I have a query here, anyone can help me to count the total duplicated fields?
SELECT *
FROM item
INNER JOIN itemgroup on item.itemgroupid = itemgroup.itemgroupid
INNER JOIN status on status.statusid = item.status
INNER JOIN owner on owner.ownerid = item.owner
INNER JOIN
(
SELECT code //, (SELECT count(*) FROM item WHERE ....) as 'total_duplicateds'
FROM item
GROUP BY code
HAVING count(code) > 1
) dup ON item.code = dup.code
Total items: 500
Total items with duplicated codes: 149
Now I get a total of 149 fields returned, how can I add this as a new field to each row?
After the slash is how I learnt to do it but this is a little higher level for me..
Can someone help me out?
To be even more specific
What I'd like to get returned is like:
itemid | code| itemname | itemgroup | owner | total_duplicateds
1 1000 X 1 1 3
2 1000 X 2 2 3
3 1001 A 1 1 3
4 1000 B 3 1 3
5 1002 U 2 1 3
Add COUNT aggregation and GROUP BY all columns that are interesting you.
Related
I am currently working on a project while trying to learn MySQL and I would like to join three tables and get the latest status for each related shipment. Here are the tables I'm working with (with example data):
shipments
id
consignee
tracking_number
shipper
weight
import_no
1
JOHN BROWN
TBA99900000121
AMAZON
1
101
2
HELEN SMITH
TBA99900000190
AMAZON
1
102
3
JACK BLACK
TBA99900000123
AMAZON
1
103
4
JOE BROWM
TBA99900000812
AMAZON
1
104
5
JULIA KERR
TBA99900000904
AMAZON
1
105
statuses
id
name
slug
1
At Warehouse
at_warehouse
2
Ready For Pickup
ready_for_pickup
3
Delivered
delivered
shipment_status (pivot table)
id
shipment_id
status_id
1
1
1
2
2
1
3
3
1
4
4
1
5
5
1
6
1
2
7
2
2
8
3
2
9
4
2
10
5
2
all tables do have created_at and updated_at timestamp columns
Example of the results I'm trying to achieve
slug
shipment_id
status_id
ready_for_pickup
1
2
ready_for_pickup
2
2
ready_for_pickup
3
2
ready_for_pickup
4
2
ready_for_pickup
5
2
Here's the query I wrote to try to achieve what I'm looking for based on examples and research I did during the past couple of days. I find that sometimes there is sometimes a mismatch with the latest status that relates to the shipment
SELECT
statuses.slug AS slug,
MAX(shipments.id) AS shipment_id,
statuses.id AS status_id,
FROM
`shipments`
INNER JOIN `shipment_status` ON `shipment_status`.`shipment_id` = `shipments`.`id`
INNER JOIN `statuses` ON `shipment_status`.`status_id` = `statuses`.`id`
GROUP BY
`shipment_id`
Because we need to reference other fields from the same record that evaluates from the MAX aggregation, you need to do it in two steps, there are other ways, but I find this syntax simpler:
SELECT
shipments.id AS id,
statuses.slug AS slug,
statuses.id AS status_id,
shipment_status.shipment_id as shipment_id
FROM
`shipments`
INNER JOIN `shipment_status` ON `shipment_status`.`shipment_id` = `shipments`.`id`
INNER JOIN `statuses` ON `shipment_status`.`status_id` = `statuses`.`id`
WHERE
shipment_status.id = (
SELECT MAX(shipment_status.id)
FROM `shipment_status`
WHERE shipment_status.shipment_id = shipments.id
)
try it out!
This query makes the assumption that the id field is an identity column, so the MAX(shipment_status.id) represents only the most recent status for the given shipment_id
You can use window functions:
SELECT s.id, st.slug, st.id
FROM shipments s JOIN
(SELECT ss.*,
ROW_NUMBER() OVER (PARTITION BY shipment_id ORDER BY ss.id DESC) as seqnum
FROM shipment_status ss
) ss
ON ss.shipment_id = s.id JOIN
statuses st
ON ss.status_id` = st.id
WHERE ss.seqnum = 1;
Also note the use of table aliases so the query is easier to write and to read.
I have 'products' table and related 'variations' table, one product can have one or more variations. 'variations' table has 'status' column, its value can be 0 or 1. I want to get the number of products (COUNT()) which have at least one variation of status 1. How to make a query that would do that?
[EDIT]
Ok, I thought that if I simplify the question I will get away with the table structure, but, here we go (only columns relevant to the question and some mock data):
It's actually 3 linked tables:
table 1: 'products'
id
name
1
t-shirt
2
shoes
3
shorts
table 2: variations
id
product_id
1
1
2
1
3
2
4
2
5
3
6
3
7
3
table 3: stock
variation_id
quantity
status [0 or 1]
1
10
1
2
15
1
3
0
0
4
0
0
5
0
0
6
3
1
7
0
0
So, with this data, I want to know how many products there are that have at least 1 of its 'variations' of 'status' 1 - in this example it would be 2 (product 1 and 3 have some variations with status 1, product 2 does not).
You just need SUM all the quantity GROUP BY products.id with criteria is stock.status equal 1.
SELECT id, name, SUM(quantity) AS total_quantity
FROM Products pr
LEFT JOIN Variations va ON pr.id = va.product_id
LEFT JOIN Stock st ON st.variation_id = va.id
WHERE st.status = 1
GROUP BY pr.id
Join two tables and apply where filter on status column
select count(*) as cnt
from
products p
join variations v
on p.product_id = v.product_id
where status = 1
I'm very inexperienced. I've prepared a select statement which gives the information I need to populate a matches table. However it is not suitable because it contains a where clause. Is there a different way to use it, or how can I change it so that it is suitable for INSERT INTO.
The tables are as follows:-
match_order
match_order_id||match_descrip||first_player||second_player
1 1v2 1 2
2 1v3 1 3
3 2v3 2 3
4 1v4 1 4
5 2v4 2 4
6 3v4 3 4
entries
entry_id||round_id||league_id||box_id||box_position
1 1 1 1 1
2 1 1 1 2
3 1 1 1 3
4 1 2 1 4
5 1 2 1 2
6 1 2 1 1
7 1 2 1 1
matches
match_id||round_id||league_id||box_id||match_order_id||player1||player2
I need to insert new rows every month for a new round of matches. League size, box size & positions change each month.
This is the statement which gives the correct rows.
SELECT e.round_id, e.league_id, e.box_id, mo.match_order_id, e.entry_id as player1, e1.entry_id as player2
FROM match_order mo
LEFT JOIN entries e ON mo.first_player = e.box_position
LEFT JOIN entries e1 ON mo.second_player = e1.box_position
WHERE e.round_id = e1.round_id AND e.league_id = e1.league_id AND e.box_id = e1.box_id
ORDER BY round_id, league_id, box_id, match_order_id
Any help & advise would be greatly appreciated.
Thank you
Assuming match_id is an auto-increment column, you have the data for the other columns. You can just add the INSERT statement before your SELECT.
INSERT INTO matches(round_id, leage_id, box_id, match_order_id, player1, player2)
SELECT e.round_id, e.league_id, e.box_id, mo.match_order_id, e.entry_id as player1, e1.entry_id as player2
FROM match_order mo
LEFT JOIN entries e ON mo.first_player = e.box_position
LEFT JOIN entries e1 ON mo.second_player = e1.box_position
WHERE e.round_id = e1.round_id AND e.league_id = e1.league_id AND e.box_id = e1.box_id
I have the following tables:
Table users
id name base_discount
1 jack 10
2 michael 20
3 richard 30
Table item
id name category_id price
1 hammer 1 10
2 knife 2 15
3 spoon 2 12
4 plate 3 20
5 tree 4 400
Table category
id name
1 tools
2 kitchen
3 dishes
4 garden
Table discount_category
id user_id category_id discount
1 1 1 20
2 1 3 25
3 3 3 10
4 1 2 15
Table discount_item
id user_id item_id discount
1 2 1 50
2 1 2 50
Now what I want to achieve. I want to attach the discount per item that a user has to the correct item. If that is not available (NULL) I want to attach the discount per category that a user has. And if that is not available (NULL), I want to attach the base discount that a user has. With the discount I then calculate the new price of the item. However, when I try using COALESCE() within SUM() I get a syntax error. What am I doing wrong?
Below is my current query:
SELECT item.id, item.name, category.id,
category.name AS category_name, item.price, SUM((100 -
COALESCE(
(
SELECT discount_item.discount
FROM discount_item
INNER JOIN users ON discount_item.user_id = users.id
WHERE users.id = '1' AND discount_item.item_id = item.id
),
(
SELECT discount_category.discount
FROM discount_category
INNER JOIN users ON discount_category.user_id = users.id
WHERE users.id = '1' AND discount_category.category_id = item.category_id
),
(
SELECT users.base_discount
FROM users
WHERE users.id = '1'
)
)) / 100 * item.price) AS new_price,
FROM item
INNER JOIN category ON item.category_id = category.id;
Please also see the below link for an SQL Fiddle (couldn't do it on sqlfiddle.com as it wouldn't load). In the example I have appended a suffix to each table name.
http://rextester.com/LCCKSD59098
You have an extra comma after new_price and before FROM ITEM, hence the error.
Rextester Demo
Do not select other columns in select if you are not using them in group by, as in other relational RDBMS, you will get error.
Also use alias for table names for better readibily and to avoid confusion.
Considering the following query:
SELECT t.recording_id, m.release_id
FROM track t
JOIN medium m ON t.medium_id = m.medium_id
i get a result set similar to this one
recording id release id
----------------------------------
1 25
1 25
1 37
1 76
1 300
1 336
2 37
... ...
i need to output the following
recording id count
---------------------------------------------------
1 5
2 1
In other words, i need to group by the recording_id but not count the release_id duplicates for that recording_id
After researching this board i've tried the following, with no success :
SELECT t.recording_id, count(t.recording_id)
FROM track t
JOIN medium m ON t.medium_id = m.medium_id
group by t.recording_id, m.release_id
but, im getting
recording id release id
--------------------------
1 2
1 1
1 1
1 1
1 1
2 1
What's wrong?
Try this, you can use distinct in your count function to return distinct release ids for a recording_id
SELECT t.recording_id, count(distinct m.release_id) cnt
FROM track t
JOIN medium m ON t.medium_id = m.medium_id
group by t.recording_id