least value in count - mysql

Question

i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute.
Show all the employee who were hired on the day of the week on which least no of employee were hired.
i have done the query, but am not able to get the least. please check if am correct.
select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count
from test.employee group by days

Answer 1

This should get you the weekday on which the least number of employees were hired:
SELECT
count(id) as `Total`,
WEEKDAY(hire_date) as `DoW`
FROM
test.employee
GROUP BY `DoW`
ORDER BY `Total` DESC LIMIT 1;

Answer 2

select id from test.employee where hire_date in
( select count(id) count,hire_date
from test.employee
order by count desc
limit 1)
this should work

Answer 3

You may try this, as it will not limit to one record if you have multiple week days where the same least number of employees were hired. In reality it makes sense. The following is based on sample data.
Query:
-- find minimum id count
SELECT MIN(e.counts) INTO #min
FROM (SELECT COUNT(*) as counts,
WEEKDAY(hire_date+1) as day
FROM employee
GROUP BY WEEKDAY(hire_date+1)) e
;
-- show weekdays with minimum id counts
SELECT e2.counts as mincount,
WEEKDAY(e1.hire_date+1) as weekday
FROM employee e1
JOIN (SELECT COUNT(id) as counts,
WEEKDAY(hire_date+1) as day
FROM employee
GROUP BY day
HAVING COUNT(*) = #min) e2
ON WEEKDAY(e1.hire_date+1) = e2.day;
Results:
MINCOUNT WEEKDAY
1 6
1 3
1 4
1 2
SQLFIDDLE

Answer 4

select min(id), WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count
from test.employee group by days

Answer 5

SELECT
*
FROM
employee
WHERE
DAYOFWEEK(hire_date)
IN
(
SELECT
weekday
FROM
(
SELECT
count(*) as bcount,
DAYOFWEEK(hire_date) as weekday
FROM
employee as a
GROUP BY
weekday
HAVING
bcount = (
SELECT
MIN(tcount)
FROM
(
SELECT
count(*) as tcount,
DAYOFWEEK(hire_date) as weekday
FROM
employee
GROUP BY
weekday
) as t
)
) as q