MYSQL query - getting totals by month - mysql

Question

http://sqlfiddle.com/#!2/6a6b1
The scheme is given above.. all I want to do is get the results as the total of sales/month... the user will enter a start date and end date and I can generate (in PHP) all the month and years for those dates. For example, if I want to know the total number of "sales" for 12 months, I know I can run 12 individual queries with start and end dates, but I want to run only one query where the result will look like:
Month numofsale
January - 2
Feb-1
March - 23
Apr - 10
and so on...
or just a list of sales without the months, I can then pair it to the array of months generated in the PHP ...any ideas...
Edit/schema and data pasted from sqlfiddle.com:
CREATE TABLE IF NOT EXISTS `lead_activity2` (
`lead_activity_id` int(11) NOT NULL AUTO_INCREMENT,
`sp_id` int(11) NOT NULL,
`act_date` datetime NOT NULL,
`act_name` varchar(255) NOT NULL,
PRIMARY KEY (`lead_activity_id`),
KEY `act_date` (`act_date`),
KEY `act_name` (`act_name`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 ;
INSERT INTO `lead_activity2` (`lead_activity_id`, `sp_id`, `act_date`, `act_name`) VALUES
(1, 5, '2012-10-16 16:05:29', 'sale'),
(2, 5, '2012-10-16 16:05:29', 'search'),
(3, 5, '2012-10-16 16:05:29', 'sale'),
(4, 5, '2012-10-17 16:05:29', 'DNC'),
(5, 5, '2012-10-17 16:05:29', 'sale'),
(6, 5, '2012-09-16 16:05:30', 'SCB'),
(7, 5, '2012-09-16 16:05:30', 'sale'),
(8, 5, '2012-08-16 16:05:30', 'sale'),
(9, 5,'2012-08-16 16:05:30', 'sale'),
(10, 5, '2012-07-16 16:05:30', 'sale');

Answer 1

SELECT DATE_FORMAT(date, "%m-%Y") AS Month, SUM(numofsale)
FROM <table_name>
WHERE <where-cond>
GROUP BY DATE_FORMAT(date, "%m-%Y")
Check following in your fiddle demo it works for me (remove where clause for testing)
SELECT DATE_FORMAT(act_date, "%m-%Y") AS Month, COUNT(*)
FROM lead_activity2
WHERE <where-cond-here> AND act_name='sale'
GROUP BY DATE_FORMAT(act_date, "%m-%Y")
It returns following result
MONTH COUNT(*)
07-2012 1
08-2012 2
09-2012 1
10-2012 3

Answer 2

You can try query as given below
select SUM(`SP_ID`) AS `Total` , DATE_FORMAT(act_date, "%M") AS Month, Month(`ACT_DATE`) AS `Month_number` from `lead_activity2` WHERE `ACT_DATE` BETWEEN '2012-05-01' AND '2012-12-17' group by Month(`ACT_DATE`)
Here 2012-05-01 and 2012-12-17 are date input from form. and It will be return you the sum of sales for particular month if exist in database.
thanks

Answer 3

Try this query -
SELECT
MONTH(act_date) month, COUNT(*)
FROM
lead_activity2
WHERE
YEAR(act_date) = 2012 AND act_name = 'sale'
GROUP BY
month
Check WHERE condition if it is OK for you - act_name = 'sale'.
If you want to output month names, then use MONTHNAME() function instead of MONTH().

Answer 4

SELECT YEAR(act_date), MONTH(act_date), COUNT(*)
FROM lead_activity2
GROUP BY YEAR(act_date), MONTH(act_date)
For getting data by month or any other data based on column you have to add GROUP BY.
You can add many columns or calculated values to GROUP BY.
I assume that "num of sales" means count of rows.

Answer 5

Sometimes you might want the month names as Jan, Feb, Mar .... Dec possibly for a Chart likeFusionChart
SELECT DATE_FORMAT(date, "%M") AS Month, SUM(numofsale)
FROM <Table_name>
GROUP BY DATE_FORMAT(date, "%M")
Results would look like this on table
MONTH COUNT(*)
Jul 1
Aug 2
SEP 1
OCT 3