No idea what is going on here. Here is the query, right from phpMyAdmin:
SELECT * FROM `la_schedule` WHERE 'start_date' >'2012-11-18';
But I consistently get all records in the table returned, including those with start date 2012-11-01. What gives?
you have enlosed start_date with single quote causing it to become string, use backtick instead
SELECT * FROM `la_schedule` WHERE `start_date` > '2012-11-18';
SQLFiddle Demo
In your statement, you are comparing a string called start_date with the time.
If start_date is a column, it should either be
SELECT * FROM `la_schedule` WHERE start_date >'2012-11-18';
(no apostrophe)
or
SELECT * FROM `la_schedule` WHERE `start_date` >'2012-11-18';
(with backticks).
Hope this helps.
Try this.
SELECT * FROM la_schedule WHERE `start_date` > '2012-11-18';
I have tried but above not working after research found below the solution.
SELECT * FROM my_table where DATE(start_date) > '2011-01-01';
Ref
Adding this since this was not mentioned.
SELECT * FROM `la_schedule` WHERE date(start_date) > date('2012-11-18');
Because that's what actually works for me. Adding date() function on both comparison values.
In my case my column was a datetime it kept giving me all records. What I did is to include time, see below example
SELECT * FROM my_table where start_date > '2011-01-01 01:01:01';
If you are comparing timestamp - you could try following
select * from table where columnInTimestamp > ((UNIX_TIMESTAMP() * 1000) - (1*24*60*60*1000))
Here UNIX_TIMESTAMP()gives current timestamp where as "12460601000" is the timestamp for 1 day -- With this you can find data just got created in 1 day or 2 days etc.
Related
Is it possible to do something like this?
select * from table where Date BETWEEN '2019-05-29' AND '2019-05-29'
Yes it is possible. If you have time part you could use DATE function to skip it:
SELECT * FROM table WHERE DATE(Date) BETWEEN '2019-05-29' AND '2019-05-29'
-- it may degrade performance, condition is not SARGable
Yes, but the better approach is:
select t.*
from table t
where t.Date >= date('2019-05-29') AND
t.Date < date('2019-05-29') + interval 1 day
Why is this better? It doesn't have a function on the column name, so it can make use of an index on the date column.
Yes you can, if you want to run it in a test window without manually changing the date within the code you can set it as a variable. Use trunc to get rid of time i.e there will be no 29-05-2019 23:59:00. If you want the same date within a time period remove the trunc and then you can set hours-minutes-seconds which makes your query more precise
SELECT t.*
FROM table t
WHERE t.date BETWEEN trunc(to_date(:datefrom, 'dd.mm.yyyy hh24:mi:ss')) AND
trunc(to_date(:dateto, 'dd.mm.yyyy hh24:mi:ss'))
As you show in the below images I want to fetch result in between date from date range.
I have try this query but it doesn't work.
I want bigger date then DTT_EVT_start start table date.
Can anyone suggest me how can I use date(not time)column in where clause ?
SELECT *
FROM `dwssgv_esp_datetime`
WHERE (DATE_FORMAT(DTT_EVT_start, '%Y-%m-%d') < '2015-05-10')
AND (DATE_FORMAT(DTT_EVT_end, '%Y-%m-%d') > '2015-05-10')
Something like this?
SELECT * FROM dwssgv_esp_datetime WHERE DTT_EVT_start < '2015-05-10' AND DTT_EVT_end > ''2015-05-10'
You can avoid DATE_FORMAT function,
as it would affect on the performance if its a huge table
you may simply do like,
SELECT
*
FROM
dwssgv_esp_datetime
WHERE
DTT_EVT_start < CAST('2015-05-10 00:00:00' AS DATETIME) AND
DTT_EVT_end > CAST('2015-05-10 00:00:00' AS DATETIME)
Here, < 2015-05-10 > is your variable date.
OR
SELECT
*
FROM
dwssgv_esp_datetime
WHERE
DATE(DTT_EVT_start) < CAST('2015-05-10' AS DATE) AND
DATE(DTT_EVT_end) > CAST('2015-05-10' AS DATE)
You can convert dates in UNIX_TIMESTAMP format and compare
Try this
SELECT
*
FROM
`dwssgv_esp_datetime`
WHERE (UNIX_TIMESTAMP(DTT_EVT_start) < UNIX_TIMESTAMP('2015-05-10')
AND (UNIX_TIMESTAMP(DTT_EVT_end) > UNIX_TIMESTAMP('2015-05-10')
Here is a simple solution:
SELECT *
FROM dwssgv_esp_datetime
WHERE
CAST('2015-05-10' AS DATE)
BETWEEN DATE(DTT_EVT_start)
AND DATE(DTT_EVT_end)
BETWEEN AND allows you to check if a value is in a particular range or not. By using this you do not have to write the value you want to compare twice.
im having a problem where i cant think of a solution, maybe im having a bad table-structure or i just dont know enough about mysql select commands to think of a good solution. Maybe you can help me out:
So i got a table that has a Column with the Date-format (yyyy-mm-dd) i wanted to select all upcoming dates so i did:
SELECT * WHERE date >= now.
This worked kinda well but i also got "dates" where only the year is entered (2014-00-00) i also wanted to select these but "now" is already bigger so i made another column with the year only and if the month, date or both arent known i will use 0000-00-00 and the Column "year" now i could select like this:
SELECT * WHERE date >= now AND year >=now(year)
Now all entrys with 0000-00-00 wont be selected. If i use OR the entrys from last year will be shown.
So thats my problem, is there any way i can change my table so i can have entries with only the year or only year and month and of course all together? I already considered get rid of the date-format and use simple INT with seperated columns for year, month and date. But i think i will have the same problem.
Sometimes i just want to do a capsuled select like
SELECT *
WHERE (date >= now AND year >= now(year))
OR date == "0000-00-00" (i know that this doesnt work)
If I understood your problem correctly, you could use this request:
WHERE (date >= now OR year > now(year))
There is probably a simpler way though, that would preserve your design, like initializing at January 1st (01-01) instead of 00-00
I think you can use this code:
$_SESSION['month'] = //set here your selected month
$_SESSION['year'] = //set here your selected year
SELECT * FROM table WHERE DATEPART(m,date) >= '".$_SESSION['month']."' AND DATEPART(yyyy,year) >= '".$_SESSION['year']."' AND date <> '0000-00-00'
Change your table structure format. Actually just allow for that field to have null value when not entered. By default it will be null then. You shouldn't be storing 0000-00-00 as a value for Date type field. I would rather leave it as null , or as suggested in some of previous answers, initialize it with some other date. It would be much easier to manipulate with database then.
the problem is that half of you write is not MySQL and your database schema is terrible...
You have the following problems:
column data date does not have the date data type.
To fix it, you need to add a cast to the select statement eg. cast(datecolumn as date)
select * from table where cast(datecolumn as date) >= '2014-01-10';
the way to use now date is using the now function.
select now(), date(now());
result> 2014-01-10 11:11:36, 2014-01-10
select * from table where cast(datecolumn as date) >= date(now());
Because your datecolumn is not a date (2014-00-00 is not a valid date), you need to use string manipulation to extract the year.
select substring('2014-01-01', 1,4)
result> 2014
select * from table where substring(datecolumn, 1,4) = year(now());
The comparassion operator is = and not ==
the select statement syntax looks like this (pay attention because you are missing the table in your statement)
select * from [Table] where [column] = condition ...
You probably need or instead of ands, therefore your query should look like this:
select * from FooTable where
cast(datecolumn as date) >= date(now())
or substring(datecolumn, 1,4) >= year(now())
or datecolumn = '0000-00-00'
You should use something like phpmyAdmin or mySQL workbench to test your sql queries before try to use them on php, java or whatever is your programing language.
i trying to do a sql query which i combine de compare operators with substring.
in my column date i have the following value inside : 09-01-2014 12:02:55
what i try to now is to select all rows which is >= 09-01-2014 and for example <=22-01-2014
how can i do it?
i have trying for example with this code:
SELECT * From table Where Name= 'Something'
AND SUBSTRING(date,1,10) = '09-01-2014'
AND SUBSTRING(date,1,10) < '22-01-2014'
You can use the BETWEEN operator
SELECT * FROM table
WHERE Name = 'Something'
AND SUBSTRING(date, 1, 10) BETWEEN '09-01-2014' AND '22-01-2014'
EDIT: I'm still leaving this here, but it is not an error proof solution (as pointed out by oerkelens down in the comments)
The BETWEEN operator will work, like this:
SELECT *
From table
Where Name= 'Something'
AND `date` BETWEEN '2014-01-09' AND '2014-01-23'
Working Demo: http://sqlfiddle.com/#!2/b4d7e
Try this:
SELECT *
FROM tableA a
WHERE a.nme= 'Something' AND
DATE(STR_TO_DATE(a.date, '%d-%m-%Y %H:%i:%s')) >= '2014-01-09' AND
DATE(STR_TO_DATE(a.date, '%d-%m-%Y %H:%i:%s')) <= '2014-01-22';
OR
SELECT *
FROM tableA a
WHERE a.nme= 'Something' AND
DATE(STR_TO_DATE(a.date, '%d-%m-%Y %H:%i:%s')) BETWEEN '2014-01-09' AND '2014-01-22';
Using the following syntax makes your query sargable. It allows query to use any Indexes defined on the date column. for more information SARGable Queries with Datetime Datatype
SELECT * From table
Where Name= 'Something'
AND [DateColumn] >= '20140109'
AND [DateColumn] <= '20140122'
You are converting the date from the table row into a string before comparing to the bookend dates. You need to do the opposite. Convert the bookend dates from strings to dates, then compare each test date.
Some form of the CONVERT or CAST function should do that for you.
The reason your approach won't work is that when SQL server compares strings, it uses alphabetical order. You want ascending date order, which is a different order.
Which Database do you use? Oracle:
SELECT *
FROM table tbl
WHERE 1=1
AND name = 'Something'
AND trim(tbl.column) >= to_date('2014-01-09','DD-MM-YYYY')
AND trim(tbl.column) <= to_date('2014-01-22','DD-MM-YYYY')
or you just convert it into a number/integer like YYYYMMDD then the >= =< operators will work too.
I am trying to only grab records that fall in a certain date range. The problem is that the timestamp and the date are stored as a string in the same cell. I want to only grab rows with a date that falls betweed 2013-05-01 and 2013-05-03.
date (stored as string)
2013-05-01T23:19:44
2013-05-02T23:19:40
2013-05-06T23:19:46
2013-05-06T23:15:17
mysql
SELECT * FROM table WHERE date BETWEEN 2013-05-01 AND 2013-05-03
Try
SELECT *
FROM table1
WHERE STR_TO_DATE(`date`,'%Y-%m-%d') BETWEEN '2013-05-01' AND '2013-05-03'
SQLFiddle
As #FreshPrinceOfSO absolutely correctly noted no index will be used in that case
SELECT * FROM table1
WHERE STR_TO_DATE(SUBSTRING(`date`,1,10),'%d-%m-%Y')
BETWEEN '2013-05-01' AND '2013-05-03'
The string is almost valid syntax for a datetime. Thus, an alternative, if perhaps slower method is to replace the 'T' with a space and then cast it to a datetime.
SELECT * FROM table1 WHERE
CAST(REPLACE(`date`, 'T', ' ') AS DATETIME)
BETWEEN '2013-05-01' AND '2013-05-03';
SELECT * FROM table
WHERE date('yourdate') BETWEEN date('2013-05-01') AND date('2013-05-03')