I'm trying to insert a ton of rows into my MySQL database. I have a query like this, but with about 700 more repetitive entries in it but for some reason the query is only inserting the first row to the database. In this case it would be '374','4957','0'.
INSERT INTO table VALUES ('374','4957','0'),('374','3834','0'),('374','4958','0'),('374','5076','0'),('374','4921','0'),('374','3835','0'),('374','4922','0'),('374','3836','0'),('374','3837','0'),('374','4879','0'),('374','3838','0')
I can't figure out what I'm doing wrong.
Thank you in advance.
Don't mean to state the obvious, but if the first field '374' is your primary key field, than this is the issue.
Otherwise, are there any error messages received from the database? That is always a good place to look for bugs.
For better understanding why something is not working next time use code like this:
$sql = "INSERT INTO table VALUES ('374','4957','0'),('374','3834','0')";
if (!mysqli_query($link, $sql)) {
printf("Errormessage: %s\n", mysqli_error($link));
}
That should display error message returned from MySQL.
More information: PHP manual - mysqli_error
Try to write the column names before values.
For example:
INSERT INTO table (column1,column2,column3) VALUES ...
Related
I am trying to select some rows from a table that I have in my database but I keep obtaining null $result. I think the problem is with my sql code.
The query is the following:
$result = mysqli_query($this->conexion, $sql);
The conexion is working fine I have checked so the problem is with $sql. My vareiable $sql is:
"SELECT * FROM `invent` WHERE `id_system` IN (500,504,502,498,499)"
My table is invent and I have a row named id_system, I have checked all the names and are correctly spelt and the column id_system contains integers and all ones of the query exist in the table.
I keep getting:
$result={"current_field":null,"field_count":null,"lengths":null,"num_rows":null,"type":null}
I don't know why is it not working, it might be because of the spelling in $sql.
Could someone help me?
Thanks in advance
I don't know if this will help, but this code might work for you:
SELECT 'id_system'
FROM 'invent'
WHERE 'id_system'=500
OR 'id_system'=504
And then you could add the rest of the values you need
I am trying to insert data into mysql table through mysql C client, through the step written below.
The command is of the Form : (A variable string generated at run time)
INSERT INTO department values('Statistics','Taylor',395051.74)
which is correct for MySQL.
if (mysql_query(con, command))
{
printf("Done\n");
}
printf("\n%s\n",command);
But my database shows no change. No rows get inserted, is there any way the above steps could not work?
Note that mysql_query returns a zero if it is successful, and an error code if it's unsucessful MySQL Docs. I think you might be treating it backward. So I think it's issuing an error you're not catching.
As a guess of what might be wrong, try telling it what columns you're inserting into:
INSERT INTO department (`column1`,`column2`,`column3`)
values ('Statistics','Taylor',395051.74)
I want to insert two dates into a specifc row on my table using MySql but have a syntax error on Workbench (Error 1064):
INSERT INTO atable (Activated,Expiry) WHERE Access_Code = 'accesscode'
VALUES('$current_date','$Expiration_Date')
What would be the correct version for this?
It would be something like this:
UPDATE atable
SET Activated='$current_date',
Expiry='$Expiration_date'
WHERE Access_Code='accesscode';
I'm assuming you will be setting $current_date and $Expiration_date via (what looks like PHP) code.
Hope this helps.
I really don't know what is happening insert query is not working for me.
$query_getgreenyear = "INSERT INTO `greenityear` `ConsolidateYear` VALUES ('".$sentdata."')";
in $sentdata the value is ('A','B') and the datatype for ConsolidateYear is varchar.I need this value to be inserted into the database.
but i am getting error
You have a SQL syntax error near 'ConsolidateYear VALUES ('('A','B')')' at line 1.
Please help me in this regard.
I am new to database activities.
You forgot to place a bracket() for your column name.
Try this:
$query_getgreenyear = "INSERT INTO `greenityear` (`ConsolidateYear`)
VALUES ('".$sentdata."')";
Please take a look at the MySQL Reference Manual.
You need to surround your column name with parantheses in your INSERT statement:
$query_getgreenyear = "INSERT INTO `greenityear` (`ConsolidateYear`) VALUES ('".$sentdata."')";
And I would highly recommend you to use prepared statements as provided by your MySQL-extension (at least if you're not using the deprectated mysql_connect). This protects you against SQL injections.
INSERT INTO `greenityear` (`ConsolidateYear`) VALUES (...)
But, you really should be using prepared statements and not constructing statements as you are.
the correct syntax is
INSERT INTO `tablename` (`columnname1`,`columnname2`) VALUES ('value1','value2')
so your example would be like this:
$query_getgreenyear = "INSERT INTO `greenityear` (`ConsolidateYear`) VALUES ('".$sentdata."')";
I am developing a PHP script and I have a table like this:
TABLE_CODE
code varchar 8
name varchar 30
this code column has to be a code using random letters from A to Z and characters from 0 to 9 and has to be unique. all uppercase. Something like
A4RTX33Z
I have create a method to generate this code using PHP. But this is a intensive task because I have to query the database to see if the generated code is unique before proceeding and the table may have a lot of records.
Because I know mySQL is a bag of tricks but not having advanced knowledge about it now, I wonder if there's some mechanism that could be built in a table to run a script (or something) every time a new record in created on that table to fill the code column with a unique value.
thanks
edit: What I wonder is if there's a way to created the code on-the-fly, as the record is being added to the table and that code being unique.
Better generate these codes in SQL. This is 8-character random "Promo code generator":
INSERT IGNORE INTO
TABLE_CODE(name, code)
VALUES(
UPPER(SUBSTRING(MD5(RAND()) FROM 1 FOR 8)), -- random 8 characters fixed length
'your code name'
)
Add UNIQUE on code field as #JW suggested, and some error-handling in PHP, because sometimes generated value may be not UNIQUE, and MySQL will raise error in that situation.
Adding a UNIQUE constraint on the code column is the first thing you would need to do. Then, to insert the code I would write a small loop like this:
// INSERT IGNORE will not generate an error if the code already exists
// rather, the affected rows will be 0.
$stmt = $db->prepare('INSERT IGNORE INTO table_code (code, name) VALUES (?, ?)');
$name = 'whatever name';
do {
$code = func_to_generate_code();
$stmt->execute(array($code, $name));
} while (!$stmt->rowCount()); // repeat until at least one row affected
As the table grows the number of loops may increase, so if you feel it should only try three times, you could add it as a loop condition and throw an error if that happens.
Btw, I would suggest using transactions to make sure if an error occurs after the code generation, rolling back will make sure the code is removed (can be reused).