Loading a form action inside a div - html

Question

I have a form and I want to load the results from it into a div. I've already searched some topics about this and I thought that this one jquery submit form and then show results in an existing div would work but it doesn't.
This is my code so far:
<script type="text/javascript"> $('#form').submit(function() { // catch the form's submit event
$.ajax({ // create an AJAX call...
data: $(this).serialize(), // get the form data
type: $(this).attr('method'), // GET or POST
url: $(this).attr('action'), // the file to call
success: function(response) { // on success..
$('#test').html(response); // update the DIV
}
});
return false; // cancel original event to prevent form submitting }); </script>
<DIV id="test"></DIV>
<FORM id="form" name="pcc" method="post" action="http://wl.breedbandwinkel.nl/postcodecheck" onSubmit="return validatePcc(this);">
<div class="one_third firstcols">
<H4>Ik ben op zoek naar:</H4>
<DIV class="ff"><INPUT type="radio" class="pccrad radio" name="sub" value="alles-in-een-pakketten" id="pcc-alles-in-een-pakketten" onclick="$('#pcc-no').hide(); $('#pcc-fpcon').css('visibility', 'visible'); if($('#pcg').val() == '') $('#pcg').focus();"><LABEL class="left pcm" for="pcc-alles-in-een-pakketten" onmouseover="mpopup('Alles-in-één pakketten','Extra voordelig pakket met internet, digitale telefonie en/of digitale televisie.');" onmouseout="kill();">Alles-in-één pakketten</LABEL></DIV> <DIV class="ff"><INPUT type="radio" class="pccrad radio" name="sub" value="internet" id="pcc-internet" onclick="$('#pcc-no').hide(); $('#pcc-fpcon').css('visibility', 'visible'); if($('#pcg').val() == '') $('#pcg').focus();"><LABEL class="left pcm" for="pcc-internet" onmouseover="mpopup('Internet','Altijd supersnel onbeperkt online tegen een vast bedrag per maand.');" onmouseout="kill();">Internet</LABEL></DIV> <DIV class="ff"><INPUT type="radio" class="pccrad radio" name="sub" value="digitale-televisie" id="pcc-digitale-televisie" onclick="$('#pcc-no').hide(); $('#pcc-fpcon').css('visibility', 'visible'); if($('#pcg').val() == '') $('#pcg').focus();"><LABEL class="left pcm" for="pcc-digitale-televisie" onmouseover="mpopup('Digitale Televisie','Geniet van haarscherp digitaal beeld en geluid inclusief de gratis digitale programmagids.');" onmouseout="kill();">Digitale Televisie</LABEL></DIV>
</div><!-- end .one_third -->
<div class="one_third">
<H4>Mijn postcode en huisnummer zijn:</H4>
<TABLE border="0" cellspacing="0" cellpadding="0">
<TR>
<TD height="14" colspan="2">Postcode</TD>
<TD>Huisnr.</TD>
</TR>
<TR>
<TD width="51"><INPUT type="text" class="text" maxlength="4" size="5" value="" name="pcg" id="pcg" onKeyUp="autoTab(event,this,4,pcl);" onFocus="chBg(pcc,'pcg');" onBlur="chBg(pcc,'reset');" style="width: 41px;"></TD>
<TD width="46"><INPUT type="text" class="text" maxlength="2" size="2" value="" name="pcl" id="pcl" onKeyUp="autoTab(event,this,2,hn);" onKeyDown="backSpace(event,this,pcg);" onFocus="chBg(pcc,'pcl');" onBlur="chBg(pcc,'reset'); upperCase(event,this);" style="width: 26px;"></TD>
<TD width="36"><INPUT type="text" class="text" maxlength="6" size="4" value="" name="hn" id="hn" onKeyDown="backSpace(event,this,pcl);" onFocus="chBg(pcc,'hn');" onBlur="chBg(pcc,'reset');" style="width: 36px;"></TD>
</TR>
</TABLE>
<U class="dot small" onmouseover="popup('Waarom mijn postcode invullen?','Om te kunnen controleren welke abonnementen op uw adres leverbaar zijn hebben wij uw postcode en huisnummer nodig.<br>Uiteraard respecteren wij uw privacy. Deze gegevens worden niet opgeslagen.');" onmouseout="kill();">
Waarom mijn postcode invullen?</U>
</div><!-- end .one_third -->
<div class="one_third lastcols">
<INPUT type="submit" name="submit" value="Vergelijk de aanbiedingen op uw adres" class="button">
</div><!-- end .one_third -->
</FORM>
So I figured out that this is not working. I would really like to show the results from the action url (http://wl.breedbandwinkel.nl/postcodecheck) into <div id="test">.
Currently I'm doing this within an iframe but that just doesn't look "professional".
I hope I gave enough information, if not let met know.

Answer 1

Most importantly, if your Web page is not running from within http://wl.breedbandwinkel.nl, the AJAX call probably won't run at all due to most every browser disabling cross-site scripting. You can't make an AJAX request to foo.com from a page served from bar.com. To circumvent this, what I usually do is write a file such as "bar.com/ajaxActions.php" and then use that PHP script to make either the GET or POST request to the foreign site. Once it retrieves the result, I simply print that result to the standard output, which then becomes the result of your AJAX request.
The other thing I would do is ditch the "method" and "action" attributes in your <form> tag and put those in the AJAX request you're trying to write with jQuery. Use an onClick() listener in your submit button instead, as such:
<INPUT type="submit" name="submit" onClick="doAjaxRequest()" value="Vergelijk de aanbiedingen op uw adres" class="button">
Then in that function, use the code you already had in place for starters:
<script type="text/javascript">
function doAjaxRequest() {
$.ajax({ // create an AJAX call...
data: $("#form").serialize(), // get the form data
type: GET, // GET or POST
url: "ajaxActions.php", // the file to call -- postcodecheck if you're on that same domain, otherwise ajaxActions.php
success: function(response) { // on success..
$('#test').html(response); // update the DIV
}
});
}
Finally, if you're not on the same domain, I will leave it to you to find out the PHP code for the GET request (use file_get_contents()) or the POST request (use cURL). Or if you can't use PHP, then use your back-end language of choice. In PHP, assuming your post code checker accepted a GET request, your ajaxActions.php file would look something like this:
$response = file_get_contents("http://wl.breedbandwinkel.nl/postcodecheck?pcg=" . $_GET["pcg"] . "&pcl=" . $_GET["pcl"] . "&hn=" . $_GET["hn"] );
print $reponse;