MySql query in cake php Api - mysql

for data retrieval i need to use binary keyword for case sensitive search in mysql
this is the query i want to make
SELECT username FROM users
WHERE BINARY first_name LIKE 'eph%'
OR BINARY last_name LIKE 'eph%'
OR BINARY username LIKE 'eph%'
and this is the query i have made in cakephp without binary
$this->User->find('list', array(
'fields' => array('User.username'),
'conditions' => array("OR" =>
array("BINARY User.last_name LIKE" => $search_data."%","BINARY User.username LIKE" => $search_data."%",
"BINARY User.first_name LIKE" => $search_data."%"))
));
can any 1 help me out making the binary query using cakephp api ....

Ok ... you were almost there. You only need to put the Field in a bracket to tell CakePHP not to deal with the BINARY keyword as a field name
Believe this should work:
$this->User->find('list', array(
'fields' => array('User.username'),
'conditions' => array(
"OR" =>array(
"BINARY (`User`.`last_name`) LIKE" => $search_data."%",
"BINARY (`User`.`username`) LIKE" => $search_data."%",
"BINARY (`User`.`first_name`) LIKE" => $search_data."%"))
));

Related

Yii2 - QueryAll is having issue

I am using Query Builder with multiple where clause. When I use this query,
$query1 = new \yii\db\Query();
$query1->select('*')
->from('assessment_score ca')
->where(['AND','ca.is_status' => 0, 'ca.assessment_type' => 'CONTINUOUS ASSESSMENT', 'ca.ca_type' => 'CONTINUOUS ASSESSMENT'])
->andFilterWhere(['ca.state_office_id' => $model->report_state_office_id])
->andFilterWhere(['ca.study_centre_id' => $model->report_study_centre_id])
->andFilterWhere(['ca.programme_id' => $model->report_programme_id])
->andFilterWhere(['ca.department_id' => $model->report_department_id])
->andFilterWhere(['ca.academic_level_id' => $model->report_academic_level_id])
->andFilterWhere(['ca.academic_year_id' => $model->report_academic_year_id])
->andFilterWhere(['ca.academic_semester_id' => $model->report_academic_semester_id])
->andFilterWhere(['ca.course_id' => $model->report_course_id]);
$command=$query1->createCommand();
$ca_data=$command->queryAll();
I got this error
Then, when I changed the code to this, no response:
$selected_list = $_POST['ca'];
$query1 = new \yii\db\Query();
$query1->select('*')
->from('assessment_score ca')
->where(['ca.is_status' => 0])
->andWhere(['ca.assessment_type' => 'CONTINUOUS ASSESSMENT'])
->andWhere(['ca.ca_type' => 'CONTINUOUS ASSESSMENT'])
->andFilterWhere(['ca.state_office_id' => $model->report_state_office_id])
->andFilterWhere(['ca.study_centre_id' => $model->report_study_centre_id])
->andFilterWhere(['ca.programme_id' => $model->report_programme_id])
->andFilterWhere(['ca.department_id' => $model->report_department_id])
->andFilterWhere(['ca.academic_level_id' => $model->report_academic_level_id])
->andFilterWhere(['ca.academic_year_id' => $model->report_academic_year_id])
->andFilterWhere(['ca.academic_semester_id' => $model->report_academic_semester_id])
->andFilterWhere(['ca.course_id' => $model->report_course_id]);
$command=$query1->createCommand();
$ca_data=$command->queryAll();
How do I re-write the code appropriately to solve the issue of multiple where clause?
You might need to change the query format for the where() statement as you need to provide every condition (name=>value pair) as a separate array rather than just name=>value pairs, you currently have
->where(['AND', 'ca.is_status' => 0, 'ca.assessment_type' => 'CONTINUOUS ASSESSMENT', 'ca.ca_type' => 'CONTINUOUS ASSESSMENT'])
which will create the query like below if no other parameter is provided for andFilterWhere() statements.
SELECT * FROM `assessment_score` `ca`
WHERE (0)
AND (CONTINUOUS ASSESSMENT) AND (CONTINUOUS ASSESSMENT)
which is incorrect and throwing the error, you can notice that in your Exception image, so change it to the one below
->where(['AND',
['ca.is_status' => 0],
['ca.assessment_type' => 'CONTINUOUS ASSESSMENT'],
['ca.ca_type' => 'CONTINUOUS ASSESSMENT']
])
which will output the query like
SELECT * FROM `assessment_score` `ca`
WHERE (`ca`.`is_status`=0)
AND (`ca`.`assessment_type`='CONTINUOUS ASSESSMENT')
AND (`ca`.`ca_type`='CONTINUOUS ASSESSMENT')
Your complete query should look like this
$query1 = new \yii\db\Query();
$query1->select('*')
->from('assessment_score ca')
->where(['AND',
['ca.is_status' => 0],
['ca.assessment_type' => 'CONTINUOUS ASSESSMENT'],
['ca.ca_type' => 'CONTINUOUS ASSESSMENT']
])
->andFilterWhere(['ca.state_office_id' => $model->report_state_office_id])
->andFilterWhere(['ca.study_centre_id' => $model->report_study_centre_id])
->andFilterWhere(['ca.programme_id' => $model->report_programme_id])
->andFilterWhere(['ca.department_id' => $model->report_department_id])
->andFilterWhere(['ca.academic_level_id' => $model->report_academic_level_id])
->andFilterWhere(['ca.academic_year_id' => $model->report_academic_year_id])
->andFilterWhere(['ca.academic_semester_id' => $model->report_academic_semester_id])
->andFilterWhere(['ca.course_id' => $model->report_course_id]);
$command = $query1->createCommand();
$ca_data = $command->queryAll();
based on yii2 guide for Operator Format
Operator format allows you to specify arbitrary conditions in a
programmatic way. It takes the following format:
[operator, operand1, operand2, ...] where the operands can each be
specified in string format, hash format or operator format
recursively, while the operator can be one of the following:
and: the operands should be concatenated together using AND. For
example, ['and', 'id=1', 'id=2']
so in your case should be
->where(['AND', 'ca.is_status = 0',
"ca.assessment_type = 'CONTINUOUS ASSESSMENT'",
"ca.ca_type = 'CONTINUOUS ASSESSMENT'"])
https://www.yiiframework.com/doc/guide/2.0/en/db-query-builder#operator-format
All you need is to remove AND from array passed to where():
->where([
'ca.is_status' => 0,
'ca.assessment_type' => 'CONTINUOUS ASSESSMENT',
'ca.ca_type' => 'CONTINUOUS ASSESSMENT'
])
If you pass associative array, it will be treated as pairs of column-value for conditions for WHERE in query. If you pass AND as first element, it is no longer a associative array, and query builder will ignore keys and only combine values as complete condition.

CakePHP 3 quoting function names defined in 'fields' configuration of my find() call

I am querying a database table conveniently named order and because of that I had to set 'quoteIdentifiers' => true in my app.php configuration. However, when I'm putting function names into the fields configuration of my find() call, CakePHP quotes them too.
$orders->find('all', array(
'fields' => array(
'DATE(Orders.date_added)',
'COUNT(*)',
),
'conditions' => array(
'Orders.order_status_id <>' => 0,
),
'group' => array(
'DATE(Orders.date_added)',
),
));
The query above ends up calling
SELECT <...>, `DATE(Orders.date_added)` FROM `order` <...>
which obviously throws an error.
I googled a lot, tried this:
$orders = $orders->find('all', array(
'conditions' => array(
'Orders.order_status_id <>' => 0,
),
'group' => array(
'DATE(Orders.date_added)',
),
))->select(function($exp) {
return $exp->count('*');
});
and that didn't work either, throwing me some array_combine error.
Is there any way for me to un-quote those function names, while keeping the rest of the query quoted automatically? Here's what I'm trying to accomplish:
SELECT <...>, DATE(Orders.date_added) FROM `order` <...>
Please help.
You should use function expressions, they will not be quoted, except for arguments that are explicitly being defined as identifiers:
$query = $orders->find();
$query
->select([
'date' => $query->func()->DATE([
'Orders.date_added' => 'identifier'
]),
'count' => $query->func()->count('*')
])
->where([
'Orders.order_status_id <>' => 0
])
->group([
$query->func()->DATE([
'Orders.date_added' => 'identifier'
])
]);
I'd generally suggest that you use expressions instead of passing raw SQL snippets wherever possible, it makes generating SQL more flexible, and more cross-schema compatible.
See also
Cookbook > Database Access & ORM > Query Builder > Using SQL Functions

Mysql CakePHP 2.0

I want to make a MySQL query in CakePHP 2.0 which looks like this:
select p.ciname HOSTNAME
,a.status HPSA
,m.status SM9
,p.status LDAP
from hpsas a, hpsms m, ldaps p
where (p.ciname = a.ciname)
and (p.ciname = m.ciname)
order by p.ciname;
Is this possible?
You can make arbitrary SQL queries in CakePHP using the Model.query() method. For example, in a controller:
$sql = ...your sql here...
$results = $this->ModelName->query($sql);
if you are trying to make this query using cake ORM I think this would be a step in that direction:
$options = array();
$options['fields'] => array('p.ciname AS HOSTNAME', 'a.status AS HPSA', 'm.status AS SM9', 'p.status AS LDAP');
$options['joins'][] => array('table' => 'hpsas', 'alias' => 'a', 'conditions' => array('p.ciname = a.ciname'));
$options['joins'][] => array('table' => 'hpsms', 'alias' => 'm', 'conditions' => array('p.ciname = m.ciname'));
$result = $this->Test->find('all', $options);
Those fields and table names don't comply with cake convention, understandable if you are migrating or integrating your project. If you are starting now, you might want to rename them.
http://book.cakephp.org/1.3/en/view/901/CakePHP-Conventions

return only column name values from mysql table

sorry but i didn't knew how to explain the question in on sentence...
actually i have code like this when i do mysql_fetch_array...
[0] => 10
[id] => 10
[1] => 58393
[iid] => 58393
[2] => 0
[ilocationid] => 0
[3] => 38389
[iapptid] => 38389
[4] => 2012-06-30T00:00:00
[ddate] => 2012-06-30T00:00:00
[5] => 1000
[ctimeofday] => 1000
but i want to return something like this
[id] => 10
[iid] => 58393
[ilocationid] => 0
[iapptid] => 38389
[ddate] => 2012-06-30T00:00:00
[ctimeofday] => 1000
i mean without the numeric representatives of the columns. how do i do it...please help...
As explained in the manual for PHP's mysql_fetch_array() function:
The type of returned array depends on how result_type is defined. By using MYSQL_BOTH (default), you'll get an array with both associative and number indices. Using MYSQL_ASSOC, you only get associative indices (as mysql_fetch_assoc() works), using MYSQL_NUM, you only get number indices (as mysql_fetch_row() works).
Therefore, you want either:
mysql_fetch_array($result, MYSQL_ASSOC);
or
mysql_fetch_assoc($result);
Note however the warning:
Use of this extension is discouraged. Instead, the MySQLi or PDO_MySQL extension should be used. See also MySQL: choosing an API guide and related FAQ for more information. Alternatives to this function include:
mysqli_fetch_array()
PDOStatement::fetch()

Joins - Merge result into single, multidimensional array

I'm performing a simple query that joins two tables together. What I get is something like this.
array(
[0] => array(
'id' => 52
'name' => 'charles',
'sale_id' => 921,
'sale_time' => 1306393996,
'sale_price' => 54.21
),
[1] => array(
'id' => 52
'name' => 'charles',
'sale_id' => 922,
'sale_time' => 1306395000,
'sale_price' => 32.41
),
...
);
...which is the expected result. However, I'd like the query to return something like this:
array(
[0] => array(
'id' => 52,
'name' => 'charles',
'sales' => array(
[0] => array(
'sale_id' => 921,
'sale_time' => 1306393996,
'sale_price' => 54.21
),
[1] => array(
'sale_id' => 922,
'sale_time' => 1306395000,
'sale_price' => 32.41
),
...
)
)
)
Now I realize I could simply perform two queries, one for the user info, and another for sales, and merge those arrays together using whatever language I'm using (PHP in this case). But I have many arrays of properties and querying and merging for those seems awfully inelegant to me (although it does work). It seems to me there'd be a way to work with a single, unified object without duplicating data.
Just wondering if there was a no-brainer query, or if that's simply not easy through MySQL alone.
I would say this is not possible with MySQL alone - you have to do some tricks at application level. That is, because even if you send a single query that will bring you all the data from MySQL to your application (PHP), they will come as a denormalized array of data - your first case.
If you want to get the data as in your second case, I'd recommend using some ORM - in Ruby there is ActiveRecord, in Perl there are Class::DBi, DBIx::Class and many more - I can not name one for PHP that is able to do this, but I am sure there are plenty.