MySQL: Combining two queries into one row result - mysql

Question

First part of the query:
SET #centerLat = '48.531157';
SET #centerLng = '-123.782959';
SELECT user_id, lat, lng, ( 3959 * acos( cos( radians( #centerLat ) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(#centerLng) ) + sin( radians( #centerLat ) ) * sin( radians( lat ) ) ) ) AS distance FROM bid_userloc HAVING distance < 25 ORDER BY distance LIMIT 0 , 20
Second aspect is taking the user_id and grabbing a bunch of information from the USERS table
I'm still learning what JOIN even means and I don't quite understand how it all works best...

Answer 1

you may try this
SELECT user_id, lat, lng, ( 3959 * acos( cos( radians( #centerLat ) )
* cos( radians( lat ) ) * cos( radians( lng ) - radians(#centerLng) )
+ sin( radians( #centerLat ) ) * sin( radians( lat ) ) ) )
AS distance,columnsfromuserstable FROM bid_userloc bid
inner join users us on bid.user_id=us.user_id
HAVING distance < 25
ORDER BY distance LIMIT 0 , 20

Answer 2

You can try something like this:
select * from users where user_id in (select user_id from(
SELECT user_id, lat, lng, ( 3959 * acos( cos( radians( #centerLat ) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(#centerLng) ) + sin( radians( #centerLat ) ) * sin( radians( lat ) ) ) ) AS distance FROM bid_userloc HAVING distance < 25 ORDER BY distance LIMIT 0 , 20
));

Answer 3

Variant with JOIN -
SET #centerLat = '48.531157';
SET #centerLng = '-123.782959';
SELECT
t1.user_id, t1.lat, t1.lng,
(3959 * ACOS(COS(RADIANS(#centerLat)) * COS(RADIANS(t1.lat)) * COS(RADIANS(t1.lng) - RADIANS(#centerLng)) + SIN(RADIANS(#centerLat)) * SIN(RADIANS(t1.lat)))) distance,
t2.*
FROM
bid_userloc t1
JOIN users t2
ON t1.user_id = t2.user_id
HAVING
distance < 25
ORDER BY
distance
LIMIT
0, 20;