Adding only one value to the table in sql - mysql

I have a table named student which consists of (rollno, name, sem, branch)
If I want to INSERT only one value (i.e only name has to be entered) what is the query?

To insert values into specific columns, you first have to specify which columns you want to populate. The query would look like this:
INSERT INTO your_table_name (your_column_name)
VALUES (the_value);
To insert values into more than one column, separate the column names with a comma and insert the values in the same order you added the column names:
INSERT INTO your_table_name (your_column_name_01, your_column_name_02)
VALUES (the_value_01, the_value_02);
If you are unsure, have a look at W3Schools.com. They usually have explanations with examples.

insert into student(name) values("The name you wan to insert");
Be careful not to forget to insert the primary key.

First, if the table is all empty, just wanna make the column 'name' with values, it is easy to use INSERT INTO. https://www.w3schools.com/sql/sql_insert.asp.
`INSERT INTO TABLE_NAME (COLUMN_NAME) VALUES ("the values")`
Second, if the table is already with some values inside, and only wanna insert some values for one column, use UPDATE. https://www.w3schools.com/sql/sql_update.asp
UPDATE table_name SET column1 = value1 WHERE condition;

insert into student (name)
select 'some name'
or
insert into student (name)
values ('some name')

Following works if other columns accept null or do have default value:
INSERT INTO Student (name) VALUES('Jack');
Further details can be found from the Reference Manual:: 13.2.5 INSERT Syntax.

Execute this query, if you want the rest of columns as "#", do insert # inside the single quote which is left blank in query.
Also, there is no need of defining column name in the query.
insert into student values('','your name','','');
Thanks...

Related

Can't insert data when use foreign key together with trigger in Mariadb [duplicate]

So I read the other posts but this question is unique. So this SQL dump file has this as the last entry.
INSERT INTO `wp_posts` VALUES(2781, 3, '2013-01-04 17:24:19', '2013-01-05 00:24:19'.
I'm trying to insert this value to the table...
INSERT INTO `wp_posts` VALUES(5, 5, '2005-04-11 09:54:35', '2005-04-11 17:54:35'
it gives me the error, "Column count doesn't match value count at row 1." So I'm lost on the concept of how the column and row apply here.
Doesn't 2781,3 mean row 2781 and column 3? And doesn't 5,5 mean row 5 and column 5?
The error means that you are providing not as much data as the table wp_posts does contain columns. And now the DB engine does not know in which columns to put your data.
To overcome this you must provide the names of the columns you want to fill. Example:
insert into wp_posts (column_name1, column_name2)
values (1, 3)
Look up the table definition and see which columns you want to fill.
And insert means you are inserting a new record. You are not modifying an existing one. Use update for that.
you missed the comma between two values or column name
you put extra values or an extra column name
You should also look at new triggers.
MySQL doesn't show the table name in the error, so you're really left in a lurch. Here's a working example:
use test;
create table blah (id int primary key AUTO_INCREMENT, data varchar(100));
create table audit_blah (audit_id int primary key AUTO_INCREMENT, action enum('INSERT','UPDATE','DELETE'), id int, data varchar(100) null);
insert into audit_blah(action, id, data) values ('INSERT', 1, 'a');
select * from blah;
select * from audit_blah;
truncate table audit_blah;
delimiter //
/* I've commented out "id" below, so the insert fails with an ambiguous error: */
create trigger ai_blah after insert on blah for each row
begin
insert into audit_blah (action, /*id,*/ data) values ('INSERT', /*NEW.id,*/ NEW.data);
end;//
/* This insert is valid, but you'll get an exception from the trigger: */
insert into blah (data) values ('data1');
MySQL will also report "Column count doesn't match value count at row 1" if you try to insert multiple rows without delimiting the row sets in the VALUES section with parentheses, like so:
INSERT INTO `receiving_table`
(id,
first_name,
last_name)
VALUES
(1002,'Charles','Babbage'),
(1003,'George', 'Boole'),
(1001,'Donald','Chamberlin'),
(1004,'Alan','Turing'),
(1005,'My','Widenius');
You can resolve the error by providing the column names you are affecting.
> INSERT INTO table_name (column1,column2,column3)
`VALUES(50,'Jon Snow','Eye');`
please note that the semi colon should be added only after the statement providing values
In my case i just passed the wrong name table, so mysql couldn't find the right columns names.

mySQL Error code 1136 with TRIGGER Syntax [duplicate]

So I read the other posts but this question is unique. So this SQL dump file has this as the last entry.
INSERT INTO `wp_posts` VALUES(2781, 3, '2013-01-04 17:24:19', '2013-01-05 00:24:19'.
I'm trying to insert this value to the table...
INSERT INTO `wp_posts` VALUES(5, 5, '2005-04-11 09:54:35', '2005-04-11 17:54:35'
it gives me the error, "Column count doesn't match value count at row 1." So I'm lost on the concept of how the column and row apply here.
Doesn't 2781,3 mean row 2781 and column 3? And doesn't 5,5 mean row 5 and column 5?
The error means that you are providing not as much data as the table wp_posts does contain columns. And now the DB engine does not know in which columns to put your data.
To overcome this you must provide the names of the columns you want to fill. Example:
insert into wp_posts (column_name1, column_name2)
values (1, 3)
Look up the table definition and see which columns you want to fill.
And insert means you are inserting a new record. You are not modifying an existing one. Use update for that.
you missed the comma between two values or column name
you put extra values or an extra column name
You should also look at new triggers.
MySQL doesn't show the table name in the error, so you're really left in a lurch. Here's a working example:
use test;
create table blah (id int primary key AUTO_INCREMENT, data varchar(100));
create table audit_blah (audit_id int primary key AUTO_INCREMENT, action enum('INSERT','UPDATE','DELETE'), id int, data varchar(100) null);
insert into audit_blah(action, id, data) values ('INSERT', 1, 'a');
select * from blah;
select * from audit_blah;
truncate table audit_blah;
delimiter //
/* I've commented out "id" below, so the insert fails with an ambiguous error: */
create trigger ai_blah after insert on blah for each row
begin
insert into audit_blah (action, /*id,*/ data) values ('INSERT', /*NEW.id,*/ NEW.data);
end;//
/* This insert is valid, but you'll get an exception from the trigger: */
insert into blah (data) values ('data1');
MySQL will also report "Column count doesn't match value count at row 1" if you try to insert multiple rows without delimiting the row sets in the VALUES section with parentheses, like so:
INSERT INTO `receiving_table`
(id,
first_name,
last_name)
VALUES
(1002,'Charles','Babbage'),
(1003,'George', 'Boole'),
(1001,'Donald','Chamberlin'),
(1004,'Alan','Turing'),
(1005,'My','Widenius');
You can resolve the error by providing the column names you are affecting.
> INSERT INTO table_name (column1,column2,column3)
`VALUES(50,'Jon Snow','Eye');`
please note that the semi colon should be added only after the statement providing values
In my case i just passed the wrong name table, so mysql couldn't find the right columns names.

how to use primary key as custId number in second table

I have two tables, the first has an auto incrementing ID number, I want to use that as custId in the second table.
I am using an insert into the first table with all the basic info, name, address etc. Then in the second table only 3 things, custId, stocknum, and location. How can I write to these two tables kinda of simultaneously since stockNum may have several values, but always attached to one custId. I hope this makes sense even without putting code in here.
You can't insert into multiple tables at the same time. You have two options. You either do two inserts
INSERT INTO table1 (col1, col2) VALUES ('value1',value2);
/* Gets the id of the new row and inserts into the other table */
INSERT INTO table2 (cust_id, stocknum, location) VALUES (LAST_INSERT_ID(), 'value3', 'value4')
Or you can use a post-insert trigger
CREATE TRIGGER table2_auto AFTER INSERT ON `table1`
FOR EACH ROW
BEGIN
INSERT INTO table2 (cust_id, stocknum, location) VALUES (NEW.id, value3, 'value4')
END
Hope this helps.
After inserting in the first table, The identity field or Auto increment field generate an ID
Get this id Refer Here(LAST_INSERT_ID() MySQL)
Then use this id to store value in the other table

Insert specific values into mysql database

I have the following problem:
I would't insert all the values in my db.
So, i would insert only id,tessera,nome,sex. I thought i had to write something like this:
INSERT INTO registries(id,tessera,'',nome,sex) VALUES (35983,35983,'DOG', 'FABIO', 'M')
I don't want to insert the DOG value in my db cause I don't have any attribute in my schema to save it.
I have 3000 rows and I take this row as example so I can't simply delete the DOG value and the attribute field in my sql query.
I remember that I have to use something like this
INSERT INTO registries(id,tessera,'',nome,sex)
I mean, I have to write '' to not consider the value in that position.
but MySQL gives me an error..
Can you help me?
You can handle this situation in following ways.
create temporary table on same server. Insert all data in temporary table then use insert into select statement and select required fields.
create temporary column and insert data in that column and delete temporary column
INSERT INTO registries (id,tessera,new_column,nome,sex)
VALUES (35983, 35983, '', 'FABIO', 'M');
Now
DROP COLUMN new_column from registries;
Try this (assuming dog is a column name):
INSERT INTO registries (id,tessera,dog_name,nome,sex) VALUES (35983, 35983, '', 'FABIO', 'M')
If dog_name is allowed to be NULL (which it is by default) you could also just not insert any value, like this:
INSERT INTO registries (id,tessera,nome,sex) VALUES (35983, 35983, 'FABIO', 'M')

why is mySQL missing a column?

This statement is not populating the image_path column. I have copied and pasted column names from phpMyAdmin to ensure accuracy.
INSERT INTO (theme_name, theme_path, image_path)
VALUES ('',
'/Applications/MAMP/htdocs/waggleb/wp-content/plugins/app-switcher/themes/Original/',
'/Applications/MAMP/htdocs/waggleb/wp-content/plugins/app-switcher/thumbnails/original.png')
You're missing a table name. If you look at the MySQL INSERT syntax, you'll see that it's mandatory to include a table name.
As such, if you alter your query to become..
INSERT INTO <TABLE NAME> (theme_name, theme_path, image_path) VALUES...
...all should be well.
you missed the table name
INSERT INTO TABLENAME(theme_name, theme_path, image_path)
VALUES ('',
'/Applications/MAMP/htdocs/waggleb/wp-content/plugins/app-switcher/themes/Original/',
'/Applications/MAMP/htdocs/waggleb/wp-content/plugins/app-switcher/thumbnails/original.png')
I believe you are missing the table name.
It should be:
Insert Into [Table_name]
([Columns])
Values ([Values])
You've forgotten to name a table to INSERT into:
INSERT INTO my_table (theme_name, theme_path, image_path)
If you omitted the table name on purpopse, check that the datatypes are correct for the columns. Check lengths of target columns are long enough to hold what you are inserting.