I have a field enq_id - it currently contains numbers such as:
80081
414365
567
Now, I need to update the field in two ways, firstly I need to find out if any of the numbers are more than 6 characters long (there shouldn't be but I need to check). I then need to set a character limit of 6 characters on that field and then, finally, add 0's to the beginning of any enq_id that isn't 6 characters long to make it 6 characters.
Any ideas?
If the following returns the result you're trying to achieve:
SELECT
`enq_id`,
IF(CHAR_LENGTH(`enq_id`) < 6,
LPAD(`enq_id`,6,'0'),
SUBSTRING(`enq_id`,1,6)
) AS 'result'
FROM `some_table`
WHERE CHAR_LENGTH(`enq_id`) != 6
Then using the following will update your table accordingly.
UPDATE `some_table`
SET `enq_id` =
IF(CHAR_LENGTH(`enq_id`) < 6,
LPAD(`enq_id`,6,'0'),
SUBSTRING(`enq_id`,1,6))
WHERE CHAR_LENGTH(`enq_id`) != 6
Note that the SUBSTRING() function deletes all the characters after the 6th character, and LPAD adds preceding zeros (in the above example) if needed, to each record.
UPDATE: For some reason I added an extra condition. The optimized code(s) should have been:
SELECT `enq_id`,LPAD(`enq_id`,6,'0') AS 'result'
FROM `some_table`
WHERE CHAR_LENGTH(`enq_id`) < 6
and
UPDATE `some_table`
SET `enq_id` = LPAD(`enq_id`,6,'0')
WHERE CHAR_LENGTH(`enq_id`) < 6
Related
I have a SQL Table in that i use BETWEEN Operater.
The BETWEEN Operater selects values within range. The values can be numbers, text , dates.
stu_id name city pin
1 Raj Ranchi 123456
2 sonu Delhi 652345
3 ANU KOLKATA 879845
4 K.K's Company Delhi 345546
5 J.K's Company Delhi 123456
I have a query like this:-
SELECT * FROM student WHERE stu_id BETWEEN 2 AND 4 //including 2 & 4
SELECT * FROM `student` WHERE name between 'A' and 'K' //including A & not K
Here My Question is why not including K.
but I want K also in searches.
Don't use between -- until you really understand it. That is just general advice. BETWEEN is inclusive, so your second query is equivalent to:
WHERE name >= 'A' AND
name <= 'K'
Because of the equality, 'K' is included in the result set. However, names longer than one character and starting with 'K' are not -- "Ka" for instance.
Instead, be explicit:
WHERE name >= 'A' AND
name < 'L'
Of course, BETWEEN can be useful. However, it is useful for discrete values, such as integers. It is a bit dangerous with numbers with decimals, strings, and date/time values. That is why I encourage you to express the logic as inequalities.
In supplement to gordon's answer, one way to get what you're expecting is to turn your name into a discrete set of values:
SELECT * FROM `student` WHERE LEFT(name, 1) between 'A' and 'K'
You need to appreciate that K.K's Company is alphabetically AFTER the letter K on its own so it is not BETWEEN, in the same way that 4.1 is not BETWEEN 2 and 4
By stripping it down to just a single character from the start of the string it will work like you expect, but take cautionary note, you should always avoid running functions on values in tables, because if you had a million names, thats a million strings that mysql has to strip out to just the first letter and it might no longer be able to use an index on name, battering the performance.
Instead, you could :
SELECT * FROM `student` WHERE name >= 'A' and name < 'L'
which is more likely to permit the use of an index as you aren't manipulating the stored values before comparing them
This works because it asks for everything up to but not including L.. Which includes all of your names starting with K, even kzzzzzzzz. Numerically it is equivalent to saying number >= 2 and number < 5 which gives you all the numbers starting with 2, 3 or 4 (like the 4.1 from before) but not the 5
Remember that BETWEEN is inclusive at both ends. Always revert to a pattern of a >= b and a < c, a >= c and a < d when you want to specify ranges that capture all possible values
Compare in lexicographical order, 'K.K's Company' > 'K'
We should convert the string to integer. You can try that mysql script with CAST and SUBSTRING. I've updated your script here. It will include the last record as well.
SELECT * FROM student WHERE name CAST(SUBSTRING(username FROM 1) AS UNSIGNED)
BETWEEN 'A' AND 'K';
The script will work. Hope it will helps to you.
Here I've attached my test sample.
I wasn't able to find this anywhere, here's my problem:
I have a string like '1 2 3 4 5' and then I have a mysql table that has a column, let's call it numbers, that look like this:
numbers
1 2 6 8 9 14
3
1 5 3 6 9
7 8 9 23 44
10
I am trying to find the easiest way (hopefully in a single query) to find the rows, where any of the numbers in my search string (1 or 2 or 3 or 4 or 5) is contained in the numbers column. In the give example I am looking for rows with 1,2 and 3 (since they share numbers with my search string).
I am trying to do this with a single query and no loops.
Thanks!
The best solution would be to get rid of the column containing a list of values, and use a schema where each value is in its own row. Then you can use WHERE number IN (1, 2, 3, 4, 5) and join this with the table containing the rest of the data.
But if you can't change the schema, you can use a regular expression.
SELECT *
FROM yourTable
WHERE numbers REGEXP '[[:<:]](1|2|3|4|5)[[:<:]]'
[[:<:]] and [[:<:]] match the beginning and end of words.
Note that this type of search will be very slow if the table is large, because it's not feasible to index it.
Here is a start point (split string function) : http://blog.fedecarg.com/2009/02/22/mysql-split-string-function/ := SplitString(string,delimiter,position)
Create a function so it converts a string to an array := stringSplitted(string,delimiter)
Create a function so it compares two arrays :=arrayIntersect(array1, array2)
SELECT numbers
FROM table
WHERE arrayIntersect(#argument, numbers)
Two function definitions with loops and one single query without any loop
SELECT * FROM MyTable WHERE (numbers LIKE '%1%' OR numbers LIKE '%2%')
or you can also use REGEX something like this
SELECT * FROM events WHERE id REGEXP '5587$'
I have more than 12000 rows in my sql table and i want to delete exceed characters from the row if it contains more than 9 character.
Before:
Id----Title
1-----Great Day For Summer
After:
Id----Title
1-----Great Day
Use substring to get the first 9 characters.
update tablename set title = substring(title,1,9)
You can also add a where clause to make sure only too long values are updated, to keep transaction size down:
update tablename set title = substring(title,1,9)
where length(title) > 9
(Is length MySQL?)
I have a csv file that contains phone numbers, some of them have 9 digits and some of them have 10. Is there a command that would allow the transformation of the column such that numbers that have only 9 digits will have a 0 appended in front of the numbers.
For example,
if the column has values "443332332" and "0441223332", I would like to have the value of the one with 9 digits changed to "0443332332"?
Sorry, I should have elaborated.
I was wondering if there was a command to do it in SQLlite easily? I prefer not to use excel to transform the column as if I can get it to working with sqllite it would be so much easier and faster.
A more generic solution would be:
select substr('0000000000'||'1234567', -10, 10) from table_name;
The above query would always return 10 digits and add leading zeroes to the missed out number of digits.
For example, the above query would return : 0001234567
For Update, use
UPDATE TABLE_NAME SET PHONE_NO = substr('0000000000'|| PHONE_NO, -10, 10);
If you're sure that just prepending a zero on strings with length 9 will work for your application, something simple will work:
SELECT CASE WHEN LENGTH(phone_number) = 9 THEN '0'||phone_number
ELSE phone_number
END AS phone_number
FROM your_table
;
You could also update the table, depending on your needs:
UPDATE your_table
SET phone_number = '0'||phone_number
WHERE LENGTH(phone_number) = 9
;
Open the .csv using Excel,
Add a filter to the column,
Sort from A-Z to get all the columns with 9 digits,
Then follow the steps here
http://office.microsoft.com/en-au/excel-help/keep-leading-zeros-in-number-codes-HA010342581.aspx
im using a v simple database and i have 3 columns A(bigINT 20) , B(bigInt 20) and c(DECIMAL(5,4)) , when i fire the following query i get the below mentioned results :
REPLACE INTO `my_table` SET `A` = 8,`B` = 44,`C` = 14;
i get these values in mysql A =8 , b= 44 and c as 9.9999 ! ?
any ideas as to why is this happening and what can i do to resolved this ?
DECIMAL(5,4) means that the number has at most 5 digits, 4 of them after decimal point. So 14 is simply overflow as it would require DECIMAL(6,4).
It must be cleared that 14 is overflow, because as constant precision point decimal it is internally 14.0000 here (so six digits over five).
So if you try to put 14.0000 (six digits) in DECIMAL(5,4) (five digits max) -> MySQL chooses value closest to the one you request. Therefore 14.0000 gets "rounded" to 9.9999.
To fit 14 in your column you can either extend it do DECIMAL(6,4) (to allow more digits in general) or change to DECIMAL(5,3) (which will allow one more digit before decimal point, but loses some precision of course).