
inner join
data as d on k.key_id = d.dat_id
) as t
inner join
prods as p on t.key_prod = p.prod_id
where tmp.RowNum <=2
This is a "groupwise max" problem. Reference. CTE does not exist in MySQL.
I'm not totally clear on how your tables are linked, but here is a stab:
SELECT
*
FROM
( SELECT #prev := '', #n := 0 ) init
JOIN
( SELECT #n := if(k.key_id != #prev, 1, #n + 1) AS n,
#prev := k.key_id,
d.*, k.*, p.*
FROM data d
JOIN keywords k ON k.key_id = d.dat_id
JOIN prods p ON k.key_prod = p.prod_id
ORDER BY
k.key_id ASC,
d.dat_date ASC
) x
WHERE n <= 2
ORDER BY k.key_id, n;
you can use this query:
select prod_id, prod_name, prod_a_id, prod_b_id, key_id, key_word,
kay_country, dat_date, dat_rank_a, dat_rank_b, dat_traffic_a, dat_traffic_b
from keywords where dat_date in (
SELECT MAX(dat_date) FROM keywords temp_1
where temp_1.prod_id = keywords.prod_id
union all
SELECT MAX(dat_date) FROM keywords
WHERE dat_date NOT IN (SELECT MAX(dat_date ) FROM keywords temp_2 where
temp_2.prod_id = keywords.prod_id)
)

MySQL derived table with join

In the following query I'm having a problem when it comes to returning the right value for count2.
What I need is to get the number of rows from table2 which could easily be done by using a derived table t:
SELECT name,
(SELECT COUNT(*) FROM `table1`) AS count1,
(SELECT COUNT(*) FROM (
SELECT COUNT(*) FROM `table2` t2) WHERE t2.user = prf.user)
) t AS count2,
(SELECT SUM(a) FROM `table3`) AS count3
FROM `profiles` prf
WHERE 1=1
AND prf.user = 1
The problem is that the WHERE t2.user = prf.user statement fails as the prf table is outside the subquery's scope.
How can I achieve the above?
EDIT: I'm adding the actual query in case it's helpful for getting a better grasp:
SELECT PRF.BranchID, PRF.user_id, CONCAT_WS(" ",PRF.lastname,PRF.firstname) Synergatis,
( SELECT COUNT(*) FROM Actions A JOIN Requests R ON R.RequestID=A.RequestID WHERE A.ActionStatus = 302 AND A.UserOwner = PRF.user_id AND A.ActionDate BETWEEN '2015-06-01' AND '2015-06-10' ) AS energeies,
( SELECT COUNT(DISTINCT RPP.RequestID) FROM VW_Xartofylakio_Synergati VV JOIN Requests_Prop RPP ON RPP.PropertyID = VV.PropertyID JOIN Requests R ON R.RequestID = RPP.RequestID WHERE VV.CurrUsr = PRF.user_id AND R.ModifyTime BETWEEN '2015-06-01' AND '2015-06-10' ) AS zitiseis_eidikes,
( SELECT COUNT(DISTINCT(CustomerID)) FROM Demo_Orders_M WHERE DemoOrderStatus=253 AND USER=PRF.user_id AND DemoOrderDate BETWEEN '2015-06-01' AND '2015-06-10' ) AS endiaferomenoi,
( SELECT COUNT(*) AS cnt FROM Demo_Orders_M DOM JOIN Actions A ON DOM.DemoOrderID = A.DemoOrderID WHERE DOM.User = PRF.user_id AND DOM.DemoOrderStatus = 253 AND A.ActionDate BETWEEN '2015-06-01 14:56:19' AND '2015-06-30 14:56:19' GROUP BY DOM.CustomerID, DOM.User HAVING COUNT(*) > 1 ) AS anakykl_endiaf,
( SELECT COUNT(*) FROM Demo_Orders_M DOM WHERE DOM.`User`=PRF.user_id AND DemoOrderStatus = 253 AND DOM.DemoOrderDate BETWEEN '2015-06-01' AND '2015-06-10' ) AS epideixeis,
( SELECT COUNT(DISTINCT(DOD.PropertyID)) AS PropertyID FROM Demo_Orders_M DOM JOIN Demo_Orders_D DOD ON DOM.DemoOrderID = DOD.DemoOrderID JOIN Actions A ON DOD.DemoOrderID = A.DemoOrderID WHERE DOM.DemoOrderStatus = 253 AND DOM.User = PRF.user_id AND A.ActionDate BETWEEN '2015-06-01' AND '2015-06-10' ) AS monadika_akinita
FROM tbl_profiles PRF
WHERE 1=1
AND PRF.user_id IN (
SELECT a.user_id FROM tbl_profiles a WHERE a.user_id IN ('248','1159','486','183')
OR a.GroupID IN (SELECT b.GroupID FROM L_Groups b WHERE b.ManagerID IN ('248','1159','486','183'))
)
ORDER BY PRF.user_id
The subquery I'm referring to is the one that returns the result as anakykl_endiaf.
I suspect it is not because of prf table, it is because of t2 table... There are no restrictions to use outer alias in inner subqueries because there are such a thing like correlated subquery. Your problem is that you have the opposite case here: you are referring inner alias in outer query.
(SELECT COUNT(*)
FROM (SELECT COUNT(*) FROM `table2` t2) WHERE t2.user = prf.user)
Why are you selecting count twice here? You can change to this:
(SELECT COUNT(*)
FROM (SELECT COUNT(*) FROM `table2` t2 WHERE t2.user = prf.user))
or this:
(SELECT COUNT(*)
FROM `table2` t2 WHERE t2.user = prf.user)
A suggestion to try.
You have sub queries in the SELECT, and in this case they must each only return a single row. For some reason (which we can't really tell without test data) one of these is returning more than 1 row, hence failing.
As an interim step, change the query to join against the sub queries, which should make it more obvious when there are duplicates (and may also be quite a bit more efficient, depending on the data).
Something like this (not tested so probably a few typos):-
SELECT PRF.BranchID,
PRF.user_id,
CONCAT_WS(" ",PRF.lastname,PRF.firstname) Synergatis,
ar.energeies,
vrr.zitiseis_eidikes,
m.endiaferomenoi,
ae.anakykl_endiaf,
d.epideixeis,
ddd.monadika_akinita
FROM tbl_profiles PRF
LEFT OUTER JOIN
(
SELECT A.UserOwner AS DomUser, COUNT(*) AS energeies
FROM Actions A
JOIN Requests R ON R.RequestID=A.RequestID
WHERE A.ActionStatus = 302
AND A.ActionDate BETWEEN '2015-06-01' AND '2015-06-10'
GROUP BY A.UserOwner
) ar
ON ar.DomUser = PRF.user_id
LEFT OUTER JOIN
(
SELECT VV.CurrUsr AS DomUser, COUNT(DISTINCT RPP.RequestID) AS zitiseis_eidikes
FROM VW_Xartofylakio_Synergati VV
JOIN Requests_Prop RPP ON RPP.PropertyID = VV.PropertyID
JOIN Requests R ON R.RequestID = RPP.RequestID
WHERE R.ModifyTime BETWEEN '2015-06-01' AND '2015-06-10'
GROUP BY VV.DomUser
) vrr
ON vrr.DomUser = PRF.user_id
LEFT OUTER JOIN
(
SELECT `USER` AS DomUser, COUNT(DISTINCT(CustomerID)) AS endiaferomenoi
FROM Demo_Orders_M
WHERE DemoOrderStatus=253
AND DemoOrderDate BETWEEN '2015-06-01' AND '2015-06-10'
GROUP BY DomUser
) m
ON PRF.user_id = m.DomUser
LEFT OUTER JOIN
(
SELECT DOM.CustomerID, DOM.`User` AS DomUser, COUNT(*) AS anakykl_endiaf
FROM Demo_Orders_M DOM
JOIN Actions A ON DOM.DemoOrderID = A.DemoOrderID
WHERE DOM.DemoOrderStatus = 253
AND A.ActionDate BETWEEN '2015-06-01 14:56:19' AND '2015-06-30 14:56:19'
GROUP BY DOM.CustomerID, DOM.DomUser
HAVING COUNT(*) > 1
) ae
ON PRF.user_id = ae.DomUser
LEFT OUTER JOIN
(
SELECT DOM.`User` AS DomUser, COUNT(*) AS epideixeis
FROM Demo_Orders_M DOM
WHERE DemoOrderStatus = 253
AND DOM.DemoOrderDate BETWEEN '2015-06-01' AND '2015-06-10'
GROUP BY DOM.DomUser
) d
EDIT
If you just want a count of the number of customerID fields for a user in the anakykl_endiaf field then change it to doing a count of distinct customerIDs. Ie, for the above query I have done change it to:-
LEFT OUTER JOIN
(
SELECT DOM.`User` AS DomUser, COUNT(DISTINCT DOM.CustomerID) AS anakykl_endiaf
FROM Demo_Orders_M DOM
JOIN Actions A ON DOM.DemoOrderID = A.DemoOrderID
WHERE DOM.DemoOrderStatus = 253
AND A.ActionDate BETWEEN '2015-06-01 14:56:19' AND '2015-06-30 14:56:19'
GROUP BY DOM.DomUser
HAVING COUNT(*) > 1
) ae

Slow MySQL query with subquery from table

I am trying to bring back a string based on an IF statement but it is extremely slow.
It has something to do with the first subquery but I am unsure of how to rearrange this as to bring back the same results but faster.
Here is my SQL:
SELECT IF
(
(
SELECT COUNT(*)
FROM
(
SELECT DISTINCT enquiryId, type
FROM parts_enquiries, parts_service_types AS pst
WHERE parts_enquiries.serviceTypeId = pst.id
) AS parts
WHERE parts.enquiryId = enquiries.id
) > 1, 'Mixed',
(
SELECT DISTINCT type
FROM parts_enquiries, parts_service_types AS pst
WHERE parts_enquiries.serviceTypeId = pst.id AND enquiryId = enquiries.id
)
) AS partTypes
FROM enquiries,
entities
WHERE enquiries.entityId = entities.id
How can I make it faster?
I have modified my original query below, but I am getting the error that subquery returns more than one row:
SELECT
(SELECT
CASE WHEN COUNT(DISTINCT type) > 1 THEN 'Mixed' ELSE `type` END AS type
FROM parts_enquiries
INNER JOIN parts_service_types AS pst ON parts_enquiries.serviceTypeId = pst.id
INNER JOIN enquiries ON parts_enquiries.enquiryId = enquiries.id
INNER JOIN entities ON enquiries.entityId = entities.id
GROUP BY enquiryId) AS partTypes
FROM enquiries,
entities
WHERE enquiries.entityId = entities.id
Please have a look if this query yields the same results:
SELECT
enquiryId,
CASE WHEN COUNT(DISTINCT type) > 1 THEN 'Mixed' ELSE `type` END AS type
FROM parts_enquiries
INNER JOIN parts_service_types AS pst ON parts_enquiries.serviceTypeId = pst.id
INNER JOIN enquiries ON parts_enquiries.enquiryId = enquiries.id
INNER JOIN entities ON enquiries.entityId = entities.id
GROUP BY enquiryId
But N.B.'s comment is still valid. To see if and index is used and other information we need to see the EXPLAIN and the table definitions.
This should get you what you want.
I would first pre-query your parts enquiries and parts service types looking for both the count and MINIMUM of the part 'type', grouped by the enquiry ID.
then, run your IF() against that result. If the distinct count is > 0, then 'Mixed'. If only one, since I did the MIN(), it would only have the description of that one value that you desire anyhow.
SELECT
E.ID
IF ( PreQuery.DistTypes > 1, 'Mixed', PreQuery.FirstType ) as PartType
from
Enquiries E
JOIN ( SELECT
PE.EnquiryID,
COUNT( DISTINCT PE.ServiceTypeID ) as DistTypes,
MIN( PST.Type ) as FirstType
from
Parts_Enquiries PE
JOIN Parts_Service_Types PST
ON PE.ServiceTypeID = PST.ID
group by
PE.EnquiryID ) as PreQuery
ON E.ID = PreQuery.EnquiryID

MySQL - Combining multiple queries + counts

I'm attempting to combine a few queries and can't seem to nail it down. I was wondering if someone could point me in the right direction.
Here are the statements:
SELECT
I.id,
I.custname,
I.custemail,
I.sku,
DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts
FROM images I
WHERE I.stat = 0
SELECT
COUNT(*) AS total1
FROM images
WHERE stat = 1 AND sku = ?
SELECT
COUNT(*) AS total2
FROM images
WHERE stat = 1
AND sku IN (SELECT subsku FROM combo WHERE sku = ?)
Right now I'm using the 3 separate queries and am using code to add the two totals and display them. But I now need to be able to sort by the sum of the totals, so I'd like to get all of that data into one statement.. something like:
SELECT
I.id,
I.custname,
I.custemail,
I.sku,
DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts,
SUM(total1+total2)
FROM images I
WHERE I.stat = 0
But I'm unsure how to do that. I tried the code below, but it failed:
SELECT
I.id,
I.custname,
I.custemail,
I.sku,
DATE_FORMAT(FROM_UNIXTIME(I.ts),'%l:%i:%s %p, %c/%e/%Y') AS ts,
(
SELECT COUNT(*) AS total1 FROM images WHERE stat = 1 AND (
sku IN (
SELECT subsku FROM combo WHERE sku = I.sku
) OR sku = I.sku)
) AS skuct
FROM images I
WHERE stat = 0
Any help would be greatly appreciated. Many thanks!
UPDATE
First off thanks to everyone who has offered assistance. I've been working on the query and think I'm getting closer, but I'm now hitting a 'subquery returns more than 1 row' error:
SELECT
I.id,
I.custname,
I.custemail,
I.sku,
DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts,
(
SELECT COUNT(*)
FROM images
WHERE stat = 1
AND sku = I.sku
OR sku IN(
SELECT subsku FROM combo WHERE sku = I.sku
)
GROUP BY sku
) AS total
FROM images I
WHERE stat = 0
The problem is that the subquery SELECT subsku FROM combo WHERE... returns a resultset (0+ rows) vs a scalar. If I can figure out that part, I think this will work.
Select I.id, I.custname, I.custemail, I.sku
, DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts
, (
Select Sum( Case
When I1.sku = ? Then 1
When I1.sku In( Select subsku From combo As S1 Where S1.sku = ? ) Then 1
Else 0
End ) As Total
From images As I1
Where I1.stat = 1
) As Total
From images As I
Where stat = 0
Another solution
Select I.id, I.custname, I.custemail, I.sku
, DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts
, (
Select Count(*)
From images As I1
Where I1.stat = 1
And (
I1.sku = ?
Or I1.sku In ( Select subsku From combo As S1 Where S1.sku = ? )
)
) As Total
From images As I
Where stat = 0
Addition
Another possible solution:
Select I.id, I.custname, I.custemail, I.sku
, DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts
, (
Select Sum( Cnt )
From (
Select Count(*) As Cnt
From images As I1
Left Join combo As C1
On C1.sku = I1.sku
Where I1.stat = 1
And I1.sku = ?
And C1.PrimaryKeyCol Is Null
Union All
Select Count( Distinct I1.PrimaryKeyCol )
From images As I1
Join combo As C1
On C1.sku = I1.sku
Where I1.stat = 1
And I1.sku = ?
) As Z
) As Total
From images As I
Where stat = 0
Edit
If you are looking for the count by image in which you correlate the counts to the outer table images sku column, that's entirely different. For that, I would use a derived table:
Select I.id, I.custname, I.custemail, I.sku
, DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts
, Counts.Total
From images As I
Join (
Select Z.sku, Sum(Z.Cnt) As Total
From (
Select I1.sku, Count(*) As Cnt
From images As I1
Left Join combo As C1
On C1.sku = I1.sku
Where I1.stat = 1
And C1.PrimaryKeyCol Is Null
Group By I1.sku
Union All
Select I1.sku, Count( Distinct I1.PrimaryKeyCol )
From images As I1
Join combo As C1
On C1.sku = I1.sku
Where I1.stat = 1
Group By I1.sku
) As Z
Group By Z.sku
) As Counts
On Counts.sku = I.sku
Where stat = 0
Obviously in all cases, replace PrimaryKeyCol with the name of the actual primary key column of the images table.
Have you considered changing the WHERE logic to perform the count in one.
Assuming the two counts are mutually exclusive you could just OR the two conditions.
Use the cross join . . .
select t1.*, t2.total1, t3.total2
from
(
SELECT I.id, I.custname, I.custemail, I.sku,
DATE_FORMAT(FROM_UNIXTIME(I.ts), '%l:%i:%s %p, %c/%e/%Y') AS ts
FROM images I
WHERE I.stat = 0
) t1
cross join
(
SELECT COUNT(*) AS total1
FROM images
WHERE stat = 1 AND sku = ?
) t2
cross join
(
SELECT COUNT(*) AS total2
FROM images
WHERE stat = 1 AND sku IN (SELECT subsku FROM combo WHERE sku = ?)
) t3
You might be able to make this more efficient, since they are all going after the same table. A single aggregation with a case statement per WHERE clause would probably be more efficient.