Select and show business open hours from MySQL - mysql

Question

I dont need to check if business is open or close, but I need to show open hours by days.
There are some options:
1 - Business open once in day (sample - from 10:00 to 18:30) - one
rows in table
2 - Business open TWICE in day (samlpe - from 10:00 to
14:00 and from 15:00 to 18:30) - two rows in table
3 - Business may
be closed (no row inserted)
Here my MySql table of hours storing. In this sample business (affiliate_id) are open twice in days from 0 to 4, once in day 5 and closed in day 6 (no records for this day)
http://postimage.org/image/yplj4rumj/
What I need to show in website its like (according to this database example:
0,1,2,3,4 - open 10:00-14:00 and 15:00-18:30
5 - open 10:00-12:00
6 - closed
How I get results like:
http://postimage.org/image/toe53en63/
?
I tried to make queries with GROUPֹ_CONCAT and LEFT JOIN the same table ON a.day=b.day but with no luck :(
There sample of my query (that is wrong)
SELECT GROUP_CONCAT( DISTINCT CAST( a.day AS CHAR )
ORDER BY a.day ) AS days, DATE_FORMAT( a.time_from, '%H:%i' ) AS f_time_from, DATE_FORMAT( a.time_to, '%H:%i' ) AS f_time_to, DATE_FORMAT( b.time_from, '%H:%i' ) AS f_time_from_s, DATE_FORMAT( b.time_to, '%H:%i' ) AS f_time_to_s
FROM business_affiliate_hours AS a LEFT
JOIN business_affiliate_hours AS b ON a.day = b.day
WHERE a.affiliate_id =57
GROUP BY a.time_from, a.time_to, b.time_from, b.time_to
ORDER BY a.id ASC
This my table:
CREATE TABLE IF NOT EXISTS `business_affiliate_hours` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`affiliate_id` int(10) unsigned NOT NULL DEFAULT '0',
`time_from` time NOT NULL,
`time_to` time NOT NULL,
`day` tinyint(1) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`id`)
) ENGINE=MyISAM;
INSERT INTO `business_affiliate_hours` (`id`, `affiliate_id`, `time_from`, `time_to`, `day`) VALUES
(53, 57, '10:00:00', '12:00:00', 5),
(52, 57, '15:00:00', '18:30:00', 4),
(51, 57, '10:00:00', '14:00:00', 4),
(50, 57, '15:00:00', '18:30:00', 3),
(49, 57, '10:00:00', '14:00:00', 3),
(48, 57, '15:00:00', '18:30:00', 2),
(47, 57, '10:00:00', '14:00:00', 2),
(46, 57, '15:00:00', '18:30:00', 1),
(45, 57, '10:00:00', '14:00:00', 1),
(44, 57, '15:00:00', '18:30:00', 0),
(43, 57, '10:00:00', '14:00:00', 0);
Open hours may be different for every day, so I want to GROUP by the same open hours, and get list of days for all unique order of open hours.
Need your help!
Sorry for links to images, I cant upload images yes to here.

Answer 1

First build a materialised table of each day's combined times, then group on that:
SELECT GROUP_CONCAT(day ORDER BY day) AS days,
DATE_FORMAT(f1, '%H:%i') AS f_time_from,
DATE_FORMAT(t1, '%H:%i') AS f_time_to,
DATE_FORMAT(f2, '%H:%i') AS f_time_from_s,
DATE_FORMAT(t2, '%H:%i') AS f_time_to_s
FROM (
SELECT day,
MIN(time_from) AS f1,
MIN(time_to ) AS t1,
IF(COUNT(*) > 1, MAX(time_from), NULL) AS f2,
IF(COUNT(*) > 1, MAX(time_to ), NULL) AS t2
FROM business_affiliate_hours
WHERE affiliate_id = 57
GROUP BY day
) t
GROUP BY f1, t1, f2, t2
ORDER BY days
See it on sqlfiddle.