I have two tables as follows :-
Table 1 Table 2
date value date value
1120101 v11 1120102 v21
1120202 v12 1120303 v22
1120203 v13 1120104 v23
what is the sql query to get following output
date value
1120101 (v11)
1120102 (v12+v21)
1120103 (v13+v22)
1120104 ( v23)
I tired following query but failed to get desired output
select table1.date,
table2.date,
table1.delta+table2.delta as delta
from table1,
table2
where table1.date=table2.date;
thanks in advance .
SELECT date, SUM(value)
FROM
(
SELECT date, value FROM table1
UNION ALL
SELECT date, value FROM table2
) a
GROUP BY date
SQLFiddle Demo (data is different but idea is the same)
play with subqueries and union:
SELECT
c.date,
COALESCE(a.value, 0) + COALESCE(z.value,0)
FROM (
SELECT
date
FROM table1
UNION
SELECT date
FROM table2
) AS c
LEFT OUTER JOIN table1 a
ON a.date = c.date
LEFT OUTER JOIN table2 z
ON z.date = c.date
Related
I have 14000 records in my sql table. They have columns ID, test_subject_id and date_created. I want to fetch all the records that have been created within a time difference of 3 minutes(difference in date_created values) and both records should have the same test_subject_id.
You should use a self join, I assume inner join is what will work for you:
SELECT a.ID, a.date_created, b.ID, b.date_created
FROM accounts a
INNER JOIN accounts b
ON a.test_subject_id = b.test_subject_id
AND TIMESTAMPDIFF(MINUTE,a.date_created,b.date_created) = 3
Note: TIMESTAMPDIFF is used assuming date_created has type datetime, details here.
You can use EXISTS:
SELECT t1.*
FROM tablename t1
WHERE EXISTS (
SELECT 1
FROM tablename t2
WHERE t2.test_subject_id = t1.test_subject_id
AND ABS(TIMESTAMPDIFF(SECOND, t1.date_created, t2.date_created)) <= 180
)
ORDER BY t1.test_subject_id, t1.date_created;
First query:
SELECT COUNT(sales.ucid) AS totalOutcomes
FROM sales
group by date(sales.saleDate)
Second query:
SELECT COUNT(*) AS joinedOutcomes
FROM sales
JOIN calls
ON sales.ucid = calls.call_id
group by date(sales.saleDate)
I now want to use the output from the second query and divide that by the output from the first query.
Can someone please help with this? Thanks!
Join the two queries.
SELECT t1.date, joinedOutcomes/totalOutcomes
FROM (
SELECT date(sales.saleDate) AS date, COUNT(sales.ucid) AS totalOutcomes
FROM sales
GROUP BY date
) AS t1
JOIN (
SELECT date(sales.saleDate) AS date, COUNT(*) AS joinedOutcomes
FROM sales
JOIN calls ON sales.ucid = calls.call_id
group by date
) AS t2 ON t1.date = t2.date
I have two tables (table 1 and table 2). Table 1 consists the options and table 2 consists the result for each options.
**table1** table2
id id
optionvalue optionvalueid
time (unixtime)
So when the data is inserted it will be stored in table2. There are 5 optionvalue in table 1 and when data is inserted, then in the table2 it will insert the optionvalueid of table 1 and timestamp in unixtimestamp. Eaach month, I want to count the number of values for each optionvalue. Evene if there is no value for an optionvalue, I still want to see count as zero.
I did the following query but only return the value with rows with data only.
SELECT
po.id,po.optionvalue, COUNT(pr.optionvalueid) as votes,
FROM_UNIXTIME(`time`, '%m-%Y') as ndate
FROM table 1
LEFT JOIN table 2 pr ON po.id=pr.optionvalueid
GROUP BY ndate, po.optionvalue ORDER BY ndate ASC
Is there any other ways to make the query so that it will return all the options even if there is no value.
You can CROSS join table1 to the distinct months of table2 and then LEFT join to table2 to aggregate:
SELECT t.ndate, t1.id, t1.optionvalue, COUNT(t2.optionvalueid) votes
FROM table1 t1
CROSS JOIN (SELECT DISTINCT FROM_UNIXTIME(`time`, '%m-%Y') ndate FROM table2) t
LEFT JOIN table2 t2 ON t1.id = t2.optionvalueid AND t.ndate = FROM_UNIXTIME(t2.`time`, '%m-%Y')
GROUP BY t.ndate, t1.id, t1.optionvalue
ORDER BY t.ndate ASC
In MS Access:
I am trying to compare two tables with:
- TABLE1.docnumb1 = TABLE2.docnumb2
- looking for: TABLE1.sum <> TABLE2.sum2
But query retrieves an error: syntax error in from clause (or when creating left join I get an error that JOIN isn't supported):
SELECT docnumb1, sum
FROM Table1
JOIN Table2 ON docnumb1 = docnumb2;
How do I query the rows with different values?
looking to your sample (image)
you could compare the subquery for sum
select t1.rownumb, t1.sum1 -t2.sum2
from (
SELECT rownumb, sum(value) sum1
FROM Table1
group by rownumb
) t1
INNER JOIN
(
SELECT rownumb, sum(value) sum2
FROM Table2
group by rownumb
) t2 ON t1.rownumb = t2.rownumb and (t1.sum1 -t2.sum2 ) <> 0
use left join
SELECT docnumb1, sum
FROM Table1 a
left JOIN Table2 b ON a.docnumb1 = b.docnumb2 and a.value=b.value
where b.docnumb2 is null
I read few articles about this: Select max date, then max time This one seems most helpful but I do not see way to implement it.
There is five tables. I join them. I need to select only one row with highest date and highest time from first table and same from second table and join the rest on some other value. With the code I wrote I get multiple rows. It seems time selection is not right.
It might be done with subquery in subquery. I've tried something like this:
SELECT * from table1
INNER JOIN table2 ON table1.date = table2.date AND table1.gm = table2.gm
INNER JOIN table3 ON table2.gm = table3.gm ...
WHERE table3.date = :date AND table4.date = :date ...
AND table1.date IN(
SELECT MAX(table1.date) FROM table1 WHERE table1.time IN(
SELECT MAX(table1.time) FROM table1
)
)
AND table2.date IN(
SELECT MAX(table2.date) FROM table1 WHERE table2.time IN(
SELECT MAX(table2.time) FROM table2 )
)
ORDER BY table1.id
Question is:
How to get single row after joining all of this where date is highest and time is highest on that date?
Thanks!
EDIT: I am sorry for this. I forgot to say that I need max time of max date related with specific value from tables(gm columns). So that is one row(in example I gave it is table1.gm and table2.gm ... ) for each one of that .gm values which are same in every table, not just one row all together. Solutions Nick and Salim provided works but I did not solved problem.
EDIT: SOLVED! after implementing solutions by Nick I just neded to add GROUP BY cntrs_reper.gm_company_no, cntrs_reper.date.
And that's it. For every row in one table enties with highest date and time from others!! Thanks to all.
EDIT. If this can help this is full query:
SELECT cntrs_gm.gm_company_no AS company_c_g,
bns_gms.ded_bns AS ded_bns_gms,
bns_gms.no_ded_bns AS no_ded_bns_gms,
bns_gms.wag_ded_bns AS wag_ded_bns_gms,
cntrs_gm.cur_credit AS cur_credit_c_g,
cntrs_gm.cdrop AS cdrop_c_g,
cntrs_gm.total_jp AS total_jp_c_g,
cntrs_gm.games AS games_c_g,
cntrs_gm.wgames AS wgames_c_g,
cntrs_gm.doors AS doors_c_g,
cntrs_gm.power AS power_c_g,
cntrs_gm.total_in AS total_in_c_g,
cntrs_gm.total_out AS total_out_c_g,
cntrs_gm.total_acc AS total_acc_c_g,
cntrs_gm.total_bet AS total_bet_c_g,
cntrs_gm.total_win AS total_win_c_g,
cntrs_gm.total_bonus AS total_bonus_c_g,
cntrs_gm.date AS date_c_g,
cntrs_reper.gm_company_no AS company_reper,
bns_reper.ded_bns AS ded_bns_reper,
bns_reper.no_ded_bns AS no_ded_bns_reper,
bns_reper.wag_ded_bns AS wag_ded_bns_reper,
cntrs_reper.cur_credit AS cur_credit_reper,
cntrs_reper.cdrop AS cdrop_reper,
cntrs_reper.total_jp AS total_jp_reper,
cntrs_reper.games AS games_reper,
cntrs_reper.wgames AS wgames_reper,
cntrs_reper.doors AS doors_reper,
cntrs_reper.power AS power_reper,
cntrs_reper.total_in AS total_in_reper,
cntrs_reper.total_out AS total_out_reper,
cntrs_reper.total_acc AS total_acc_reper,
cntrs_reper.total_bet AS total_bet_reper,
cntrs_reper.total_win AS total_win_reper,
cntrs_reper.total_bonus AS total_bonus_reper,
cntrs_reper.date AS date_reper,
cntrs_reper.time AS time_reper,
bns_reper.time AS time_c_g,
gms_cfg.gm_no AS machine_id,
gms_cfg.denom_cin AS machine_cin
FROM bns_gms
INNER JOIN cntrs_gm
ON bns_gms.gm_company_no = cntrs_gm.gm_company_no AND bns_gms.date = cntrs_gm.date
INNER JOIN bns_reper
ON cntrs_gm.gm_company_no = bns_reper.gm_company_no
INNER JOIN cntrs_reper
ON bns_reper.gm_company_no = cntrs_reper.gm_company_no AND bns_reper.date = cntrs_reper.date
INNER JOIN gms_cfg
ON cntrs_reper.gm_company_no = gms_cfg.gm_no
WHERE bns_reper.date IN(
SELECT MAX(DATE(bns_reper.date)) FROM bns_reper WHERE bns_reper.time IN(
SELECT MAX(TIME(bns_reper.time)) FROM bns_reper
)
)
AND cntrs_reper.date IN(
SELECT MAX(DATE(cntrs_reper.date)) FROM cntrs_reper WHERE cntrs_reper.time IN(
SELECT MAX(TIME(cntrs_reper.time)) FROM cntrs_reper
)
)
ORDER BY cntrs_gm.gm_company_no
DB example
bns_gms
bns_reper
cntrs_gm
cntrs_reper
gms_cfg
The problem with your current query is that it will select all rows where table1.date is the latest date on which the highest time occurs, which may well be more than one e.g. for data such as
id date time
1 2018-03-30 18:40
2 2018-03-31 12:20
3 2018-03-31 19:20
Your WHERE clause:
table1.date IN(
SELECT MAX(table1.date) FROM table1 WHERE table1.time IN(
SELECT MAX(table1.time) FROM table1
)
will select rows with id=2 and id=3 as they both have date = '2018-03-31' which is when the maximum time occurs.
What you want to do is select the row which has the latest time on the latest date, for which you could use
table1.date = (SELECT MAX(date) FROM table1) AND
table1.time = (SELECT MAX(time) FROM table1 WHERE date = (SELECT(MAX(date) FROM table1))
By using aliasing, that can be simplified (since we already know table1.date = MAX(date) FROM table1) to
table1.date = (SELECT MAX(date) FROM table1) AND
table1.time = (SELECT MAX(time) FROM table1 AS t1 WHERE t1.date = table1.date)
I don't have MySQL but here is the general idea you can use. I don't have enough points to write a comment so I am responding as a reply. Essentially make a subquery/inline view for each table to select max of a column, then join those subqueries/inline views together.
Here is Oracle syntax. You can convert it to ANSI syntax.
select table1.column1, table2.column2,table3.column3
from
(select id1, max(column1) as column1 from table1 group by id1) as table1
(select id2, max(column2) as column2 from table2 group by id2) as table2
(select id3, max(column3) as column3 from table3 group by id3) as table3
where
table1.id1 = table2.id2
and table1.id1 = table3.id3
;